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| Tags: cmbr, neutron, stars |
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Dear Tom Roberts:
"Tom Roberts" wrote in message . .. N:dlzc D:aol T:com (dlzc) wrote: Dear Tom Roberts: "Tom Roberts" wrote in message ... N:dlzc D:aol T:com (dlzc) wrote: The CMBR appears to have a perfect blackbody emission curve, at least from what is left after passing through intergalactic and interstellar "stuff". Normal matter does not produce the kind of emission curve that the CMBR produces (apparently). Sure it does, as long as it is black. I find no reference that supports this claim, Tom. Look in elementary textbooks on thermodynamics and/or quantum mechanics. You'll have a difficult time finding a reference for 1+1=2 also. Thanks for your efforts, Tom. Bilge provided the missing (for me) piece with the plasma, excited beyond the absorption/emission energies. Any black object will emit a black body spectrum. And virtually all astronomical objects are very close to black (with some absorbtion/emission lines added -- ignore them). That's why the black body model is so useful. I have always imagined the thermal emissions of normal matter as the typical material "emission bands", smeared by thermal velocities (gamma factor from individual atomic motions). Neutrons don't have emission bands. I suppose their "atmospheres" do... iron. There is more to it that that. You are just considering atomic emission for atoms that to not ionize. But in many materials there are free electrons (i.e. electrons not bound to any particular atom), and for hot enough objects some/most atoms will ionize -- both of these contribute a continuous spectrum. The combination of all of the radiation from a black object reproduces the blackbody spectrum because of the thermodynamics of the situation. Tom, I am given to understand that the CMBR was produced by an opaque "medium" (CMBRM). Yes. In the early universe no atom could remain an atom very long because the high temperature gave other particles enough kinetic energy so a simple collision often/usually would ionize the atom. So between a few seconds and ~300k years after the big bang the universe was filled with a charged plasma consisting primarily of electrons and protons. When the temperature had been reduced enough so most collisions did not have enough K.E. to ionize the atoms the electromagnetic attraction between protons and electrons quickly caused them to form hydrogen atoms. The charged plasma was essentially opaque to all types of EM radiation (hence it was black), but the hydrogen is transparent to most EM radiation. So in a short time the radiation emitted by the plasma could suddenly propagate over large distances. It is remnants of this radiation we see as the CMBR. But the CMBR is free of the absorption bands of "cooler" hydrogen. Let's pretend a timeline, with "CMBRM stops glowing" at 300,000 pBB (post-Big Bang). What about this Universe filling, formerly opticaly dense, hydrogen at 301,000 pBB? Does this mean that it all coalesced to "structures" in next-to-no-time? I am further given to understand that the CMBR shows an intensity vs. frequency curve that is NOT reproducable by hydrogen at 3000 K "locally". Right. Because it was not generated by hydrogen, it was generated by the charged plasma, and modified by transmisstion through the subsequent universe.... The CMBRM filed the early Universe. The CMBRM emitted blackbody radiation. The radiation was not absorbed by the same Universe-filling hydrogen because... Because hydrogen is transparent to most of the CMBR radiation. The CMBR was emitted as a continuous blackbody spectrum ~3000 K; hydrogen can only absorb discrete lines from it, and the large redshift and Doppler shifting of the hydrogen in the early universe smeared out the bands so much they are not prominent (or perhaps not apparent at all, I don't know). Not detectable at all. At some point the CMBR had redshifted enough so it could not be absorbed at all by hydrogen, and since then the universe has been transparent to it (except for isolated objects we call stars). Let me ask a related question. The CMBRM has been described as opaque and isothermal. Presumably "opaque" could be defined as no emissions detectable from beyond a certain place (watch my terms). So let me ask this question about the Universe that contains ours... It would be certainly opaque, since we cannot see beyond the Big Bang, but would the container Universe appear isothermal? Rather than the CMBRM being some intermediate matter state on *this* side of the Big Bang, could it simply be infalling light? I gave you a couple of "days off" so hopefully I don't elicit an ulcer on your part... David A. Smith |
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#2
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"N:dlzc D:aol T:com (dlzc)" N: dlzc1 D:cox wrote in message news:tfUHe.236624$Qo.33184@fed1read01... Dear Tom Roberts: "Tom Roberts" wrote in message . .. N:dlzc D:aol T:com (dlzc) wrote: .... Tom, I am given to understand that the CMBR was produced by an opaque "medium" (CMBRM). Yes. In the early universe no atom could remain an atom very long because the high temperature gave other particles enough kinetic energy so a simple collision often/usually would ionize the atom. So between a few seconds and ~300k years after the big bang the universe was filled with a charged plasma consisting primarily of electrons and protons. When the temperature had been reduced enough so most collisions did not have enough K.E. to ionize the atoms the electromagnetic attraction between protons and electrons quickly caused them to form hydrogen atoms. The charged plasma was essentially opaque to all types of EM radiation (hence it was black), but the hydrogen is transparent to most EM radiation. So in a short time the radiation emitted by the plasma could suddenly propagate over large distances. It is remnants of this radiation we see as the CMBR. But the CMBR is free of the absorption bands of "cooler" hydrogen. Let's pretend a timeline, with "CMBRM stops glowing" at 300,000 pBB (post-Big Bang). What about this Universe filling, formerly opticaly dense, hydrogen at 301,000 pBB? Does this mean that it all coalesced to "structures" in next-to-no-time? No, it was still hot, though