"Paul B. Andersen" wrote in message
...
| Sorcerer wrote:
| "Paul B. Andersen" wrote in message
| ...
| | Sorcerer wrote:
| | "Randy Poe" wrote in message
| | ups.com...
| |
| | Sorcerer wrote:
| | "Randy Poe" wrote in message
| | ups.com...
| |
| | Sorcerer wrote:
| | "Paul B. Andersen" wrote in
message
| | ...
| | | Sorcerer wrote:
| | | "Paul B. Andersen" wrote in
| | message
| | | ...
| | | | Henri Wilson wrote:
| | | | On Sun, 05 Nov 2006 03:39:49 GMT, "Sorcerer"
| | |
| | | | wrote:
| | | |
| | | | For simplicity and given:
| | | | all sats are at altitude r = 26,000 km
| | | | all sats have a reliable clock
| | | | the receiver has a broken clock, do not use.
| | | |
| | | | Sat_A says it's at 90° 00' 00.00"N, 00° 00' 00.00"E, at
time
| | 0.0
| | | | Sat_B says it's at 30° 00' 00.00"S, 00° 00' 00.00"E, at
| time
| | 0.0
| | | | Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E, at
| time
| | | | 0.000086726665272239762249227670859584 seconds.
| | | |
| | | | That time gives ct = ?
| | | | It doesn't get any easier, ****** Wilson.
| | | | A B and C are three points around a hexagon (in a plane)
| | | | Teenage trigonometry, a fifteen-year-old could do it.
| | | |
| | | | I would have to be a clever fifteen year old. :-)
| | |
| | | But you are a stupid 60-year-old.
| | | Most 15-year-olds can multiply c by t.
| | |
| | |
| | | | I think you left out some vital information.
| | | |
| | | | Indeed he did.
| | | | I guess the missing vital information is that all the three
| | | | signals are received simultaneously.
| | |
| | |
| | | Wrong guess, Tusseladd. The calculation is made after all the
| data
| | | is in, however long that takes. Should the receiver move
between
| | | signals there will be error, but no 15-year-old would consider
| that
| | | as significant.
| | |
| | | I see.
| | | So it doesn't matter at all when the receiver received the
signals.
| |
| | The sat's have to be above the horizon, an hour before or after
| | doesn't work shrug.
| |
| | |
| | | So we have:
| | | | For simplicity and given:
| | | | all sats are at altitude r = 26,000 km
| | | | Sat_A says it's at 40° 00' 00.00"N, 00° 00' 00.00"E, at
time
| | 0.0
| | | | Sat_B says it's at 10° 00' 00.00"N, 00° 00' 00.00"E, at
| time
| | 0.0
| | | | Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E,
| | | | at time 0.0000033356409720092216249702950330609 seconds
| | |
| | | And from that, with no information about when the receiver
| | | received the signals, you claim it can calculate it's position
| | | to be 1 km from C and equidistant from A and B. :-)
| |
| | Yes.
| | Hint which Androcles will not understand: For every
| | receiver in the footprint of these three satellites, the
| | transmit times are the same.
| |
| | Will all those receivers determine that they are in the
| | same location? Is every receiver listening to this signal
| | from C located 1 km from C?
| |
| | Hint for Blind Ignorant Stupid Brandy Poe:
| | http://www.androcles01.pwp.blueyonder.co.uk/GPS.htm
| |
| | Yes, your description on your web site, such as it is, does at
| | least say that there is also an arrival time measured by the
| | receiver. Have you noticed that in the discussion above you
| | said it is not necessary to know the arrival time?
| |
| | - Randy
| |
| | Hint which Blind Brandy Poe will not understand: For every
| | receiver in the footprint of these three satellites, the
| | transmit times are the same.
| |
| | And that's why all the receivers on Earth in the footprint
| | of these three satellites will determine their position to
| | be 1 km from satellite C? :-)
|
| No.
|
| So what will a receiver at Earth determine its position to be
| after it has received these signals?
|| Sat_A says it's at 40° 00' 00.00"N, 00° 00' 00.00"E, at time 0.0
|| Sat_B says it's at 10° 00' 00.00"N, 00° 00' 00.00"E, at time 0.0
|| Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E,
|| at time 0.0000033356409720092216249702950330609 seconds
|
|
| | This must be your greatest blunder of all, Androcles.
| | And that's GREAT!
| |
| I said "No", didn't I?
|
| So you did.
| Sobered up?
| Realized your blunder?
| Blushing?

I haven't blundered. You did.


|
| So there is no blunder except yours, and that's ... NORMAL!
|
| If "no" is the correct answer, then "yes" was a blunder.
| Wasn't it?
| Or was it?
| It was, wasn't it?

| Paul B. Andersen wrote:
|| And from that, with no information about when the receiver
|| received the signals, you claim it can calculate it's position
|| to be 1 km from C and equidistant from A and B. :-)
|
| Androcles responded:
|| Yes.


Q. And that's why all the receivers on Earth in the footprint
of these three satellites will determine their position to
be 1 km from satellite C? :-)
A. NO

Q. || And from that, with no information about when the receiver
|| received the signals, you claim it can calculate it's position
|| to be 1 km from C and equidistant from A and B. :-)
A. YES.

Oh look, different questions have different answers. How amazing!

| Paul, the amused stupid ****wit ****head loving to rub it in

Do rub, its your nose and your ****.
My turn:
| Come on, Androcles. Flee like hell. Snip, snip.
|
| Assume we have a plane EM-wave propagating along
| the x-axis with the B-field:
| B_y = 0
| B_z = Bo*sin(wt - kx) where k = w/c

B_z = Bo*sin(wt - xw/c) where c = x/t
B_z = Bo*sin(wt - txw/x)
B_z = Bo*sin(wt - tw)
B_z = Bo*sin(0)
B_z = Bo*0
B_z = 0
B_y = 0, given.

Answered without flight.
Come on, dumb****. Flee like hell. Snip, snip.

http://www.androcles01.pwp.blueyonder.co.uk/RifleB.JPG

Given:
x-axis is along the barrel
y-axis is as shown, horizontal
z-axis is as shown, vertical
r is radius of bore, not shown
t is time
v is velocity, x/t
w = 1 rotation for a distance 2pi along the x-axis
A and B are curls
http://z.about.com/d/beauty/1/0/V/H/holidayup3.JPG (Girl with curl).
http://mathworld.wolfram.com/Curl.html (math description of curl)
http://www.androcles01.pwp.blueyonder.co.uk/RifleB.JPG (pic. of curl)

Provide an equation to describe the position of a point on a projectile
moving with velocity v along the x-axis that follows the groove B
in the form:

B_x = function1(t,x,y,z)
B_y = function2(?)
B_z = function3(?)
B_t = function4(?)

given the starting position is
B_x = 0,
B_y = r.sin(315 degrees),
B_z = r.cos(7pi/4),
B_t = 0.

Explain the phase relation between groove A and groove B.

Androcles

"Randy Poe" wrote in message
oups.com...

Sorcerer wrote:
"Randy Poe" wrote in message
oups.com...

Sorcerer wrote:
"Randy Poe" wrote in message
ups.com...

