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"Sue..." wrote in message oups.com... Len Gaasenbeek wrote: "Sue..." wrote in message ups.com... Len Gaasenbeek wrote: .................................................. ...................... Does your paper explain how that corkscrewing critter illuminates all four of these: http://www.eso.org/projects/vlti/ima...-smallsize.jpg http://www.eso.org/projects/vlti/ ...so it can add constructivly or destructivly after passing the four delay lines ? Sue... http://web.mit.edu/8.02t/www/802TEAL3D/teal_tour.htm .................................................. ........... To Sue, In essence what you are saying is, that the since the workable size of an optical telescope is limited and consequently can only project the image of an observed star on a screen of limited quality. To improve the sharpness and detail of the projected image of a distant star astronomers hit on the idea of using several telescopes and have each telescope project the image of the observed star on the same spot on the screen. The resulting improved image is comparable to what one telescope of the same light gathering capacity as the 4 separate telescopes, would produce. The added complication is that the projected images of the four telescopes have to reach the screen in phase with each other for them to add up successfully. (Similar to the two split experiment) To this end the distance traveled by the light from each telescope to the screen must be the same for the images to arrive in phase. This way the images will add to, rather than subtract from, each other. This latest development has not come about as a result of a better understanding exactly what a light beam consists off. It is simply a practical solution to an old problem. However the helical photon wave concept does provide for a better understanding what happens when similar light beams are in or out of phase with each other. Then you have some inclusion of Feynman's path integral ? http://www.physics.yorku.ca/undergra...ch/Feynm4.html Sue... .................................................. .............. To Sue, First of all, I am not an admirer of Feynman since he was the worst (academic) offender in turning the science of particle physics into a religious magic show and himself into its prophet. Secondly, I think that your above quotation by Feynman confuses the issue rather than add to our understanding of the use of multiple telescopes. Basically what I was saying in my previous posting was that, if you were giving a slide show in a large hall and wanted to brighten the projected image of the slide projector, you could use a second slide projector on top of your existing projector to project a copy of the same slide on the screen, making the projected image twice as bright. However for this to work, the second projector would have to be the same distance away from the screen as the first projector. It would have to be pointed at exactly the same spot on the screen and the second projected image would have to be of the same size as the first image. In so doing the two projected images should also be in phase and strengthen rather than detract from each other. In today's computer world the television image of the star produced by each telescope can be digitally added to the television images generated by any number of other telescopes. This way, the image of the star produced by each telescope can be computer manipulated to make them a near perfect match, before they are digitally added together to form the resultant image. Len. Suppose I want to take the emission of a single star-atom (photon?) and subtract two of the mirrors from the other two to get a complete null ? The light from one projector will not destructivly interfer with the light from another as you have described the overlay of images. The VLTI however permits both constructive and destructive interference. Does your theory account for the destructive interferrance that is observed at VLTI Paranal ? Sue... .................................................. .................. To Sue, Feynman analysis does not correspond with reality since the vacuum of space gradually changes into the medium of the world's atmosphere, i.e. there is no distinct dividing line between the two. Moreover the earth atmosphere is not homogeneous, as it gets progressively denser the closer you come to earth. In addition its mixture changes as you go along. Beyond that, I have said about as much as I wanted to say in my previous postings, to explain the use of multiple telescopes, especially since I don't really understand your last question. If you want more from me, I am afraid I can't help you. Len. .................................................. ... |
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Len Gaasenbeek wrote: "Sue..." wrote in message oups.com... Len Gaasenbeek wrote: "Sue..." wrote in message ups.com... Len Gaasenbeek wrote: .................................................. ..................... Does your paper explain how that corkscrewing critter illuminates all four of these: http://www.eso.org/projects/vlti/ima...-smallsize.jpg http://www.eso.org/projects/vlti/ ...so it can add constructivly or destructivly after passing the four delay lines ? Sue... http://web.mit.edu/8.02t/www/802TEAL3D/teal_tour.htm .................................................. ........... To Sue, In essence what you are saying is, that the since the workable size of an optical telescope is limited and consequently can only project the image of an observed star on a screen of limited quality. To improve the sharpness and detail of the projected image of a distant star astronomers hit on the idea of using several telescopes and have each telescope project the image of the observed star on the same spot on the screen. The resulting improved image is comparable to what one telescope of the same light gathering capacity as the 4 separate telescopes, would produce. The added complication is that the projected images of the four telescopes have to reach the screen in phase with each other