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#101
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Juan R. wrote: [snip] New to me. The linearized limit doesn't derive *that* definition of the potential because it is assumed to be static. Read Wald again. I don't know if GR can derive that limit or not, for I haven't tried and it doesn't really interest me. But before criticising GR for not deriving your preferred flavor of Newton, it would help if you realised that what you use as the definition of a Newtonian potential is not the standard definition. ii) The element of line in the flat spacetime of SR (using both trace +2 and summation conventions) is ds^2 = -c^2dt^2 + dx^2 + dy^2 + dz^2 = g_{ab} dx^a dx^b As clearly explained in the page 2 of Sean Carroll basic online manual (pancake.uchicago.edu/~carroll/notes/grtinypdf.pdf), the spacetime dimensions are x^0 = ct (this is EXACTLY equation 2 of Carroll manual) x^1 = x x^2 = y x^3 = z and the SR metric is g_{ab} = (-1 +1 +1 +1) which is, EXACTLY, Carroll equation 3. If one takes a system of units with c=1 ds^2 = -dt^2 + dx^2 + dy^2 + dz^2 = g_{ab} dx^a dx^b x^0 = t (this is EXACTLY equation 2 of Carroll manual with the asumption c=1) x^1 = x x^2 = y x^3 = z and the SR metric continues being the SAME g_{ab} = diag(-1 +1 +1 +1) The metric does NOT contain any c^2 term as you incorrectly write and this is independent of choice of system of units, with either c the unity or NOT. That is because the metric is using units where c =1. It is explained on the page you cite. You are familiar with units, right? [snip more of the same] iii) Between the couple of nonsense you wrote in last days i selected this If all the connection coefficients are zero, which is what you desire, then there is no acceleration. It is flat space. Well, i proved just the contrary you claim. ALL connections are zero and, however, acceleration is not zero, doing the standard curvature interpretation of GR just wrong. The hell you did. You just asserted that the coefficients were zero even when they were manifestly not. Read Wald again. Before saying stuff like "the standard interpretation of GR is wrong", you might want to look into your own understanding. It would be a waste of time atempt to explain to you why i followed this way on my research; i.e. which were my motivations for ignoring the geometric (curvature) interpretation. Curiously, people as Dirac, Schrödinguer, Weinberg, or Feynmann between others, followed similar thoughts. *yawn* Then why even mention it? I guess if you didn't, you wouldn't be able to get in some name-dropping time. I simply will say that S. Carlip just also proved here in sci.physics.relativity on 7 Oct 2005 18:51:33 +0000 (UTC) that with ALL connections zero, the aceleration is NOT zero. That is, Carlip (as i did at beggining of 2005) proved just the CONTRARY to your recent (wrong) claim. The geodesic equation when (v/c) -- 0 is d^2x^i/ds^2 = -\Gamma^i_{00}(dx^0/ds)^2 Since x^0=ct, and g_{00} =1 - 2Gm/Rc^2 d^2x^i/(dt)^2 = -(1/2)\partial_i g_{00} (c^2) The c^2 term cancels out. Incidently, you have one less thing to complain about. I thought the c^2 term was still contained within the acceleration equation, but I see that it in fact does cancel out after working your example out. Nifty. Keep going, you eventually arrive at d^2x^i/dt^2 = - (partial/partial_x^i)*(GM/r), or - grad*phi. Notice the lack of c^2. acelleration is nonzero BUT for all index a, b, and c \Gamma^a_{bc} -- 0 and spacetime looks flat... WRONG! IT IS NOT ZERO! YOU JUST PROVED IT! Do you not understand what you are doing when you manipulate the geodesic equation? As i already said in page 17 of www.canonicalscience.com/stringcriticism.pdf on April, the curvature interpretation of gravitation does not hold in the nonrelativistic limit, doing the causal foundation of general relativity misleading. Except you just proved there are nonzero curvature components in this particular case. Oops. Precisely the belief on a 'curvature interpretation' is the basis of the foundation -still unsolved- problems of GR: the (famous) problem of energy, cosmological discrepancies, problem of reference frames, etc. Energy is not a problem, nor are reference frames. Cosmological discrepancies stem from GR not being used [simulations have been Newtonian]. Why not complain about something that has merit? The 'curvature interpretation' also has been one of barriers on a proper quantization of GR and is the basis of the complete ***disconection*** between GR and the physics of the rest of interactions. The interpretation isn't the barrier. Our approach unifies gravity with electromagnetism and can be unified with other forces; it explains data that GR cannot explain, probably solves the problem of energy, probably solves the problem of reference frames, verifies the same solar systems test that GR, and obtains the same experimental value for others tests, e.g. for binary pulsars BUT without the use of real gravitational waves and EXPLAIN why. Hahahahahaha. GR and classical electromagnetism get along just fine even without your assistance. I see lots of