Sorcerer wrote:
"Randy Poe" wrote in message
ups.com...

Sorcerer wrote:
"Paul B. Andersen" wrote in
message
...
| Sorcerer wrote:
| "Paul B. Andersen" wrote in
message
| ...
| | Henri Wilson wrote:
| | On Sun, 05 Nov 2006 03:39:49 GMT, "Sorcerer"
|
| | wrote:
| |
| | For simplicity and given:
| | all sats are at altitude r = 26,000 km
| | all sats have a reliable clock
| | the receiver has a broken clock, do not use.
| |
| | Sat_A says it's at 90° 00' 00.00"N, 00° 00' 00.00"E, at
time
0.0
| | Sat_B says it's at 30° 00' 00.00"S, 00° 00' 00.00"E, at
time
0.0
| | Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E, at
time
| | 0.000086726665272239762249227670859584 seconds.
| |
| | That time gives ct = ?
| | It doesn't get any easier, ****** Wilson.
| | A B and C are three points around a hexagon (in a plane)
| | Teenage trigonometry, a fifteen-year-old could do it.
| |
| | I would have to be a clever fifteen year old. :-)
|
| But you are a stupid 60-year-old.
| Most 15-year-olds can multiply c by t.
|
|
| | I think you left out some vital information.
| |
| | Indeed he did.
| | I guess the missing vital information is that all the three
| | signals are received simultaneously.
|
|
| Wrong guess, Tusseladd. The calculation is made after all the
data
| is in, however long that takes. Should the receiver move between
| signals there will be error, but no 15-year-old would consider
that
| as significant.
|
| I see.
| So it doesn't matter at all when the receiver received the
signals.

The sat's have to be above the horizon, an hour before or after
doesn't work shrug.

|
| So we have:
| | For simplicity and given:
| | all sats are at altitude r = 26,000 km
| | Sat_A says it's at 40° 00' 00.00"N, 00° 00' 00.00"E, at
time
0.0
| | Sat_B says it's at 10° 00' 00.00"N, 00° 00' 00.00"E, at
time
0.0
| | Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E,
| | at time 0.0000033356409720092216249702950330609 seconds
|
| And from that, with no information about when the receiver
| received the signals, you claim it can calculate it's position
| to be 1 km from C and equidistant from A and B. :-)

Yes.

Hint which Androcles will not understand: For every
receiver in the footprint of these three satellites, the
transmit times are the same.

Will all those receivers determine that they are in the
same location? Is every receiver listening to this signal
from C located 1 km from C?

Hint for Blind Ignorant Stupid Brandy Poe:
http://www.androcles01.pwp.blueyonder.co.uk/GPS.htm

Yes, your description on your web site, such as it is, does at
least say that there is also an arrival time measured by the
receiver. Have you noticed that in the discussion above you
said it is not necessary to know the arrival time?

- Randy

Hint which Blind Brandy Poe will not understand: For every
receiver in the footprint of these three satellites, the
transmit times are the same.

| So on your web site you say the arrival time at the
| receiver is needed.

True.

| In this thread you say it isn't.

False.

Look up. Read this:

| And from that, with no information about when the receiver
| received the signals, you claim it can calculate it's position
| to be 1 km from C and equidistant from A and B. :-)

Yes.

| They can't both be right. Which statement of yours is
| correct and which is wrong?

The part that was snipped explains it.

| No snip. Every word lovingly preserved. Look up. See the quote.

Maybe not by you. Tusseladd snipped. Read the entire thread and
lovingly preserve every word.



Have a nice snip.
Oh, and read the thread title.
Does it say "GPS AGAIN! (for Tusseladd)"?
Does it say "GPS AGAIN! (for Blind Poe)"?
No.
So **** off, ineducable ****head.

What is says above is:
"Sat_A says it's at 90° 00' 00.00"N, 00° 00' 00.00"E, at time 0.0
Sat_B says it's at 30° 00' 00.00"S, 00° 00' 00.00"E, at time 0.0
Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E, at time
0.000086726665272239762249227670859584 seconds.
That time gives ct = ?"

That doesn't mean satellite C was at 30° 00' 00.00"N, 00° 00' 00.00"E
at time 0.0, does it?
No.
It gives ct(AC) = 26,000 km
It gives ct(BC) = 26,000 km
It gives ct(CC) = 0 km

Two different receivers, at different places in the footprint,
both receive all three of the pieces of information above.

Yes. So?



"Sat_A says it's at 90° 00' 00.00"N, 00° 00' 00.00"E, at time 0.0
Sat_B says it's at 30° 00' 00.00"S, 00° 00' 00.00"E, at time 0.0
Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E, at time
0.000086726665272239762249227670859584 seconds.

This is what those three satellites transmit at those
times, this is what any receiver down below receives. Right?

Yes. So?



So how do those two receivers conclude they are in different
positions?

Hint which Blind Brandy Poe will not understand: For every
receiver in the footprint of these three satellites, the
transmit times are the same.

Read the entire thread and lovingly preserve every word, you may
find the answer.



It doesn't get any easier, Blind Poe.
Hint which Blind Brandy Poe will not understand: For every
receiver in the footprint of these three satellites, the
transmit times are the same.
Hint for a ****head: the receiver is at C which is equidistant
from A and B, and C *DOES* have a precise clock.

You mean "Sat_C" refers to a ground receiver in the footprint
of Sat_A and Sat_B, and "Sat_C" is not a satellite?

I have no recollection of mentioning a ground receiver, that was
the Norwegian tusseladd, ASSistant professor Tusseladd.
"Tusseladd" is Norwegian for "troll".

You are a troll who denies he's a troll but admits to trolling me.
In other words, a lying **** and a hypocrite.

Hint for a ****head: the receiver is at C which is equidistant
from A and B, and C *DOES* have a precise clock.

Hint for a blind ****head: Read the entire thread and lovingly
preserve every word, you may find the answer.

Hint for a ****wit: It doesn't get any easier.

Hint for a troll: There is no way I'm helping you, ****.

Androcles

"Randy Poe" wrote in message
oups.com...

Sorcerer wrote:
"Randy Poe" wrote in message
oups.com...

Sorcerer wrote:
"Randy Poe" wrote in message
ups.com...

Sorcerer wrote:
"Randy Poe" wrote in message
ups.com...

Sorcerer wrote:
"Paul B. Andersen" wrote in
message
...
| Sorcerer wrote:
| "Paul B. Andersen" wrote in
message
| ...
| | Henri Wilson wrote:
| | On Sun, 05 Nov 2006 03:39:49 GMT, "Sorcerer"
|
| | wrote:
| |
| | For simplicity and given:
| | all sats are at altitude r = 26,000 km
| | all sats have a reliable clock
| | the receiver has a broken clock, do not use.
| |
| | Sat_A says it's at 90° 00' 00.00"N, 00° 00' 00.00"E, at
time
0.0
| | Sat_B says it's at 30° 00' 00.00"S, 00° 00' 00.00"E, at
time
0.0
| | Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E, at
time
| | 0.000086726665272239762249227670859584 seconds.
| |
| | That time gives ct = ?
| | It doesn't get any easier, ****** Wilson.
| | A B and C are three points around a hexagon (in a plane)
| | Teenage trigonometry, a fifteen-year-old could do it.
| |
| | I would have to be a clever fifteen year old. :-)
|
| But you are a stupid 60-year-old.
| Most 15-year-olds can multiply c by t.
|
|
| | I think you left out some vital information.
| |
| | Indeed he did.
| | I guess the missing vital information is that all the three
| | signals are received simultaneously.
|
|
| Wrong guess, Tusseladd. The calculation is made after all the
data
| is in, however long that takes. Should the receiver move between
| signals there will be error, but no 15-year-old would consider
that
| as significant.
|
| I see.
| So it doesn't matter at all when the receiver received the
signals.

