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| Tags: blackholes, exclusion, pauli, principle |
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#1
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Why doesn't the pauli exclusion principle prevent the collapse of
matter in a black hole down to a singularity. |
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#2
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#3
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Dear michalchik:
wrote in message ups.com... Why doesn't the pauli exclusion principle prevent the collapse of matter in a black hole down to a singularity. "Gravitationally bound" is not a bound state to which Pauli applies. David A. Smith |
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#4
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N:dlzc D:aol T:com (dlzc) wrote: Dear michalchik: wrote in message ups.com... Why doesn't the pauli exclusion principle prevent the collapse of matter in a black hole down to a singularity. "Gravitationally bound" is not a bound state to which Pauli applies. David A. Smith Well that's in juxtaposition to my post (Tucker), by implying 2 neutrons in the center of a n-star may occupy the same space at the same time because gravity did it. NUTZ and Regards Ken |
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#6
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#7
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Bilge wrote: : Why doesn't the pauli exclusion principle prevent the collapse of matter in a black hole down to a singularity. The pressure from the neutron degeneracy in a neutron star prevents the collapse of the neutron star (obviously). The pressure needed to prevent the collapse can be obtained from an equation of state (which comes mostly from extrapolations of nuclear equations of state to nuclear matter). Once the pressure can no longer support the neutron star against gravitational collapse, the matter will collapse until either something halts the collapse or an event horizon forms around the collapsing matter. Once the matter is inside the event horizon, I believe you can avoid the issue of the exclusion principle for the following reason. The radial direction (in a schwarzchild hole) is now timelike and the t-direction is now spacelike, so there is not necessarily a ``lack of spatial volume'' inside the black hole. The area covererd by the \theta and \phi coordinates shrinks to zero as r - 0, but the t-coordinate becomes infinite. Since the exclusion principle places a constraint on the wave vectors (which correspond to the spatial directions that are now dt and r^2 d\Omega^2), the exclusion principle is not necessarily an issue. Knee-jerk Suppose I set a CS at the center of an average n-star, relatively to which we should expect the laws of physics - specifically Pauli's Exclusion Principle - are valid. Then by astronomics, matter is added to the n-stars surface, increasing it's mass in a continuous way. I think we're safe to assume the pressure also increases but not necessarily the density because incompressible fluid density does NOT change linearily with pressure. The assumption of an "incompressible fluid" is actually an application of the PEP. However PEP allows two neutrons to change their relative spins under sufficient containment to begin to occupy the same location. In that case each 2 neutrons change relative spin by 90 degrees for a total of 180 relative, meaning they become relatively neutron-antineutron couples. At some point in the relative spin variation the neutrons become an attractive couple, and the usual neutron-antineutron decay occurs, ultimately decaying to gamma rays. The powerful gamma ray bursts would support that theory. Regards Ken S. Tucker .... |
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#8
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its
Incompressibility is relative. Everything is compressible. Electric forces are saturated and "shielded" (balanced, rather) whereas gravital forces are not, so the latter easily overcomes the former. The charges are still excluded though. Tucker, stop making up antineutrons. |
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#9
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Ken S. Tucker wrote:
[...] because incompressible fluid density [...] You just defined the problem away. In fact, the Pauli exclusion principle does NOT cause a neutron star to be "incompressible". See my earlier reply -- at some critical density further reduction of the surface area does NOT reduce the number of states available to the neutrons, and they can obey Pauli all the way down to zero volume. In that case each 2 neutrons change relative spin by 90 degrees for a total of 180 relative, meaning they become relatively neutron-antineutron couples. You mean isospin, not spin. That's a WHOLE different beast.... But isospin does not behave this way (neither does spin...). At some point in the relative spin variation the neutrons become an attractive couple, and the usual neutron-antineutron decay occurs, ultimately decaying to gamma rays. The powerful gamma ray bursts would support that theory. Nonsense. neutron-anitneutron annihilation has a Q value of ~1 GeV/gamma; gamma ray bursts have observed energies billions of times that. And that is AFTER any redshift from either gravitation or cosmology (because it is measured here on earth). Tom Roberts |
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#10
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Tom Roberts wrote: Ken S. Tucker wrote: [...] because incompressible fluid density [...] Quote out of context is immature. You just defined the problem away. In fact, the Pauli exclusion principle does NOT cause a neutron star to be "incompressible". See my earlier reply -- at some critical density further reduction of the surface area does NOT reduce the number of states available to the neutrons, and they can obey Pauli all the way down to zero volume. Tom, that's silly you got 2 neutrons in a zero volume, like two same spin particles occupying the same point, and then claim that's ok with PEP, then you have your own version of PEP. Ken .... |
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