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#101
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Dear George Dishman:
"George Dishman" wrote in message ... "N:dlzc D:aol T:com (dlzc)" N: dlzc1 D:cox wrote in message news:4p2Ye.256955$E95.192022@fed1read01... Dear George Dishman: "George Dishman" wrote in message ... "N:dlzc D:aol T:com (dlzc)" N: dlzc1 D:cox wrote in message news:3QKXe.253945$E95.216149@fed1read01... "George Dishman" wrote in message ... ... just snipping header a bit... I'll snip the experiment, we can always look back. .... If I draw a line from me to you and project it some tens of billions of light years, way off in the distance there is an alien for whom you are moving slightly less than c due to cosmological expansion while I am moving slightly faster than c. Does that mean you and I are in different universes? Superlumenal scissors. No. No, superluminal scissors is not related, this was an alien in a fixed distant galaxy. Perhaps if I had used the Andromeda galaxy and our it would have been clearer. I am talking simply of the observed expansion of the universe. OK. A distant observer look back at our region and sees a red patch in the CMBR which will later become the Virgo cluster. The Andromeda galaxy is sufficiently close to his location that light emitted 'now' will reach that observer billions of years from now. It will take a long time because initially he sees that galaxy moving away from him at nearly the speed of light. However light from our galaxy will never reach him because we are a little farther away and hence we are moving "faster than c" relative to him. Okay, it's loose wording to talk of movement, really the space between Andromeda and him is expanding at the rates I indicate but I'm sure you get the point, that we and the Andromeda galaxy are not in separate universes just because some distant alien sees an event horizon between us. Can you prove that? I'm not trying to be a ball buster, but if you cannot *ever* measure something, it is neither in your future, nor your present, does it have any effect on you? That is how two people in my 3m radius lab would view the 'observer at infinity' and his claim that a point half way between them was "falling at c". Yet said alien would receive light from us, and we could receive from him (given sufficent time). He would receive light from you but space is expanding so fast that he can never receive light from me, I'm just that little bit farther away. OK. .... a) The lab is sitting on the surface of the Earth and the lower mirror is level with the surface of the Earth. Parallel. Not as exciting as "falling at c"... Light going from source to upper mirror will be red shifted as in Pound-Rebka but after reflection it is blue shifted by an equal amount so a frequency change is not detected. This is very poor wording, IMO. It was phenomenologically worded. We observe a frequency shift without assuming a specific mechanism. However, I'll correct that below! The light emitted is characeristic of the process that emitted it and the location of the process in curved space at the time of emission. Oh dear. No, frequency of the light measured locally is characteristic of the process, period. Note where I said "location of the process in curved space". This means *not* local. See next. Since we cannot steal some energy from a photon, then the photon does not change on the trip "up and down"... only the clocks, that decide what the frequency is, change. Not in SR or GR, you are describing aether theory. Yes, in GR, and in QM. You cannot alter a photon, except by absorbing or scattering it. "Position in a gravity well" is meaningless to a photon. I don't know about what aether theory would predict, and I don't claim to. Let's correct the wording in relation to Pound-Rebka. An atom at the bottom of their tower produced light of a characteristic frequency. Considering one cycle, it has a well defined period. The atom's proper time is measured as always along the tangent to its worldline (4-velocity) so consider a vector in that direction of length equal to the period. Now parallel-transport that along a null (light-like) geodesic to the mirror or in the case of Pound-Rebka to the reference atom at the top of the tower. Because of the curvature, this transported vector is not parallel to the 4-velocity of the upper atom. .... and hence the apparent "frequency change". Project the transported vector onto the worldline of the atom and it does not match the period of the local atom, in other words it exhibits a 'red shift'. Which is not altering the light, only acknowledging the variance in curvature at the two *non-local* endpoints. (Neglecting differential motion between the emitting process and the observer's instruments, of course.) Any differential motion adds to the angle between the transported vector from the lower atom and the tangent to the worldline of the upper atom. Adds or *subtracts*, yes. Just correlate the observations with GPS-vs-ground clocks to light emitting processes. Two factors, one due to gravity and one due to the orbital speed, exactly as described above. Yet the characteristic process indicates a different "time base" at different altitudes. Hence Shapiro time delay. Or type II supernovae spectra to supervonvae duration. I think you mean type Ia. Probably. But I have "6200 ly" down pat! ;) This is more interesting. If you