The sat's have to be above the horizon, an hour before or after
doesn't work shrug.

|
| So we have:
| | For simplicity and given:
| | all sats are at altitude r = 26,000 km
| | Sat_A says it's at 40° 00' 00.00"N, 00° 00' 00.00"E, at
time
0.0
| | Sat_B says it's at 10° 00' 00.00"N, 00° 00' 00.00"E, at
time
0.0
| | Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E,
| | at time 0.0000033356409720092216249702950330609 seconds
|
| And from that, with no information about when the receiver
| received the signals, you claim it can calculate it's position
| to be 1 km from C and equidistant from A and B. :-)

Yes.

Hint which Androcles will not understand: For every
receiver in the footprint of these three satellites, the
transmit times are the same.

Will all those receivers determine that they are in the
same location? Is every receiver listening to this signal
from C located 1 km from C?

Hint for Blind Ignorant Stupid Brandy Poe:
http://www.androcles01.pwp.blueyonder.co.uk/GPS.htm

Yes, your description on your web site, such as it is, does at
least say that there is also an arrival time measured by the
receiver. Have you noticed that in the discussion above you
said it is not necessary to know the arrival time?

- Randy

Hint which Blind Brandy Poe will not understand: For every
receiver in the footprint of these three satellites, the
transmit times are the same.

| So on your web site you say the arrival time at the
| receiver is needed.

True.

| In this thread you say it isn't.

False.

| They can't both be right. Which statement of yours is
| correct and which is wrong?

The part that was snipped explains it. Have a nice snip.
Oh, and read the thread title.
Does it say "GPS AGAIN! (for Tusseladd)"?
Does it say "GPS AGAIN! (for Blind Poe)"?
No.
So **** off, ineducable ****head.

What is says above is:
"Sat_A says it's at 90° 00' 00.00"N, 00° 00' 00.00"E, at time 0.0
Sat_B says it's at 30° 00' 00.00"S, 00° 00' 00.00"E, at time 0.0
Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E, at time
0.000086726665272239762249227670859584 seconds.
That time gives ct = ?"

That doesn't mean satellite C was at 30° 00' 00.00"N, 00° 00' 00.00"E
at time 0.0, does it?
No.
It gives ct(AC) = 26,000 km
It gives ct(BC) = 26,000 km
It gives ct(CC) = 0 km

It doesn't get any easier, Blind Poe.
Hint which Blind Brandy Poe will not understand: For every
receiver in the footprint of these three satellites, the
transmit times are the same.
Hint for a ****head: the receiver is at C which is equidistant
from A and B, and C *DOES* have a precise clock.

But you said it doesn't have to know what time the signals from
A and B arrived.

| And from that, with no information about when the receiver
| received the signals, you claim it can calculate it's position
| to be 1 km from C and equidistant from A and B. :-)

Yes.

So without that information, how can it know it is equidistant
from A and B?

When you've understood that (if you ever do) we can go on
to step 2.

I'm afraid I still don't understand

Too ****ing bad, troll. You burnt your bridge.
"I'm trolling you, if you like." - Blind Poe.

Androcles

Sorcerer wrote:
"Paul B. Andersen" wrote in message
...
| Sorcerer wrote:
| "Paul B. Andersen" wrote in message
| ...
| | Sorcerer wrote:
| | "Randy Poe" wrote in message
| | ups.com...
| |
| | Sorcerer wrote:
| | "Randy Poe" wrote in message
| | ups.com...
| |
| | Sorcerer wrote:
| | "Paul B. Andersen" wrote in
message
| | ...
| | | Sorcerer wrote:
| | | "Paul B. Andersen" wrote in
| | message
| | | ...
| | | | Henri Wilson wrote:
| | | | On Sun, 05 Nov 2006 03:39:49 GMT, "Sorcerer"
| | |
| | | | wrote:
| | | |
| | | | For simplicity and given:
| | | | all sats are at altitude r = 26,000 km
| | | | all sats have a reliable clock
| | | | the receiver has a broken clock, do not use.
| | | |
| | | | Sat_A says it's at 90° 00' 00.00"N, 00° 00' 00.00"E, at
time
| | 0.0
| | | | Sat_B says it's at 30° 00' 00.00"S, 00° 00' 00.00"E, at
| time
| | 0.0
| | | | Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E, at
| time
| | | | 0.000086726665272239762249227670859584 seconds.
| | | |
| | | | That time gives ct = ?
| | | | It doesn't get any easier, ****** Wilson.
| | | | A B and C are three points around a hexagon (in a plane)
| | | | Teenage trigonometry, a fifteen-year-old could do it.
| | | |
| | | | I would have to be a clever fifteen year old. :-)
| | |
| | | But you are a stupid 60-year-old.
| | | Most 15-year-olds can multiply c by t.
| | |
| | |
| | | | I think you left out some vital information.
| | | |
| | | | Indeed he did.
| | | | I guess the missing vital information is that all the three
| | | | signals are received simultaneously.
| | |
| | |
| | | Wrong guess, Tusseladd. The calculation is made after all the
| data
| | | is in, however long that takes. Should the receiver move
between
| | | signals there will be error, but no 15-year-old would consider
| that
| | | as significant.
| | |
| | | I see.
| | | So it doesn't matter at all when the receiver received the
signals.
| |
| | The sat's have to be above the horizon, an hour before or after
| | doesn't work shrug.
| |
| | |
| | | So we have:
| | | | For simplicity and given:
| | | | all sats are at altitude r = 26,000 km
| | | | Sat_A says it's at 40° 00' 00.00"N, 00° 00' 00.00"E, at
time
| | 0.0
| | | | Sat_B says it's at 10° 00' 00.00"N, 00° 00' 00.00"E, at
| time
| | 0.0
| | | | Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E,
| | | | at time 0.0000033356409720092216249702950330609 seconds
| | |
| | | And from that, with no information about when the receiver
| | | received the signals, you claim it can calculate it's position
| | | to be 1 km from C and equidistant from A and B. :-)
| |
| | Yes.
| | Hint which Androcles will not understand: For every
| | receiver in the footprint of these three satellites, the
| | transmit times are the same.
| |
| | Will all those receivers determine that they are in the
| | same location? Is every receiver listening to this signal
| | from C located 1 km from C?
| |
| | Hint for Blind Ignorant Stupid Brandy Poe:
| | http://www.androcles01.pwp.blueyonder.co.uk/GPS.htm
| |
| | Yes, your description on your web site, such as it is, does at
| | least say that there is also an arrival time measured by the
| | receiver. Have you noticed that in the discussion above you
| | said it is not necessary to know the arrival time?
| |
| | - Randy
| |
| | Hint which Blind Brandy Poe will not understand: For every
| | receiver in the footprint of these three satellites, the
| | transmit times are the same.
| |
| | And that's why all the receivers on Earth in the footprint
| | of these three satellites will determine their position to
| | be 1 km from satellite C? :-)
|
| No.
|
| So what will a receiver at Earth determine its position to be
| after it has received these signals?
|| Sat_A says it's at 40° 00' 00.00"N, 00° 00' 00.00"E, at time 0.0
|| Sat_B says it's at 10° 00' 00.00"N, 00° 00' 00.00"E, at time 0.0
|| Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E,
|| at time 0.0000033356409720092216249702950330609 seconds
|
|
| | This must be your greatest blunder of all, Androcles.
| | And that's GREAT!
| |
| I said "No", didn't I?
|
| So you did.
| Sobered up?
| Realized your blunder?
| Blushing?

