The classical far-field transverse EM field stress-energy tensor is
traceless. Therefore, for a random SED EM field

(Energy Density) + 3(Pressure) = 0

w = +1/3

QED

This is indeed what Hal Puthoff assumed in his charge cluster paper.

It is clearly wrong as shown below.

The above stress-tensor is not a complete description. One must add

(c^4/8piG)/\zpfguv(x)

If there is no torsion /\zpf = constant.

In QED /\zpf is infinite.

It's a fudge to subtract. You can't subtract it in GR! If you put in a
quantum gravity cutoff then

/\zpf = 1/Lp^2 = (c^3/hG) = 10^+66 cm^-2

This is the cosmological constant problem.

Note that traceguv = -2 for +--- signature

This corresponds to w = -1

i.e. energy density - 3(pressure) = -2(energy density)

Therefore, you cannot consistently use the classical

Tuv(EM) = -FuwF^wv - guvL

in curved spacetime to get the effect of the virtual photons.

We need to distinguish the zero point virtual photons that are
on-mass-shell in the purely QED Casimir force calculations from the
coherent states of off-mass-shell virtual photons that make up near EM
fields.

PS Note that the BCS vacuum coherent state |0' is

|0' = Product over modes k (uk + vkbk*)|0

where bk* creates a bound virtual electron-positron pair +k & - k (may
not be a singlet). Since this is neutral there is no problem of charge
conservation. We can extend this idea to virtual quark-antiquark pairs.

Note that zero point quantum gravity terms c^2/\zpfr^2 are like "bag
potentials" that confine quarks. With torsion fields /\zpf is a local
variable scalar Higgs field.

On Sep 26, 2005, at 11:18 AM, Jack Sarfatti wrote:

1. Lorentz invariance and the equivalence principle imply

w = -1

for all zero point fluctuations not only for virtual photons.

2. Unlike QED you cannot simply stick in a plate(s) as in Casimir force
and forget the absolute background of ZPE. This is precisely the
"cosmological constant problem."

i.e. zero point energy gravitates (and anti-gravitates depending)
absolutely.

The QED Casimir force calculation for virtual photons (excluding even
vacuum polarization, which makes no essential difference here) is
irrelevant to the "charge cluster", or, more fundamentally, the
stability of a single electron as an extended micro-geon. More precisely
the Casimir energy is merely one term of several in the effective
potential for the micro-geon including gravity.

i.e.

V = @hc/mr + Q^2/mr + J^2/mr^2 + c^2/\zpfr^2

The "gravity term" in this Newtonian approx is c^2/\zpfr^2 for a uniform
core of positive ZPE of negative pressure. The Casmir term is @hc/mr
that simply renormalizes the Coulomb barrier Q^2/mr. Everything Hal
Puthoff talks about simply determines the pure number @ from QED.

dV/dr =0

d^2V/dr^2 0

3. The single electron Bohm hidden variable is not a point particle.
Renormalization theory needs to be trashed as Feynman told me in his Cal
Tech office in 1968. The electron (& quarks) is an extended shell of
charge held in balance by its inner core of zero point dark energy where
the vacuum coherence ODLRO field drops to zero exactly like in the core
of a superfluid vortex except here we have a point defect rather than a
string defect.

Jack Sarfatti wrote:
On Sep 26, 2005, at 11:18 AM, Jack Sarfatti wrote:
1. Lorentz invariance and the equivalence principle
imply w = -1

Note - 1 is usually i^2 ..(i^4 = + 1). Why w, jACK.?!!

VERY sincerely u c,
```Brian
p.s.
(La PoEsy) The PRiNCiPLE of EQUiVALENT SYNONYMs:
G*M1*m1 / r1^2 G~FORCE FRAME of REFERENCE;
= m1*(n - 1)*a_1
= m1*(n - 1)*v1^2 / r1
= 4*(pi)^2*m1*(n - 1)*r1 / t1^2
= 4*(pi)^2*m1*(n - 1)*(ORBiT radius) /(PERiOD sec)^2
= 4*(pi)^2*m2*(n - 1)*lbob / tbob^2
= m2*(n - 1)*vbob^2 / lbob
= m2*(n - 1)*a_2
= m3*(n - 1)*g_Eotvos
= m3*(n - 1)*a_3
= LATERAL FORCE = m4*(LATERAL DiSTANCE) / (DURATiON sec)^2
= m4*a_4.
CONCLUSiONs:
1. All, mass m1 = m2 = m3 = m4 ..are equal iDENTiCALLY.
2. Accelerations a_1, a_2, a_3 & a_4 equal DiFFERENTLY.
3. Let LATERAL FORCE and G~FORCE be equal iDENTiCALLY.
4. The LATERAL FORCE is NOT affected by (n - 1) LiFT.
5. A CURRENT TEST is ONLY for m3*g_Eotvos = m3*a_3.
6. Let, mass m1, m2, m3 & m4 be PENDULUM CLOCKs.
7. A ROSE is still a ROSE by any other name.