In 1915 plain vanilla GR no zero point energy and no torsion

Guv(geometry) = -kTuv(Matter)

The global energy-momentum 4-vector of matter is

E(Matter) = P^0(Matter) = Spacelike integral d^3x(-g(x))^1/2T^0^0(x)

P^i(Matter) = Spacelike integral d^3x(-g(x))^1/2T^0^i(x)

i = 1,2,3

g(x) = detguv(x)

There is no local experiment to measure P^u(Matter)

Tuv^;v(Matter) = Tuv^v(Matter) + tuv(Matter-Geometry)^,v = 0

tuv(Matter-Geometry) is implicit and is wrongly called the pseudo
energy/stress tensor for the gravity field. It is nothing of the kind.

(1/k)Guv(Geometry) = Tuv(Geometry)

Einstein's eq is Free Lunch

Tuv(Geometry) + Tuv(Matter) = 0

In "classical" vacuum (no dark energy)

Tuv(Geometry) = 0

However, we cannot conclude that this vacuum has zero total energy
because the gravity energy has a non-local part beyond the space
integral of local T^u^v(Geometry) = 0.

That is we cannot conclude that the total energy of the universe is
zero, or even that it must be conserved.

"Jack Sarfatti" wrote
That is we cannot conclude that the total energy of the universe is zero, or
even that it must be conserved.

[hanson]
But Jack, be careful with that "we"...... because your
assertion/conclusion does not carry any more weight then
does Albi's, DeSitters' or Stephen Hawkings' conclusion,
read OPINIONS. For you and them to assert with certainty
to know what's going on that cosmic scale is preposterous,
considering that none of you even knows what tricks the
hookers yondern Barstow are upto and into... ahahaha....
Thanks for the laughs.... ahahaha... ahahanson

"Jack Sarfatti" wrote in message
. ..
In 1915 plain vanilla GR no zero point energy and no torsion

Guv(geometry) = -kTuv(Matter)

The global energy-momentum 4-vector of matter is

E(Matter) = P^0(Matter) = Spacelike integral d^3x(-g(x))^1/2T^0^0(x)

P^i(Matter) = Spacelike integral d^3x(-g(x))^1/2T^0^i(x)

i = 1,2,3

g(x) = detguv(x)

There is no local experiment to measure P^u(Matter)

Tuv^;v(Matter) = Tuv^v(Matter) + tuv(Matter-Geometry)^,v = 0

tuv(Matter-Geometry) is implicit and is wrongly called the pseudo
energy/stress tensor for the gravity field. It is nothing of the kind.

(1/k)Guv(Geometry) = Tuv(Geometry)

Einstein's eq is Free Lunch

Tuv(Geometry) + Tuv(Matter) = 0

In "classical" vacuum (no dark energy)

Tuv(Geometry) = 0

However, we cannot conclude that this vacuum has zero total energy because the
gravity energy has a non-local part beyond the space integral of local
T^u^v(Geometry) = 0.

That is we cannot conclude that the total energy of the universe is zero, or
even that it must be conserved.