parallel transport a unit time vector *v*/|v| where *v* is the 4-velocity of the CoM from the source to the observer along a light-like path, the result is at a significant angle to our local 4-velocity due to curvature hence is 'gravitational red shift'. However over short distances one can extend the local coordinate patch to nearby SNe and the angle can then be thought of as 'motion of the SNe'. "Motion" as Ned Wright has presented, OK. Yet it is still "only" characteristic of the relative positions (and yes kinetic velocities) of the emitters and receiver in curved space. I think there would be a very slight Shapiro delay hence the vertical height might not be quite the same as the horizontal width but I'm not sure if that too would cancel out. It is exactly equal to the detected red shift. The delay would need be the integral of the shift over the path to get the units right. Good point. The next question may shed some light on this. The acceleration of gravity varies between lower and upper as r^-2 from the centre of the Earth but this is not evident as the profile remains constant throughout the duration of the experiment. 3m is still pretty small. Send a signal to the altitude of GPS and transpond it back (without an onboard shift) and you get the same frequency you sent. The gravitational effects cancel. (I'm glossing over the speed effect.) No issues. It is not the fact that 3m is small but that everything is exactly reversed on the way back down. More clear is to say the at the emitting clock is not affected by the path the reflected photon took. Since the photon's frequency is unaffected by the path (other than deflection of vector, and possible boosting by frame dragging). b) The lab is on a ship in deep space which is undergoing constant acceleration as measured by an accelerometer on the ship. .... no inertial frames in GR so would there be measurable length contraction vertically? Yes. But not for our "too small to detect system". If so could the observer attribute it to Shapiro delay? Yes, and correctly so, I believe. For a different observer. For the observer at the centre. The effect applies in his frame when the photon is at some distance from him. It is very slight but integrated over the path could be comparable to any length effect. I disagree. I suspect, but don't know without doing the math, that given sufficient resolution, the observer will appear to simply "shift away from center" towards the "gravitational source". Not really length contraction... since one axis should "symmetrically" get longer. BTW these aren't rhetorical questions, I don't know the answers myself yet but I intend to find out if I can. OK. I think we agree, but we might both be wrong. Nah! ;) c) The lab is freefalling frame into a mine having been dropped from a high crane and event '2' occurs when the lower mirror is level with the surface of the Earth. The curvature is still present, and increasing slightly for some distance down, before it levels out. The "curvature penalty" is permanent. Clocks don't run faster deeper in. The light going from source to upper mirror is red shifted as in Pound-Rebka. The base process is "red shifted", rather. Not according to SR/GR, it is a system effect rather than local to either end. The base process is changed by an interaction with the aether in LET. In LET (I believe) as in SR/GR, it is still a system effect, since both the emitter and receiver are immersed in aether that controls "local" processes/measurements. I was not as clear as I should have been. Sorry. It is also blue shifted while returning to the detector however the lab has fallen some distance so on the return the gravitational acceleration is greater so there will be a net blue shift. This allows the tidal force to be measured even in a freefall condition. Do you agree? Not if 3m is "too small to detect". Well yes, I am saying that there is a blue shift in question c) where there is none in questions a) and b) which allows it to be distinguished assuming your can measure such a small quantity. Pound-Rebka used 22.5m so my 3m isn't unreasonable. .... as long as you aren't falling into a black hole, with a short finite time before impacting at a "central singularity". Pound-Rebka accumulated counts over a (relatively) long period of time to achieve a measureable result. .... You are right, a sensitive spectrometer could do that but it still produces only a minimal change to the distance measurement (if any). IMHO I can still claim the roof and floor are in the same universe during the measurement. As long as the roof and floor are interchanging light, this would be a valid claim. OK, that was where I wanted to get to. I finally did the diagram for an inertial lab, just SR: http://www.georgedishman.f2s.com/david/in_the_lab.png Waaaaay, too much time on your hands! ;) I have also shown a couple of past/future light cones in green. The colours just let you distinguish the light going to the upper (red) and lower (blue) mirrors. They mimic the shift that would be observed at the mirrors but aren't intended to mean anything, just to clarify that the beams aren't crossing the centre. And even if they were, they would still be red or blue shifted when detected on that side. The 'deliberate mistake I mentioned was that strictly it would be better to bound the region classed as 'in the same universe' by the past lightcone of the first reception