I haven't blundered. You did.

OK.
I made a blunder when I said you had sobered up.
You haven't sobered up.
You haven't realized your blunder.
You are not blushing.
You are not embarrassed.

But I love to rub it in, so I will yet again repeat your
blunder which you don't understand is a blunder:

Androcles:
| For simplicity and given: all sats are at altitude r = 26,000 km
| Sat_A says it's at 40° 00' 00.00"N, 00° 00' 00.00"E, at time 0.0
| Sat_B says it's at 10° 00' 00.00"N, 00° 00' 00.00"E, at time 0.0
| Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E,
| at time 0.0000033356409720092216249702950330609 seconds

Paul:
| And from that, with no information about when the receiver
| received the signals, you claim it can calculate it's position
| to be 1 km from C and equidistant from A and B. :-)

Androcles:
| Yes.

Please repeat that you made no blunder.
It gets even funnier that way.

Paul

Sorcerer wrote:
"Randy Poe" wrote in message
oups.com...

Sorcerer wrote:
"Randy Poe" wrote in message
oups.com...

Sorcerer wrote:
"Randy Poe" wrote in message
ups.com...

Sorcerer wrote:
"Randy Poe" wrote in message
ups.com...

Sorcerer wrote:
"Paul B. Andersen" wrote in
message
...
| Sorcerer wrote:
| "Paul B. Andersen" wrote in
message
| ...
| | Henri Wilson wrote:
| | On Sun, 05 Nov 2006 03:39:49 GMT, "Sorcerer"
|
| | wrote:
| |
| | For simplicity and given:
| | all sats are at altitude r = 26,000 km
| | all sats have a reliable clock
| | the receiver has a broken clock, do not use.
| |
| | Sat_A says it's at 90° 00' 00.00"N, 00° 00' 00.00"E, at
time
0.0
| | Sat_B says it's at 30° 00' 00.00"S, 00° 00' 00.00"E, at
time
0.0
| | Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E, at
time
| | 0.000086726665272239762249227670859584 seconds.
| |
| | That time gives ct = ?
| | It doesn't get any easier, ****** Wilson.
| | A B and C are three points around a hexagon (in a plane)
| | Teenage trigonometry, a fifteen-year-old could do it.
| |
| | I would have to be a clever fifteen year old. :-)
|
| But you are a stupid 60-year-old.
| Most 15-year-olds can multiply c by t.
|
|
| | I think you left out some vital information.
| |
| | Indeed he did.
| | I guess the missing vital information is that all the three
| | signals are received simultaneously.
|
|
| Wrong guess, Tusseladd. The calculation is made after all the
data
| is in, however long that takes. Should the receiver move between
| signals there will be error, but no 15-year-old would consider
that
| as significant.
|
| I see.
| So it doesn't matter at all when the receiver received the
signals.

The sat's have to be above the horizon, an hour before or after
doesn't work shrug.

|
| So we have:
| | For simplicity and given:
| | all sats are at altitude r = 26,000 km
| | Sat_A says it's at 40° 00' 00.00"N, 00° 00' 00.00"E, at
time
0.0
| | Sat_B says it's at 10° 00' 00.00"N, 00° 00' 00.00"E, at
time
0.0
| | Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E,
| | at time 0.0000033356409720092216249702950330609 seconds
|
| And from that, with no information about when the receiver
| received the signals, you claim it can calculate it's position
| to be 1 km from C and equidistant from A and B. :-)

Yes.
Hint which Androcles will not understand: For every
receiver in the footprint of these three satellites, the
transmit times are the same.

Will all those receivers determine that they are in the
same location? Is every receiver listening to this signal
from C located 1 km from C?

Hint for Blind Ignorant Stupid Brandy Poe:
http://www.androcles01.pwp.blueyonder.co.uk/GPS.htm
Yes, your description on your web site, such as it is, does at
least say that there is also an arrival time measured by the
receiver. Have you noticed that in the discussion above you
said it is not necessary to know the arrival time?

- Randy

Hint which Blind Brandy Poe will not understand: For every
receiver in the footprint of these three satellites, the
transmit times are the same.
| So on your web site you say the arrival time at the
| receiver is needed.

True.

| In this thread you say it isn't.

False.

| They can't both be right. Which statement of yours is
| correct and which is wrong?

The part that was snipped explains it. Have a nice snip.
Oh, and read the thread title.
Does it say "GPS AGAIN! (for Tusseladd)"?
Does it say "GPS AGAIN! (for Blind Poe)"?
No.
So **** off, ineducable ****head.

What is says above is:
"Sat_A says it's at 90° 00' 00.00"N, 00° 00' 00.00"E, at time 0.0
Sat_B says it's at 30° 00' 00.00"S, 00° 00' 00.00"E, at time 0.0
Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E, at time
0.000086726665272239762249227670859584 seconds.
That time gives ct = ?"

That doesn't mean satellite C was at 30° 00' 00.00"N, 00° 00' 00.00"E
at time 0.0, does it?
No.
It gives ct(AC) = 26,000 km
It gives ct(BC) = 26,000 km
It gives ct(CC) = 0 km

It doesn't get any easier, Blind Poe.
Hint which Blind Brandy Poe will not understand: For every
receiver in the footprint of these three satellites, the
transmit times are the same.
Hint for a ****head: the receiver is at C which is equidistant
from A and B, and C *DOES* have a precise clock.

But you said it doesn't have to know what time the signals from
A and B arrived.

| And from that, with no information about when the receiver
| received the signals, you claim it can calculate it's position
| to be 1 km from C and equidistant from A and B. :-)

Yes.

So without that information, how can it know it is equidistant
from A and B?

When you've understood that (if you ever do) we can go on
to step 2.

I'm afraid I still don't understand

Too ****ing bad, troll. You burnt your bridge.
"I'm trolling you, if you like." - Blind Poe.

Androcles


This IS fun, isn't it? :-)

Please don't admit your blunder, Androcles.
That would be no fun at all.
Your delirious desperation is much more entertaining.

