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| Tags: doesnt, electron, hand, here, obey, right, rule |
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#1
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At the web link below: the electron gets fired from an electron gun
and it's deflection doesn't obey the right hand rule? In fact it deflects towards the magnets and in relation with it's spin? http://www.upscale.utoronto.ca/Gener...rnGerlach.html (PS: look at spin of the electron section as opposed to spin of ball section) QUOTE: "One half of the electrons in the beam are deflected up, the other half were deflected down." QUOTE: "It seems that the "spin" of electrons comes in only two states......For some electrons, the spin axis is what we are calling "spin up", for others "spin down." |
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#2
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On Jul 27, 9:20 pm, " wrote:
At the web link below: the electron gets fired from an electron gun and it's deflection doesn't obey the right hand rule? In fact it deflects towards the magnets and in relation with it's spin? [...] What, "elements of physics" doesn't cover quantum mechanics and the Stern-Gerlach experiment? Imagine that. Electrons don't "obey the right hand rule". The right hand rule is simply a convention used to decide where the resultant of a cross product will point. |
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#4
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On Jul 28, 4:45 am, "T.M. Sommers" wrote:
wrote: At the web link below: the electron gets fired from an electron gun and it's deflection doesn't obey the right hand rule? In fact it deflects towards the magnets and in relation with it's spin? http://www.upscale.utoronto.ca/Gener.../SternGerlach/... (PS: look at spin of the electron section as opposed to spin of ball section) QUOTE: "One half of the electrons in the beam are deflected up, the other half were deflected down." QUOTE: "It seems that the "spin" of electrons comes in only two states......For some electrons, the spin axis is what we are calling "spin up", for others "spin down." The situation being discussed here earlier involved a uniform magnetic field. The Stern-Gerlach experiment uses a non-uniform field. In the case of a non-uniform field, there is an additional force on the charge due to the gradient of the field, and this additional force is what causes the vertical separation. Actually, this force is always present, but when the field is uniform, the gradient, and thus the force, are zero, and they are ignored, especially in more elementary contexts. At the web link, the Nrth magnet only is pointy, would anything different happen if the South magnet "also" had the same shape? -- Thomas M. Sommers -- -- AB2SB- Hide quoted text - - Show quoted text - |
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#5
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wrote:
On Jul 28, 4:45 am, "T.M. Sommers" wrote: wrote: At the web link below: the electron gets fired from an electron gun and it's deflection doesn't obey the right hand rule? In fact it deflects towards the magnets and in relation with it's spin? http://www.upscale.utoronto.ca/Gener.../SternGerlach/... (PS: look at spin of the electron section as opposed to spin of ball section) QUOTE: "One half of the electrons in the beam are deflected up, the other half were deflected down." QUOTE: "It seems that the "spin" of electrons comes in only two states......For some electrons, the spin axis is what we are calling "spin up", for others "spin down." The situation being discussed here earlier involved a uniform magnetic field. The Stern-Gerlach experiment uses a non-uniform field. In the case of a non-uniform field, there is an additional force on the charge due to the gradient of the field, and this additional force is what causes the vertical separation. Actually, this force is always present, but when the field is uniform, the gradient, and thus the force, are zero, and they are ignored, especially in more elementary contexts. At the web link, the Nrth magnet only is pointy, would anything different happen if the South magnet "also" had the same shape? The B field would be different, so of course the results would be different. I don't feel like calculating it, though. -- Thomas M. Sommers -- -- AB2SB |
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#6
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On Jul 28, 9:45 pm, "T.M. Sommers" wrote:
wrote: On Jul 28, 4:45 am, "T.M. Sommers" wrote: wrote: At the web link below: the electron gets fired from an electron gun and it's deflection doesn't obey the right hand rule? In fact it deflects towards the magnets and in relation with it's spin? http://www.upscale.utoronto.ca/Gener.../SternGerlach/... (PS: look at spin of the electron section as opposed to spin of ball section) QUOTE: "One half of the electrons in the beam are deflected up, the other half were deflected down." QUOTE: "It seems that the "spin" of electrons comes in only two states......For some electrons, the spin axis is what we are calling "spin up", for others "spin down." The situation being discussed here earlier involved a uniform magnetic field. The Stern-Gerlach experiment uses a non-uniform field. In the case of a non-uniform field, there is an additional force on the charge due to the gradient of the field, and this additional force is what causes the vertical separation. Actually, this force is always present, but when the field is uniform, the gradient, and thus the force, are zero, and they are ignored, especially in more elementary contexts. At the web link, the Nrth magnet only is pointy, would anything different happen if the South magnet "also" had the same shape? The B field would be different, so of course the results would be different. I don't feel like calculating it, though. Ok, at the same web link, the deflections seem to be the same magnitude toward the Nrth and towards the Sth magnet even though only the Nrth is receded and not the South magnet. -- Thomas M. Sommers -- -- AB2SB- Hide quoted text - - Show quoted text - |
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#7
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On Jul 29, 12:44 pm, " wrote:
On Jul 28, 9:45 pm, "T.M. Sommers" wrote: wrote: On Jul 28, 4:45 am, "T.M. Sommers" wrote: wrote: At the web link below: the electron gets fired from an electron gun and it's deflection doesn't obey the right hand rule? In fact it deflects towards the magnets and in relation with it's spin? http://www.upscale.utoronto.ca/Gener.../SternGerlach/... (PS: look at spin of the electron section as opposed to spin of ball section) QUOTE: "One half of the electrons in the beam are deflected up, the other half were deflected down." QUOTE: "It seems that the "spin" of electrons comes in only two states......For some electrons, the spin axis is what we are calling "spin up", for others "spin down." The situation being discussed here earlier involved a uniform magnetic field. The Stern-Gerlach experiment uses a non-uniform field. In the case of a non-uniform field, there is an additional force on the charge due to the gradient of the field, and this additional force is what causes the vertical separation. Actually, this force is always present, but when the field is uniform, the gradient, and thus the force, are zero, and they are ignored, especially in more elementary contexts. At the web link, the Nrth magnet only is pointy, would anything different happen if the South magnet "also" had the same shape? The B field would be different, so of course the results would be different. I don't feel like calculating it, though. Ok, at the same web link, the deflections seem to be the same magnitude toward the Nrth and towards the Sth magnet even though only the Nrth is receded and not the South magnet. Learn some physics. "north magnet" and "south magnet" mean absolutely nothing. -- Thomas M. Sommers -- -- AB2SB- Hide quoted text - - Show quoted text - |
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#8
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wrote:
On Jul 28, 9:45 pm, "T.M. Sommers" wrote: wrote: On Jul 28, 4:45 am, "T.M. Sommers" wrote: wrote: At the web link below: the electron gets fired from an electron gun and it's deflection doesn't obey the right hand rule? In fact it deflects towards the magnets and in relation with it's spin? http://www.upscale.utoronto.ca/Gener.../SternGerlach/... (PS: look at spin of the electron section as opposed to spin of ball section) QUOTE: "One half of the electrons in the beam are deflected up, the other half were deflected down." QUOTE: "It seems that the "spin" of electrons comes in only two states......For some electrons, the spin axis is what we are calling "spin up", for others "spin down." The situation being discussed here earlier involved a uniform magnetic field. The Stern-Gerlach experiment uses a non-uniform field. In the case of a non-uniform field, there is an additional force on the charge due to the gradient of the field, and this additional force is what causes the vertical separation. I should have said the force is on the charge's magnetic moment. Actually, this force is always present, but when the field is uniform, the gradient, and thus the force, are zero, and they are ignored, especially in more elementary contexts. At the web link, the Nrth magnet only is pointy, would anything different happen if the South magnet "also" had the same shape? The B field would be different, so of course the results would be different. I don't feel like calculating it, though. Ok, at the same web link, the deflections seem to be the same magnitude toward the Nrth and towards the Sth magnet even though only the Nrth is receded and not the South magnet. There is only one B field, not one for one magnet and a different one for the other magnet. -- Thomas M. Sommers -- -- AB2SB |
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