conditional statements like "can be", "probably"...you don't really know what your new theory does, assuming it isn't founded upon several false premises nor contains severe logic gaps. GR is a pure hidrodynamic theory. Our theory is more general and permits us compute kinetics terms without appeal to Vlasov-Einstein theory, etc. Moreover Vlasov-Einstein theory works just for conditional averages. Our theory is more general... Gibberish. Moreover, the theory has been already quantized: there is not 'problem of time' and explain why (is better than GD, HQG, Astherkar, and related approaches), is not a perturbative approch (therefore is best than string theory), there is not renormalization (therefore is best that nonrenormalizable Feynman/Weinberg spin-two field theory), one can obtain quantum g_{ab} (Wheeler geometrodynamics and similar approaches cannot), a concept of spin naturally arises (remember that GR cannot treat systems with spin and one needs the so-called Cartan extension), at ultrashort distances dimension of space reduces to 2 (there some link with most recent advances in triangulation thechniques), etc. Let us know when you derive something already known, like lensing. Or something unknown but testable. Now we are working in topological properties of spacetime at short distances. Interestingly, into one topological regime one finds stable configurations of 2 and 3 'pre-particles', this is some kind of QCD? What is the link with Finkelstein pre-spinors and Coxeter groups? **** if I know, I don't know anything about QCD. Why not ask someone who knows? Canonical science approach to gravitation is, of course, not a finished theory but it is a very interesting approach. Not if the way you think is any indication. Juan R. Center for CANONICAL SCIENCE) |
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#102
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Juan R.:
Bilge ha escrito: Most people would disgree that a theory based on instantaneous action at a distance is a better idea, since the instantaneous part conflicts with observations. Completely wrong!!! Let me know when you plan to explain that statement. As proven by many authors retarded LW potentials disagree with many recent experimental data on Mercury forces on Hg, railguns, tokamaks anomalies, etc. From a theoretical point of view, several authors have proven in recent years that LW potentials are theoretically incorrect. In the PRE article i cited above authors proved 1) LW potentials are not complete solutions of Maxwell equations 2) The introductions of an instantaneous action does the solutions complete. My only criticism to that paper is the dualism concept which is solved in my approach. Is there some point to this superfluous digression or are you just posting to read your own press? [*lots of unsupported assertions snipped*] One can formulate quantum field theory, e.g., QED, without using fields as basic concepts. This sounds rather controversial, but it can be done. Sure. You can rename anything and then claim you've eliminated the concept. That doesn't make it so. It does, however, make it easier to make the mistake of treating what is supposed to be unobservable in field theory as observable. Colleague, have your hear about Wheeler/Feynmann theory of absortion? Numbskull, have you heard about the nuclear optical model? It has the same relevance to this thread as everything you've posted - zero. Basically, both you and eugene suffer from the same misconceptions. You believe the universe is _really_ galilean, deep down, and the rest is a facade. |
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#103
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Eugene Stefanovich:
Bilge wrote: Eugene Stefanovich: Bilge wrote: Eugene starts with the same theory. All he does is perform a unitary transform. Changing representations doesn't change any physics. Your statements are formally correct. However they misrepresent the idea of the dressing transformation. "Changing representation" implies that you transform unitarily both operators of observables and state vectors. Then, of course, physics is not changed. In the "dressing transformation" only the Hamiltonian is transformed. State vectors are not touched. Then physics IS different. No, it isn't. However, you have provided yet another illustration of of where you attribute physics to unobservable phases: Consider two Hamiltonians H and H' that are related by a unitary transformation (U does not commute with H) H' = U H U^{-1} Which means that if H and H' describe the same system, then at time t = 0, \Psi|H'|\Psi = \Psi|U^{-1}HU|\Psi = \Phi|H|\Phi \Phi = U\Psi Obviously, H' acting on \Psi is the same as H acting on \Psi' and since [H,U] != 0, by hypothesis, there is no \Psi which are simultaneous eigenstates of both H and H'. Or equivalently, H' = U^{-1}HU = H + U^{-1} [H,U] (H' - H) = U^{-1} [H,U] Take an arbitrary state vector |Psi at time t=0 and consider its time evolution described by the two Hamiltonians |Psi(t) = exp(iHt) |Psi |Psi'(t) = exp(iH't) |Psi So what? Is that your so-called proof? \Psi can't be an eigenvector of