Paul, with malicious pleasure

"Paul B. Andersen" wrote in message
...
| Sorcerer wrote:
| "Paul B. Andersen" wrote in message
| ...
| | Sorcerer wrote:
| | "Paul B. Andersen" wrote in
message
| | ...
| | | Sorcerer wrote:
| | | "Randy Poe" wrote in message
| | | ups.com...
| | |
| | | Sorcerer wrote:
| | | "Randy Poe" wrote in message
| | | ups.com...
| | |
| | | Sorcerer wrote:
| | | "Paul B. Andersen" wrote in
| message
| | | ...
| | | | Sorcerer wrote:
| | | | "Paul B. Andersen"
wrote in
| | | message
| | | | ...
| | | | | Henri Wilson wrote:
| | | | | On Sun, 05 Nov 2006 03:39:49 GMT, "Sorcerer"
| | | |
| | | | | wrote:
| | | | |
| | | | | For simplicity and given:
| | | | | all sats are at altitude r = 26,000 km
| | | | | all sats have a reliable clock
| | | | | the receiver has a broken clock, do not use.
| | | | |
| | | | | Sat_A says it's at 90° 00' 00.00"N, 00° 00' 00.00"E,
at
| time
| | | 0.0
| | | | | Sat_B says it's at 30° 00' 00.00"S, 00° 00'
00.00"E, at
| | time
| | | 0.0
| | | | | Sat_C says it's at 30° 00' 00.00"N, 00° 00'
00.00"E, at
| | time
| | | | | 0.000086726665272239762249227670859584 seconds.
| | | | |
| | | | | That time gives ct = ?
| | | | | It doesn't get any easier, ****** Wilson.
| | | | | A B and C are three points around a hexagon (in a
plane)
| | | | | Teenage trigonometry, a fifteen-year-old could do it.
| | | | |
| | | | | I would have to be a clever fifteen year old. :-)
| | | |
| | | | But you are a stupid 60-year-old.
| | | | Most 15-year-olds can multiply c by t.
| | | |
| | | |
| | | | | I think you left out some vital information.
| | | | |
| | | | | Indeed he did.
| | | | | I guess the missing vital information is that all the
three
| | | | | signals are received simultaneously.
| | | |
| | | |
| | | | Wrong guess, Tusseladd. The calculation is made after all
the
| | data
| | | | is in, however long that takes. Should the receiver move
| between
| | | | signals there will be error, but no 15-year-old would
consider
| | that
| | | | as significant.
| | | |
| | | | I see.
| | | | So it doesn't matter at all when the receiver received the
| signals.
| | |
| | | The sat's have to be above the horizon, an hour before or
after
| | | doesn't work shrug.
| | |
| | | |
| | | | So we have:
| | | | | For simplicity and given:
| | | | | all sats are at altitude r = 26,000 km
| | | | | Sat_A says it's at 40° 00' 00.00"N, 00° 00' 00.00"E,
at
| time
| | | 0.0
| | | | | Sat_B says it's at 10° 00' 00.00"N, 00° 00'
00.00"E, at
| | time
| | | 0.0
| | | | | Sat_C says it's at 30° 00' 00.00"N, 00° 00'
00.00"E,
| | | | | at time 0.0000033356409720092216249702950330609
seconds
| | | |
| | | | And from that, with no information about when the receiver
| | | | received the signals, you claim it can calculate it's
position
| | | | to be 1 km from C and equidistant from A and B. :-)
| | |
| | | Yes.
| | | Hint which Androcles will not understand: For every
| | | receiver in the footprint of these three satellites, the
| | | transmit times are the same.
| | |
| | | Will all those receivers determine that they are in the
| | | same location? Is every receiver listening to this signal
| | | from C located 1 km from C?
| | |
| | | Hint for Blind Ignorant Stupid Brandy Poe:
| | | http://www.androcles01.pwp.blueyonder.co.uk/GPS.htm
| | |
| | | Yes, your description on your web site, such as it is, does at
| | | least say that there is also an arrival time measured by the
| | | receiver. Have you noticed that in the discussion above you
| | | said it is not necessary to know the arrival time?
| | |
| | | - Randy
| | |
| | | Hint which Blind Brandy Poe will not understand: For every
| | | receiver in the footprint of these three satellites, the
| | | transmit times are the same.
| | |
| | | And that's why all the receivers on Earth in the footprint
| | | of these three satellites will determine their position to
| | | be 1 km from satellite C? :-)
| |
| | No.
| |
| | So what will a receiver at Earth determine its position to be
| | after it has received these signals?
| || Sat_A says it's at 40° 00' 00.00"N, 00° 00' 00.00"E, at time 0.0
| || Sat_B says it's at 10° 00' 00.00"N, 00° 00' 00.00"E, at time 0.0
| || Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E,
| || at time 0.0000033356409720092216249702950330609 seconds
| |
| |
| | | This must be your greatest blunder of all, Androcles.
| | | And that's GREAT!
| | |
| | I said "No", didn't I?
| |
| | So you did.
| | Sobered up?
| | Realized your blunder?
| | Blushing?
|
| I haven't blundered. You did.
|
| OK.
| I made a blunder when I said you had sobered up.
| You haven't sobered up.
| You haven't realized your blunder.
| You are not blushing.
| You are not embarrassed.
|
| But I love to rub it in, so I will yet again repeat your
| blunder which you don't understand is a blunder:
|
| Androcles:
|| For simplicity and given: all sats are at altitude r = 26,000 km
|| Sat_A says it's at 40° 00' 00.00"N, 00° 00' 00.00"E, at time 0.0
|| Sat_B says it's at 10° 00' 00.00"N, 00° 00' 00.00"E, at time 0.0
|| Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E,
|| at time 0.0000033356409720092216249702950330609 seconds
|
| Paul:
|| And from that, with no information about when the receiver
|| received the signals, you claim it can calculate it's position
|| to be 1 km from C and equidistant from A and B. :-)
|
| Androcles:
|| Yes.
|
| Please repeat that you made no blunder.

We'll take this two tiny steps at a time.
Equidistant from A and B is easy, isn't it (even if we are not yet sure of
the distance)?
Is C equidistant from where A and B were
0.0000033356409720092216249702950330609 seconds after time 0.0?
You can't answer those two questions, can you?
I made no blunder.

| It gets even funnier that way.

It sure does. Always funny to see you snip or fail to answer a simple
question.