and the future lightcone of the final transmission so that it includes only the crosshatched area where we have two-way light propagation at every event but that is academic for our purposes. But something to consider carefully if one is to construct a homogenous solution "from whole cloth". If this was plotted by an observer moving at constant speed past the lab, it should be clear that you would get a picture like the "Rocket Frame" diagram on the same page (112) of T&W. OK. Now consider what happens if that is drawn for a free falling lab as in my question c). Since curvature cannot be removed, the central line for the observer must become curved and if the lab structure is rigid in the sense of no measurable strain due to the tidal forces then the mirror worldlines would run almost parallel to that of the observer (not quite parallel due to rotation of the spatial axis - at a constant distance). Agreed. Keep in mind that aether cannot be killed, so dual interchange of light will be required "to be in the same Universe". What aether? I am talking GR and I thought you were too, I have no interest in aether theories. "The laws of physics are the same for all inertial observers." Aether cannot be killed in any inertial frame. .... Anyway, I meant we were the students trying to figure out what the experts are telling us. I hope that's OK with you. Absolutely. I never got into D&D, but role playing can be instructive. Press on. Two students, and the professor has simply left clues in "strange" places. Ok, the next instalment is applying our agreement on the 'same universe' test to a free-falling lab and the next will be that as seen by an observer falling at constant speed in the gravitational field. The step after that should get us back to the web pages. Sounds good. I've got to get to an "integration surface", which hopefully is similar for sources near (eg. infalling matter colliding with an accretion disk) and far. David A. Smith |
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#102
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"Jeff Root" wrote in message ups.com... Seems to me the analogy using Andromeda has the same problem as that using two points on Earth, because Andromeda and the Milky Way are moving closer together, not moving apart. I certainly agree with the point, though. No, the problem was that a line through Sussex and Arizona rotates once a day while that through the Milky Way to Andromeda is in a stable direction hence David was concerned about "superluminal scissors" since the rotation of the line can be likened to the rotation of a blade. http://math.ucr.edu/home/baez/physic.../scissors.html The fact that the separation is reducing isn't a problem, there can still be a hypothetical observer for whom accelerating cosmological expansion gives an event horizon half way between the galaxies. George |
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#103
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"N:dlzc D:aol T:com (dlzc)" N: dlzc1 D:cox wrote in message news:jxoYe.261460$E95.141026@fed1read01... Dear George Dishman: "George Dishman" wrote in message ... "N:dlzc D:aol T:com (dlzc)" N: dlzc1 D:cox wrote in message news:4p2Ye.256955$E95.192022@fed1read01... Dear George Dishman: "George Dishman" wrote in message ... "N:dlzc D:aol T:com (dlzc)" N: dlzc1 D:cox wrote in message news:3QKXe.253945$E95.216149@fed1read01... "George Dishman" wrote in message ... ... just snipping header a bit... A distant observer look back at our region and sees a red patch in the CMBR which will later become the Virgo cluster. The Andromeda galaxy is sufficiently close to his location that light emitted 'now' will reach that observer billions of years from now. It will take a long time because initially he sees that galaxy moving away from him at nearly the speed of light. However light from our galaxy will never reach him because we are a little farther away and hence we are moving "faster than c" relative to him. Okay, it's loose wording to talk of movement, really the space between Andromeda and him is expanding at the rates I indicate but I'm sure you get the point, that we and the Andromeda galaxy are not in separate universes just because some distant alien sees an event horizon between us. Can you prove that? Not without contacting an alien observer and asking hime :-( I'm not trying to be a ball buster, but if you cannot *ever* measure something, it is neither in your future, nor your present, does it have any effect on you? That's not the point. We can measure light from the Andromeda galaxy with no problem, and also from other galaxies in the opposite direction. That is how two people in my 3m radius lab would view the 'observer at infinity' and his claim that a point half way between them was "falling at c". Yet said alien would receive light from us, and we could receive from him (given sufficent time). He would receive light from you but space is expanding so fast that he can never receive light from me, I'm just that little bit farther away. OK. Well that is the meaning of "event horizon". Events can happen in the same universe as us but we may not be able to ever receive light from them. ... a) The lab is sitting on the surface of the Earth and the lower mirror is level with the surface of the Earth. Parallel. Not as exciting as "falling at c"... Light going from source to upper mirror will be red