slightly cooler, and still ubiquitous and pretty much homogenous but instead of being a hot dense opaque plasma, it was a hot dense transparent non-ionised gas. To get a picture in your mind, watch this video of the Landolt reaction and imagine it happening in reverse: http://video.uni-regensburg.de:8080/...lt_Reaction.rm At some point the CMBR had redshifted enough so it could not be absorbed at all by hydrogen, and since then the universe has been transparent to it (except for isolated objects we call stars). Let me ask a related question. The CMBRM has been described as opaque and isothermal. Presumably "opaque" could be defined as no emissions detectable from beyond a certain place (watch my terms). "a certain place" may give the wrong impression although obviously we are "here". It is perhaps better to consider opaque in this case in terms of the mean free path of a photon being greater than the time from emission to the time of complete transparency multiplied by the speed of light regardless of where the photon is emitted since the CMBRM was almost homogenous throughout the universe. So let me ask this question about the Universe that contains ours... There is no "Universe that contains ours" in the Big Bang model so it is not meaningful to ask the question. George |
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#3
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Dear George Dishman:
"George Dishman" wrote in message ... "N:dlzc D:aol T:com (dlzc)" N: dlzc1 D:cox wrote in message news:tfUHe.236624$Qo.33184@fed1read01... Dear Tom Roberts: "Tom Roberts" wrote in message . .. N:dlzc D:aol T:com (dlzc) wrote: ... Tom, I am given to understand that the CMBR was produced by an opaque "medium" (CMBRM). Yes. In the early universe no atom could remain an atom very long because the high temperature gave other particles enough kinetic energy so a simple collision often/usually would ionize the atom. So between a few seconds and ~300k years after the big bang the universe was filled with a charged plasma consisting primarily of electrons and protons. When the temperature had been reduced enough so most collisions did not have enough K.E. to ionize the atoms the electromagnetic attraction between protons and electrons quickly caused them to form hydrogen atoms. The charged plasma was essentially opaque to all types of EM radiation (hence it was black), but the hydrogen is transparent to most EM radiation. So in a short time the radiation emitted by the plasma could suddenly propagate over large distances. It is remnants of this radiation we see as the CMBR. But the CMBR is free of the absorption bands of "cooler" hydrogen. Let's pretend a timeline, with "CMBRM stops glowing" at 300,000 pBB (post-Big Bang). What about this Universe filling, formerly opticaly dense, hydrogen at 301,000 pBB? Does this mean that it all coalesced to "structures" in next-to-no-time? No, it was still hot, though slightly cooler, and still ubiquitous and pretty much homogenous but instead of being a hot dense opaque plasma, it was a hot dense transparent non-ionised gas. To get a picture in your mind, watch this video of the Landolt reaction and imagine it happening in reverse: http://video.uni-regensburg.de:8080/...lt_Reaction.rm I don't have the applet required to play it. I found another site that had it in Quicktime. Hydrogen absorbs light. We find its signature everywhere we look, when we look at point sources. But we don't find it with the CMBR. And it has been exposed longer, assuming the Universe filling gas didn't coalesce. At some point the CMBR had redshifted enough so it could not be absorbed at all by hydrogen, and since then the universe has been transparent to it (except for isolated objects we call stars). Let me ask a related question. The CMBRM has been described as opaque and isothermal. Presumably "opaque" could be defined as no emissions detectable from beyond a certain place (watch my terms). "a certain place" may give the wrong impression although obviously we are "here". We can't see beyond the CMBRM, so it is opaque. If we were on the inside of an event horizon, we could not see beyond that Universe's Big Bang, and see specular images of the container Universe. The Big Bang (aka. the inside of an event horizon) is opaque *without* invoking space-filling hydrogen plasma. It is perhaps better to consider opaque in this case in terms of the mean free path of a photon being greater than the time from emission to the time of complete transparency multiplied by the speed of light regardless of where the photon is emitted since the CMBRM was almost homogenous throughout the universe. So let me ask this question about the Universe that contains ours... There is no "Universe that contains ours" in the Big Bang model so it is not meaningful to ask the question. The Schwarzchild solution to GR for a black hole, describes another Universe inside the black hole, with internal time starting where external space leaves off. Since the Big Bang model is commonly dressed in the clothes of GR, are you sure 'There is no "Universe that contains ours" in the Big Bang model so it is not meaningful to ask the question'? You say imagine the Landolt reaction in reverse... imagine that our Big Bang is the inside of the event horizon of the (probably really big) black hole that contains our Universe. So sure are you? David A. Smith |
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#4
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N:dlzc D:aol T:com (dlzc) wrote:
Dear Tom Roberts: "Tom Roberts" wrote in message . .. Yes. In the early universe no atom could remain an atom very long because the high temperature gave other particles enough kinetic energy so a simple collision often/usually would ionize the atom. So between a few seconds and ~300k years after the big bang the universe was filled with a charged plasma consisting primarily of electrons and protons. When the temperature had been reduced enough so most collisions did not have enough K.E. to ionize the atoms the electromagnetic attraction between protons and electrons quickly caused them to form hydrogen atoms. The charged plasma was essentially opaque to all types of EM radiation (hence it was black), but the hydrogen is transparent to most EM radiation. So in a short time the radiation emitted by the plasma could suddenly propagate over large distances. It is remnants of this radiation we see as the CMBR. But the CMBR is free of the absorption bands of "cooler" hydrogen. Let's pretend a timeline, with "CMBRM stops glowing" at 300,000 pBB (post-Big Bang). What about this Universe filling, formerly opticaly dense, hydrogen at 301,000 pBB? Does this mean that it all coalesced to "structures" in next-to-no-time? Not at all. At Z~1000 the 3000K background glow was isotropic and the distance to the surface of last scattering correspondingly shorter. The distance to the surface of last scattering for H-alpha and other wavelengths where neutral hydrogen can absorb (and re-emit) will be different and second order effects may make for a slight change in the BB radiation intensity at those wavelengths, but to first order every neutral hydrogen atom is surrounded by an isotropic black body emitter at 3000K. Each hydrogen atom that absorbs an H-alpha photon will enventually re-emit it in some other direction. The radiation field stays isotropic - to first order all the neutral hydrogen in that era does is to make the universe more opaque at certain resonant frequencies. Because hydrogen is transparent to most of the CMBR radiation. The CMBR was emitted as a continuous blackbody spectrum ~3000 K; hydrogen can only absorb discrete lines from it, and the large redshift and Doppler shifting of the hydrogen in the early universe smeared out the bands so much they are not prominent (or perhaps not apparent at all, I don't know). Not detectable at all. Beyond experimental limits. I think your problem is that you are not imagining the situation correctly. The universe is bathed in an isotropic radiation field from the big bang. It is now a tiny 3K background but at Z~1000 it was 3000K (and still isotropic). Let me ask a related question. The CMBRM has been described as opaque and isothermal. Presumably "opaque" could be defined as no emissions detectable from beyond a certain place (watch my terms). So let me ask this question about the Universe that contains ours... It would be certainly opaque, since we cannot see beyond the Big Bang, but would the container Universe appear isothermal? Rather than the CMBRM being some intermediate matter state on *this* side of the Big Bang, could it simply be infalling light? The observable horizon is moving away from us at the speed of light. The challenge for cosmology is to explain why our patch of universe is so isotropic. Alan Guth's inflation is one possible solution: http://nedwww.ipac.caltech.edu/level..._contents.html You need to think more carefully about how absorbtion lines arise in a continuum spectrum. Energy is always conserved. Regards, Martin Brown |
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#5
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"N:dlzc D:aol T:com (dlzc)" N: dlzc1 D:cox wrote in message news:jNbJe.275166$Qo.182521@fed1read01... I don't have the applet required to play it. I found another site that had it in Quicktime. It used Real Player but as long as you got the idea, a bulk material can switch from opaque to transparent. Hydrogen absorbs light. Hydrogen also emits light. By the laws of thermodynamics, there must be a precise relationship between the two. We find its signature everywhere we look, when we look at point sources. But we don't find it with the CMBR. And it has been exposed longer, assuming the Universe filling gas didn't coalesce. If the gas is in equilibrium, the energy absorbed must be balanced by that emitted. It is therefore exactly at the crossover between producing absorption and emission lines. Given the slight anisotropy, perhaps it will be possible some time soon to detect a line redshifted down but it has taken sensitive space-borne missions just to measure the anisotropy in broad bands so looking for individual lines would require another step up in design. At some point the CMBR had redshifted enough so it could not be absorbed at all by hydrogen, and since then the universe has been transparent to it (except for isolated objects we call stars). Let me ask a related question. The CMBRM has been described as opaque and isothermal. Presumably "opaque" could be defined as no emissions detectable from beyond a certain place (watch my terms). "a certain place" may give the wrong impression although obviously we are "here". We can't see beyond the CMBRM, so it is opaque. That is correct, it rapidly absorbs any light that passes through it. If we were on the inside of an event horizon, we could not see beyond that That is not correct. Light does not pass out across the horizon but it does fall in. If you could hover just inside the event horizon you would be bombarded by high energy photons falling in. Universe's Big Bang, and see specular images of the container Universe. The Big Bang (aka. the inside of an event horizon) is opaque *without* invoking space-filling hydrogen plasma. The event horizon is not opaque, light passes through it without being absorbed. It is perhaps better to consider opaque in this case in terms of the mean free path of a photon being greater than the time from emission to the time of complete transparency multiplied by the speed of light regardless of where the photon is emitted since the CMBRM was almost homogenous throughout the universe. So let me ask this question about the Universe that contains ours... There is no "Universe that contains ours" in the Big Bang model so it is not meaningful to ask the question. The Schwarzchild solution to GR for a black hole, describes another Universe inside the black hole, with internal time starting where external space leaves off. I'm not sure about that, it seems to depend on the coordinate system you use but I know too little of GR to comment sensibly. Since the Big Bang model is commonly dressed in the clothes of GR, are you sure 'There is no "Universe that contains ours" in the Big Bang model so it is not meaningful to ask the question'? I am fairly sure that the picture of the event horizon of a black hole to which you are referring is related to an isolated mass in a lower density environment while the big bang scenario has uniform density throughout. You can get a similar effect I believe in a uniform density regime: http://scienceworld.wolfram.com/phys...ntDensity.html