Come on, dumb****. Flee like hell. Snip, snip, fail to answer. :-)
Androcles

"Paul B. Andersen" wrote in message
...
| Sorcerer wrote:
| "Randy Poe" wrote in message
| oups.com...
|
| Sorcerer wrote:
| "Randy Poe" wrote in message
| oups.com...
|
| Sorcerer wrote:
| "Randy Poe" wrote in message
| ups.com...
|
| Sorcerer wrote:
| "Randy Poe" wrote in message
| ups.com...
|
| Sorcerer wrote:
| "Paul B. Andersen" wrote in
| message
| ...
| | Sorcerer wrote:
| | "Paul B. Andersen" wrote in
| message
| | ...
| | | Henri Wilson wrote:
| | | On Sun, 05 Nov 2006 03:39:49 GMT, "Sorcerer"
| |
| | | wrote:
| | |
| | | For simplicity and given:
| | | all sats are at altitude r = 26,000 km
| | | all sats have a reliable clock
| | | the receiver has a broken clock, do not use.
| | |
| | | Sat_A says it's at 90° 00' 00.00"N, 00° 00' 00.00"E, at
| time
| 0.0
| | | Sat_B says it's at 30° 00' 00.00"S, 00° 00' 00.00"E, at
| time
| 0.0
| | | Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E, at
| time
| | | 0.000086726665272239762249227670859584 seconds.
| | |
| | | That time gives ct = ?
| | | It doesn't get any easier, ****** Wilson.
| | | A B and C are three points around a hexagon (in a plane)
| | | Teenage trigonometry, a fifteen-year-old could do it.
| | |
| | | I would have to be a clever fifteen year old. :-)
| |
| | But you are a stupid 60-year-old.
| | Most 15-year-olds can multiply c by t.
| |
| |
| | | I think you left out some vital information.
| | |
| | | Indeed he did.
| | | I guess the missing vital information is that all the three
| | | signals are received simultaneously.
| |
| |
| | Wrong guess, Tusseladd. The calculation is made after all the
| data
| | is in, however long that takes. Should the receiver move between
| | signals there will be error, but no 15-year-old would consider
| that
| | as significant.
| |
| | I see.
| | So it doesn't matter at all when the receiver received the
| signals.
|
| The sat's have to be above the horizon, an hour before or after
| doesn't work shrug.
|
| |
| | So we have:
| | | For simplicity and given:
| | | all sats are at altitude r = 26,000 km
| | | Sat_A says it's at 40° 00' 00.00"N, 00° 00' 00.00"E, at
| time
| 0.0
| | | Sat_B says it's at 10° 00' 00.00"N, 00° 00' 00.00"E, at
| time
| 0.0
| | | Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E,
| | | at time 0.0000033356409720092216249702950330609 seconds
| |
| | And from that, with no information about when the receiver
| | received the signals, you claim it can calculate it's position
| | to be 1 km from C and equidistant from A and B. :-)
|
| Yes.
| Hint which Androcles will not understand: For every
| receiver in the footprint of these three satellites, the
| transmit times are the same.
|
| Will all those receivers determine that they are in the
| same location? Is every receiver listening to this signal
| from C located 1 km from C?
|
| Hint for Blind Ignorant Stupid Brandy Poe:
| http://www.androcles01.pwp.blueyonder.co.uk/GPS.htm
| Yes, your description on your web site, such as it is, does at
| least say that there is also an arrival time measured by the
| receiver. Have you noticed that in the discussion above you
| said it is not necessary to know the arrival time?
|
| - Randy
|
| Hint which Blind Brandy Poe will not understand: For every
| receiver in the footprint of these three satellites, the
| transmit times are the same.
| | So on your web site you say the arrival time at the
| | receiver is needed.
|
| True.
|
| | In this thread you say it isn't.
|
| False.
|
| | They can't both be right. Which statement of yours is
| | correct and which is wrong?
|
| The part that was snipped explains it. Have a nice snip.
| Oh, and read the thread title.
| Does it say "GPS AGAIN! (for Tusseladd)"?
| Does it say "GPS AGAIN! (for Blind Poe)"?
| No.
| So **** off, ineducable ****head.
|
| What is says above is:
| "Sat_A says it's at 90° 00' 00.00"N, 00° 00' 00.00"E, at time 0.0
| Sat_B says it's at 30° 00' 00.00"S, 00° 00' 00.00"E, at time 0.0
| Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E, at time
| 0.000086726665272239762249227670859584 seconds.
| That time gives ct = ?"
|
| That doesn't mean satellite C was at 30° 00' 00.00"N, 00° 00' 00.00"E
| at time 0.0, does it?
| No.
| It gives ct(AC) = 26,000 km
| It gives ct(BC) = 26,000 km
| It gives ct(CC) = 0 km
|
| It doesn't get any easier, Blind Poe.
| Hint which Blind Brandy Poe will not understand: For every
| receiver in the footprint of these three satellites, the
| transmit times are the same.
| Hint for a ****head: the receiver is at C which is equidistant
| from A and B, and C *DOES* have a precise clock.
|
| But you said it doesn't have to know what time the signals from
| A and B arrived.
|
| | And from that, with no information about when the receiver
| | received the signals, you claim it can calculate it's position
| | to be 1 km from C and equidistant from A and B. :-)
|
| Yes.
|
| So without that information, how can it know it is equidistant
| from A and B?
|
| When you've understood that (if you ever do) we can go on
| to step 2.
|
| I'm afraid I still don't understand
|
| Too ****ing bad, troll. You burnt your bridge.
| "I'm trolling you, if you like." - Blind Poe.
|
| Androcles
|
|
| This IS fun, isn't it? :-)
|
| Please don't admit your blunder, Androcles.
| That would be no fun at all.
| Your delirious desperation is much more entertaining.
|
| Paul, with malicious pleasure
No blunder to admit.
The malice is all yours, duly noted. Trolls are by nature malicious.
Your delirious lies are much more entertaining.

BTW, You fit this description to a tee:

"Some of the guys are so small that they aren't even noticed by a lot of
people. One will notice the trouble they cause, that's for sure. Because
small causes can make big headaches! The Tusselader know this, it makes them
feel important and very busy..


Many of these pests choose to live on the bodies of people who are dirty and
smelly just like themselves. Big families of Tusselader sometimes make their
homes in the beds of careless dirty people. So remember to clean up before
going to bed.



They are also known to annoy many housewifes by sneaking into kitchens where
they cause food to spoil, bread to become moldy, milk to go sour and butter
to turn rancid. Tusselader are also great friends of the flies, bugs,
mosquitoes and all kinds of other insects.



But should you be suspicious about Tusselader having moved into your home,
it's important to live very clean and well-ordered lives. This is a good way
of spoiling many of the best plans laid by Tusselader."

http://www.trollshop.net/trolls/tusselader/

Sorcerer wrote:
"Randy Poe" wrote in message
oups.com...

Sorcerer wrote:
"Randy Poe" wrote in message
oups.com...

Sorcerer wrote:
"Randy Poe" wrote in message
ups.com...

Sorcerer wrote:
"Randy Poe" wrote in message
ups.com...

Sorcerer wrote:
"Paul B. Andersen" wrote in
message
...
| Sorcerer wrote:
| "Paul B. Andersen" wrote in
message
| ...
| | Henri Wilson wrote:
| | On Sun, 05 Nov 2006 03:39:49 GMT, "Sorcerer"
|
| | wrote:
| |
| | For simplicity and given:
| | all sats are at altitude r = 26,000 km
| | all sats have a reliable clock
| | the receiver has a broken clock, do not use.
| |
| | Sat_A says it's at 90° 00' 00.00"N, 00° 00' 00.00"E, at
time
0.0
| | Sat_B says it's at 30° 00' 00.00"S, 00° 00' 00.00"E, at
time
0.0
| | Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E, at
time
| | 0.000086726665272239762249227670859584 seconds.
| |
| | That time gives ct = ?
| | It doesn't get any easier, ****** Wilson.
| | A B and C are three points around a hexagon (in a plane)
| | Teenage trigonometry, a fifteen-year-old could do it.
| |
| | I would have to be a clever fifteen year old. :-)
|
| But you are a stupid 60-year-old.
| Most 15-year-olds can multiply c by t.
|
|
| | I think you left out some vital information.
| |
| | Indeed he did.
| | I guess the missing vital information is that all the three
| | signals are received simultaneously.
|
|
| Wrong guess, Tusseladd. The calculation is made after all the
data
| is in, however long that takes. Should the receiver move between
| signals there will be error, but no 15-year-old would consider
that
| as significant.
|
| I see.
| So it doesn't matter at all when the receiver received the
signals.