both H and H'. so unitary transformation of the Hamiltonian DOES change physics. No, it changes your description of the physics. You just failed to include the transformation between H and H'. That's exactly what is done in the dressing transformation approach: A unitary transformation U is found that transforms the Hamiltonian of QED H (with infinite counterterms) to a finite well-defined Hamiltonian H' which can be used for time evolution calculations. You keep restating the obvious and avoiding the point. I am sorry, it seems that we have very different ideas about quantum mechanics. I am not going to buy your interpretation, What interpretation? What I wote above regarding the unitary transforms you gave is mathematical fact. It's the definition of a unitary transform. You do realize that, \Psi|U^{-1}HU|\Psi = \Psi'|H|\Psi' = \Psi|H'|\Psi are just different ways to say the same thing, righ? If not, I refer you to any quantum mechanics textbook, and if you need a page number, I'll find one in schiff for you. and I am sure you will not accept my arguments either. I suggest we stop this fruitless discussion and switch to something more productive. Eugene. |
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#104
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Juan R., jargon thrower:
Bilge, it is easy, you simply are arrogantly attacking people without subtanting your discourse. If you have something to say, post it. I already told you I'm not going to play 20 questions or try to read your mind. If you want to go on endless digressions, find someone else to jump through your hoops. In fact you are still not replied to Case in point - If you have something to say, just get to your point. With is the relativistic interaction between two electrons at second order in c and e? I also ask tou you, what is the relativisitic quantum equation for one electron? You have just cited a page, please to wrote down the equation or just write its name. (Dirac?) Are you claiming that QED is a relativisitc quantum MECHANICS? Please write also the relativistic uncertainty relations. Please prove also why (2) light which propagates at `c', and (3) electromagnetic interactions which propagate instantaneously are incompatible. Or at least proves that PRE 1996 53(5) 5373-5381 is wrong. Write also the diference between a field and a potential? Juan R. Center for CANONICAL |SCIENCE) |
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#105
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Juan R.:
Where is there a complete bound-state theory in Weinberg manual for example? R-QFT clearly states that only possible observables are those derived from S-matrix, which is only valid for independent particles (remember the cluster decomposition principle). In rigor R-QFT only deal with free fields. QED is only part of a quantum field theory called the standard model. The stardard model is believed to be asymptotically free. What makes you think that _any_ theory of E&M which is completely independent of the weak and strong interaction at any energy could be consistent with the unification of all three forces? If you believe qed should require the inclusion of qcd at high enough energies, why would you expect qed to be valid in that regime without including qcd? If you don't think qcd is required at any energy, how do you explain the fact that the muon magnetic moment is correctly predicted by including qcd corrections? In the e + e = 2 photon scattering. R-QFT only can study the wavefunction of the electrons or the photons when are not interacting. That is when the wavefunction factorizes |12 = |1|2. Well, gee... Did you ever stop to consider the possibilty that if you _define_ electrons, photons, etc., as free particles, then the interacting particles just might not be separable into free particle wavefunctions plus an interaction? You and eugene share the same misconception. You want to define particles on constant slices of time, but you expect to obtain solutions inconsistent with that choice. Obviously, I can choose all sorts of ways to define t = 0. The choice is not unique. You appear to have some underlying belief in a galilean universe. If you want to solve the equations in a form which is manifestly covariant, use point form to write the hamiltonian. Then you'll have an eigentime for the hamiltonian. Eugene is essentially working in instant form (where all of the particles are quantized on a single time slice) then interpreting his results as if they had been obtained in point form, in which the causal relationship is explicit. Unfortunately, the point form is a lot harder to work with, which is why there's not been much done in that area compared with instant form. In an atom or molecule you can claim that electrons are infinitely separated and |12 is NOT |1|2. All test of QED are for nonboundend states for example scattering two two electrons in acellerator physics (which is an ONE-body problem), hidrogen atoms or hidrogenic ions He^(++). In fact, recent test of two electrons in bound states has been a failure. Irrelevant babbling. Apparently, you think a rebuttal