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| Tags: cmbr, neutron, stars |
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#11
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George replied to David:
Is the "photon historical record" of infalling light through the event horizon isothermal? No, it has the spectrum of whatever stars and external objects produced it only severely blue shifted (depending on the motion of the infalling observer as you said). I'd expect a free-falling observer to see infalling light redshifted. The longer the time since crossing the horizon, the greater the redshift. An observer slowing his downward acceleration sufficiently would see infalling light blueshifted. -- Jeff, in Minneapolis |
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#12
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Dear George Dishman:
"George Dishman" wrote in message ... "N:dlzc D:aol T:com (dlzc)" N: dlzc1 D:cox wrote in message news:yxdKe.308849$Qo.131840@fed1read01... Dear George Dishman: "George Dishman" wrote in message ... "N:dlzc D:aol T:com (dlzc)" N: dlzc1 D:cox wrote in message news:wTpJe.286569$Qo.235834@fed1read01... Dear George Dishman: "George Dishman" wrote in message ... ... If we were on the inside of an event horizon, we could not see beyond that That is not correct. Light does not pass out across the horizon but it does fall in. But (outer) space becomes (inner) timelike. This is the area I'm less sure about but I think that is an artefact of the Schwarzchild coordinates and it get resolved using Kruskal but please check that, I could easily be wrong. Probably not. The answers I find I cannot yet understand. URL:http://xxx.lanl.gov/abs/astro-ph/9905144 URL:http://xxx.lanl.gov/abs/gr-qc/0406109 Kruskal does not appear to do away with timelike... I might be thinking of Eddington-Finkelstein Coordinates http://scholar.uwinnipeg.ca/courses/...lack_Holes.htm However, you might find this site interesting: http://www.etsu.edu/physics/plntrm/relat/blackhl.htm Follow the "next" link at the bottom. This is the contents page: http://www.etsu.edu/physics/plntrm/relat/relatabs.htm Will do. URL:http://xxx.lanl.gov/abs/astro-ph/9904162 ... but this "fellow" seem to say that the singularity is *coincident* with "just inside the event horizon". Which would be true for the container Universe... just don't know how the paper fared in peer review. When I see "We insist that our derivation is straightforward and there is no scope for any ambiguity ... ", I get very suspicious. Why is he having to have a little rant in a simple abstract? Agreed, because it continues to be discussed for long after 1999. I just didn't want to load one side of the "teeter-totter"... but provide some sort of balance. So any light that falls in loses any correlation to frequency, or momentum. Only energy would be conserved, right? No, have you looked at Andrew Hamilton's animations? http://casa.colorado.edu/~ajsh/schw.shtml External objects end up sweeping an arc across the sky. Other objects in other places do the same. Definitely NOT specular images. And this is a non-rotating BH, which adds yet another twist (literally) to the infalling light. And note that in the simulation, the external-Universe stars don't change color. The point is that you can see them, there is nothing at the event horizon but vacuum. It isn't a physical barrier but just a location. You can't "see them". They are no longer point sources, but area sources. "Like" the CMBRM. This paragraph and image show the view of external objects from 0.35 Schwarzschild radii: http://casa.colorado.edu/~ajsh/singu...tml#distortion The blue, orange and green shapes are the other stars in his hypothetical double binary system. Yes. Unfortunately, if outer-r becomes timelike, the entire history of the container Universe is written on the inner Big Bang... at least until the contained Universe evaporates. Anything that ever (outer-time) infalls, arrvies at the inner "Big Bang". I don't believe that is physical though, just an artificial peculiarity of the coordinates Schwarzschild used. Kruskal still has it timelike. It is not a peculiarity, but a requirement. Andrew Hamilton's pages would take such effects into account. Perhaps. Not doubting the abilities, just questioning what a "Universe full of stars" would look like. True but the point was simply that you would still receive photons from outside. Still receive photons is not at issue. Are they specular? No. Are they diffuse? Yes and no. Is the surfaceo-of-last-emission transparent? What surface? The surface of the star that originally emitted the light. There is no material to emit at the event horizon, it is a location and all matter is passing it at the speed of light as determined by an observer at infinity (I think!). Not quite. It is a location in *time*, and all matter (and energy) propagate from there. And I understand that you are uncomfortable with this. The kinetic velocities obtained in the new internal space will likely only be sufficient to conserve energy and momentum. No. Is the "photon historical record" of infalling light through the event horizon isothermal? No, it has the spectrum of whatever stars and external objects produced it only severely blue shifted (depending on the