The sat's have to be above the horizon, an hour before or after
doesn't work shrug.

|
| So we have:
| | For simplicity and given:
| | all sats are at altitude r = 26,000 km
| | Sat_A says it's at 40° 00' 00.00"N, 00° 00' 00.00"E, at
time
0.0
| | Sat_B says it's at 10° 00' 00.00"N, 00° 00' 00.00"E, at
time
0.0
| | Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E,
| | at time 0.0000033356409720092216249702950330609 seconds
|
| And from that, with no information about when the receiver
| received the signals, you claim it can calculate it's position
| to be 1 km from C and equidistant from A and B. :-)

Yes.

Hint which Androcles will not understand: For every
receiver in the footprint of these three satellites, the
transmit times are the same.

Will all those receivers determine that they are in the
same location? Is every receiver listening to this signal
from C located 1 km from C?

Hint for Blind Ignorant Stupid Brandy Poe:
http://www.androcles01.pwp.blueyonder.co.uk/GPS.htm

Yes, your description on your web site, such as it is, does at
least say that there is also an arrival time measured by the
receiver. Have you noticed that in the discussion above you
said it is not necessary to know the arrival time?

- Randy

Hint which Blind Brandy Poe will not understand: For every
receiver in the footprint of these three satellites, the
transmit times are the same.

| So on your web site you say the arrival time at the
| receiver is needed.

True.

| In this thread you say it isn't.

False.

Look up. Read this:

| And from that, with no information about when the receiver
| received the signals, you claim it can calculate it's position
| to be 1 km from C and equidistant from A and B. :-)

Yes.

| They can't both be right. Which statement of yours is
| correct and which is wrong?

The part that was snipped explains it.

| No snip. Every word lovingly preserved. Look up. See the quote.

Maybe not by you. Tusseladd snipped. Read the entire thread and
lovingly preserve every word.



Have a nice snip.
Oh, and read the thread title.
Does it say "GPS AGAIN! (for Tusseladd)"?
Does it say "GPS AGAIN! (for Blind Poe)"?
No.
So **** off, ineducable ****head.

What is says above is:
"Sat_A says it's at 90° 00' 00.00"N, 00° 00' 00.00"E, at time 0.0
Sat_B says it's at 30° 00' 00.00"S, 00° 00' 00.00"E, at time 0.0
Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E, at time
0.000086726665272239762249227670859584 seconds.
That time gives ct = ?"

That doesn't mean satellite C was at 30° 00' 00.00"N, 00° 00' 00.00"E
at time 0.0, does it?
No.
It gives ct(AC) = 26,000 km
It gives ct(BC) = 26,000 km
It gives ct(CC) = 0 km

Two different receivers, at different places in the footprint,
both receive all three of the pieces of information above.

Yes. So?

So if this is the only information they use to derive
their position, and they have the same information,
how do they end up calculating different positions?

Which I already asked below. And which, in your weird
quoting style, you made look like you said it instead of me.

"Sat_A says it's at 90° 00' 00.00"N, 00° 00' 00.00"E, at time 0.0
Sat_B says it's at 30° 00' 00.00"S, 00° 00' 00.00"E, at time 0.0
Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E, at time
0.000086726665272239762249227670859584 seconds.

This is what those three satellites transmit at those
times, this is what any receiver down below receives. Right?

Yes. So?

So how do those two receivers conclude they are in different
positions?

Hint which Blind Brandy Poe will not understand: For every
receiver in the footprint of these three satellites, the
transmit times are the same.

Right. And if the transmit times are the same for everybody,
and the only information used is the transmit times, how
do they get different answers.

Hint for Androcles: For two calculations to arrive at different
numbers, some input must be different. Telling me every
input is the same is not an explanation for how the
answers come out different.

I know you know what you left out. It's on your website.
Why are you so fanatically pretending here you don't
need the receive time?

Read the entire thread and lovingly preserve every word, you may
find the answer.



It doesn't get any easier, Blind Poe.
Hint which Blind Brandy Poe will not understand: For every
receiver in the footprint of these three satellites, the
transmit times are the same.
Hint for a ****head: the receiver is at C which is equidistant
from A and B, and C *DOES* have a precise clock.

You mean "Sat_C" refers to a ground receiver in the footprint
of Sat_A and Sat_B, and "Sat_C" is not a satellite?

I have no recollection of mentioning a ground receiver, that was
the Norwegian tusseladd, ASSistant professor Tusseladd.
"Tusseladd" is Norwegian for "troll".

Ah, so A, B and C are the only things in this problem.

And when you said "it is 1 km from C", you meant
"the receiver at C is 1 km from C". Is that right?

You are a troll who denies he's a troll but admits to trolling me.

Yes.

In other words, a lying **** and a hypocrite.

Nope. But you'll never comprehend the difference
between not bothering to exchange information with
*YOU*, a foul-mouthed cretin who never actually
injects content into the newsgroup, and actual
trolling.

Hint for a ****head: the receiver is at C which is equidistant
from A and B, and C *DOES* have a precise clock.

Got it. The receiver is at C. And it is 1 km from C.
And it is trying to determine its position by information
from only two satellites, A and B. Without the receive time.
But it already knows its precise position to be at
30° 00' 00.00"N, 00° 00' 00.00"E, 26000 km altitude at time
0.000086726665272239762249227670859584 seconds.

Right?

- Randy

"Randy Poe" wrote in message
oups.com...

Sorcerer wrote:
"Randy Poe" wrote in message
oups.com...

Sorcerer wrote:
"Randy Poe" wrote in message
oups.com...

Sorcerer wrote:
"Randy Poe" wrote in message
ups.com...

Sorcerer wrote:
"Randy Poe" wrote in message
ups.com...

Sorcerer wrote:
"Paul B. Andersen" wrote in
message
...
| Sorcerer wrote:
| "Paul B. Andersen" wrote in
message
| ...
| | Henri Wilson wrote:
| | On Sun, 05 Nov 2006 03:39:49 GMT, "Sorcerer"
|
| | wrote:
| |
| | For simplicity and given:
| | all sats are at altitude r = 26,000 km
| | all sats have a reliable clock
| | the receiver has a broken clock, do not use.
| |
| | Sat_A says it's at 90° 00' 00.00"N, 00° 00' 00.00"E, at
time
0.0
| | Sat_B says it's at 30° 00' 00.00"S, 00° 00' 00.00"E, at
time
0.0
| | Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E, at
time
| | 0.000086726665272239762249227670859584 seconds.
| |
| | That time gives ct = ?
| | It doesn't get any easier, ****** Wilson.
| | A B and C are three points around a hexagon (in a plane)
| | Teenage trigonometry, a fifteen-year-old could do it.
| |
| | I would have to be a clever fifteen year old. :-)
|
| But you are a stupid 60-year-old.
| Most 15-year-olds can multiply c by t.
|
|
| | I think you left out some vital information.
| |
| | Indeed he did.
| | I guess the missing vital information is that all the three
| | signals are received simultaneously.
|
|
| Wrong guess, Tusseladd. The calculation is made after all the
data
| is in, however long that takes. Should the receiver move
between
| signals there will be error, but no 15-year-old would consider
that
| as significant.
|
| I see.
| So it doesn't matter at all when the receiver received the
signals.