but in this case it would be more like the horizon that is expected to be produced by cosmic acceleration and is a limitation on visibility _within_ the universe. However, that needn't mean our universe isn't embedded in something different. The idea I find most understandable to illustrate the possibility is that of Alan Guth where he talks of multiple universes embedded in 'false vacuum' which is in a permanent state of inflation. That is not exclusive though, just indicative of the feasibility. You say imagine the Landolt reaction in reverse... Purely to suggest the change from opaque to transparent could be due to a phase change in the hydrogen/helium mix (plasma to gas) rather than requiring the material to coalesce into structures leaving vacuum between as you were suggesting. That could come later. imagine that our Big Bang is the inside of the event horizon of the (probably really big) black hole that contains our Universe. So sure are you? I am sure that the H/He mix was present because we see the radiation from it in the form of the CMBR, it is predicted by nucleosynthesis and we can see the mix in primeval stars. I can be sure it was opaque for over 300k years from lab experiments and WMAP. I can't be sure what we would have seen had it not existed, but then we wouldn't be here to see anything. Beyond that, I would just point you at the faq entry and say that I wouldn't presume to be any more sure than Philip Gibbs, and since it is 8 years old, perhaps even that might be slightly outdated. http://math.ucr.edu/home/baez/physic.../universe.html George |
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#6
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Dear George Dishman:
"George Dishman" wrote in message ... "N:dlzc D:aol T:com (dlzc)" N: dlzc1 D:cox wrote in message news:jNbJe.275166$Qo.182521@fed1read01... I don't have the applet required to play it. I found another site that had it in Quicktime. It used Real Player but as long as you got the idea, a bulk material can switch from opaque to transparent. The "bromate clock" does this too, but the symbolism would invoke the "constant creation" and "recycling Universe" crowds... ;) Hydrogen absorbs light. Hydrogen also emits light. By the laws of thermodynamics, there must be a precise relationship between the two. Yes, I finally got it. Only the "vector part of the momentum" will be altered, since the momentum of the "intervening" hydrogen (indicating *its* temperature) will average out to no net contribution. I think. We find its signature everywhere we look, when we look at point sources. But we don't find it with the CMBR. And it has been exposed longer, assuming the Universe filling gas didn't coalesce. If the gas is in equilibrium, the energy absorbed must be balanced by that emitted. It is therefore exactly at the crossover between producing absorption and emission lines. Given the slight anisotropy, perhaps it will be possible some time soon to detect a line redshifted down but it has taken sensitive space-borne missions just to measure the anisotropy in broad bands so looking for individual lines would require another step up in design. I'm always up for sharper tools. At some point the CMBR had redshifted enough so it could not be absorbed at all by hydrogen, and since then the universe has been transparent to it (except for isolated objects we call stars). Let me ask a related question. The CMBRM has been described as opaque and isothermal. Presumably "opaque" could be defined as no emissions detectable from beyond a certain place (watch my terms). "a certain place" may give the wrong impression although obviously we are "here". We can't see beyond the CMBRM, so it is opaque. That is correct, it rapidly absorbs any light that passes through it. If we were on the inside of an event horizon, we could not see beyond that That is not correct. Light does not pass out across the horizon but it does fall in. But (outer) space becomes (inner) timelike. So any light that falls in loses any correlation to frequency, or momentum. Only energy would be conserved, right? If you could hover just inside the event horizon you would be bombarded by high energy photons falling in. I don't agree, and I can't quite tell you why that is. Ultimately I think it is because you cannot hover just inside the event horizon, since to do so would be to stop time. So if you infall at a rate of 1 second per second, the light should be received at finite energy, since your "motion along the time axis" is also closely correlated to c. My question to Tom is would this also achieve the appearance of being isothermal? The entire history of our container Universe (up until the point we evaporated) is written on/into the event horizon. Given what we know/expect of Universal temperature, and size of the Universe at that temeprature, I think this also would provide a very nice blackbody curve. Universe's Big Bang, and see specular images of the container Universe. The Big Bang (aka. the inside of an event horizon) is opaque *without* invoking space-filling hydrogen plasma. The event horizon is not opaque, light passes through it without being absorbed. The classical surface of last emission is not within the Universe inside the event horizon. The closest "place" in this Universe is "just inside the event horizon". You can't see beyond it. It is opaque, if you accept my "abomination" of the word. We won't get specular images from before the CMBRM... either way. It is perhaps better to consider opaque in this case in terms of the mean free path of a photon being greater than the time from emission to the time of complete transparency multiplied by the speed of light regardless of where the photon is emitted since the CMBRM was almost homogenous throughout the universe. So let me ask this question about the Universe that contains ours... There is no "Universe that contains ours" in the Big Bang model so it is not meaningful to ask the question. The Schwarzchild solution to GR for a black hole, describes another Universe inside the black hole, with internal time starting where external space leaves off. I'm not sure about that, it seems to depend on the coordinate system you use but I know too little of GR to comment sensibly. You are no more God than I am. You have tried on the hat more than once, in