consists of inserting a bunch of irrelevant nonsense. Yes one can obtain a Dirac equation for a single particle. What is the corresponding equation for two particles. It cannot be derived from field theory and equations proposed in literature /ad hoc/, for example two-body covariant are not rigorous and not complete. Naturally. You insist on a formalism that cannot be covariant under what you insist upon, so what do you expect? Bethe-Salpeter and others are incorrect. At one hand, one claims that two body state is a 16 component wavefunction. At the other hand in the interaction regime one uses propagators derived from formals series of QED which clearly state that there is not two body wavefunction for the two electrons. Why you think that R-QFT states that only scattering states are observables? Oh. Gee... I guess you've never been on the inside of a physics laboratory, but let's see if we can shed some light on this conundrum. Solid state Si detectors, for example, come in a range of sizes, but just to get a 15-order of magnitude approximation, lets say that it's circular with a planar area of about 500 mm^2 x 1000 microns thick. Let's say we are interested in the details of the interaction at the order of a compton wavelength. For an electron, that's about 386 fm. Wow! There is no way to fit my detectors aound a couple of electrons at that distance, not to mention alignment difficulties or the kind of naievete required to actually postulate such a scenario to motivate even a gedanken experiment). So, first we note the detectors are a long way from all of the excitement. Also, the particles involved in the interaction aren't initially very close either. We might even be inclined to treat the particles as not interacting initially or at the time they strike the detector. Gee, what to do? But wait -- By using quantum theory with a liberal helping of common sense, we have a solution. Since we are free to choose a representation for our states any way we choose, subject to unitarity constraints, viola, we can break the evolution of the interaction into pieces: lim \exp(iH_0t')\exp(-iH(t'-t)\exp(-iH_0t) By taking the limits for t',t to +/- \infty. repectively, we have defined the S-matrix. Obviously, in the limit, the interaction H, specifies all of the S-matrix elements. Still today, nobody has found the correct, consistent, and complete relativistic equation for N-bodies (perhaps our center has already done but are cheking details). Nobody has found the nonrelativistic equations for N bodies either. If you think so, write down the exact equations of motion for three bodies interacting under a 1/r (newtonian) potential. |
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#106
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Juan R. wrote: [snip] Still today, nobody has found the correct, consistent, and complete relativistic equation for N-bodies (perhaps our center has already done but are cheking details). Why do insist on 'nice' solutions to multibody problems? You are making the same argument as before. Juan R. Center for CANONICAL |SCIENCE) |
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#107
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Bilge wrote: [snip] Yes one can obtain a Dirac equation for a single particle. What is the corresponding equation for two particles. It cannot be derived from field theory and equations proposed in literature /ad hoc/, for example two-body covariant are not rigorous and not complete. Naturally. You insist on a formalism that cannot be covariant under what you insist upon, so what do you expect? Is the notion of covariance fundamental to QFT also? If so, it is something I will keep in mind. Still today, nobody has found the correct, consistent, and complete relativistic equation for N-bodies (perhaps our center has already done but are cheking details). Nobody has found the nonrelativistic equations for N bodies either. If you think so, write down the exact equations of motion for three bodies interacting under a 1/r (newtonian) potential. Nor are there exact solutions in general relativity, to my knowledge, that handle multiple particles. |
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#108
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Gregory L. Hansen:
What's-his-name, author of a Dover book on classical field theory written with the purpose of being extensible to quantum field theories, wrote about a delayed action at a distance theory. I had trouble understanding how a theory could be both action at a distance and delayed. Just wondering if you know anything about that and have comments on it. Without knowing for sure what the theory is, the opinion based on my impression of what you described woud be ``misguided'' or ``thumb- twiddling.'' One could ask the same question about the spatial axes, i.e., how come everything that happens at a different time doesn't happen in the same place? I would think the simplest solution is to just take relativity at face value. I mean, what's wrong with simply choosing the most obvious explanation: Events A and B are connected by a null ray. What