I have been working on a theory of gravity, and would like help
modeling everything else that we know about gravity into the theory. So
I can self publish my work in a journal or on a website like Wikipedia.
Gravity is represented as F= G( (m1*m2) / r^2 ) , and I would like to
change this theory, but make sure that the math still works exactly the
same. The Force Of Gravity is equal to the Gravitiational Constant
multiplide by the masses of two objects, and divided by their distance
appart.


So in my game where you form a circle of 10 pennies that represent the
gravitational pull of one object, and my individual penny which sits
outside of the circle entirely solitary. The odds still remain 10/11,
when you are flipping a fair coin to decide which pile wins each round.

As the piles move there is a .09765625% of flipping 10 wins in a row
for the individual penny, and a 50% chance that the pile of 10 pennies
will win on the first round. But my question was, how do I calculate
the average number of coin flips before the larger pile wins.

And the answer is k(n-k)

That's right, k(n-k). So in my illistration, you can see that the
circle of 10 pennies attracts to lonely penny into its gravitational
field after 10 coin flips on average. But theoretically the number of
rounds in the game could come close to infinity. And in practice you
win after the first round or too.

And I think you can see how this example illistrates a basic
understanding of gravity. If we assume that gravity accelerates
everything on earth at 9.8 m/s^2.

For example if we look at the earth as being a mass of 10 pennies, and
we look as the signle penny as being a distance of 4.9 meters, then if
we follow this equation.

t = sqrt( ( 2(4.9 m) ) / ( 9.8 m/s^2 ) ) = 1 s

And if we say the average number of coin flips it takes to produce this
effect is 10, then each coin flip represents 1/10th of a second. So on
average it takes just 1 second.

Now obviously with correct preportions of pennies, and more
sophisticated mathematics, and a better understanding of the physical
formulas for gravity. We could do a lot more. And be far more
precise.

So here is my final gravity theory. If the earth is represented as 10
pennies, then each meter of distance is represented as 0.225876976
pennies. And the equation k(n-k) calculates the average time in actual
seconds for the object to land.

For example 10(10.0451752951-10)=0.451752951

Which is the time it takes for an object 1 meter high to fall and land
on the earth.

But to make things more difficult we are going to use intervals of 1
millionth of a second. So instead of just using the number for one
meter, and multiplying it by 2 in the gravity equation. We devide it
by 1 million first, and that leaves us with an average number of
millionths of a second. That will not be as experientially variable.

wrote in message
ups.com...
I have been working on a theory of gravity, and would like help
modeling everything else that we know about gravity into the theory. So
I can self publish my work in a journal or on a website like Wikipedia.
Gravity is represented as F= G( (m1*m2) / r^2 ) ,

Wrong,. Learn the basics of GR. Gravity is space-time curvature.

Bill

and I would like to
change this theory, but make sure that the math still works exactly the
same. The Force Of Gravity is equal to the Gravitiational Constant
multiplide by the masses of two objects, and divided by their distance
appart.


So in my game where you form a circle of 10 pennies that represent the
gravitational pull of one object, and my individual penny which sits
outside of the circle entirely solitary. The odds still remain 10/11,
when you are flipping a fair coin to decide which pile wins each round.

As the piles move there is a .09765625% of flipping 10 wins in a row
for the individual penny, and a 50% chance that the pile of 10 pennies
will win on the first round. But my question was, how do I calculate
the average number of coin flips before the larger pile wins.

And the answer is k(n-k)

That's right, k(n-k). So in my illistration, you can see that the
circle of 10 pennies attracts to lonely penny into its gravitational
field after 10 coin flips on average. But theoretically the number of
rounds in the game could come close to infinity. And in practice you
win after the first round or too.

And I think you can see how this example illistrates a basic
understanding of gravity. If we assume that gravity accelerates
everything on earth at 9.8 m/s^2.

For example if we look at the earth as being a mass of 10 pennies, and
we look as the signle penny as being a distance of 4.9 meters, then if
we follow this equation.

t = sqrt( ( 2(4.9 m) ) / ( 9.8 m/s^2 ) ) = 1 s

And if we say the average number of coin flips it takes to produce this
effect is 10, then each coin flip represents 1/10th of a second. So on
average it takes just 1 second.

Now obviously with correct preportions of pennies, and more
sophisticated mathematics, and a better understanding of the physical
formulas for gravity. We could do a lot more. And be far more
precise.

So here is my final gravity theory. If the earth is represented as 10
pennies, then each meter of distance is represented as 0.225876976
pennies. And the equation k(n-k) calculates the average time in actual
seconds for the object to land.

For example 10(10.0451752951-10)=0.451752951

Which is the time it takes for an object 1 meter high to fall and land
on the earth.