an effort to help me (and those that might someday have these or related questions). For that I thank you. Some questions are so poorly worded that they cannot be understood, and some questions just cannot be answered. I'm thinking I've formulated the former, but you never know. ;) Since the Big Bang model is commonly dressed in the clothes of GR, are you sure 'There is no "Universe that contains ours" in the Big Bang model so it is not meaningful to ask the question'? I am fairly sure that the picture of the event horizon of a black hole to which you are referring is related to an isolated mass in a lower density environment while the big bang scenario has uniform density throughout. You can get a similar effect I believe in a uniform density regime: http://scienceworld.wolfram.com/phys...ntDensity.html but in this case it would be more like the horizon that is expected to be produced by cosmic acceleration and is a limitation on visibility _within_ the universe. However, that needn't mean our universe isn't embedded in something different. The idea I find most understandable to illustrate the possibility is that of Alan Guth where he talks of multiple universes embedded in 'false vacuum' which is in a permanent state of inflation. That is not exclusive though, just indicative of the feasibility. You say imagine the Landolt reaction in reverse... Purely to suggest the change from opaque to transparent could be due to a phase change in the hydrogen/helium mix (plasma to gas) rather than requiring the material to coalesce into structures leaving vacuum between as you were suggesting. That could come later. imagine that our Big Bang is the inside of the event horizon of the (probably really big) black hole that contains our Universe. So sure are you? I am sure that the H/He mix was present because we see the radiation from it in the form of the CMBR, This is not conclusive, but *assumed*. That is the crux of my problem. It is a perfect blackbody radiator, with some hint of structure (variable intensity) written in/on it. The Universe should have been mostly hydrogen and helium. Therefore the CMBRM must be mostly hydrogen and helium. A logical chain, just not one I am fond of. it is predicted by nucleosynthesis and we can see the mix in primeval stars. I can be sure it was opaque for over 300k years from lab experiments and WMAP. I can't be sure what we would have seen had it not existed, but then we wouldn't be here to see anything. I don't agree with "lab experiments" since we cannot generate an opaque plasma in the lab. I also don't agree with the infalling light being necessarily fatal. If Joe were to don a spacesuit, and fall into the BH at the center of the Milky Way, would the infalling light kill him? No. If other stuff didn't kill him (with differential orbital velocity) he'd just see infalling light that became more and more distorted (non-specular). Beyond that, I would just point you at the faq entry and say that I wouldn't presume to be any more sure than Philip Gibbs, and since it is 8 years old, perhaps even that might be slightly outdated. http://math.ucr.edu/home/baez/physic.../universe.html Thanks George. I hope you have/had a great Sunday. David A. Smith |
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#7
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Dear Martin Brown:
"Martin Brown" wrote in message ... N:dlzc D:aol T:com (dlzc) wrote: .... Let me ask a related question. The CMBRM has been described as opaque and isothermal. Presumably "opaque" could be defined as no emissions detectable from beyond a certain place (watch my terms). So let me ask this question about the Universe that contains ours... It would be certainly opaque, since we cannot see beyond the Big Bang, but would the container Universe appear isothermal? Rather than the CMBRM being some intermediate matter state on *this* side of the Big Bang, could it simply be infalling light? The observable horizon is moving away from us at the speed of light. The challenge for cosmology is to explain why our patch of universe is so isotropic. Alan Guth's inflation is one possible solution: http://nedwww.ipac.caltech.edu/level..._contents.html You need to think more carefully about how absorbtion lines arise in a continuum spectrum. Energy is always conserved. Not always is energy conserved in GR, but I understand your point. I did finally "get it". And my question also provides an isotropic Universe, since we "infell" from such a Universe. Perhaps. Cake batter always gets more uniform with each "folding". Now I made myself hungry! ;) Have a good Sunday. David A. Smith |
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#8
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"N:dlzc D:aol T:com (dlzc)" N: dlzc1 D:cox wrote in message news:wTpJe.286569$Qo.235834@fed1read01... Dear George Dishman: "George Dishman" wrote in message ... .... If we were on the inside of an event horizon, we could not see beyond that That is not correct. Light does not pass out across the horizon but it does fall in. But (outer) space becomes (inner) timelike. This is the area I'm less sure about but I think that is an artefact of the Schwarzchild coordinates and it get resolved using Kruskal but please check that, I could easily be wrong. So any light that falls in loses any correlation to frequency, or momentum. Only energy would be conserved, right? No, have you looked at Andrew Hamilton's animations? http://casa.colorado.edu/~ajsh/schw.shtml This paragraph and image show the view of external objects from 0.35 Schwarzschild radii: http://casa.colorado.edu/~ajsh/singu...tml#distortion The blue, orange and green shapes are the other stars in his hypothetical double binary system. If you could hover just inside the event horizon you would be bombarded by high energy photons falling in. I don't agree, and I can't quite tell you why that is. Ultimately I think it is because you cannot hover just inside the event horizon, since to do so would be to stop time. Indeed, I was glossing over that. So if you infall at a rate of 1 second per second, the light should be received at finite energy, since your "motion along the time axis" is also closely correlated to c. True but the point was simply that you would still receive photons from outside. snip question to Tom The classical