motion of the infalling observer as you said). *Integrated over time*. Is the integral light history of our Universe from formation of a BH, until it evaporates, isothermal? I think it is *to a close approximation*. The classical surface of last emission is not within the Universe inside the event horizon. The closest "place" in this Universe is "just inside the event horizon". You can't see beyond it. It is opaque, if you accept my "abomination" of the word. We won't get specular images from before the CMBRM... either way. Well it is certainly opaque around 379,000 years because we have the photos ;-) I'm not aware of any other "classical surface of last emission" though. This is my quest. I wonder if the "structures" were already formed (coalescence not a problem), the Universe-filling gas, wasn't Universe filling (the non-issue of absoprtion spectra disappears), and the CMBRM is a/the "photographic record" of our container Universe. Go back far enough, to the end of the inflationary period IIRC, and what now constitutes the observable universe was the size of a grapefruit. There wouldn't be much space for light to get through at that density. Note I am not entirely diagreeing. I wonder whether primordial black holes could have grown rapidly in such a high density environment that they existed before the mix became transparent and were the seeds of what are now galactic clusters. I think we may lewarn a lot when we can detect Pop III SNe but we will have to wait for at least the next generation of telescopes to come on line. No one currently believes the Universe started out "the size of a grapefruit", unless they also posit "c_BB c_now". You "helped establish" the CMBRM was many tens of million light years thick, only ~300,000 years after the BB, based on the (lack of) spectra. You can't get that big from a point (essentially) in that time. Or am I misunderstanding again? I think you are being misled by the coordinate feature of the Schwarzschild solution. Perhaps after looking at Andrew's site, you could reformulate the question. I can't. I think you have above. Bjoern tried to help me "get it", but the ground is rocky, and crops will not (yet) grow. I'm not dead yet, so maybe there is hope. The simple answer is that GR says there was no container and the density was far too high to see through it anyway when you go back far enough. The "surface of last scattering" is a feature of the gas _in_ the universe and a black hole has nothing equivalent. GR *does* allow description of a container, but it is a description you are not comfortable with. The inside of the event horizon is the only spatial location in the newly minted space from which the light could have come, so is therefore opaque. And you are reciting the established/accepted source of the CMBR, that does not obviate an alternate choice of sources *fully in compliance with GR*. GR doesn't require that the CMBRM be Universe filling gas, unless gas is the source. The source could be a container Universe, depending on the answer to my question to Tom. Even so, it could be a way to resolve the age of the Universe that contains us, since only certain light profiles could result in what we see. Or not. The mix is not assumed, it is observed in primitive stars and other ways. It isn't the mix, George. It is the distribution. Yes, I follow your question now. From nearly patternless to fully coalesced in less than 1 Gy. A universal *smooth* distribution can't coalesce under the effects of gravity. So we started out pretty lumpy (which we are still working on resolving). Our theories of galactic formation have a long way to go. The roles of dark matter and super- massive black holes are far from being fully understood so watch this space. ;) Always do! And I do try and understand. It also predicted from nucleosynthesis as the best fit to other measurements as I said below. Check the bands in the diagram at the bottom http://www.astro.ucla.edu/~wright/BBNS.html You are right we assume that is the source, but at a high enough temperature you get a black body from any mix. Why do you think this is a problem? As I have said, my "hypothesis" allows for structures to be found right up to the CMBRM, even for heavier elements to be present from the "get go". And since infalling light is not fatally blue shifted for those that are "falling towards the singularity", the CMBRM is not necessary to have protected us from the "fires of creation". I don't follow, if we were falling towards a singularity, the universe would be shrinking. No. The outer r becomes inner t. The outer Universe "expects us" to become more and more dense. We have internal-space that is orthogonal to our time. This space is defined by c and time. The speed of light (as expected by the outer Universe) is an inverse function of density. As we approach a singularity (from outer reconing), c approaches 0 (as the outer Universe expects, not as we would observe), and space becomes larger and larger. Viola! Expansion. The problem is the "discontinuity" that occurs at the event horizon, and the confusion between inner and outer coordinates that results. But that is just a description problem (eg: non-standard verbage is required). I also don't agree with the infalling light being necessarily fatal. I wasn't