But to make things more difficult we are going to use intervals of 1
millionth of a second. So instead of just using the number for one
meter, and multiplying it by 2 in the gravity equation. We devide it
by 1 million first, and that leaves us with an average number of
millionths of a second. That will not be as experientially variable.

wrote:
I have been working on a theory of gravity, and would like help
modeling everything else that we know about gravity into the theory. So
I can self publish my work in a journal or on a website like Wikipedia.
Gravity is represented as F= G( (m1*m2) / r^2 ) , and I would like to
change this theory, but make sure that the math still works exactly the
same. The Force Of Gravity is equal to the Gravitiational Constant
multiplide by the masses of two objects, and divided by their distance
appart.


So in my game where you form a circle of 10 pennies that represent the
gravitational pull of one object, and my individual penny which sits
outside of the circle entirely solitary. The odds still remain 10/11,
when you are flipping a fair coin to decide which pile wins each round.

As the piles move there is a .09765625% of flipping 10 wins in a row
for the individual penny, and a 50% chance that the pile of 10 pennies
will win on the first round. But my question was, how do I calculate
the average number of coin flips before the larger pile wins.

And the answer is k(n-k)

That's right, k(n-k). So in my illistration, you can see that the
circle of 10 pennies attracts to lonely penny into its gravitational
field after 10 coin flips on average. But theoretically the number of
rounds in the game could come close to infinity. And in practice you
win after the first round or too.

And I think you can see how this example illistrates a basic
understanding of gravity. If we assume that gravity accelerates
everything on earth at 9.8 m/s^2.

For example if we look at the earth as being a mass of 10 pennies, and
we look as the signle penny as being a distance of 4.9 meters, then if
we follow this equation.

t = sqrt( ( 2(4.9 m) ) / ( 9.8 m/s^2 ) ) = 1 s

And if we say the average number of coin flips it takes to produce this
effect is 10, then each coin flip represents 1/10th of a second. So on
average it takes just 1 second.

Now obviously with correct preportions of pennies, and more
sophisticated mathematics, and a better understanding of the physical
formulas for gravity. We could do a lot more. And be far more
precise.

So here is my final gravity theory. If the earth is represented as 10
pennies, then each meter of distance is represented as 0.225876976
pennies. And the equation k(n-k) calculates the average time in actual
seconds for the object to land.

For example 10(10.0451752951-10)=0.451752951

Which is the time it takes for an object 1 meter high to fall and land
on the earth.

But to make things more difficult we are going to use intervals of 1
millionth of a second. So instead of just using the number for one
meter, and multiplying it by 2 in the gravity equation. We devide it
by 1 million first, and that leaves us with an average number of
millionths of a second. That will not be as experientially variable.

You have no premises, and you don't even have an understandable
conclusion. Why would the pennies attract? Replacing the force of
gravity with some other force only leaves you in need of an explanation
for the new force. Physics cannot answer the question "why?", it can
only quantify the interactions that are observed. Physics is just math
in the form of a simulation of nature, the rest is entirely
philosophical bias.

It is possible however to show that there are not different types of
force, there is just force, which is itself nothing more than a
mathematical abstraction. It is dp/dt, nothing more. If we choose to
add a descriptor to the force such as "gravitational" or
"electromagnetic", then in doing so we've assumed the consequent when
we conclude that there are different types of force. In other words,
the illusion that there are different types of force stems directly
from an initial assumption that there are different types of force.
Physicists as a group in general aren't necessarily fond of sound
logical principles. Those that are impressed by logic don't necessarily
have time to critically examine every semantic interpretation of the
abstract math that they work with. It is however worth examining when
you are attempting to formulate a TOE or GUT, because inevitably these
are going to amount to nothing more than a streamlining of our semantic
interpretations of the math, or in other words, to a consistent
philosophy.

The sentiment that gravity is the result of curved space-time is
nothing more than a sentiment. Curved space-time is just a semantic
interpretation of a mathematical structure known as General Relativity.
If curved space-time is understood to be synonymous with General
Relativity, then the statement that gravity is the result of curved
space-time becomes a bit ridiculous, since that is all the same as
stating that a mere set of mathematical equations causes the
attraction. Hobba has yet to rid himself of modellitis. The map isn't
the territory.

On the other hand, if you want to describe gravity in terms of a bunch
of pennies, then you still have quite a long road before you are so
much as in Hobba's league. If you intend to formulate theories of
gravity, then you'll still have a long way to go after that. There is a
substantial difference between a working physicist and a theoretical
physicist. Hobba is a great working physicist, he's usually
technically correct, but he's not the greatest critical thinker in this
group. For that matter, neither are most of the well know theoretical
physicists. There are a few, but they are rare. Feynman showed fits of
sanity, but then he would discredit his own philosophical observations
by going ahead and writing junk such as QED. He knew it was mostly
just philosophy, yet treated it in lectures as though it was the
fundamental truth.

If you want to generate knew approaches, then you should begin by first
studying the human psyche and its relationship to the natural universe.
If you can't know something as comparatively simple as yourself, then
how do you expect to understand what spawned you. Study up on
empiricism, because the only correct source of premises in physics is
the actual universe.