surface of last emission is not within the Universe inside the event horizon. The closest "place" in this Universe is "just inside the event horizon". You can't see beyond it. It is opaque, if you accept my "abomination" of the word. We won't get specular images from before the CMBRM... either way. Well it is certainly opaque around 379,000 years because we have the photos ;-) I'm not aware of any other "classical surface of last emission" though. The Schwarzchild solution to GR for a black hole, describes another Universe inside the black hole, with internal time starting where external space leaves off. I'm not sure about that, it seems to depend on the coordinate system you use but I know too little of GR to comment sensibly. You are no more God than I am. You have tried on the hat more than once, in an effort to help me (and those that might someday have these or related questions). For that I thank you. Some questions are so poorly worded that they cannot be understood, and some questions just cannot be answered. I'm thinking I've formulated the former, but you never know. ;) I think you are being misled by the coordinate feature of the Schwarzschild solution. Perhaps after looking at Andrew's site, you could reformulate the question. .... I am sure that the H/He mix was present because we see the radiation from it in the form of the CMBR, This is not conclusive, but *assumed*. That is the crux of my problem. The mix is not assumed, it is observed in primitive stars and other ways. It also predicted from nucleosynthesis as the best fit to other measurements as I said below. Check the bands in the diagram at the bottom http://www.astro.ucla.edu/~wright/BBNS.html You are right we assume that is the source, but at a high enough temperature you get a black body from any mix. Why do you think this is a problem? It is a perfect blackbody radiator, with some hint of structure (variable intensity) written in/on it. The Universe should have been mostly hydrogen and helium. Therefore the CMBRM must be mostly hydrogen and helium. A logical chain, just not one I am fond of. it is predicted by nucleosynthesis and we can see the mix in primeval stars. I can be sure it was opaque for over 300k years from lab experiments and WMAP. I can't be sure what we would have seen had it not existed, but then we wouldn't be here to see anything. I don't agree with "lab experiments" since we cannot generate an opaque plasma in the lab. No but we can measure the cross section of the particles and calulate the depth need for the plasma to be opaque. I also don't agree with the infalling light being necessarily fatal. I wasn't really saying that earlier. If Joe were to don a spacesuit, and fall into the BH at the center of the Milky Way, would the infalling light kill him? No. If other stuff didn't kill him (with differential orbital velocity) he'd just see infalling light that became more and more distorted (non-specular). That was my point, even after crossing the event horizon, you would still be able to see the part of the universe you had left hence the horizon cannot be opaque. George |
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#9
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Dear George Dishman:
"George Dishman" wrote in message ... "N:dlzc D:aol T:com (dlzc)" N: dlzc1 D:cox wrote in message news:wTpJe.286569$Qo.235834@fed1read01... Dear George Dishman: "George Dishman" wrote in message ... ... If we were on the inside of an event horizon, we could not see beyond that That is not correct. Light does not pass out across the horizon but it does fall in. But (outer) space becomes (inner) timelike. This is the area I'm less sure about but I think that is an artefact of the Schwarzchild coordinates and it get resolved using Kruskal but please check that, I could easily be wrong. Probably not. The answers I find I cannot yet understand. URL:http://xxx.lanl.gov/abs/astro-ph/9905144 URL:http://xxx.lanl.gov/abs/gr-qc/0406109 Kruskal does not appear to do away with timelike... URL:http://xxx.lanl.gov/abs/astro-ph/9904162 .... but this "fellow" seem to say that the singularity is *coincident* with "just inside the event horizon". Which would be true for the container Universe... just don't know how the paper fared in peer review. So any light that falls in loses any correlation to frequency, or momentum. Only energy would be conserved, right? No, have you looked at Andrew Hamilton's animations? http://casa.colorado.edu/~ajsh/schw.shtml External objects end up sweeping an arc across the sky. Other objects in other places do the same. Definitely NOT specular images. And this is a non-rotating BH, which adds yet another twist (literally) to the infalling light. And note that in the simulation, the external-Universe stars don't change color. This paragraph and image show the view of external objects from 0.35 Schwarzschild radii: http://casa.colorado.edu/~ajsh/singu...tml#distortion The blue, orange and green shapes are the other stars in his hypothetical double binary system. Yes. Unfortunately, if outer-r becomes timelike, the entire history of the container Universe is written on the inner Big Bang... at least until the contained Universe evaporates. Anything that ever (outer-time) infalls, arrvies at the inner "Big Bang". If you could hover just inside the event horizon you would be bombarded by high energy photons falling in. I don't agree, and I can't quite tell you why that is. Ultimately I think it is because you cannot hover just inside the event horizon, since to do so would be to stop time. Indeed, I was glossing over that. So if you infall at a rate of 1 second per second, the light should be received at finite energy, since your "motion along the time axis" is also closely correlated to c. True but the point was simply that you would still receive photons from outside. Still receive photons is not at issue. Are they specular? No. Are they diffuse? Yes and no. Is the surfaceo-of-last-emission transparent? No. Is the "photon historical record" of infalling light through the event horizon isothermal? snip question to Tom It may not have an answer that I can understand. The classical surface of last emission is not within the Universe inside the event horizon. The closest "place" in this Universe is "just inside the event horizon". You can't see