shifted as in Pound-Rebka but after reflection it is blue shifted by an equal amount so a frequency change is not detected. This is very poor wording, IMO. It was phenomenologically worded. We observe a frequency shift without assuming a specific mechanism. However, I'll correct that below! The light emitted is characeristic of the process that emitted it and the location of the process in curved space at the time of emission. Oh dear. No, frequency of the light measured locally is characteristic of the process, period. Note where I said "location of the process in curved space". This means *not* local. I don't tread it that way, "location of the process" refers to the one location where the atom is situated when it was involved in the process of emitting the photon. It's my turn to say "This is very poor wording, IMO." See next. Since we cannot steal some energy from a photon, then the photon does not change on the trip "up and down"... only the clocks, that decide what the frequency is, change. Not in SR or GR, you are describing aether theory. Yes, in GR, and in QM. You cannot alter a photon, except by absorbing or scattering it. You don't "alter a photon" when receiving it on a moving detector yet the Doppler effect alters the frequency. However, I wasn't talking about the photon. You said "the photon does not change on the trip ... only the clocks" but according to GR good clocks are not directly affected as they would be in aether theory. "Position in a gravity well" is meaningless to a photon. I don't know about what aether theory would predict, and I don't claim to. Lorentzian aether theory says clocks run slow if they are in motion through the aether. Let's correct the wording in relation to Pound-Rebka. An atom at the bottom of their tower produced light of a characteristic frequency. Considering one cycle, it has a well defined period. The atom's proper time is measured as always along the tangent to its worldline (4-velocity) so consider a vector in that direction of length equal to the period. Now parallel-transport that along a null (light-like) geodesic to the mirror or in the case of Pound-Rebka to the reference atom at the top of the tower. Because of the curvature, this transported vector is not parallel to the 4-velocity of the upper atom. ... and hence the apparent "frequency change". which is what I said next: Project the transported vector onto the worldline of the atom and it does not match the period of the local atom, in other words it exhibits a 'red shift'. Which is not altering the light, only acknowledging the variance in curvature at the two *non-local* endpoints. That's right, GR says gravitational potential doesn't influence the emitting or detecting processes, it is the relationship between the ends (integrated curvature if I have it right) that produces the effects. (Neglecting differential motion between the emitting process and the observer's instruments, of course.) Any differential motion adds to the angle between the transported vector from the lower atom and the tangent to the worldline of the upper atom. Adds or *subtracts*, yes. I assumed you were happy with signed numbers ;-) Just correlate the observations with GPS-vs-ground clocks to light emitting processes. Two factors, one due to gravity and one due to the orbital speed, exactly as described above. Yet the characteristic process indicates a different "time base" at different altitudes. "time base" is not a standard term so I have to guess what you mean. The "time bases" are not different in that an atomic transition gives the same frequency in terms of proper time of the atom. It is the angle between one and the other after parallel transport that produces the effect. Hence Shapiro time delay. Or type II supernovae spectra to supervonvae duration. I think you mean type Ia. Probably. But I have "6200 ly" down pat! ;) This is more interesting. If you parallel transport a unit time vector *v*/|v| where *v* is the 4-velocity of the CoM from the source to the observer along a light-like path, the result is at a significant angle to our local 4-velocity due to curvature hence is 'gravitational red shift'. However over short distances one can extend the local coordinate patch to nearby SNe and the angle can then be thought of as 'motion of the SNe'. "Motion" as Ned Wright has presented, OK. Yes, just "motion" in the normal sense. Yet it is still "only" characteristic of the relative positions (and yes kinetic velocities) of the emitters and receiver in curved space. Right. I think there would be a very slight Shapiro delay hence the vertical height might not be quite the same as the horizontal width but I'm not sure if that too would cancel out. It is exactly equal to the detected red shift. The delay would need be the integral of the shift over the path to get the units right. Good point. Just nitpicking again. The next question may shed some light on this. The acceleration of gravity varies between lower and upper as r^-2 from the centre of the Earth but this is not evident as the profile remains constant throughout the duration of the experiment. 