Richard Perry

I have been working on a theory of gravity, and would like help
modeling everything else that we know about gravity into the theory.
So I can self publish my work in a journal or on a website like
Wikipedia. Gravity is represented as F= G( (m1*m2) / r^2 ) , and I
would like to change this theory, but make sure that the math still
works exactly the same. The Force Of Gravity is equal to the
Gravitiational Constant multiplide by the masses of two objects, and
divided by their distance appart.

So in my game where you form a circle of 10 pennies that represent the
gravitational pull of one object, and my individual penny which sits
outside of the circle entirely solitary. The odds still remain 10/11,
when you are flipping a fair coin to decide which pile wins each
round. As the piles move there is a .09765625% of flipping 10 wins in a
row for the individual penny, and a 50% chance that the pile of 10
pennies will win on the first round. But my question was, how do I
calculate the average number of coin flips before the larger pile
wins.

And the answer is k(n-k)

That's right, k(n-k). So in my illistration, you can see that the
circle of 10 pennies attracts to lonely penny into its gravitational
field after 10 coin flips on average. But theoretically the number of
rounds in the game could come close to infinity. And in practice you
win after the first round or too. And I think you can see how this
example illistrates a basic understanding of gravity. If we assume
that gravity accelerates everything on earth at 9.8 m/s^2. For example
if we look at the earth as being a mass of 10 pennies, and we look as
the signle penny as being a distance of 4.9 meters, then if we follow
this equation.

t = sqrt( ( 2(4.9 m) ) / ( 9.8 m/s^2 ) ) = 1 s

And if we say the average number of coin flips it takes to produce this
effect is 10, then each coin flip represents 1/10th of a second. So
on average it takes just 1 second. Now obviously with correct
preportions of pennies, and more sophisticated mathematics, and a
better understanding of the physical formulas for gravity. We could do
a lot more. And be far more precise.

So here is my gravity theory. We are using the quadratic formula to
solve: 2*n/9.8 = k(n-k) , for k
k=(1/14) (7n +- sqrt(49 n^2 - 40 n)).

So now an example...

We are dropping a ball from 10 meters above the ground. So we plug 10
meters into n to solve for k.

k=(1/14) (7n +- sqrt(49 n^2 - 40 n))
k=9.791574237

My question to calculate the average number of coin flips in my game is
k(n-k), so we plug in k & n:

k*(10-k) = 2.040816327 = average number of coin flips

Now we take the square root of the average number of flips to get the
actual time it takes to land:

sqrt(avg flips) = 1.428571429 = number of seconds to land.

Now finally to factor in a problem with my equation we say that if k is
9.791574327, that means our large gravity pile is that many pennies.
And our small gravity pile is exactly 0.208425673 pennies!

wrote:
I have been working on a theory of gravity, and would like help
modeling everything else that we know about gravity into the theory. So
I can self publish my work in a journal or on a website like Wikipedia.
Gravity is represented as F= G( (m1*m2) / r^2 ) , and I would like to
change this theory, but make sure that the math still works exactly the
same. The Force Of Gravity is equal to the Gravitiational Constant
multiplide by the masses of two objects, and divided by their distance
appart.


So in my game where you form a circle of 10 pennies that represent the
gravitational pull of one object, and my individual penny which sits
outside of the circle entirely solitary. The odds still remain 10/11,
when you are flipping a fair coin to decide which pile wins each round.

As the piles move there is a .09765625% of flipping 10 wins in a row
for the individual penny, and a 50% chance that the pile of 10 pennies
will win on the first round. But my question was, how do I calculate
the average number of coin flips before the larger pile wins.

And the answer is k(n-k)

That's right, k(n-k). So in my illistration, you can see that the
circle of 10 pennies attracts to lonely penny into its gravitational
field after 10 coin flips on average. But theoretically the number of
rounds in the game could come close to infinity. And in practice you
win after the first round or too.

And I think you can see how this example illistrates a basic
understanding of gravity. If we assume that gravity accelerates
everything on earth at 9.8 m/s^2.

For example if we look at the earth as being a mass of 10 pennies, and
we look as the signle penny as being a distance of 4.9 meters, then if
we follow this equation.

t = sqrt( ( 2(4.9 m) ) / ( 9.8 m/s^2 ) ) = 1 s

And if we say the average number of coin flips it takes to produce this
effect is 10, then each coin flip represents 1/10th of a second. So on
average it takes just 1 second.

Now obviously with correct preportions of pennies, and more
sophisticated mathematics, and a better understanding of the physical
formulas for gravity. We could do a lot more. And be far more
precise.

So here is my final gravity theory. If the earth is represented as 10
pennies, then each meter of distance is represented as 0.225876976
pennies. And the equation k(n-k) calculates the average time in actual
seconds for the object to land.

For example 10(10.0451752951-10)=0.451752951

Which is the time it takes for an object 1 meter high to fall and land
on the earth.

But to make things more difficult we are going to use intervals of 1
millionth of a second. So instead of just using the number for one
meter, and multiplying it by 2 in the gravity equation. We devide it
by 1 million first, and that leaves us with an average number of
millionths of a second. That will not be as experientially variable.