beyond it. It is opaque, if you accept my "abomination" of the word. We won't get specular images from before the CMBRM... either way. Well it is certainly opaque around 379,000 years because we have the photos ;-) I'm not aware of any other "classical surface of last emission" though. This is my quest. I wonder if the "structures" were already formed (coalescence not a problem), the Universe-filling gas, wasn't Universe filling (the non-issue of absoprtion spectra disappears), and the CMBRM is a/the "photographic record" of our container Universe. The Schwarzchild solution to GR for a black hole, describes another Universe inside the black hole, with internal time starting where external space leaves off. I'm not sure about that, it seems to depend on the coordinate system you use but I know too little of GR to comment sensibly. You are no more God than I am. You have tried on the hat more than once, in an effort to help me (and those that might someday have these or related questions). For that I thank you. Some questions are so poorly worded that they cannot be understood, and some questions just cannot be answered. I'm thinking I've formulated the former, but you never know. ;) I think you are being misled by the coordinate feature of the Schwarzschild solution. Perhaps after looking at Andrew's site, you could reformulate the question. I can't. Bjoern tried to help me "get it", but the ground is rocky, and crops will not (yet) grow. I'm not dead yet, so maybe there is hope. ... I am sure that the H/He mix was present because we see the radiation from it in the form of the CMBR, This is not conclusive, but *assumed*. That is the crux of my problem. The mix is not assumed, it is observed in primitive stars and other ways. It isn't the mix, George. It is the distribution. From nearly patternless to fully coalesced in less than 1 Gy. A universal *smooth* distribution can't coalesce under the effects of gravity. So we started out pretty lumpy (which we are still working on resolving). It also predicted from nucleosynthesis as the best fit to other measurements as I said below. Check the bands in the diagram at the bottom http://www.astro.ucla.edu/~wright/BBNS.html You are right we assume that is the source, but at a high enough temperature you get a black body from any mix. Why do you think this is a problem? As I have said, my "hypothesis" allows for structures to be found right up to the CMBRM, even for heavier elements to be present from the "get go". And since infalling light is not fatally blue shifted for those that are "falling towards the singularity", the CMBRM is not necessary to have protected us from the "fires of creation". It is a perfect blackbody radiator, with some hint of structure (variable intensity) written in/on it. The Universe should have been mostly hydrogen and helium. Therefore the CMBRM must be mostly hydrogen and helium. A logical chain, just not one I am fond of. it is predicted by nucleosynthesis and we can see the mix in primeval stars. I can be sure it was opaque for over 300k years from lab experiments and WMAP. I can't be sure what we would have seen had it not existed, but then we wouldn't be here to see anything. I don't agree with "lab experiments" since we cannot generate an opaque plasma in the lab. No but we can measure the cross section of the particles and calulate the depth need for the plasma to be opaque. I also don't agree with the infalling light being necessarily fatal. I wasn't really saying that earlier. I wasn't sure what you meant by: I can't be sure what we would have seen had it not existed, but then we wouldn't be here to see anything. .... perhaps that there would be no matter for us to be comprised of... If Joe were to don a spacesuit, and fall into the BH at the center of the Milky Way, would the infalling light kill him? No. If other stuff didn't kill him (with differential orbital velocity) he'd just see infalling light that became more and more distorted (non-specular). That was my point, even after crossing the event horizon, you would still be able to see the part of the universe you had left hence the horizon cannot be opaque. There is no part of the external Universe that extends into the internal Universe. What you see, perhaps, is all the positions and all the intensities of all the stars, and the container Universe's CMBR, spread across 2 pi steradians... for all time. Neglecting expansion, which only serves to red shift the panopoly. It *is* opaque, it is NOT specular. You cannot see before the Big Bang, even without a CMBRM. And if we can... David A. Smith |
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"N:dlzc D:aol T:com (dlzc)" N: dlzc1 D:cox wrote in message news:yxdKe.308849$Qo.131840@fed1read01... Dear George Dishman: "George Dishman" wrote in message ... "N:dlzc D:aol T:com (dlzc)" N: dlzc1 D:cox wrote in message news:wTpJe.286569$Qo.235834@fed1read01... Dear George Dishman: "George Dishman" wrote in message ... ... If we were on the inside of an event horizon, we could not see beyond that That is not correct. Light does not pass out across the horizon but it does fall in. But (outer) space becomes (inner) timelike. This is the area I'm less sure about but I think that is an artefact of the Schwarzchild coordinates and it get resolved using Kruskal but please check that, I could easily be wrong. Probably not. The answers I find I cannot yet understand. URL:http://xxx.lanl.gov/abs/astro-ph/9905144 URL:http://xxx.lanl.gov/abs/gr-qc/0406109 Kruskal does not appear to do away with timelike... I might be thinking of Eddington-Finkelstein Coordinates http://scholar.uwinnipeg.ca/courses/...lack_Holes.htm However, you might find this site interesting: http://www.etsu.edu/physics/plntrm/relat/blackhl.htm Follow the "next" link at the bottom. This is the contents page: http://www.etsu.edu/physics/plntrm/relat/relatabs.htm URL:http://xxx.lanl.gov/abs/astro-ph/9904162 ... but this "fellow" seem to say that the singularity is *coincident* with "just inside the event horizon". Which would be true for the container Universe... just don't know how the paper fared in peer review. When I see "We insist that our derivation is straightforward and there is no scope for any ambiguity ... ", I get very suspicious. Why is he having to have a little rant in a simple abstract? So