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| Tags: anisotropy, experiment, light, speed |
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#1
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Hi,
Imagine a square with 300,000 km long sides. Diagonals are around 423,000 km long. A light is flashed at one corner. One light beam travels the diagonal and directly reaches the observer at the opposite corner, while the other light beam is reflected off the mirror at the other corner and again reaches the observer. http://i95.photobucket.com/albums/l1.../untitled3.gif In the first figure, the delay between observed direct light and reflected light is 0.59 seconds ( (1+1) - 1.41 ). In figure two, suppose that one way speed of light is only 150,000 km/second in the opposite horizontal direction (but same in the vertical direction). I calculated that the delay would be 1.2 seconds ( (2+1) - 1.80 ). So, can this setup detect one way light speed anisotropy, or where is my error? (I assumed that in the first figure the x and y speed components of light are both 210,000 km/sec. In the second figure they would be 105,000 and 210,000 so the diagonal speed is around 234,000 km/sec. 423,000 divided by diagonal speed yields the 1.80) |
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#2
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That will not detect anisotropy.
There are so many errors in your description that I do not know where to start. |
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#3
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#4
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Thanks for the reply, but please do tell me the first major error.
"suppose that one way speed of light is only 150,000 km/second..." Suppose 0=1. You can get anything from that. And when one invokes owls vs twls, the synch and measurement procedures must be specified. And if you are thinking of ether theories (you are talking about owls), lengths of objects are contracted by gamma. aso...aso..aso... |
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#5
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#7
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Well, imagine a person's running speed forward and backwards, they can be different. This is just an experiment setup like MM experiment, to detect the difference. Correct. Just like the mmx. Just like the mmx, just as predicted by sr and ether theories, there will b no difference. No sync is needed here, because there's only one clock, we're only measuring the time delay that light takes by travelling two different paths. Same in the second figure, only the orientation is changed. Ok, no synch is necesary, just as in the mmx. You can use one clock or use none with interference patterns. And if you are thinking of ether theories (you are talking about owls), lengths of objects are contracted by gamma. As I mentioned, there's only one reference frame involved here. The contraction doesn't apply locally. In ether theories it does apply to all frames. Wrt the ether frame, the length of one of the sides of ur setup is "really" contracted and thus you must use the apropriate equations. Try to be more explicative of your setup... |
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#8
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I haven't done any math on this one (and don't intend to) but my guess
would be that the measured "difference in the differences" in the two cases would be, at best, second order in both the size of the apparatus and in the difference in OWLS. There would be NO measured difference, exactly. I would try to explain him further but I will need a more explicative setup. How (and especially why) he did his calculations the way he did. |
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#9
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In the first figure, the delay between observed direct light and reflected light is 0.59 seconds ( (1+1) - 1.41 ). Correct. According to SR, the time interval indicated on the clock at the observer's location would be 1+1 - 1.41.... Here why do you (implicitly) assume that the speed of light on the straight segments are c where as in fig 2, you do not assume that? In fig 1, why do you assume that the speed of light is c and not c+v or c-v like in fig 2?... And anyhow, SR predicts the same time interval for the two figures. Both will give 2-1.41 as predicted by sr, as predicted by ethers. |
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#10
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