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| Tags: but, dilation, recession, redshift, speed, time |
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#21
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On Sun, 24 Jun 2007 00:01:20 -0700, Roland PJ
wrote: Red-shift of distant objects could be due to two different reasons: 1. Recession speed away from the earth, a special relativistic effect. 2. Time dilation due to proximity to a concentration of mass, a general relativistic effect. Gravitational redshift is far weaker than Doppler. Here's a couple of figures, for a "nearby" star at 1 million LY. H*D = 27,560 m/s more or less Redshift is 9.1x10^-5 both Doppler Redshift at Sun is 635 m/s (and, presumably for typical star) z = 2x10^-6 so doppler is about 43 times as much. The tolerances on distance, the Hubble constant, mass of star, make it difficult to separate the two. In this case you could guess the redshift/distance is "fat" by 1/43. For a star at 1 billion LY, z = .1 or so from Doppler, but the gravitational remains a low 2e-6 as above. It seems that most discussion of red-shift centres around the assumption that SR recession is the cause (and hence that the universe is expanding). Why has GR time dilation been eliminated as a cause? So, why should most objects exhibit a red-shift, rather than a neutral average shift? My best answer is that we, on earth, are at the edge of our galaxy (the milky way), and hence quite far from the concentration of mass near the centre of our galaxy. On the other hand, most matter (stars) in the universe are close to the centre of their galaxies, so, on average, most objects should exhibit a red-shift to us on earth. A corollary of this is that stars near the centre of our own galaxy (the milky way) should also exhibit red-shift to us (even though they are clearly not moving away from us on average). This should be testable, although I'm not sure how one would identify a bright object as a star in the center of our galaxy, rather than a distant object shining through (brightness?). Hubble, Edwin, "A Relation between Distance and Radial Velocity among Extra-Galactic Nebulae" (1929) Proceedings of the National Academy of Sciences of the United States of America, Volume 15, Issue 3, pp. 168-173 Note that Hubble (and presumably all that follow) use _luminosity_ as a measure of _distance_. However, luminosity is actually also a measure of GR time dilation, independent of distance, as described above. Just some ideas. Flame away ![]() Roland John Polasek |
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#22
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On Jun 24, 2:27 am, Roland PJ wrote:
[...] Ugh. You don't know what Hubble's law is. You don't understand Cephid variables. You don't understand why time dilation is not a viable explanation. http://en.wikipedia.org/wiki/Cepheid_variables http://www.astro.ucla.edu/~wright/cosmolog.htm |
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#23
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Dear Roland PJ:
"Roland PJ" wrote in message oups.com... On Jun 24, 8:02 pm, "N:dlzc D:aol T:com \(dlzc\)" wrote: Dear Roland PJ: "Roland PJ" wrote in message oups.com... Red-shift of distant objects could be due to two ... or more ... different reasons: 1. Recession speed away from the earth, a special relativistic effect. ... also just classical Doppler. Except it needs finite light speed doesn't it, which was one of the foundations of SR? I'd better check ![]() Classical Doppler shift does require finite "wave" speed. Recession red shift could simply be classical Doppler, without invoking Minkowski spacetime. Just another "reason" to add to the list. 2. Time dilation due to proximity to a concentration of mass, a general relativistic effect. No. We can measure gravitational time dialtion in the spectrum of the sources. Distant sources are more redshifted... regardless of their mass, only their distance. Um, how can spectral analysis discriminate between time- dilation and recession (or expansion, if you like)? The spectra are shifted in both case, not so? Can you explain some more? The spectra are shifted more, if the source is further away. We cannot discern from the shift alone all we need to know. But what we do see, is that similar stars / objects, have spectra that are red shifted more, the more distant they are. This means they have to be uniformly more massive (to use your "reason"), the physics had to be different in the past, or more simply more space is being created between objects. "Uniformly more massive with distance" is not possible, since the stars could not produce the spectra we do see. They would become supernovae, neutron stars, or black holes. The "different physics" is a possibility, in which case we have no model at all to use. "More space created" is in line with the second law of thermodynamics, and is not an irreconcilable violation of any of the other conservation laws. What you picture will require special physics as a function of distance, to red shift more distant stars more than gravitation red shift shifts the same size and type of star locally. OK, I have no idea what you mean by this. Hopefully clearer now. We see the equivalent of Sagitarius-A locally and far away. If Sagitarius-A were