for them to add up successfully. (Similar to the two split experiment) To this end the distance traveled by the light from each telescope to the screen must be the same for the images to arrive in phase. This way the images will add to, rather than subtract from, each other. This latest development has not come about as a result of a better understanding exactly what a light beam consists off. It is simply a practical solution to an old problem. However the helical photon wave concept does provide for a better understanding what happens when similar light beams are in or out of phase with each other. Then you have some inclusion of Feynman's path integral ? http://www.physics.yorku.ca/undergra...ch/Feynm4.html Sue... .................................................. .............. To Sue, First of all, I am not an admirer of Feynman since he was the worst (academic) offender in turning the science of particle physics into a religious magic show and himself into its prophet. Secondly, I think that your above quotation by Feynman confuses the issue rather than add to our understanding of the use of multiple telescopes. Basically what I was saying in my previous posting was that, if you were giving a slide show in a large hall and wanted to brighten the projected image of the slide projector, you could use a second slide projector on top of your existing projector to project a copy of the same slide on the screen, making the projected image twice as bright. However for this to work, the second projector would have to be the same distance away from the screen as the first projector. It would have to be pointed at exactly the same spot on the screen and the second projected image would have to be of the same size as the first image. In so doing the two projected images should also be in phase and strengthen rather than detract from each other. In today's computer world the television image of the star produced by each telescope can be digitally added to the television images generated by any number of other telescopes. This way, the image of the star produced by each telescope can be computer manipulated to make them a near perfect match, before they are digitally added together to form the resultant image. Len. Suppose I want to take the emission of a single star-atom (photon?) and subtract two of the mirrors from the other two to get a complete null ? The light from one projector will not destructivly interfer with the light from another as you have described the overlay of images. The VLTI however permits both constructive and destructive interference. Does your theory account for the destructive interferrance that is observed at VLTI Paranal ? Sue... .................................................. ................. To Sue, Feynman analysis does not correspond with reality since the vacuum of space gradually changes into the medium of the world's atmosphere, i.e. there is no distinct dividing line between the two. Moreover the earth atmosphere is not homogeneous, as it gets progressively denser the closer you come to earth. In addition its mixture changes as you go along. Beyond that, I have said about as much as I wanted to say in my previous postings, to explain the use of multiple telescopes, especially since I don't really understand your last question. If you want more from me, I am afraid I can't help you. Len. I take that to be a negative response to my question. I encourage you to spend a bit more time with Feynman's path integral approach because it *does* model the VLTI in interference mode. Kind regards, Sue... .................................................. .. |
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.................................................. .................... I take that to be a negative response to my question. I encourage you to spend a bit more time with Feynman's path integral approach because it *does* model the VLTI in interference mode. Kind regards, Sue... .................................................. ................. To Sue, I don't want to cut you off as long as we are having a real discussion. So I will give it one more try. When we look at a multicoloured light image of a body, the light consists of many colours and frequencies in a multiple complex phase relationship. Consequently if we do the two slit experiment with two separate white light images NO INTERFERENCE PATTERN WILL RESULT! Only if we use one light source and split it in two by letting it go trough two adjoining slits, will an interference pattern show on the screen. On the other hand if we take two separate monochromatic laser light sources and have one shine on each slit, an interference pattern will once more show at the screen behind the slits, EVEN THOUGH WE ARE NOW DEALING WITH TWO SEPARATE LIGHT SOURCES. This is the case because a pure laser source of a single colour can only be either in or out of phase with another laser of exactly the same monochrome colour. In the case of two separate slide projectors projecting the same image on the screen at the same location, the light source that illuminates each slide is NOT the same. Consequently, interference between the two projected images will not result even though the projected image is the same. (In addition it is difficult to make two identical copies of a slide.) In the case of the multiple telescopes, the same star is used as a light source which means that an interference pattern may result, although not to the same extend as would have occurred if we had used the star in a two slit experiment. This is the case because it is much harder to make two telescopes which are exactly alike than two slits. I hope this answers your question since I am still not quite sure what was bothering you about my previous postings. Good luck, Len. ................................................. |
