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| Tags: question, wavelengthfrequency |
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#1
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I have a question.
A beam of light (or radio waves) is thrown at Venus, which for purposes of this problem is a mirror moving 5 km/s or 1.667 * 10^-5 c away from us. The beam is, say, 100 cm wavelength and 2.99792458 GHz frequency. The energy of each photon would be about 6.626 * 10^-34 J-s * 2.99792458 GHz = 12.39829 micro-eV. Assuming no disruption from climbing out of Earth's gravity well, atmospheric issues, or falling into Venus's well, what would be the expected return wavelength, frequency, and energy? Special Relativity (SR): The beam leaves Earth at speed c, reflects off Venus at speed c, and comes back to Earth at speed c. The calculations for the Lorentz are somewhat involved but boil down to the following: nu = 2.99792458 * (c-v)/(c+v) = 2.9978246309 GHz lambda = 100 cm * (c+v)/(c-v) or 100.003334 cm energy = 12.39829 * (c-v)/(c+v) = 12.38970 micro-eV. Frictionless Newtonian: The beam leaves Earth at speed c, bounces off Venus at speed c-v, returns to Earth at speed c-2v. This leads to the following event calculations, if one assumes the Galilean transform: x_E = x_V-vt_V t_E = t_V and because an observer can't see light pulses unless his local x is 0, we get: (0,1)_E = (-v,1)_V = (0,1+v/(c-v))_V (0,1+v/(c-v))_V = (v+v^2/(c-v)), 1+v/(c-v))_E = (0,1+v/(c-v)-(v+v^2)/((c-v)(c-2v)))_E = (0,(v^2+(2c+1)v-c^2)/(3cv-2v^2-c^2))_E Therefore, nu = 2.99792458 GHz * (v^2+(2c+1)v-c^2)/(3cv-2v^2-c^2) = 2.9979245775 GHz lambda = (c-2v)/nu = 99.996666 cm energy = 12.39829 * ((c-2v)/c)^2 = 12.39746 micro-eV. There are some other theories, such as absolute aether theory (motionless Sun), absolute aether theory (motionless Venus), absolute aether theory (motionless Earth -- which should lead to the same results as frictionless Newtonian for obvious reasons), decaying aether theory (motionless Sun), decaying aether theory (motionless Earth), decaying aether theory (motionless Venus), and mirror reemitter theory (which assumes a mirror somehow adds more energy to the reflected particle) that I could consider, were I organized enough to make the calculations. (In decaying aether theory the light is considered to start out at a velocity c+w for some w, then decay in velocity to c relative to the rigid aether; this decay factor is exponential relative to time of propagation. It is far from clear how well any of these coincide with H. Wilson's H-aether theory, Louis Savain's particle lattice jump theory, or Ken Seto's IRT.) Presumably this has already been verified in some form by radar waves, and with far greater sophistication, to the point of checking a *General Relativity* theory, not just a special one. Comments? [sci.math included for checking of my math. sci.physics included because this might be construed a general physics question. Followups set to sci.physics.relativity.] -- #191, It's still legal to go .sigless. |
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#2
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A beam of light (or radio waves) is thrown at Venus, which for purposes of this problem is a mirror moving 5 km/s or 1.667 * 10^-5 c away from us. The beam is, say, 100 cm wavelength and 2.99792458 GHz frequency. The energy of each photon would be about 6.626 * 10^-34 J-s * 2.99792458 GHz = 12.39829 micro-eV. Assuming no disruption from climbing out of Earth's gravity well, atmospheric issues, or falling into Venus's well, what would be the expected return wavelength, frequency, and energy? Special Relativity (SR): The beam leaves Earth at speed c, reflects off Venus at speed c, and comes back to Earth at speed c. The calculations for the Lorentz are somewhat involved but boil down to the following: nu = 2.99792458 * (c-v)/(c+v) = 2.9978246309 GHz lambda = 100 cm * (c+v)/(c-v) or 100.003334 cm energy = 12.39829 * (c-v)/(c+v) = 12.38970 micro-eV. Correct. In modern ether theories (prefered frame theories), we obtain the exact same result, and the calculations are very simple. We get f_obsserved = f_source *(1-b)/(1+b), b=v/c , just as in SR. But, 'v' in this case should not be taken as the speed of venus withinn the ether but as the measured speed, the speed earthings measure it to be. In ether theories, speed measured speed. Frictionless Newtonian: SNIP other theories |
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#3
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there is a few wrong in the equation...
regards http://www.geocities.com/iibm2323 http://unificationgamez.50megs.com/ http://unificationgamers.50megs.com/ http://unificationwars.worldbreak.com/ |
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#4
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On a sunny day (Mon, 07 Aug 2006 00:00:14 GMT) it happened The Ghost In The
Machine wrote in : I have a question. A beam of light (or radio waves) is thrown at Venus, which for purposes of this problem is a mirror moving 5 km/s or 1.667 * 10^-5 c away from us. The beam is, say, 100 cm wavelength and 2.99792458 GHz frequency. For starters, 100 cm (1 meter) is about 300 MHz, you are a factor 10 off. Lightspeed is 300 000 000 meter /second, so 300 000 000 / 1 = 300 000 000 = 300 MHz. Now with the new values... I dunno, Tom v Flandern? Interesting experiment worth doing... |
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#5
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On Mon, 07 Aug 2006 00:00:14 GMT, The Ghost In The Machine
wrote: I have a question. A beam of light (or radio waves) is thrown at Venus, which for purposes of this problem is a mirror moving 5 km/s or 1.667 * 10^-5 c away from us. The beam is, say, 100 cm wavelength and 2.99792458 GHz frequency. 100cm is 299.792458MHz Regards, Boris Mohar Got Knock? - see: Viatrack Printed Circuit Designs (among other things) http://www.viatrack.ca void _-void-_ in the obvious place -- Posted via a free Usenet account from http://www.teranews.com |
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#6
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"Boris Mohar" wrote in message ... | On Mon, 07 Aug 2006 00:00:14 GMT, The Ghost In The Machine | wrote: | | I have a question. | | A beam of light (or radio waves) is thrown at Venus, which for purposes of | this problem is a mirror moving 5 km/s or 1.667 * 10^-5 c away from us. | The beam is, say, 100 cm wavelength and 2.99792458 GHz frequency. | | 100cm is 299.792458MHz | Egads... 100 cm = 1 metre, but why is 100 chestnuts one macadamia? Have nice mix of units, nut. Androcles. | | Regards, | | Boris Mohar | | Got Knock? - see: | Viatrack Printed Circuit Designs (among other things) http://www.viatrack.ca | | void _-void-_ in the obvious place | | | | -- | Posted via a free Usenet account from http://www.teranews.com | |
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