any light that falls in loses any correlation to frequency, or momentum. Only energy would be conserved, right? No, have you looked at Andrew Hamilton's animations? http://casa.colorado.edu/~ajsh/schw.shtml External objects end up sweeping an arc across the sky. Other objects in other places do the same. Definitely NOT specular images. And this is a non-rotating BH, which adds yet another twist (literally) to the infalling light. And note that in the simulation, the external-Universe stars don't change color. The point is that you can see them, there is nothing at the event horizon but vacuum. It isn't a physical barrier but just a location. This paragraph and image show the view of external objects from 0.35 Schwarzschild radii: http://casa.colorado.edu/~ajsh/singu...tml#distortion The blue, orange and green shapes are the other stars in his hypothetical double binary system. Yes. Unfortunately, if outer-r becomes timelike, the entire history of the container Universe is written on the inner Big Bang... at least until the contained Universe evaporates. Anything that ever (outer-time) infalls, arrvies at the inner "Big Bang". I don't believe that is physical though, just an artificial peculiarity of the coordinates Schwarzschild used. Andrew Hamilton's pages would take such effects into account. True but the point was simply that you would still receive photons from outside. Still receive photons is not at issue. Are they specular? No. Are they diffuse? Yes and no. Is the surfaceo-of-last-emission transparent? What surface? There is no material to emit at the event horizon, it is a location and all matter is passing it at the speed of light as determined by an observer at infinity (I think!). No. Is the "photon historical record" of infalling light through the event horizon isothermal? No, it has the spectrum of whatever stars and external objects produced it only severely blue shifted (depending on the motion of the infalling observer as you said). The classical surface of last emission is not within the Universe inside the event horizon. The closest "place" in this Universe is "just inside the event horizon". You can't see beyond it. It is opaque, if you accept my "abomination" of the word. We won't get specular images from before the CMBRM... either way. Well it is certainly opaque around 379,000 years because we have the photos ;-) I'm not aware of any other "classical surface of last emission" though. This is my quest. I wonder if the "structures" were already formed (coalescence not a problem), the Universe-filling gas, wasn't Universe filling (the non-issue of absoprtion spectra disappears), and the CMBRM is a/the "photographic record" of our container Universe. Go back far enough, to the end of the inflationary period IIRC, and what now constitutes the observable universe was the size of a grapefruit. There wouldn't be much space for light to get through at that density. Note I am not entirely diagreeing. I wonder whether primordial black holes could have grown rapidly in such a high density environment that they existed before the mix became transparent and were the seeds of what are now galactic clusters. I think we may lewarn a lot when we can detect Pop III SNe but we will have to wait for at least the next generation of telescopes to come on line. I think you are being misled by the coordinate feature of the Schwarzschild solution. Perhaps after looking at Andrew's site, you could reformulate the question. I can't. I think you have above. Bjoern tried to help me "get it", but the ground is rocky, and crops will not (yet) grow. I'm not dead yet, so maybe there is hope. The simple answer is that GR says there was no container and the density was far too high to see through it anyway when you go back far enough. The "surface of last scattering" is a feature of the gas _in_ the universe and a black hole has nothing equivalent. The mix is not assumed, it is observed in primitive stars and other ways. It isn't the mix, George. It is the distribution. Yes, I follow your question now. From nearly patternless to fully coalesced in less than 1 Gy. A universal *smooth* distribution can't coalesce under the effects of gravity. So we started out pretty lumpy (which we are still working on resolving). Our theories of galactic formation have a long way to go. The roles of dark matter and super- massive black holes are far from being fully understood so watch this space. It also predicted from nucleosynthesis as the best fit to other measurements as I said below. Check the bands in the diagram at the bottom http://www.astro.ucla.edu/~wright/BBNS.html You are right we assume that is the source, but at a high enough temperature you get a black body from any mix. Why do you think this is a problem? As I have said, my "hypothesis" allows for structures to be found right up to the CMBRM, even for heavier elements to be present from the "get go". And since infalling light is not fatally blue shifted for those that are "falling towards the singularity", the CMBRM is not necessary to have protected us from the "fires of creation". I don't follow, if we were falling towards a singularity, the universe would be shrinking. I also don't agree with the infalling light being necessarily fatal. I wasn't really saying that earlier. I wasn't sure what you meant by: I can't be sure what we would have seen had it not existed, but then we wouldn't be here to see anything. ... perhaps that there would be no matter for us to be comprised of... Yes, that was it. What the universe would look like if it contained no matter whatsoever is moot! That was my point, even after crossing the event horizon, you would still be able to see the part of the universe you had left hence the horizon cannot be opaque. There is no part of the external Universe that extends into the internal Universe. What you see, perhaps, is all the positions and all the intensities of all the stars, and the container Universe's CMBR, spread across 2 pi steradians... for all time. Neglecting expansion, which only serves to red shift the panopoly. It *is* opaque, it is NOT specular. You cannot see before the Big Bang, even without a CMBRM. But you would in what you describe, you would be seeing "all the stars" in the container Universe, the horizon would only be a location in the vacuum. George |