really saying that earlier. I wasn't sure what you meant by: I can't be sure what we would have seen had it not existed, but then we wouldn't be here to see anything. ... perhaps that there would be no matter for us to be comprised of... Yes, that was it. What the universe would look like if it contained no matter whatsoever is moot! This is where I diverge with Bjoern. He believes you can have a Universe without matter. But Einstein suggests that spacetime is the product of all mass-energy in the Universe (if I understand correctly). This means no mass/energy provides null spacetime. Given a Universe, you have mass/energy. Given mass/energy, you have spacetime. That was my point, even after crossing the event horizon, you would still be able to see the part of the universe you had left hence the horizon cannot be opaque. There is no part of the external Universe that extends into the internal Universe. What you see, perhaps, is all the positions and all the intensities of all the stars, and the container Universe's CMBR, spread across 2 pi steradians... for all time. Neglecting expansion, which only serves to red shift the panopoly. It *is* opaque, it is NOT specular. You cannot see before the Big Bang, even without a CMBRM. But you would in what you describe, you would be seeing "all the stars" in the container Universe, the horizon would only be a location in the vacuum. Only as a plenum. The "off ramp" is all you can see, with the CMBR as the "sound of car horns" on a freeway to which we are but a side road. Structures can infall into large black holes and survive... probably not gravitationally bound ones, but who knows. Maybe the nature of the early Universe actually tells us how steep the off ramp is (namely something about how many of the four forces yield to the curvature of the event horizon). David A. Smith |
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#13
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Dear George Dishman:
"George Dishman" wrote in message ... .... Probably not. The answers I find I cannot yet understand. URL:http://xxx.lanl.gov/abs/astro-ph/9905144 URL:http://xxx.lanl.gov/abs/gr-qc/0406109 Kruskal does not appear to do away with timelike... I might be thinking of Eddington-Finkelstein Coordinates http://scholar.uwinnipeg.ca/courses/...lack_Holes.htm They still have an inner time coordinate v, that is a blend of outer time and outer space (specifically r). It only helps to describe the inner in terms the outer can "comprehend". And it blends two orthogonal axes to do it. However, you might find this site interesting: http://www.etsu.edu/physics/plntrm/relat/blackhl.htm .... only for r r_B (the surface of the mass). When, in this Universe, did the quarks making up your protons and neutrons and your electrons *not* exist? If mass existed right up to the Big Bang, this coordinate definition sounds like it is invalid. Follow the "next" link at the bottom. This is the contents page: http://www.etsu.edu/physics/plntrm/relat/relatabs.htm Good stuff! Thanks! David A. Smith |
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#14
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Dear Jeff Root:
"Jeff Root" wrote in message ups.com... George replied to David: Is the "photon historical record" of infalling light through the event horizon isothermal? No, it has the spectrum of whatever stars and external objects produced it only severely blue shifted (depending on the motion of the infalling observer as you said). I'd expect a free-falling observer to see infalling light redshifted. The longer the time since crossing the horizon, the greater the redshift. An observer slowing his downward acceleration sufficiently would see infalling light blueshifted. True with expansion. As to how you would reverse time to "slow your downward acceleration"... David A. Smith |
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#15
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David wrote to George:
the CMBRM was many tens of million light years thick I ripped that out of context, and I'm not at all certain I know what you meant, but about ten years ago I asked an astronomer who specializes in IR light from plasmas and gases (nebulae, galactic jets, and the like) what the optical depth (thickness) of the CMBR was, and he said it was about 100 parsecs. That is, all the light we see in the CMBR is from a shell only 100 parsecs (300 light-yers) thick. -- Jeff, in Minneapolis |
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#16
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David replied to Jeff:
I'd expect a free-falling observer to see infalling light redshifted. The longer the time since crossing the horizon, the greater the redshift. An observer slowing his downward acceleration sufficiently would see infalling light blueshifted. True with expansion. As to how you would reverse time to "slow your downward acceleration"... Expansion? Are you referring to the fact that everything falling into a black hole gets stretched out? Of course, it also gets squeezed in on the sides. An explorer free-falling into a very large black hole would not see anything change at the instant he crossed the event horizon. As he fell in farther and farther the tide would pull his socks down and make his hair stand on end. Eventually it would pull his feet and head off of his body. It wouldn't be necessary to reverse time to slow acceleration. A rocket would still work, although I don't know what direction you would aim it, and of course it wouldn't do much good for very long. -- Jeff, in Minneapolis |