more massive to yield the red shift, then I collapses into a neutron star... and is not like Sagitarius-A. Same for massive galaxies... their rotation curves do not correlate to being more massive the further they are from us. So, why should most objects exhibit a red-shift, rather than a neutral average shift? Because there is increased space(time) between you and the source between instants. Imagine space(time) as sal****er taffy stretched between your two hands, with your hands as two distant stars. As time goes on (weather permitting) the taffy stretches, and the distance between the two "stars" (measured along the taffy) increases and signals between them take longer (red shift). From this poor analogy, better ones are the balloon analogy and the raisin bread analogy. Note that I was trying to answer this question according to my theory, not pose it . Yes, I can see thatexpansion theories explain the Hubble red-shift phenomenon. I was simply trying to propose a simpler solution, namely plain old GR in a non-expanding universe. Occam's razor and all. Fails the most simple tests. You asked if it could be, and no it cannot. *That* way. Now consider emission of a spectra from a star in a Universe with a certain global curvature, but received in a more expanded Universe with a more "relaxed" curvature. The spectra would be seen as redshifted due to gravitational time dilation... between *time of emission* and *time of absorbance*. Not "place" but "when". My best answer is that we, on earth, are at the edge of our galaxy (the milky way), Not quite... we are about halfway out. 2/3 if you want to nit-pick ![]() and hence quite far from the concentration of mass near the centre of our galaxy. Doesn't matter. The spectra locally (inclusive of even the Andromeda galaxy) are unsurprising. And we have all sorts of candidates visible locally. Yes it does matter. GR time dilation is directly related to your matter/energy environment. The fact that we are at the edge of our galaxy means that matter near the denser core is red-shifted relative to us. As Eric has pointed out, this difference might be too small to matter, but you can't just wave it away with a magic wand without doing the sums (which I intend to do... see questions below). How is this different for the "central mass" of a distant galaxy? The *whole curve* is redshifted... central stars or rim stars. Or perhaps we are missing each other here - I'm not sure how your 'spectra' comment relates. Or are you saying that the spectra from stars all over the milky way display no shift at all? Shifts similar to other members of the Milky Way. Shifts similar to other members of the Andromeda galaxy. Shifts *different* for similar objects outside the Virgo supercluster. In which case time dilation clearly can't be a factor within our own galaxy. It is "in the dirt". It can theoretically be measured, but is "orthogonal" to the problem you wish to solve. You want to get at why a distant Milky-Way-like object doesn't have an identical spectra to our Milky Way et al. You really are not interested in the distribution across a single object... because after a certain distance, they get resolved (if at all) en masse. If you are interested in more than your own ideas, you can start he http://www.astro.ucla.edu/~wright/cosmolog.htm http://www.astro.ucla.edu/~wright/cosmo_01.htm ... and if you have questions, you can either ask here or on sci.astro. Thanks for the links. Will follow them up. Now, what I really need to see whether my idea has any legs is an accurate map of the Milky Way. Way different than describing Hubble red shift, which is where I thought you wanted to go. David A. Smith |
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#24
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On Jun 24, 11:49 pm, John C. Polasek wrote:
On Sun, 24 Jun 2007 00:01:20 -0700, Roland PJ wrote: Red-shift of distant objects could be due to two different reasons: 1. Recession speed away from the earth, a special relativistic effect. 2. Time dilation due to proximity to a concentration of mass, a general relativistic effect. Gravitational redshift is far weaker than Doppler. Here's a couple of figures, for a "nearby" star at 1 million LY. H*D = 27,560 m/s more or less Redshift is 9.1x10^-5 both Doppler Redshift at Sun is 635 m/s (and, presumably for typical star) z = 2x10^-6 so doppler is about 43 times as much. Oh. You've calculated the GR red-shift due to the mass of the star itself. Right? I'm actually surprised it's so big. What I'm more interested in is the GR effects due to the surrounding mass (the star's galaxy in particular). For isolated stars out on the edge of galaxies the answer should be as the above. But for stars near the middle of galaxies there should be arbitrary red-shift depending on how close they are to the center of the galaxy, and how dense the centre is. It seems to be generally proposed that there are 'black holes' at the centre of most galaxies. And the crux is that 'most' stars are collected in the centre of the galaxy. To find out the 'typical' red-shift of the average star then, we need to know the star density gradient of the 'average' galaxy. I have no ide how to obtain this gradient density. Thanks for the help. Regards Roland |
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#25