is their separation is spacetime? Well, ds^2 = 0 and d\tau^2 = 0, which makes it rather evident that the proper distances and times separating the events are zero. I don't see that interactions which take place over an interval of zero to be action at a distance. Even better - all observers will agree that the events are separated by zero proper time and proper distance. Evidently, the description of a particle (apart from its quantum numbers) depends the coordinates we choose to describe it. Quantum numbers like mass, spin, charge, etc. have no coordinate dependence, so trying to describe them as classical ``things'' doesn't work too well. Here's a really obvious problem with the action at a distance idea. t | | .C A and B are simultaneous, so they occur | at the ``same time,'' i.e., t = 0 +----+----+ x A B I now perform a lorentz transform, t | A and C occur at the ``same time,'' i.e., t = 0 | | +--------+-- x A . C B If interactions are instantaneous, then obviously, at most only one of the above can be correct, in which case, the system isn't lorentz invariant, since the two choices for t = 0 differ only by a lorentz transform. I guess that about sums up my opinion. |
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#109
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Eric Gisse:
Bilge wrote: [snip] Yes one can obtain a Dirac equation for a single particle. What is the corresponding equation for two particles. It cannot be derived from field theory and equations proposed in literature /ad hoc/, for example two-body covariant are not rigorous and not complete. Naturally. You insist on a formalism that cannot be covariant under what you insist upon, so what do you expect? Is the notion of covariance fundamental to QFT also? Yes, but... Let's distinguish between the formalism and the practical application. In the formal sense quantum field theory takes the covariance to the extreme. Field theory applies noether's theorem to everything with a vengence. Noether's theorem says that every continuous symmetry of the lagrangian corresponds to a conserved current, which ends up being where gauge bosons originate. If so, it is something I will keep in mind. Actually, by insisting on covariance quite a number of results just fall into your lap. Regardless of whether or not quantum field theory is the last word (which is unlikely), the results you get as freebies from covariance are remarkable. It turns out that if you start with the assumptions of (1) special relativity, (2) the quantum mechanical prescription for replacing classical variables with quantum operators, (e.g. E - i\hbar d/dt, p - -i\hbar\grad), the following sequence of derivations follows from insisting on invariance under spacetime displacements and little else. (1) Obtain the lorentz or galilean transforms. Those are the possible candidates for a description of spacetime which aren't obviously wrong. (2) rule out galilean transforms from experimental observation (for example, galilean transforms preserve mass locally) (3) Insist that the lagrangian be invariant under spacetime displacements. (It's sufficiant to just assume L satisfies the euler-lagrange eqns and that it depends on some field and the first derivatives of the fields. This is the equivalent of using generalized coordinates and momenta as done in classical physics carried over to special relativity). That gives a conserved four-momentum via noether's theorem. (4) Since the conserved four-momentum is E^2 - p^2 = m^2, try obtaining a linear verison which is covariant, i.e., E = a.p + bm by solving for a and b. Doing that gives a set of 4 - 4x4 matrices, a_i, b. Inserting i\hbar d/dt for E and -i\hbar\grad for p. We now have a candidate for a relativistic wave equation (well, a second candidate, the first being the second order equation from which this one was derived.) The wave equation just obtained is the dirac equation. (Really, it takes no more than a couple of pages to derive everything so far). (5) The equation derived is now, i(d/dt)\Psi = (-i a.\grad + bm/hbar)\Psi which after multiplying through by b gives the dirac equation in in standard form. Since b^2 = 1 (actually, the 4x4 identity), we define the dirac matrices \gamma^0 = b, \gamma^i = ba^i. Then, writing p_u rather than (E,p), we get (\gamma^u p_u - m)\Psi = 0. And finally by defining the slash notation to mean a scalar product of a four vector and dirac matrix, p/ == \gamma^u p_u, The dirac equation is compactly written, (p/ - m)\Psi = 0. (6) From that you can gets lots of things. For example, the dirac matrices anticommute to give you the metric tensor and commute to give the spin tensor. Every potential which is possible in the dirac theory can be written as a combination of dirac matrices. There are only five. You also get anti-particles and particles with spin-1/2. (7) The most compelling reason for taking field theory seriously, is that at this point, one can derive E&M from scratch, without assuming much of anything else. In lagrangian form, the dirac equation is L = (\Psi+)(p/ - m)\Psi, where \Psi+ means hermitian conjugate of \Psi. Since phases cannot be