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#17
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Dear Jeff Root:
"Jeff Root" wrote in message ups.com... David wrote to George: the CMBRM was many tens of million light years thick I ripped that out of context, and I'm not at all certain I know what you meant, but about ten years ago I asked an astronomer who specializes in IR light from plasmas and gases (nebulae, galactic jets, and the like) what the optical depth (thickness) of the CMBR was, and he said it was about 100 parsecs. That is, all the light we see in the CMBR is from a shell only 100 parsecs (300 light-yers) thick. That is significantly smaller than what was arrived at here in sci.astro, in Jan 2003 (thread Olber's paradox). Tens of million light years was the number then. Maybe new information has come to light? ;) David A. Smith |
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#18
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Dear Jeff Root:
"Jeff Root" wrote in message ups.com... David replied to Jeff: I'd expect a free-falling observer to see infalling light redshifted. The longer the time since crossing the horizon, the greater the redshift. An observer slowing his downward acceleration sufficiently would see infalling light blueshifted. True with expansion. As to how you would reverse time to "slow your downward acceleration"... Expansion? Are you referring to the fact that everything falling into a black hole gets stretched out? No. I am referring to the solution to a Black Hole using Kruskal coordinates in GR. As you propagate towards the singularity (outer Universe), inner space gets larger, just like Universal expansion. Of course, it also gets squeezed in on the sides. An explorer free-falling into a very large black hole would not see anything change at the instant he crossed the event horizon. Not locally, no. But what he would see of the outer Universe would be distorted before he arrived at the event horizon, and would only distort more. As he fell in farther and farther the tide would pull his socks down and make his hair stand on end. Eventually it would pull his feet and head off of his body. Not likely, if a new Universe is formed inside (Kruskal and GR), and your infall direction becomes propagating along your time axis. It wouldn't be necessary to reverse time to slow acceleration. A rocket would still work, although I don't know what direction you would aim it, and of course it wouldn't do much good for very long. It wouldn't work, since you can't stop time for the Universe at large. David A. Smith |
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#19
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"Jeff Root" wrote in message ups.com... George replied to David: Is the "photon historical record" of infalling light through the event horizon isothermal? No, it has the spectrum of whatever stars and external objects produced it only severely blue shifted (depending on the motion of the infalling observer as you said). [Note the parenthetical qualification.] I'd expect a free-falling observer to see infalling light redshifted. A free-falling observer should see red-shift behind and ahead but blue-shift on all sides, a side-effect of 'spaghettification'. My point however was that it would be a shifted view of the original spectrum, there is no mechanism to thermalise what would be seen. The longer the time since crossing the horizon, the greater the redshift. An observer slowing his downward acceleration sufficiently would see infalling light blueshifted. That's what I meant, the closest achievable to hovering just inside the event horizon which is impossible of course. George |
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#20
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"N:dlzc D:aol T:com (dlzc)" N: dlzc1 D:cox wrote in message news:AvzKe.6008$E95.4317@fed1read01... Dear George Dishman: "George Dishman" wrote in message ... "N:dlzc D:aol T:com (dlzc)" N: dlzc1 D:cox wrote in message news:yxdKe.308849$Qo.131840@fed1read01... Dear George Dishman: "George Dishman" wrote in message ... .... ... have you looked at Andrew Hamilton's animations? http://casa.colorado.edu/~ajsh/schw.shtml External objects end up sweeping an arc across the sky. Other objects in other places do the same. Definitely NOT specular images. And this is a non-rotating BH, which adds yet another twist (literally) to the infalling light. And note that in the simulation, the external-Universe stars don't change color. The point is that you can see them, there is nothing at the event horizon but vacuum. It isn't a physical barrier but just a location. You can't "see them". They are no longer point sources, but area sources. Why? Those on Andrew's page are nearby and start as areas (just as we see the Sun) and are then distorted. Distant point sources would surely remain as points, wouldn't they? "Like" the CMBRM. .... Yes. Unfortunately, if outer-r becomes