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Len Gaasenbeek wrote: .................................................. ................... I take that to be a negative response to my question. I encourage you to spend a bit more time with Feynman's path integral approach because it *does* model the VLTI in interference mode. Kind regards, Sue... .................................................. ................ To Sue, I don't want to cut you off as long as we are having a real discussion. So I will give it one more try. When we look at a multicoloured light image of a body, the light consists of many colours and frequencies in a multiple complex phase relationship. Consequently if we do the two slit experiment with two separate white light images NO INTERFERENCE PATTERN WILL RESULT! Only if we use one light source and split it in two by letting it go trough two adjoining slits, will an interference pattern show on the screen. On the other hand if we take two separate monochromatic laser light sources and have one shine on each slit, an interference pattern will once more show at the screen behind the slits, EVEN THOUGH WE ARE NOW DEALING WITH TWO SEPARATE LIGHT SOURCES. This is the case because a pure laser source of a single colour can only be either in or out of phase with another laser of exactly the same monochrome colour. Get a pair of laser pointers and try it. In the case of two separate slide projectors projecting the same image on the screen at the same location, the light source that illuminates each slide is NOT the same. Consequently, interference between the two projected images will not result even though the projected image is the same. (In addition it is difficult to make two identical copies of a slide.) They will be twice as bright because it is random light. In the case of the multiple telescopes, the same star is used as a light source which means that an interference pattern may result, although not to the same extend as would have occurred if we had used the star in a two slit experiment. This is the case because it is much harder to make two telescopes which are exactly alike than two slits. Click on the VLTI delay line to see just how hard it is. Flying machines are hard too, but I don't discount that such devices might exist just because the problem is difficult. I hope this answers your question since I am still not quite sure what was bothering you about my previous postings. You have the photon clocks of Feynman's path integral but you seem to be lacking the abilty to explore all paths. Asking about the VLTI is just a convenient way to inquire about your theory because a real device leaves no ambiguity. Without ability to explore all paths, your theory predicts that VLTI does not work in interferometer mode... but it does work so you need to go break their telescope. ;o) Sue... Good luck, Len. ................................................ |
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"Sue..." wrote in message ups.com... Len Gaasenbeek wrote: .................................................. ................... I take that to be a negative response to my question. I encourage you to spend a bit more time with Feynman's path integral approach because it *does* model the VLTI in interference mode. Kind regards, Sue... .................................................. ................ To Sue, I don't want to cut you off as long as we are having a real discussion. So I will give it one more try. When we look at a multicoloured light image of a body, the light consists of many colours and frequencies in a multiple complex phase relationship. Consequently if we do the two slit experiment with two separate white light images NO INTERFERENCE PATTERN WILL RESULT! Only if we use one light source and split it in two by letting it go trough two adjoining slits, will an interference pattern show on the screen. On the other hand if we take two separate monochromatic laser light sources and have one shine on each slit, an interference pattern will once more show at the screen behind the slits, EVEN THOUGH WE ARE NOW DEALING WITH TWO SEPARATE LIGHT SOURCES. This is the case because a pure laser source of a single colour can only be either in or out of phase with another laser of exactly the same monochrome colour. Get a pair of laser pointers and try it. In the case of two separate slide projectors projecting the same image on the screen at the same location, the light source that illuminates each slide is NOT the same. Consequently, interference between the two projected images will not result even though the projected image is the same. (In addition it is difficult to make two identical copies of a slide.) They will be twice as bright because it is random light. In the case of the multiple telescopes, the same star is used as a light source which means that an interference pattern may result, although not to the same extend as would have occurred if we had used the star in a two slit experiment. This is the case because it is much harder to make two telescopes which are exactly alike than two slits. Click on the VLTI delay line to see just how hard it is. Flying machines are hard too, but I don't discount that such devices might exist just because the problem is difficult. I hope this answers your question since I am still not quite sure what was bothering you about my previous postings. You have the photon clocks of Feynman's path integral but you seem to be lacking the abilty to explore all paths. Asking about the VLTI is just a convenient way to inquire about your theory because a real device leaves no ambiguity. Without ability to explore all paths, your theory predicts that VLTI does not work in interferometer mode... but it does work so you need to go break their telescope. ;o) Sue... .................................................. ............... To Sue, Where does my theory predict that VLTI does not work? You are beginning to **** me off. Len. .................................................. ............ |
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Len Gaasenbeek wrote:
"Sue..." wrote in message ups.com... Len Gaasenbeek wrote: .................................................. ................... I take that to be a negative response to my question. I encourage you to spend a bit more time with Feynman's path integral approach because it *does* model the VLTI in interference mode. Kind regards, Sue... .................................................. ................ To Sue, I don't want to cut you off as long as we are having a real discussion. So I will give it one more try. When we look at a multicoloured light image of a body, the light consists of many colours and frequencies in a multiple complex phase relationship. Consequently if we do the two slit experiment with two separate white light images NO INTERFERENCE PATTERN WILL RESULT! Only if we use one light source and split it in two by letting it go trough two adjoining slits, will an interference pattern show on the screen. On the other hand if we take two separate monochromatic laser light sources and have one shine on each slit, an interference pattern will once more show at the screen behind the slits, EVEN THOUGH WE ARE NOW DEALING WITH TWO SEPARATE LIGHT SOURCES. This is the case because a pure laser source of a single colour can only be either in or out of phase with another laser of exactly the same monochrome colour. Get a pair of laser pointers and try it. In the case of two separate slide projectors projecting the same image on the screen at the same location, the light source that illuminates each slide is NOT the same. Consequently, interference between the two projected images will not result even though the projected image is the same. (In addition it is difficult to make two identical copies of a slide.) They will be twice as bright because it is random light. In the case of the multiple telescopes, the same star is used as a light source which means that an interference pattern may result, although not to the same extend as would have occurred if we had used the star in a two slit experiment. This is the case because it is much harder to make two telescopes which are exactly alike than two slits. Click on the VLTI delay line to see just how hard it is. Flying machines are hard too, but I don't discount that such devices might exist just because the problem is difficult. I hope this answers your question since I am still not quite sure what was bothering you about my previous postings. You have the photon clocks of Feynman's path integral but you seem to be lacking the abilty to explore all paths. Asking about the VLTI is just a convenient way to inquire about your theory because a real device leaves no ambiguity. Without ability to explore all paths, your theory predicts that VLTI does not work in interferometer mode... but it does work so you need to go break their telescope. ;o) Sue... .................................................. .............. To Sue, Where does my theory predict that VLTI does not work? Light, on the other hand, behaves quite differently. It travels best through a vacuum and consists of a stream of particles called photons. http://www2.rideau.net/gaasbeek/spap1.html Light does not exist absent the motion of an electron. A space with an electron is not a vacuum. As a matter of fact, when we look out anywhere and see light, we can always "see" some matter as the source of the light. We don't just see light http://nobelprize.org/physics/laurea...n-lecture.html You are beginning to **** me off. Your problem is with Feynman, not with me. His mirrors work... your mirrors don't work. Break some mirrors or fix your theory. )"Antenna arrays" http://www.ee.surrey.ac.uk/Personal/.../antarray.html Sue... Len. .................................................. ........... |
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"Sue..." wrote in message ups.com... Len Gaasenbeek wrote: "Sue..." wrote in message ups.com... Len Gaasenbeek wrote: .................................................. .................... I take that to be a negative response to my question. I encourage you to spend a bit more time with Feynman's path integral approach because it *does* model the VLTI in interference mode. Kind regards, Sue... .................................................. ................ To Sue, I don't want to cut you off as long as we are having a real discussion. So I will give it one more try. When we look at a multicoloured light image of a body, the light consists of many colours and frequencies in a multiple complex phase relationship. Consequently if we do the two slit experiment with two separate white light images NO INTERFERENCE PATTERN WILL RESULT! Only if we use one light source and split it in two by letting it go trough two adjoining slits, will an interference pattern show on the screen. On the other hand if we take two separate monochromatic laser light sources and have one shine on each slit, an interference pattern will once more show at the screen behind the slits, EVEN THOUGH WE ARE NOW DEALING WITH TWO SEPARATE LIGHT SOURCES. This is the case because a pure laser source of a single colour can only be either in or out of phase with another laser of exactly the same monochrome colour. Get a pair of laser pointers and try it. In the case of two separate slide projectors projecting the same image on the screen at the same location, the light source that illuminates each slide is NOT the same. Consequently, interference between the two projected images will not result even though the projected image is the same. (In addition it is difficult to make two identical copies of a slide.) They will be twice as bright because it is random light. In the case of the multiple telescopes, the same star is used as a light source which means that an interference pattern may result, although not to the same extend as would have occurred if we had used the star in a two slit experiment. This is the case because it is much harder to make two telescopes which are exactly alike than two slits. Click on the VLTI delay line to see just how hard it is. Flying machines are hard too, but I don't discount that such devices might exist just because the problem is difficult. I hope this answers your question since I am still not quite sure what was bothering you about my previous postings. You have the photon clocks of Feynman's path