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| Tags: force, motion, without |
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#1
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Is it possible to move a particle without applying a force on it? One
observation suggests that the answer is 'yes'. And that phenomenon is the bending of light in intense gravitational field (like that of a huge star,say sun). F= force experienced by the photon(s) due to the gravitational field a= Acceleration of the photon due to F M=mass of photon Ms=mass of sun r=Distance b\w sun and photon(s) F=M*a F=0*a=0 But the Gravitational force(f)=(G*Ms*M)/(r^2) Where f=F therefore, F=f=M*a=(G*Ms*M)/(r^2) = a=(G*Ms)/(r^2) This acceleration causes the change in the velocity(Not the change of the speed of the photon(s), but the direction aspect of the velocity) of the photon(s) and this acceleration is caused by?.........Zero force? Thanx, rAgAv. |
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#2
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Whether, in the mean time, it is already clear as known, that every body perseveres in its state of resting, or uniformly moving in a right line, unless however, it is compelled to any change along that state by forces impressed upon it. However, the change of a motion, a definitely remains a proportionnal to the motive of the force impressed, and therefore, it would be made in the direction of the right line in which, however, that force is impressed. Therefore, along that case, would be always along every action opposed an equal reaction, or along, a mutual actions of two bodies upon each other, which would be always an equal matter, and a definitely directed to a define opposed directions. -- Ahmed Ouahi, Architect Best Regards! "rAgAv" wrote in message ps.com... Is it possible to move a particle without applying a force on it? One observation suggests that the answer is 'yes'. And that phenomenon is the bending of light in intense gravitational field (like that of a huge star,say sun). F= force experienced by the photon(s) due to the gravitational field a= Acceleration of the photon due to F M=mass of photon Ms=mass of sun r=Distance b\w sun and photon(s) F=M*a F=0*a=0 But the Gravitational force(f)=(G*Ms*M)/(r^2) Where f=F therefore, F=f=M*a=(G*Ms*M)/(r^2) = a=(G*Ms)/(r^2) This acceleration causes the change in the velocity(Not the change of the speed of the photon(s), but the direction aspect of the velocity) of the photon(s) and this acceleration is caused by?.........Zero force? Thanx, rAgAv. |
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#3
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As far as I know they change the direction of there movement because
they are following the shhortest in between point A and point B. The shortest path is not a straight line due to deformation in space-time caused by the pressence of a massive object like a star. |
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#4
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rAgAv wrote:
Is it possible to move a particle without applying a force on it? By removing a force from it. |
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#5
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"rAgAv" kirjoitti egroups.com... Is it possible to move a particle without applying a force on it? One observation suggests that the answer is 'yes'. And that phenomenon is the bending of light in intense gravitational field (like that of a huge star,say sun). F= force experienced by the photon(s) due to the gravitational field a= Acceleration of the photon due to F M=mass of photon Ms=mass of sun r=Distance b\w sun and photon(s) F=M*a F=0*a=0 But the Gravitational force(f)=(G*Ms*M)/(r^2) Where f=F therefore, F=f=M*a=(G*Ms*M)/(r^2) = a=(G*Ms)/(r^2) This acceleration causes the change in the velocity(Not the change of the speed of the photon(s), but the direction aspect of the velocity) of the photon(s) and this acceleration is caused by?.........Zero force? Thanx, rAgAv. There is an answer, but only one. http://www.wakkanet.fi/~fields/ Henry Haapalainen |
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#6
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"Ned" kirjoitti ... rAgAv wrote: Is it possible to move a particle without applying a force on it? By removing a force from it. All particles are moving in free-fall. That means that there is no force acting on them. That sounds insane, but there is an answer, only one. http://www.wakkanet.fi/~fields/ Henry Haapalainen |
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#7
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"rAgAv" wrote in message ps.com... Is it possible to move a particle without applying a force on it? Of course - remember Newtons first law. One observation suggests that the answer is 'yes'. And that phenomenon is the bending of light in intense gravitational field (like that of a huge star,say sun). F= force experienced by the photon(s) due to the gravitational field a= Acceleration of the photon due to F M=mass of photon Ms=mass of sun r=Distance b\w sun and photon(s) F=M*a F=0*a=0 But the Gravitational force(f)=(G*Ms*M)/(r^2) Wrong model - you need GR for this - not classical mechanics. Bill Where f=F therefore, F=f=M*a=(G*Ms*M)/(r^2) = a=(G*Ms)/(r^2) This acceleration causes the change in the velocity(Not the change of the speed of the photon(s), but the direction aspect of the velocity) of the photon(s) and this acceleration is caused by?.........Zero force? Thanx, rAgAv. |
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#8
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"rAgAv" wrote in message ps.com... Is it possible to move a particle without applying a force on it? Well, if you really mean 'Is it possible to change the state of motion without an imbalanced force being applied', the answer is ...maybe. One good example is how virtual particles can perturb the state of motion of real particles. Now, a virtual particle is a character that pops into existence and then very quickly disappears once again into the ether. But while it is here it acts just like a real particle whose energy is permanent. What you have here is a good example of imaginary energy being able to perform real work. The long and the short of it is that you will observe a particle moving around with no detectable mechanism. Greysky www.allocations.cc Learn how to build a FTL radio. |
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#9
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greysky wrote: "rAgAv" wrote in message ps.com... Is it possible to move a particle without applying a force on it? Well, if you really mean 'Is it possible to change the state of motion without an imbalanced force being applied', the answer is ...maybe. One good example is how virtual particles can perturb the state of motion of real particles. Now, a virtual particle is a character that pops into existence and then very quickly disappears once again into the ether. But while it is here it acts just like a real particle whose energy is permanent. What you have here is a good example of imaginary energy being able to perform real work. The long and the short of it is that you will observe a particle moving around with no detectable mechanism. Greysky www.allocations.cc Learn how to build a FTL radio. ------------------------------------------------ Quot from above ''Now, a virtual particle is a character that pops into existence and then very quickly disappears once again into the ether. But ....."" end of quote it could be funny (:-) if it was not sad !!! (:-( ) sad to se how far physics stupidity and cheating can go !! Y.Porat ----------------------------------------- |
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