timelike, the entire history of the container Universe is written on the inner Big Bang... at least until the contained Universe evaporates. Anything that ever (outer-time) infalls, arrvies at the inner "Big Bang". I don't believe that is physical though, just an artificial peculiarity of the coordinates Schwarzschild used. Kruskal still has it timelike. It is not a peculiarity, but a requirement. Of course, but isn't the time axis contiguous through the horizon? It was the switch between spatial and temporal that I thought was the artefact. Andrew Hamilton's pages would take such effects into account. Perhaps. Not doubting the abilities, just questioning what a "Universe full of stars" would look like. Go out in your back yard one night ;-) Serously though, why would you expect to see anything different? True but the point was simply that you would still receive photons from outside. Still receive photons is not at issue. Are they specular? No. Are they diffuse? Yes and no. Is the surfaceo-of-last-emission transparent? What surface? The surface of the star that originally emitted the light. Someone well outside the event horizon would see a sky not unlike our own (perhaps brighter if the were in the core of a galaxy). Someone infalling just inside the horizon would see the same but squished into a smaller fraction of the sky with the rest looking devoid of sources. You seem to be saying the whole sky would be illuminated but it should be more like looking through a pinhole lens above you. There is no material to emit at the event horizon, it is a location and all matter is passing it at the speed of light as determined by an observer at infinity (I think!). Not quite. It is a location in *time*, and all matter (and energy) propagate from there. And I understand that you are uncomfortable with this. I am uncomfortable with the idea that there is a physical exchange of axes because I have read many times that it was never real, just a problem with the coordinates, but I can't find useful references and I may be mistaken about which coordinates had and resolved the problem. The kinetic velocities obtained in the new internal space will likely only be sufficient to conserve energy and momentum. Velocity relative to what? Relative to an observer outside the horizon, it is greater than the speed of light (I think). No. Is the "photon historical record" of infalling light through the event horizon isothermal? No, it has the spectrum of whatever stars and external objects produced it only severely blue shifted (depending on the motion of the infalling observer as you said). *Integrated over time*. Why? We only see what is on our past light cone. Is the integral light history of our Universe from formation of a BH, until it evaporates, isothermal? I think it is *to a close approximation*. .... Note I am not entirely diagreeing. I wonder whether primordial black holes could have grown rapidly in such a high density environment that they existed before the mix became transparent and were the seeds of what are now galactic clusters. I think we may lewarn a lot when we can detect Pop III SNe but we will have to wait for at least the next generation of telescopes to come on line. No one currently believes the Universe started out "the size of a grapefruit", Put "grapefruit inflation cosmology" into Google and you will get about 600 hits ;-) It is the conventional view at the moment I believe. http://zebu.uoregon.edu/~imamura/123...lecture-7.html "During inflation, the Universe increases in size by a huge factor -- perhaps by as much as a factor of 10^(10^12)!!! Some models say that the size of the current Universe increased from 10^-50 centimeters to roughly the size of a grapefruit during inflation." The lecture seems contradictory on the period of inflation, saying it started at the end of the era from 10^-43s to 10^-35s and ending at the start of the next period. Anyway, the use of a grapefruit to illustrate the size wasn't my idea! unless they also posit "c_BB c_now". You "helped establish" the CMBRM was many tens of million light years thick, only ~300,000 years after the BB, based on the (lack of) spectra. You can't get that big from a point (essentially) in that time. Or am I misunderstanding again? You are misunderstanding something but this has moved on so I'll reply to a later post. The simple answer is that GR says there was no container and the density was far too high to see through it anyway when you go back far enough. The "surface of last scattering" is a feature of the gas _in_ the universe and a black hole has nothing equivalent. GR *does* allow description of a container, It does allow it for a black hole but not for the big bang AIUI. The big bang is closer to a white hole in GR. but it is a description you are not comfortable with. No it was your switching of teporal and spatial axes that I doubt. The inside of the event horizon is the only spatial location in the newly minted space from which the light could have come, so is therefore opaque. And you are reciting the established/accepted source of the CMBR, that does not obviate an alternate choice of sources *fully in compliance with GR*. GR says the event horizon is just a place in the vacuum so it allows light to pass inwards freely. Light could