integral but you seem to be lacking the abilty to explore all paths. Asking about the VLTI is just a convenient way to inquire about your theory because a real device leaves no ambiguity. Without ability to explore all paths, your theory predicts that VLTI does not work in interferometer mode... but it does work so you need to go break their telescope. ;o) Sue... .................................................. .............. To Sue, Where does my theory predict that VLTI does not work? Light, on the other hand, behaves quite differently. It travels best through a vacuum and consists of a stream of particles called photons. http://www2.rideau.net/gaasbeek/spap1.html Light does not exist absent the motion of an electron. A space with an electron is not a vacuum. As a matter of fact, when we look out anywhere and see light, we can always "see" some matter as the source of the light. We don't just see light http://nobelprize.org/physics/laurea...n-lecture.html You are beginning to **** me off. Your problem is with Feynman, not with me. His mirrors work... your mirrors don't work. Break some mirrors or fix your theory. )"Antenna arrays" http://www.ee.surrey.ac.uk/Personal/.../antarray.html Sue... Len. .................................................. ........... To Sue, Some for renown, on scraps of learning dote, And think they grow immortal as they quote. Edward Young (1683-1765) British poet. Love of Fame, II Len. .................................................. ................... |
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Len Gaasenbeek wrote: "Sue..." wrote in message ups.com... Len Gaasenbeek wrote: "Sue..." wrote in message ups.com... Len Gaasenbeek wrote: .................................................. ................... I take that to be a negative response to my question. I encourage you to spend a bit more time with Feynman's path integral approach because it *does* model the VLTI in interference mode. Kind regards, Sue... .................................................. ................ To Sue, I don't want to cut you off as long as we are having a real discussion. So I will give it one more try. When we look at a multicoloured light image of a body, the light consists of many colours and frequencies in a multiple complex phase relationship. Consequently if we do the two slit experiment with two separate white light images NO INTERFERENCE PATTERN WILL RESULT! Only if we use one light source and split it in two by letting it go trough two adjoining slits, will an interference pattern show on the screen. On the other hand if we take two separate monochromatic laser light sources and have one shine on each slit, an interference pattern will once more show at the screen behind the slits, EVEN THOUGH WE ARE NOW DEALING WITH TWO SEPARATE LIGHT SOURCES. This is the case because a pure laser source of a single colour can only be either in or out of phase with another laser of exactly the same monochrome colour. Get a pair of laser pointers and try it. In the case of two separate slide projectors projecting the same image on the screen at the same location, the light source that illuminates each slide is NOT the same. Consequently, interference between the two projected images will not result even though the projected image is the same. (In addition it is difficult to make two identical copies of a slide.) They will be twice as bright because it is random light. In the case of the multiple telescopes, the same star is used as a light source which means that an interference pattern may result, although not to the same extend as would have occurred if we had used the star in a two slit experiment. This is the case because it is much harder to make two telescopes which are exactly alike than two slits. Click on the VLTI delay line to see just how hard it is. Flying machines are hard too, but I don't discount that such devices might exist just because the problem is difficult. I hope this answers your question since I am still not quite sure what was bothering you about my previous postings. You have the photon clocks of Feynman's path integral but you seem to be lacking the abilty to explore all paths. Asking about the VLTI is just a convenient way to inquire about your theory because a real device leaves no ambiguity. Without ability to explore all paths, your theory predicts that VLTI does not work in interferometer mode... but it does work so you need to go break their telescope. ;o) Sue... .................................................. .............. To Sue, Where does my theory predict that VLTI does not work? Light, on the other hand, behaves quite differently. It travels best through a vacuum and consists of a stream of particles called photons. http://www2.rideau.net/gaasbeek/spap1.html Light does not exist absent the motion of an electron. A space with an electron is not a vacuum. As a matter of fact, when we look out anywhere and see light, we can always "see" some matter as the source of the light. We don't just see light http://nobelprize.org/physics/laurea...n-lecture.html You are beginning to **** me off. Your problem is with Feynman, not with me. His mirrors work... your mirrors don't work. Break some mirrors or fix your theory. )"Antenna arrays" http://www.ee.surrey.ac.uk/Personal/.../antarray.html Sue... Len. .................................................. ........... To Sue, Some for renown, on scraps of learning dote, And think they grow immortal as they quote. Edward Young (1683-1765) British poet. Love of Fame, II Len. I quote what is probably the most successful theories in physics. You have your work cut out for you if you think cutting it in half impoves it. http://www.physorg.com/news8731.html Sue... .................................................. .................. |
