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| Tags: background, cosmic, microwave, radiation |
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It's not possible for me to explain the contents of this post
without including fairly detailed images. I've included the links to these images, but it's far easier to pay a visit to this web page. http://www.ozemail.com.au/~mkeon/cmbonly.html B.Y.O. --------- Cosmic Microwave Background Radiation (3) My earliest attempt at properly justifying the zero origin universe within the microwave background data failed because I failed to recognize a flaw in my reasoning at the time. Attempt no.2 was fairly well demolished in a rather lengthy debate over the way in which I had combined blackbody curves, and how those curves came to be. I was thus forced to go back to square one and do it all over again. The flaw in my original reasoning, which should have correctly described how the CMBR came to be in the zero origin universe, quickly became apparent. My graph plot of the CMBR spectrum was based on emissive power per wavelength, where the CMBR spectrum is normally displayed as spectral energy density, which is power according to frequency. I was attempting to fit my curve to the wrong curve shape. ------------------- The CMBR monopole spectrum graph is supposedly the expanded blackbody temperature plot of the early universe after it had evolved for 300,000 or 10 million years (the goal posts keep changing), at which time it had cooled to 4000 degrees K, being the temperature threshold where hydrogen was no longer ionized. The universe became fairly abruptly transparent and all of the previously entrapped radiation was released into the universe from everywhere to travel the universe to everywhere. A background radiation is also expected in a zero origin universe, but certainly not for the same reasons. The temperature of that universe would range from absolute zero at the origin to its current temperature. And because the universe has evolved from nothing, there can be no doubt that it will continue to evolve. The rate of that evolution is clearly demonstrated in the red shifting of the characteristic spectral lines of atoms per increasing distance into the past. The very early universe would have remained relatively unchanged for a very long time (relative to the current time rate) and the temperature of the entire universe could be summed up as a general heat source (but not a blackbody) and averaged to give a temperature that represents the heat of the universe at the time, and whatever curve shape the combined temperatures generate, the power curve will peak at a specific wavelength. That wavelength can represent the entire spectrum for that era in the evolution of the universe, which should be quite valid because the relationship between the curve peak and the rest of the spectrum would remain consistent as the universe evolves. i.e. Double the temperature and every wavelength in the spectrum halves. The purpose of the next image is only to graphically demonstrate that all wavelengths halve if the temperature is doubled. Each curve in the graph was computer generated using Planck's blackbody equation for emissive power per wavelength. The power spectrums have been brought into an alignment using multipliers so that they can be directly compared. http://www.ozemail.com.au/~mkeon/compare2.jpg Notice that the curve shape is always exactly proportional no matter what temperature it's plotted for? Those proportions never change. The power peak of any blackbody spectrum can be adjusted with a multiplier so that it peaks at the same level as a curve who's shape is to be tested against a blackbody spectrum, and then a multiplier sets the peak of the spectrums to align at the same wavelength, and it always tells the same story. The fit with the blackbody curve will never vary, no matter what radiator temperature is used in the test. Or, the test curve itself can be varied with a simple multiplier so that it can be compared with a specific blackbody radiator temperature, and exactly the same story unfolds. The test spectrum also never changes. The asymmetry in the curve shapes of the spectrums plotted for energy density per frequency and emissive power per wavelength can be deemed to be always exactly the same, no matter what the temperature difference is between the two. The set of black curves in this image are extensions of the 8 K curve, created with appropriate wavelength multipliers. i.e. # * 1, # * 32, # * 32^2 and # * 32^3. The green curve is the spectral energy density spectrum for 2 K. The two curves can't be directly compared of course, but the point I'm trying to make should be obvious. http://www.ozemail.com.au/~mkeon/compare3.jpg Since the evolution of the universe is dependent on interactions between existing matter, the more advanced the stage of evolution the faster will be its development. Even though the universe is heating up at a squaring rate, the time that the temperature stays current is changing at an inverse squaring rate. Neither the origin nor the present will contribute to the background. Background