The sat's have to be above the horizon, an hour before or after
doesn't work shrug.

|
| So we have:
| | For simplicity and given:
| | all sats are at altitude r = 26,000 km
| | Sat_A says it's at 40° 00' 00.00"N, 00° 00' 00.00"E, at
time
0.0
| | Sat_B says it's at 10° 00' 00.00"N, 00° 00' 00.00"E, at
time
0.0
| | Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E,
| | at time 0.0000033356409720092216249702950330609 seconds
|
| And from that, with no information about when the receiver
| received the signals, you claim it can calculate it's position
| to be 1 km from C and equidistant from A and B. :-)

Yes.

Hint which Androcles will not understand: For every
receiver in the footprint of these three satellites, the
transmit times are the same.

Will all those receivers determine that they are in the
same location? Is every receiver listening to this signal
from C located 1 km from C?

Hint for Blind Ignorant Stupid Brandy Poe:
http://www.androcles01.pwp.blueyonder.co.uk/GPS.htm

Yes, your description on your web site, such as it is, does at
least say that there is also an arrival time measured by the
receiver. Have you noticed that in the discussion above you
said it is not necessary to know the arrival time?

- Randy

Hint which Blind Brandy Poe will not understand: For every
receiver in the footprint of these three satellites, the
transmit times are the same.

| So on your web site you say the arrival time at the
| receiver is needed.

True.

| In this thread you say it isn't.

False.

Look up. Read this:

| And from that, with no information about when the receiver
| received the signals, you claim it can calculate it's position
| to be 1 km from C and equidistant from A and B. :-)

Yes.

| They can't both be right. Which statement of yours is
| correct and which is wrong?

The part that was snipped explains it.

| No snip. Every word lovingly preserved. Look up. See the quote.

Maybe not by you. Tusseladd snipped. Read the entire thread and
lovingly preserve every word.



Have a nice snip.
Oh, and read the thread title.
Does it say "GPS AGAIN! (for Tusseladd)"?
Does it say "GPS AGAIN! (for Blind Poe)"?
No.
So **** off, ineducable ****head.

What is says above is:
"Sat_A says it's at 90° 00' 00.00"N, 00° 00' 00.00"E, at time 0.0
Sat_B says it's at 30° 00' 00.00"S, 00° 00' 00.00"E, at time 0.0
Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E, at time
0.000086726665272239762249227670859584 seconds.
That time gives ct = ?"

That doesn't mean satellite C was at 30° 00' 00.00"N, 00° 00' 00.00"E
at time 0.0, does it?
No.
It gives ct(AC) = 26,000 km
It gives ct(BC) = 26,000 km
It gives ct(CC) = 0 km

Two different receivers, at different places in the footprint,
both receive all three of the pieces of information above.

Yes. So?

So if this is the only information they use to derive
their position, and they have the same information,
how do they end up calculating different positions?

In hypothetical sentences introduced by 'if' and referring to
past time, where conditions are to be deemed 'unfulfilled',
the verb will regularly be found in the pluperfect subjunctive,
in both protasis and apodosis.
-- Donet, "Principles of Elementary Latin Syntax"

It's quite easy to be equidistant from two points.



Which I already asked below.

I dont give a **** what you asked, I said read the original, not
Tusseladd's snippped version, you ****ing moron.


And which, in your weird
quoting style, you made look like you said it instead of me.

Posts from others are automatically indented with "|" or "" or ":"
by Outlook Express when I hit "Reply".
Yours are not and I'm too lazy to bother much with a troll anyway.
Bring your sending format into line with the majority or live with it.


"Sat_A says it's at 90° 00' 00.00"N, 00° 00' 00.00"E, at time 0.0
Sat_B says it's at 30° 00' 00.00"S, 00° 00' 00.00"E, at time 0.0
Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E, at time
0.000086726665272239762249227670859584 seconds.

This is what those three satellites transmit at those
times, this is what any receiver down below receives. Right?

Yes. So?

So how do those two receivers conclude they are in different
positions?

Hint which Blind Brandy Poe will not understand: For every
receiver in the footprint of these three satellites, the
transmit times are the same.

Right. And if the transmit times are the same for everybody,
and the only information used is the transmit times, how
do they get different answers.

If that's a question it needs a "?" at the end.
I won't bother to reply.



Hint for Androcles:
I don't need your ****ing stupid hints.
[hint snipped]


I know you know what you left out. It's on your website.
Why are you so fanatically pretending here you don't
need the receive time?

Hey ****head! I left nothing out. You responded to a post
the **** Andersen snipped, you stupid ****.




Read the entire thread and lovingly preserve every word, you may
find the answer.



It doesn't get any easier, Blind Poe.
Hint which Blind Brandy Poe will not understand: For every
receiver in the footprint of these three satellites, the
transmit times are the same.
Hint for a ****head: the receiver is at C which is equidistant
from A and B, and C *DOES* have a precise clock.

You mean "Sat_C" refers to a ground receiver in the footprint
of Sat_A and Sat_B, and "Sat_C" is not a satellite?

I have no recollection of mentioning a ground receiver, that was
the Norwegian tusseladd, ASSistant professor Tusseladd.
"Tusseladd" is Norwegian for "troll".

Ah, so A, B and C are the only things in this problem.

Stupid ****. NO!



And when you said "it is 1 km from C", you meant
"the receiver at C is 1 km from C". Is that right?

You are a troll who denies he's a troll but admits to trolling me.

Yes.

In other words, a lying **** and a hypocrite.

Nope. But you'll never comprehend the difference
between not bothering to exchange information with
*YOU*, a foul-mouthed cretin who never actually
injects content into the newsgroup, and actual
trolling.

You were stupid enough to reply to a snipped post, dumb****.
All you ****s are so snip crazy you **** each other up. Don't
blame me for your failures, imbecile.



Hint for a ****head: the receiver is at C which is equidistant
from A and B, and C *DOES* have a precise clock.

Got it. The receiver is at C.

Well done.

And it is 1 km from C.
There are two sets of data, blind ****.

Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E,
| | at time 0.0000033356409720092216249702950330609 seconds
Sat_C says it's at 30° 00' 00.00"N, 00° 00' 00.00"E, at time
0.000086726665272239762249227670859584 seconds.


**** off.




And it is trying to determine its position by information
from only two satellites, A and B. Without the receive time.
But it already knows its precise position to be at
30° 00' 00.00"N, 00° 00' 00.00"E, 26000 km altitude at time
0.000086726665272239762249227670859584 seconds.

Right?

Wrong. As I said, read the original. Now **** off, troll.
Androcles