observables in quantum theory, the dirac lagrangian must be invariant under a change of phase, \Psi - \exp(-iS)\Psi. Furthermore, we want to require that different observers be allowed to choose their phase conventions locally, so that the phase S is a function of x^u, S(x^u). This means that observers don't need to check with the rest of the universe to decide if they've measured an electron. (8) The result is that the dirac lagrangian as written will not be invariant under a change of phase (i.e., a gauge transformation). The reason is that p_u take the derivative of \exp(-iS)\Psi to give p_u\Psi - i\Psi \d_u S, so we have an extra term. That extra term is the electromagnetic field. In order that the new lagrangian be invariant, the field must transform covariantly, which happens to be precisely the transformation properties we need for identifiying the term with the A_u in maxwell's equations and with the photon. The tranformation above is a U(1) tranformation. (9) If we require covariance under a more complex phase transformation, where the S is now a matrix instead of a function, we get more particles. For SU(2) we get the weak interaction and for SU(3), we get qcd. So, from the brief sketch above you can see that covariance is central to field theory (even though the above was pretty terse and won't substitute for a textbook). In particular, you should note that we didn't need to say anything at all about what \Psi is. Every result followed from a requirement on how it must transform such that everything remains covariant. The other aspect of field theory is formally quantizing the stuff above, which so far has been manifestly covariant and required knowing nothing at all about the fields. In order to quantize the fields, you change over to the hamiltonian formalism. Unfortunately, if you choose the usual cartesian coordinates, the manifest covariance is broken, since you are choosing some frame in which to quantize the theory. Special relativity is poincare invariant, so there are 10 conserved quantities as a result of the 10 possible transformations under which the invariance holds: 4 momenta, (i.e., E and p_i), 3 spatial rotations and 3 boosts. You cannot choose all 10 to be simultaneous observables in _any_ representation. (you can choose at most 7 and only then if you work in light-cone coordinates. Otherwise, you can choose at most, 6). That's ok, so long as you don't disregard the fact that the choice rules out using some of those 10 as quantum observables. (This is not unlike having to choose between working in momentum space or configuration space. You can choose either, but your choice can't let you measure both p and x). That is the origin of eugene's misconceptions. What he calls a physical effect is an artifact of choosing to quantize the qed lagrangian in a particular way and then promptly disregardig the limitations of that choice on his onservables. Still today, nobody has found the correct, consistent, and complete relativistic equation for N-bodies (perhaps our center has already done but are cheking details). Nobody has found the nonrelativistic equations for N bodies either. If you think so, write down the exact equations of motion for three bodies interacting under a 1/r (newtonian) potential. Nor are there exact solutions in general relativity, to my knowledge, that handle multiple particles. Right. Juan is deliberately misconstruing the technical difficulties to be major theoretical problems and being hypocritical about it, too. The same technical difficulties exist in classical physics. In addition, classical physics has severe theoretical difficulties if one tries to create a theory of the electron, for example. |
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#110
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Bilge wrote: Eric Gisse: Bilge wrote: [snip] Yes one can obtain a Dirac equation for a single particle. What is the corresponding equation for two particles. It cannot be derived from field theory and equations proposed in literature /ad hoc/, for example two-body covariant are not rigorous and not complete. Naturally. You insist on a formalism that cannot be covariant under what you insist upon, so what do you expect? Is the notion of covariance fundamental to QFT also? Yes, but... Let's distinguish between the formalism and the practical application. In the formal sense quantum field theory takes the covariance to the extreme. Field theory applies noether's theorem to everything with a vengence. Noether's theorem says that every continuous symmetry of the lagrangian corresponds to a conserved current, which ends up being where gauge bosons originate. If so, it is something I will keep in mind. Actually, by insisting on covariance quite a number of results just fall into your lap. Regardless of whether or not quantum field theory is the last word (which is unlikely), the results you get as freebies from covariance are remarkable. What strikes me as interesting is how important covariance seems to be. In SR, covariance is there by default otherwise the theory wouldn't work. In GR, covariance is there because