radiation curves can then be plotted within the parameters of, infinite background emissions of zero energy (1 x 0), and zero background emission in the present (0 x 1). The black curve in the next graph was generated according to those conditions. The yellow curve was generated likewise, but the whole x-scale is shifted so that the zero mark aligns with the .34mm wavelength mark. The reason for this is that the entire spectrum of the *obviously* visible universe is not represented in the CMBR. The 13E+9 light year chunk of the past since the big bang universe became transparent can't be included as a component of the background radiation in that universe, and since the zero origin curve is compelled to obey big bang's rules, the present for that curve is necessarily set in the past by 13E+9 years, when the zero origin universe was in a lesser evolved state. However, the curve shape will never change, no matter what stage of evolution it's plotted to. The .34mm x-scale offset was chosen because it was the best fit, I certainly couldn't predict it. But this time it should help to determine how far and how fast the universe is evolving. No part of the black curve would fall below the yellow curve if the true relationship between the power spectrums was shown. http://www.ozemail.com.au/~mkeon/cmbzro.jpg The zero origin curve is not a particularly good fit with the 2.73 blackbody curve, but I now find that it doesn't need to be. There is now one major difference in that the power attributed to a representative wavelength for a stage of evolution is raised to the fifth power instead of the fourth, as it was before. That is of course the normal relationship between wavelength and power, as specified in Planck's blackbody radiation equation. Exactly the same wavelength-power relationship will prevail regardless of what kind of spectrum a wavelength belongs in, so long as the conditions that create the spectrum shape don't change. Double the temperature and the power received from any equivalent wavelength (halved wavelength) in the newly generated spectrum will have increased 32 fold. And it doesn't have to be an enclosure in thermal equilibrium either. The only significance of that, is that it produces a specific spectrum shape. The following is extracted from the program that plotted the curves for the zero origin universe. It will make a lot more sense as it is than if I try developing any sort of formula from it. a = a + .005 ' "a" are stages of evolution in steps ' from 0 to 1 in increments of .005 IF a 1 THEN END b = 1 - a ^ 2 ' "b" stores the power ratio per time rate ' of evolution at each step of "a". wl = (1 / a) - 1 ' The initial time zone wavelength on the graph plot is 199mm. ' That's the first step recorded from infinity, and the universe ' had then already existed for an eternity. That wavelength ' bridges the infinite gap to zero, and blends in with the next ' evolution stage. There are of course no discrete stages. zl = (b * a) ^ 5 * 28000 ' "b * a" sets the power for the stage of evolution. That result ' is now raised to the fifth power because that's the rate at which ' each wavelength of a power spectrum increases per temperature ' increase. That rule applies for every object in the universe. ' Double its temperature and the emissive power at each halved ' (equivalent) wavelength increases 32 fold. ' "28000" is obviously a multiplier for curve comparison. Such ' a multiplier sets the power peak, and will not change the curve ' shape one bit. ' --------------------------- The Qbasic program that generated the curves can be found here http://www.ozemail.com.au/~mkeon/cmbbas.exe as a self extracting zip file. Something that has concerned me for some time is the fact that even at the peak of the hype for an expanded blackbody explanation for the CMBR, the raw monopole spectrum data was conspicuously absent, while the dipole data was clearly set out for all to see. Since I've never come across any raw data for the monopole, I've had to improvise by using the raw dipole spectrum data. Because the dipole is taking the same picture of the cosmic background as the monopole, by default it has the same spectrum as the monopole. Apart from its power peak falling a long way short of the all sky spectrum, the only difference is that the entire spectrum has been slightly red or blue shifted depending on which way the dipole is being measured. What I can't understand though is why the following dipole graph, which was plotted with the raw dipole data set, shows such an enormous blue shift. The peak of its spectrum has been shifted to that of a 3.4 K radiator. That represents a substantial velocity relative to the cosmic background. In trying to compare curves in the graph, I found it easier to shift the monopole curve to align with the dipole than vice versa. The monopole is shifted to the right with a multiplier based from the zero mark on the graph scale. And that adjustment is quite valid for the purpose of the comparison. As you can see, the monopole was certainly no exact match with the raw dipole data, and as a consequence would be no better a match with the raw monopole