Are electric and magnetic fields merely distortions of spacetime?

wrote:

Are electric and magnetic fields merely distortions of spacetime?


No.

wrote in message ups.com...
Are electric and magnetic fields merely distortions of spacetime?

There have been attempts to model electromagnetism that way.
See:
http://en.wikipedia.org/wiki/Kaluza-Klein_theory
for example.

Martin Hogbin

wrote:
Are electric and magnetic fields merely distortions of spacetime?

1) Yes.
2) No.
3) Maybe so.

We don't know which.

wrote:
Are electric and magnetic fields merely distortions of spacetime?

Yes, electric and magnetic fields could be viewed as 'distortions' of
space-time or dynamic deformations in the space continuum with physical
properties of eps_0 and mu_0. Let U be a time dependent 'displacement'
vector in the space continuum such that it satisfies the Maxwell's
vector wave equation

Del^2(U) = (1/c^2) D^2(U)/Dt^2 ...... (1)
where D represents the partial derivative symbol.

A solution of equation (1) for U that satisfies the essential boundary
conditions, will represent a transverse wave field if Del.U = 0.
Further, we may identify U with the conventional electric and magnetic
fields E & B in 'free space' through the identities,

E = - (1/eps_0).(1/c). DU/Dt
and B = (1/c).(1/eps_0).(Del X U).

The displacement vector field U will now satisfy all the
electromagnetic field equations that are satisfied by E & B in 'free
space'.

GSS

GSS wrote:
wrote:
Are electric and magnetic fields merely distortions of spacetime?

Yes, electric and magnetic fields could be viewed as 'distortions' of
space-time or dynamic deformations in the space continuum with physical
properties of eps_0 and mu_0. Let U be a time dependent 'displacement'
vector in the space continuum such that it satisfies the Maxwell's
vector wave equation

Del^2(U) = (1/c^2) D^2(U)/Dt^2 ...... (1)
where D represents the partial derivative symbol.

A solution of equation (1) for U that satisfies the essential boundary
conditions, will represent a transverse wave field if Del.U = 0.
Further, we may identify U with the conventional electric and magnetic
fields E & B in 'free space' through the identities,

E = - (1/eps_0).(1/c). DU/Dt
and B = (1/c).(1/eps_0).(Del X U).

The displacement vector field U will now satisfy all the
electromagnetic field equations that are satisfied by E & B in 'free
space'.

GSS

If electron motion causes a magnetic field and the electron is viewed
as a large compaction of spacetime, then by inference magnetism appears
to take the form of spacetime disturbance with a dipole nature due to
low compaction in front of the electron and low rarification behind the
electron.
If the electron is viewed as compaction of spacetime then, again by
inference, the proton must be an expansion of spacetime. This would
then agree with the size difference between the 2 particles. Infact,
forces and particles can all be derived from the expansion or
contraction of spacetime (case dependant), with specific requirements
for each separate particle or force (again, obviously case dependant).
Is this all making sense to you? I'm trying to work out why this has
not really been spotted by anyone before? I must be missing something,
it all seems so obvious and straight forward.

wrote:
GSS wrote:
wrote:
Are electric and magnetic fields merely distortions of spacetime?

Yes, electric and magnetic fields could be viewed as 'distortions' of
space-time or dynamic deformations in the space continuum with physical
properties of eps_0 and mu_0. Let U be a time dependent 'displacement'
vector in the space continuum such that it satisfies the Maxwell's
vector wave equation

Del^2(U) = (1/c^2) D^2(U)/Dt^2 ...... (1)
where D represents the partial derivative symbol.

A solution of equation (1) for U that satisfies the essential boundary
conditions, will represent a transverse wave field if Del.U = 0.
Further, we may identify U with the conventional electric and magnetic
fields E & B in 'free space' through the identities,

E = - (1/eps_0).(1/c). DU/Dt
and B = (1/c).(1/eps_0).(Del X U).

The displacement vector field U will now satisfy all the
electromagnetic field equations that are satisfied by E & B in 'free
space'.

GSS

If electron motion causes a magnetic field and the electron is viewed
as a large compaction of spacetime, then by inference magnetism appears
to take the form of spacetime disturbance with a dipole nature due to
low compaction in front of the electron and low rarification behind the
electron.
If the electron is viewed as compaction of spacetime then, again by
inference, the proton must be an expansion of spacetime. This would
then agree with the size difference between the 2 particles. Infact,
forces and particles can all be derived from the expansion or
contraction of spacetime (case dependant), with specific requirements
for each separate particle or force (again, obviously case dependant).
Is this all making sense to you? I'm trying to work out why this has
not really been spotted by anyone before? I must be missing something,
it all seems so obvious and straight forward.

The 'rarification' of spacetime
that is the proton is spin.

A vortex.

At the center of the vortex all the
virtual pairs that make up spacetime
are spun so fast that they become plasma.
Negative is separated from positive because both
are given the same spin. The plasma is repelled
along the magnetic poles of the vortex. It is kept
at a distance by its charge and goes through
a cycle of plasma - radiating charged spheroids -
spent uncharged spheroids which fall back into the
vortex and are continually recharged and expelled as
plasma. So spacetime where the electron is has
more density than where the proton is. The density
of the proton within a certain radius would be zero.

John
Galaxy Model for the Atom
http://users.accesscomm.ca/john

On 2006-12-28 02:23:58 +0000, Sam Wormley said:

malibu wrote:


At the center of the vortex all the
virtual pairs that make up spacetime
are spun so fast that they become plasma.
Negative is separated from positive because both
are given the same spin. The plasma is repelled
along the magnetic poles of the vortex. It is kept
at a distance by its charge and goes through
a cycle of plasma - radiating charged spheroids -
spent uncharged spheroids which fall back into the
vortex and are continually recharged and expelled as
plasma. So spacetime where the electron is has
more density than where the proton is. The density
of the proton within a certain radius would be zero.

John

ILLUCID

Sam Wormley getting in early there for "Understatement of the year 2007" ;-)
--

For me, it is far better to grasp the Universe as it really is than to
persist in delusion, however satisfying and reassuring.

Carl Sagan


--
Posted via a free Usenet account from http://www.teranews.com

wrote:
If the electron is viewed as compaction of spacetime then, again by
inference, the proton must be an expansion of spacetime. This would
then agree with the size difference between the 2 particles. Infact,

Wrong, dumbass, their mutual attraction means that they're both
contractions.

Autymn D. C. wrote:
wrote:
If the electron is viewed as compaction of spacetime then, again by
inference, the proton must be an expansion of spacetime. This would
then agree with the size difference between the 2 particles. Infact,

Wrong, dumbass, their mutual attraction means that they're both
contractions.

Do not confuse gravity with all forces! Gravity has a gradual gradient
compared to the extreme compaction or expansion of spacetime with
electromagnetic etc. Therefore, there is a repulsion between like
charges. That is also why gravity attracts everything.