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Now, what I really need to see whether my idea has any legs is an accurate map of the Milky Way. Way different than describing Hubble red shift, which is where I thought you wanted to go. David, thanks again for your considered response. Let me start again by explaining my reasoning from scratch. It seems to be plausible that the centre of galaxies is very dense. In fact, it seems to be generally held that the centre of our Milky Way is dense enough to be described as a 'black hole'. An immediate consequence of this is that stars 'near' the centre of a galaxy will be red-shifted according to the enormous GR effects of the centre of the galaxy itself. Indeed, consider a Cepheid variable living near the center of the Milky Way. This Cepheid will be subject to much larger GR effects than us on earth, so we will view it, on earth, as being red-shifted, dim, and having a larger period, than what is experienced in the Cepheid's own frame. I don't think any of the above is contentious at all. It's a well understood consequence of GR. So, at least some of the stars in a galaxy will display exaggerated red-shifts and dimness, due to their position near the middle of the galaxy, and due to GR time dilation, not expansion or recession speed. What I want to know is 'How many stars in a typical galaxy have an exaggerated red-shift and dimness'. This depends critically on the star density function towards the middle of a galaxy. In other words, what proportion of the stars are close enough to the middle to be affected by GR effects. It's clear that, for any galaxy with a dense centre, at least _some_ stars will have red-shifts dominated by GR time-dilation effects. What I'm asking, is how many stars will have red-shifts (as viewed on earth) that are dominated by GR time-dilation, rather than universal expansion, or recession. Is it 0.0001% (i.e. irrelevent). Is it 10% (interesting). Is it 90% (in which case the standard Hubble constant is broken by GR). Do you understand now why I need a 'map' of the Milky Way. It seems that the Milky Way itself is close enough to map all stars with red- shift-free methods, such as the parallax methods. I can do some relatively (no pun intended) simple estimations of the GR effect, but I need to know the mass density function towards the centre. Regards Roland |
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#26
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Dear Roland PJ:
On Jun 25, 2:16 am, Roland PJ wrote: .... What I'm asking, is how many stars will have red-shifts (as viewed on earth) that are dominated by GR time- dilation, rather than universal expansion, or recession. Is it 0.0001% (i.e. irrelevent). Is it 10% (interesting). Is it 90% (in which case the standard Hubble constant is broken by GR). The answer is "about 0%". Spiral galaxies *all* have massive centers. So comparison of spiral galaxies is inclusive of the center, the arms, and probably some contribution from the attendant globular clusters. Compare a galaxy to a bus-load of people. You think that you need to analyze the bus-load you are in, to be able to analyze / compare / contrast other bus loads visible. It might help you compare the Milky Way to Andromeda to do this, but it won't help you with galaxies outside our supercluster. Do you feel the distant "bus loads of people" are significantly different than the bus on the Andromeda route? If so, why? David A. Smith |
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#27
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On Jun 25, 5:38 pm, dlzc wrote:
Dear Roland PJ: On Jun 25, 2:16 am, Roland PJ wrote: ... What I'm asking, is how many stars will have red-shifts (as viewed on earth) that are dominated by GR time- dilation, rather than universal expansion, or recession. Is it 0.0001% (i.e. irrelevent). Is it 10% (interesting). Is it 90% (in which case the standard Hubble constant is broken by GR). The answer is "about 0%". Spiral galaxies *all* have massive centers. So comparison of spiral galaxies is inclusive of the center, the arms, and probably some contribution from the attendant globular clusters. Compare a galaxy to a bus-load of people. You think that you need to analyze the bus-load you are in, to be able to analyze / compare / contrast other bus loads visible. It might help you compare the Milky Way to Andromeda to do this, but it won't help you with galaxies outside our supercluster. Do you feel the distant "bus loads of people" are significantly different than the bus on the Andromeda route? If so, why? No. I'm just trying to understand the Milky Way better, under the assumption that it's somewhat 'typical'. So, some specific questions, which might be more fruitful: What's the greatest red-shift we have measured for an object that's definitely in the Milky Way (according to parallax, for example). And, generalising this, what proportion of stars in the Milky Way do we find at various red-shifts? And, then another specific question, but not directly related (it came up earlier in the thread): http://en.wikipedia.org/wiki/Andromeda_Galaxy This says that Andromeda is estimated to contain 10^12 stars (compared to the Milky Way's ~ 10^11 estimated?), but that the masses only differ by about 80%. Is it really true that average star sizes can vary by so much between galaxies. I'd expect similar physics at this vast scale to provide almost identical statistical populations. Thanks for taking the time to answer my questions. Kind regards Roland |