data, if it could be found. http://www.ozemail.com.au/~mkeon/cmb5-05.jpg I've also included the trailing end of a 13 degree K plot, which only indicates the presence of the galaxy. The galaxy power spectrum is not in proportion of course, but the curve mismatch on the hotter side of the graph could be adjusted all over the place by making different assumptions regarding dust and thermal contributions to the data from the galaxy. The CMBR graph for the zero origin universe was plotted along a line between the origin and the present and is therefore plotted on intensity per wavelength. It can of course also be plotted according to spectral energy density. Or I can simply convert the intensity per wavelength to spectral energy density. The conversion is very simple. c/(w*pi^.5) does the x-scale conversion. Then the power attributed to each wavelength on the intensity per wavelength scale is raised to power^.5 which converts the emissive power curve to the realm of spectral energy density. The entire power spectrum of the blackbody enclosure can be elevated to the scale of the spectral energy density realm and the curve shape can, with an appropriate power multiplier, be directly compared with anything else plotted in that realm, but not outside that realm. For the sole purpose of comparing curve shapes, there is nothing whatever wrong with converting between emissive power per wavelength and energy density per frequency, nothing at all. Swapping between frequency and wavelength doesn't alter anything because the two properties of the single entity are inseparable. And I can choose any graph scale I like for the energy density per frequency, even if the x-scale happens to coincidentally align with a linear wavelength scale. The curves in the two frames of this animation were plotted accordingly. They compare the elevated zero origin curve and the monopole with the graph plotted from the raw dipole data, which has been shifted to the colder end with a multiplier so that it can be directly compared after the power spectrums of each are set to peak at the same height. Once again, that method of adjustment is quite valid. Notice how close a fit the zero origin curve is? http://www.ozemail.com.au/~mkeon/cmbcom.gif Using an x-scale where frequency is linear hides a substantial curve misalignment between the raw dipole data and the monopole on the lower frequency end of the graph, doesn't it. I've often wondered why the CMBR was invariably depicted using a linear frequency scale. ----- Max Keon |
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#2
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I wrote:
My earliest attempt at properly justifying the zero origin universe within the microwave background data failed because I failed to recognize a flaw in my reasoning at the time. Attempt no.2 was fairly well demolished in a rather lengthy debate over the way in which I had combined blackbody curves, and how those curves came to be. I was thus forced to go back to square one and do it all over again. The flaw in my original reasoning, which should have correctly described how the CMBR came to be in the zero origin universe, quickly became apparent. My graph plot of the CMBR spectrum was based on emissive power per wavelength, where the CMBR spectrum is normally displayed as spectral energy density, which is power according to frequency. I was attempting to fit my curve to the wrong curve shape. It's probably doesn't make much difference, but after some fossicking around in some old files, I found that paragraph was not correct. It should more appropriately read; My earliest attempt at properly justifying the zero origin universe within the microwave background data failed because I failed to recognize *many* flaws in my reasoning at the time. Attempt no.2 was fairly well demolished in a rather lengthy debate over the way in which I had combined blackbody curves, and how those curves came to be. I was thus forced to go back to square one and do it all over again. It seems I might have it right this time. But my main concern was the wording in this later paragraph; The set of black curves in this image are extensions of the 8 K curve, created with appropriate wavelength multipliers. i.e. # * 1, # * 32, # * 32^2 and # * 32^3. The green curve is the spectral energy density spectrum for 2 K. The two curves can't be directly compared of course, but the point I'm trying to make should be obvious. This may better convey what I was trying to say; The set of black curves in this image are extensions of the 8 K curve, created with appropriate power multipliers for each doubling wavelength step. i.e. # * 1, # * 32, # * 32^2 and # * 32^3. The green curve is the spectral energy density spectrum for 2 K. The two curves can't be directly compared of course, but the point I'm trying to make should be obvious. http://www.ozemail.com.au/~mkeon/compare3.jpg The updated web version is stored at http://www.ozemail.com.au/~mkeon/cmbonly.html These little problems seem to appear within ten seconds of clicking the send button. ----- Max Keon |
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