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"Sue..." wrote in message ups.com... Len Gaasenbeek wrote: "Sue..." wrote in message ups.com... Len Gaasenbeek wrote: "Sue..." wrote in message ups.com... Len Gaasenbeek wrote: .................................................. ................... I take that to be a negative response to my question. I encourage you to spend a bit more time with Feynman's path integral approach because it *does* model the VLTI in interference mode. Kind regards, Sue... .................................................. ................. To Sue, I don't want to cut you off as long as we are having a real discussion. So I will give it one more try. When we look at a multicoloured light image of a body, the light consists of many colours and frequencies in a multiple complex phase relationship. Consequently if we do the two slit experiment with two separate white light images NO INTERFERENCE PATTERN WILL RESULT! Only if we use one light source and split it in two by letting it go trough two adjoining slits, will an interference pattern show on the screen. On the other hand if we take two separate monochromatic laser light sources and have one shine on each slit, an interference pattern will once more show at the screen behind the slits, EVEN THOUGH WE ARE NOW DEALING WITH TWO SEPARATE LIGHT SOURCES. This is the case because a pure laser source of a single colour can only be either in or out of phase with another laser of exactly the same monochrome colour. Get a pair of laser pointers and try it. In the case of two separate slide projectors projecting the same image on the screen at the same location, the light source that illuminates each slide is NOT the same. Consequently, interference between the two projected images will not result even though the projected image is the same. (In addition it is difficult to make two identical copies of a slide.) They will be twice as bright because it is random light. In the case of the multiple telescopes, the same star is used as a light source which means that an interference pattern may result, although not to the same extend as would have occurred if we had used the star in a two slit experiment. This is the case because it is much harder to make two telescopes which are exactly alike than two slits. Click on the VLTI delay line to see just how hard it is. Flying machines are hard too, but I don't discount that such devices might exist just because the problem is difficult. I hope this answers your question since I am still not quite sure what was bothering you about my previous postings. You have the photon clocks of Feynman's path integral but you seem to be lacking the abilty to explore all paths. Asking about the VLTI is just a convenient way to inquire about your theory because a real device leaves no ambiguity. Without ability to explore all paths, your theory predicts that VLTI does not work in interferometer mode... but it does work so you need to go break their telescope. ;o) Sue... .................................................. .............. To Sue, Where does my theory predict that VLTI does not work? Light, on the other hand, behaves quite differently. It travels best through a vacuum and consists of a stream of particles called photons. http://www2.rideau.net/gaasbeek/spap1.html Light does not exist absent the motion of an electron. A space with an electron is not a vacuum. As a matter of fact, when we look out anywhere and see light, we can always "see" some matter as the source of the light. We don't just see light http://nobelprize.org/physics/laurea...n-lecture.html You are beginning to **** me off. Your problem is with Feynman, not with me. His mirrors work... your mirrors don't work. Break some mirrors or fix your theory. )"Antenna arrays" http://www.ee.surrey.ac.uk/Personal/.../antarray.html Sue... Len. .................................................. ........... To Sue, Some for renown, on scraps of learning dote, And think they grow immortal as they quote. Edward Young (1683-1765) British poet. Love of Fame, II Len. I quote what is probably the most successful theories in physics. You have your work cut out for you if you think cutting it in half impoves it. http://www.physorg.com/news8731.html Sue.. .................................................. .................. To Sue, Goody goody! They can now see their z and w particles ten times better than they could before! It is all a public relations smoke screen designed to keep their research grants from drying up. Their multi-million dollar hocus-pocus 'science' doesn't mean a thing and never has had, nor will have, any practical applications. It is the biggest confidence (snow) job in the history of science, and tax payers like you and I are paying for it. It makes me sick every time I think about it. Len. .................................................. ................... |
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Len Gaasenbeek wrote:
THE CONSTANT SPEED OF LIGHT. If we look at the electromagnetic spectrum which shows the frequency of electromagnetic waves (such as x-rays, visible light, micro-waves, television waves, fm waves and long radio waves etc.) versus their wavelength, we notice a direct relationship between the two. If we multiply any given frequency with its corresponding wavelength, we get the speed of light c, providing the electromagnetic wave travels through a vacuum. That is to say, the speed at which all electromagnetic waves travel through a vacuum is constant (c), and is the product of their frequency and wavelength. If we accept the fact that electromagnetic waves consists of photons that follow a helical trajectory, it is easy to understand why this should be so. Because the frequency of a helical photon wave is the number of times each photon completes one helical spiral per second, during which time it travels the same number of wavelengths. Why not a double helix? If a photon consisted of a pair of massless positive and negative charges rotating about a common centre then one might get around to explaining how alternating em fields are somehow involved e.g. Maxwell? You also have the angle between the axis of rotation and the direction of motion to give a concept of polarisation. [snip] -- John Kennaugh to email convert the number from hex to decimal |
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