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| Tags: problem, rigid, rod |
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#71
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Todd wrote:
wrote in message oups.com... Todd wrote: wrote in message ups.com... Todd wrote: [snip] Note that the corkscrew must be almost straight to begin with (i.e. even 2piR is a pretty long pitch, and anything close to that would require a relativistic spin) yet we require it to provide, through its own torsional rigidity, the centripetal force to accelerate a relativistic mass through a small-radius arc. I think this requirement is too great. I guess I should not have referred to the radius as necessarily small. Well, as a 'thought experiment', I don't see why we can't consider a helix of *very* large radius. Then the helix could rotate so that points of the helix move at relativistic speed and yet have small centripetal acceleration. So, the rigidity would not have to be great. Yes it would, because we would have miles and miles more material in each turn. For a given thickness of material, and constant angular velocity, the rigidity must increase as R increases. It would of course be different if we were dealing here with a closed hoop, but we're not. [snip] Yes, I goofed in thinking that increasing R would reduce the stress. Instead I believe that the stress would be independent of R just as for a closed hoop. For a closed hoop spinning such that the material has a speed u, the tension in the hoop will equal lambda*u^2 which is independent of R (at least for nonrelativistic speeds). For the helix I suspect that the tension will still be lambda*u^2 except for an extra numerical factor that would depend on the ratio of the pitch to the radius. But this ignores an important difference: the helix's two ends have nothing to pull on, so the tension stress must be zero there. The only thing that keeps the material curved at all is tension on the inside of the curve and compression on the outside, similar to the case of a straight bar subject to a bending stress. This is a huge demand. A one-mile ring of steel can easily be spun so that it keeps its circular shape. Not so a one-mile bar of steel bent in a helix of one or two turns. As you scale up the helix with larger radius, you would also scale up the pitch so that the ratio of pitch to radius would stay constant. (For example, we might choose the pitch to equal 2*Pi*R) So, I think the tension would be independent of R for a given rotational speed u and a given mass per unit length lambda. I also think that the tension stress would be essentially independent of the length (number of wraps) of the helix. But the tension-compression stress that is *really* responsible for the shape is dependent on the total length of the bar; you can't just keep adding turns and length to the helix, keeping other things constant, and expect it not to distort under the centrifugal force. At least this is what I think, without doing any calculations... Anyway, I was wrong in believing that increasing R would help. Nevertheless, I don't believe that the resolution of the paradox lies in establishing that there are no real materials that are rigid enough to withstand the rotations imagined in the thought experiment. For some reason, that doesn't seem to me to get to the heart of the paradox. It does seem unsatisfying, yes. Btw it bothered me that we hadn't considered the density of the material at all, and then I remembered that speed of sound of course depends on density as well as stiffness, so maybe I'm not completely full of crap after all. I could be wrong of course. As in David's original post, we can consider a thought experiment in which the pitch is astronomically long and then we can get by with a slow rotation speed. I think the stress would then be small and we wouldn't have to worry about the strength of the material. The stress would *not* be small. Btw before you posted your nifty helix-balancing calc, I thought of some other ways to rectify the principal axis, e.g. by using a double-helix with the two strands attached only by a single cross-bar at one end. The strands could then unwind into perfectly straight rods attached at one end, like a very long tuning fork (and of course we would not have the paradox we did before). But just imagine what that would mean for the stress in the two rods. It would be enormous. I think your single helix would be subject to exactly the same stresses from the end to the middle, because for all that length it wouldn't really "know" that it wasn't attached by a crossbar to some partner helix. And I think this probably also gets to Tom Roberts' notion of "driving" the rotation even though as I said, I didn't really understand everything he wrote. |
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#72
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#73
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wrote in message oups.com... Todd wrote: wrote in message oups.com... Todd wrote: wrote in message ups.com... Todd wrote: [snip] Note that the corkscrew must be almost straight to begin with (i.e. even 2piR is a pretty long pitch, and anything close to that would require a relativistic spin) yet we require it to provide, through its own torsional rigidity, the centripetal force to accelerate a relativistic mass through a small-radius arc. I think this requirement is too great. I guess I should not have referred to the radius as necessarily small. Well, as a 'thought experiment', I don't see why we can't consider a helix of *very* large radius. Then the helix could rotate so that points of the helix move at relativistic speed and yet have small centripetal acceleration. So, the rigidity would not have to be great. Yes it would, because we would have miles and miles more material in each turn. For a given thickness of material, and constant angular velocity, the rigidity must increase as R increases. It would of course be different if we were dealing here with a closed hoop, but we're not. [snip] Yes, I goofed in thinking that increasing R would reduce the stress. Instead I believe that the stress would be independent of R just as for a closed hoop. For a closed hoop spinning such that the material has a speed u, the tension in the hoop will equal lambda*u^2 which is independent of R (at least for nonrelativistic speeds). For the helix I suspect that the tension will still be lambda*u^2 except for an extra numerical factor that would depend on the ratio of the pitch to the radius. But this ignores an important difference: the helix's two ends have nothing to pull on, so the tension stress must be zero there. The only thing that keeps the material curved at all is tension on the inside of the curve and compression on the outside, similar to the case of a straight bar subject to a bending stress. This is a huge demand. A one-mile ring of steel can easily be spun so that it keeps its circular shape. Not so a one-mile bar of steel bent in a helix of one or two turns. Yes indeed, thanks. It helped me to think about a rotating circular ring in which you make a cross sectional slice at one point so that the surfaces of the slice are free of stress. Then, as you say, in the rest of the rotating ring you get inner tension and outer compression that increase as you move around to the diametrically opposite point. These stresses can be huge and they would increase with an increase in radius of the ring. I hope I've got it right now. As you scale up the helix with larger radius, you would also scale up the pitch so that the ratio of pitch to radius would stay constant. (For example, we might choose the pitch to equal 2*Pi*R) So, I think the tension would be independent of R for a given rotational speed u and a given mass per unit length lambda. I also think that the tension stress would be essentially independent of the length (number of wraps) of the helix. But the tension-compression stress that is *really* responsible for the shape is dependent on the total length of the bar; you can't just keep adding turns and length to the helix, keeping other things constant, and expect it not to distort under the centrifugal force. At least this is what I think, without doing any calculations... Anyway, I was wrong in believing that increasing R would help. Nevertheless, I don't believe that the resolution of the paradox lies in establishing that there are no real materials that are rigid enough to withstand the rotations imagined in the thought experiment. For some reason, that doesn't seem to me to get to the heart of the paradox. It does seem unsatisfying, yes. Btw it bothered me that we hadn't considered the density of the material at all, and then I remembered that speed of sound of course depends on density as well as stiffness, so maybe I'm not completely full of crap after all. I could be wrong of course. As in David's original post, we can consider a thought experiment in which the pitch is astronomically long and then we can get by with a slow rotation speed. I think the stress would then be small and we wouldn't have to worry about the strength of the material. The stress would *not* be small. Agreed Btw before you posted your nifty helix-balancing calc, I thought of some other ways to rectify the principal axis, e.g. by using a double-helix with the two strands attached only by a single cross-bar at one end. The strands could then unwind into perfectly straight rods attached at one end, like a very long tuning fork (and of course we would not have the paradox we did before). But just imagine what that would mean for the stress in the two rods. It would be enormous. I think your single helix would be subject to exactly the same stresses from the end to the middle, because for all that length it wouldn't really "know" that it wasn't attached by a crossbar to some partner helix. Interesting And I think this probably also gets to Tom Roberts' notion of "driving" the rotation even though as I said, I didn't really understand everything he wrote. I didn't understand what Tom was getting at either. Todd |
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