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#28
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On Jun 25, 7:41 pm, Sam Wormley wrote:
Roland PJ wrote: And, generalising this, what proportion of stars in the Milky Way do we find at various red-shifts? The red/blue shifts for stars in the Milky way are not relativistic, but simply Doppler effect due to relative motion between the star and the earth. The sensitivity of measurement approaches 1 m/s. Hi Sam - if there's a 'black hole' at the centre, then there _must_ be some GR red-shifted objects nearby, surely? Roland |
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#29
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Dear Roland PJ:
On Jun 25, 10:34 am, Roland PJ wrote: On Jun 25, 5:38 wrote: Dear Roland PJ: On Jun 25, 2:16 am, Roland PJ wrote: ... What I'm asking, is how many stars will have red-shifts (as viewed on earth) that are dominated by GR time- dilation, rather than universal expansion, or recession. Is it 0.0001% (i.e. irrelevent). Is it 10% (interesting). Is it 90% (in which case the standard Hubble constant is broken by GR). The answer is "about 0%". Spiral galaxies *all* have massive centers. So comparison of spiral galaxies is inclusive of the center, the arms, and probably some contribution from the attendant globular clusters. Compare a galaxy to a bus-load of people. You think that you need to analyze the bus-load you are in, to be able to analyze / compare / contrast other bus loads visible. It might help you compare the Milky Way to Andromeda to do this, but it won't help you with galaxies outside our supercluster. Do you feel the distant "bus loads of people" are significantly different than the bus on the Andromeda route? If so, why? No. I'm just trying to understand the Milky Way better, under the assumption that it's somewhat 'typical'. The Milky Way bus is filled with people as tall as you, with only a few taller. Also there are some serious smokers, that smoke so much you can't even see the middle of the bus, unless someone is poking his head above / below the smoke. The Milky Way is not necessarily typical, so lets concentrate on Andromeda, which is much more visible. I will attempt to answer based on assuming "Milky Way" = "Andromeda" So, some specific questions, which might be more fruitful: What's the greatest red-shift we have measured for an object that's definitely in the Milky Way (according to parallax, for example). Nearly zero. Gravitational red shift would be measured from the coronasphere of the star, which is not under many Gs if it is luminous enough to see. This leaves neutron stars which we have detected emissions from, and they are in X-ray energies... since infalling particles are the source and had that much "potential energy" starting out ... that is what we see spalling from the surface on collision. And, generalising this, what proportion of stars in the Milky Way do we find at various red-shifts? Inconsequential. Lump it as "the spectra from a red giant" (for example) and move on. It is a very small gravitational shift from a luminous object, and should be the same as a similar mass red giant star in a very distant galaxy. And, then another specific question, but not directly related (it came up earlier in the thread): http://en.wikipedia.org/wiki/Andromeda_Galaxy This says that Andromeda is estimated to contain 10^12 stars (compared to the Milky Way's ~ 10^11 estimated?), but that the masses only differ by about 80%. Is it really true that average star sizes can vary by so much between galaxies. I'd expect similar physics at this vast scale to provide almost identical statistical populations. We cannot see the middle of the bus. We could be in the rarefied space between two arms. What should we expect then? And yes, I would expect a lot of variation in the populations of stars, depending on the age and type of the galaxy. David A. Smith |
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#30
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On Jun 25, 7:53 pm, Sam Wormley wrote:
Roland PJ wrote: On Jun 25, 7:41 pm, Sam Wormley wrote: Roland PJ wrote: And, generalising this, what proportion of stars in the Milky Way do we find at various red-shifts? The red/blue shifts for stars in the Milky way are not relativistic, but simply Doppler effect due to relative motion between the star and the earth. The sensitivity of measurement approaches 1 m/s. Hi Sam - if there's a 'black hole' at the centre, then there _must_ be some GR red-shifted objects nearby, surely? Roland Gas falling into the black hole can exhibit gravitational red shift. But this is local near the event horizon(s) of the black hole... not a galactic phenomenon... do the calculations. Sure. I'm busy gathering data... Wheeler reckons the 'black hole' at the center of the milky way is estimated to be 3.8 x 10^9 m, which is ~ 3 x 10^-6 light years (is that right?) Not very big, is it, on a galactic scale? Thanks Roland |
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