also pass outwards execpt that any source inside is moving away from an external observer faster than the speed of light so it cannot reach them, the light falls inwards even if emitted in an outwards direction. I am saying that the horizon isn't opaque and I don't know why you are suggesting it would be. GR doesn't require that the CMBRM be Universe filling gas, unless gas is the source. GR doesn't provide a source for the CMBR of any kind, you need matter to produce it. The source could be a container Universe, depending on the answer to my question to Tom. If there were a container then the source could be the matter in the container universe in which case the light would have falling in through the horizon. That is quite different to saying it was the horizon that produced the light or that the horizon is opaque and could in some way thermalise the spectrum of the stars in the container. Even so, it could be a way to resolve the age of the Universe that contains us, since only certain light profiles could result in what we see. Or not. I'm not sure what you are trying to resolve, the age appears to be 13.7 billion years. As I have said, my "hypothesis" allows for structures to be found right up to the CMBRM, even for heavier elements to be present from the "get go". And since infalling light is not fatally blue shifted for those that are "falling towards the singularity", the CMBRM is not necessary to have protected us from the "fires of creation". I don't follow, if we were falling towards a singularity, the universe would be shrinking. No. The outer r becomes inner t. I don't accept that, I believe it was found to be an artefact of the maths only. I will be happy if you can show me to be wrong though. The outer Universe "expects us" to become more and more dense. We have internal-space that is orthogonal to our time. This space is defined by c and time. The speed of light (as expected by the outer Universe) is an inverse function of density. As we approach a singularity (from outer reconing), c approaches 0 (as the outer Universe expects, Pardon? c is invariant in GR locally. The outer universe sees increasing time dialtion but that doesn't change c. I'm realy not following what you are saying here at all. not as we would observe), and space becomes larger and larger. Viola! Expansion. The problem is the "discontinuity" that occurs at the event horizon, and the confusion between inner and outer coordinates that results. But that is just a description problem (eg: non-standard verbage is required). Or better coordinates! I also don't agree with the infalling light being necessarily fatal. I wasn't really saying that earlier. I wasn't sure what you meant by: I can't be sure what we would have seen had it not existed, but then we wouldn't be here to see anything. ... perhaps that there would be no matter for us to be comprised of... Yes, that was it. What the universe would look like if it contained no matter whatsoever is moot! This is where I diverge with Bjoern. He believes you can have a Universe without matter. You can solve the equations for that condition, but we wouldn't be in it. But Einstein suggests that spacetime is the product of all mass-energy in the Universe (if I understand correctly). This means no mass/energy provides null spacetime. It is partly philosophical, what does it mean to calculate the trajectory of a test paticle in a universe devoid of particles ;-) Given a Universe, you have mass/energy. Given mass/energy, you have spacetime. That seems more relevant to our situation. That was my point, even after crossing the event horizon, you would still be able to see the part of the universe you had left hence the horizon cannot be opaque. There is no part of the external Universe that extends into the internal Universe. What you see, perhaps, is all the positions and all the intensities of all the stars, and the container Universe's CMBR, spread across 2 pi steradians... for all time. Neglecting expansion, which only serves to red shift the panopoly. It *is* opaque, it is NOT specular. You cannot see before the Big Bang, even without a CMBRM. But you would in what you describe, you would be seeing "all the stars" in the container Universe, the horizon would only be a location in the vacuum. Only as a plenum. The "off ramp" is all you can see, with the CMBR as the "sound of car horns" on a freeway to which we are but a side road. It would have to be seeing the lights of cars coming down the off ramp. Even from a great distance where the individual lights cannot be distinguished, the integrated spectrum would be a blend of many thermal curves but at different temperatures (types of bulbs) and that mix wouldn't be thermal itself. Structures can infall into large black holes and survive... probably not gravitationally bound ones, but who knows. Maybe the nature of the early Universe actually tells us how steep the off ramp is (namely something about how many of the four forces yield to the curvature of the event horizon). for a very large black hole, the acceleration at the horizon is negligible. I believe a human in a spacesuit could easily survive crossing the horizon of a super-massive BH with nothing more than a spacesuit. George |
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