it reduces to SR at "local" distances, and it is there globally due to the covariant derivative and various other tensorial objects. It sounds like, on a simple level, if you demand covariance and by extention special relativity and work within those bounds what you get is QFT. Now I really want that Dover QFT book. It turns out that if you start with the assumptions of (1) special relativity, (2) the quantum mechanical prescription for replacing classical variables with quantum operators, (e.g. E - i\hbar d/dt, p - -i\hbar\grad), the following sequence of derivations follows from insisting on invariance under spacetime displacements and little else. (1) Obtain the lorentz or galilean transforms. Those are the possible candidates for a description of spacetime which aren't obviously wrong. (2) rule out galilean transforms from experimental observation (for example, galilean transforms preserve mass locally) Is this the same process that yields 4 types of transforms that occurs when you assume the principle of relativity but don't explicitly assume the existance of c? [snip] So, from the brief sketch above you can see that covariance is central to field theory (even though the above was pretty terse and won't substitute for a textbook). In particular, you should note that we didn't need to say anything at all about what \Psi is. Every result followed from a requirement on how it must transform such that everything remains covariant. Terse doesn't even scratch the surface but it is the best introduction I have seen. I suppose thats why I need a book :O) http://store.yahoo.com/doverpublicat...486442284.html Do you have any opinions on this particular book? I have had good experiences with various other Dover books in the past so I don't think I will be steered wrong by grabbing a Dover on a lark. The other aspect of field theory is formally quantizing the stuff above, which so far has been manifestly covariant and required knowing nothing at all about the fields. In order to quantize the fields, you change over to the hamiltonian formalism. Unfortunately, if you choose the usual cartesian coordinates, the manifest covariance is broken, since you are choosing some frame in which to quantize the theory. Special relativity is poincare invariant, so there are 10 conserved quantities as a result of the 10 possible transformations under which the invariance holds: 4 momenta, (i.e., E and p_i), 3 spatial rotations and 3 boosts. You cannot choose all 10 to be simultaneous observables in _any_ representation. (you can choose at most 7 and only then if you work in light-cone coordinates. Otherwise, you can choose at most, 6). I was going to ask 'why', but I figure I would be better served by asking how does one know how many transformations are allowable or observables that are observable at one time? In my GR text [It should be ok, it was in the context of SR], the notion of isometries was detailed. While the finite number of invariants and transformations was mentioned, I have never seen them constrained before. Then again, Carroll probably skipped it. But I don't see it in either Wald or MTW. Or...is the only reason this is occuring is because of the way the theory is quantified? That's ok, so long as you don't disregard the fact that the choice rules out using some of those 10 as quantum observables. (This is not unlike having to choose between working in momentum space or configuration space. You can choose either, but your choice can't let you measure both p and x). That is the origin of eugene's misconceptions. What he calls a physical effect is an artifact of choosing to quantize the qed lagrangian in a particular way and then promptly disregardig the limitations of that choice on his onservables. Still today, nobody has found the correct, consistent, and complete relativistic equation for N-bodies (perhaps our center has already done but are cheking details). Nobody has found the nonrelativistic equations for N bodies either. If you think so, write down the exact equations of motion for three bodies interacting under a 1/r (newtonian) potential. Nor are there exact solutions in general relativity, to my knowledge, that handle multiple particles. Right. Juan is deliberately misconstruing the technical difficulties to be major theoretical problems and being hypocritical about it, too. The same technical difficulties exist in classical physics. In addition, classical physics has severe theoretical difficulties if one tries to create a theory of the electron, for example. There is a crank for every level of physics. Every little bit I learn shines the light on a new person in here, or perhaps the same one in a different way, who obviously got "stuck" somewhere along the line. At the bottom, we have Don1 and crew who can't grasp units. Then we have the people who can't grasp abstract things like algebra. Like Jim Greenfield. Next, the people who just can't let go of Newton. Like Henri Wilson. Now, Juan R, who among other things, does not understand what he is doing when he is manipulating the geodesic equation. |
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