3m is still pretty small. Send a signal to the altitude of GPS and transpond it back (without an onboard shift) and you get the same frequency you sent. The gravitational effects cancel. (I'm glossing over the speed effect.) No issues. It is not the fact that 3m is small but that everything is exactly reversed on the way back down. More clear is to say the at the emitting clock is not affected by the path the reflected photon took. Since the photon's frequency is unaffected by the path (other than deflection of vector, and possible boosting by frame dragging). I think that's actually less clear. For example "photon's frequency" sounds like some intrinsic attribute but like kinetic energy frequency is only meaningful so a specific observer. Also, in later examples where the frequency is affected, there is still no effect on "the emitting clock". It is purely a path thing. b) The lab is on a ship in deep space which is undergoing constant acceleration as measured by an accelerometer on the ship. ... no inertial frames in GR so would there be measurable length contraction vertically? Yes. But not for our "too small to detect system". If so could the observer attribute it to Shapiro delay? Yes, and correctly so, I believe. For a different observer. For the observer at the centre. The effect applies in his frame when the photon is at some distance from him. It is very slight but integrated over the path could be comparable to any length effect. I disagree. I suspect, but don't know without doing the math, that given sufficient resolution, the observer will appear to simply "shift away from center" towards the "gravitational source". Not really length contraction... since one axis should "symmetrically" get longer. I was using 'centre' perhaps a little loosely just to identify which observer, good nitpick. BTW these aren't rhetorical questions, I don't know the answers myself yet but I intend to find out if I can. OK. I think we agree, but we might both be wrong. Nah! ;) c) The lab is freefalling frame into a mine having been dropped from a high crane and event '2' occurs when the lower mirror is level with the surface of the Earth. The curvature is still present, and increasing slightly for some distance down, before it levels out. The "curvature penalty" is permanent. Clocks don't run faster deeper in. The light going from source to upper mirror is red shifted as in Pound-Rebka. The base process is "red shifted", rather. Not according to SR/GR, it is a system effect rather than local to either end. The base process is changed by an interaction with the aether in LET. In LET (I believe) as in SR/GR, it is still a system effect, since both the emitter and receiver are immersed in aether that controls "local" processes/measurements. I was not as clear as I should have been. Sorry. No that is still wrong. In aether theory, the emitter is slowed by speed relative to the aether (characterised by the usual gamma function) due to some unexplained interaction at the atomic level. The same happens to any clock measuring it but there is no change along the path. In SR there is no interaction because there is no aether so processes are unaltered and the effects are due to curvature along the path. There is no curvature in LET. It is also blue shifted while returning to the detector however the lab has fallen some distance so on the return the gravitational acceleration is greater so there will be a net blue shift. This allows the tidal force to be measured even in a freefall condition. Do you agree? Not if 3m is "too small to detect". Well yes, I am saying that there is a blue shift in question c) where there is none in questions a) and b) which allows it to be distinguished assuming your can measure such a small quantity. Pound-Rebka used 22.5m so my 3m isn't unreasonable. ... as long as you aren't falling into a black hole, with a short finite time before impacting at a "central singularity". Pound-Rebka accumulated counts over a (relatively) long period of time to achieve a measureable result. We just need quicker tools which are always available in thought experiments. However, perhaps you would like to work out how long (proper time of course) it takes from the event horizon to the centre for a black hole large enough to have a 1g acceleration at the horizon. You are right, a sensitive spectrometer could do that but it still produces only a minimal change to the distance measurement (if any). IMHO I can still claim the roof and floor are in the same universe during the measurement. As long as the roof and floor are interchanging light, this would be a valid claim. OK, that was where I wanted to get to. I finally did the diagram for an inertial lab, just SR: http://www.georgedishman.f2s.com/david/in_the_lab.png Waaaaay, too much time on your hands! ;) I have also shown a couple of past/future light cones in green. The colours just let you distinguish the light going to the upper (red) and lower (blue) mirrors. They mimic the shift that would be observed at the mirrors but aren't intended to mean anything, just to clarify that the beams aren't crossing the centre. And even if they were, they would still be red or blue shifted when detected on that side. The 'deliberate mistake I mentioned was that strictly it would be better to bound the region classed as 'in the same universe' by the past lightcone of the first reception and the future lightcone of the final transmission so that it includes only the crosshatched area where we have two-way light propagation at every event but that is academic for our purposes. But something to consider carefully if one is to construct a homogenous solution "from whole cloth". If this was plotted by an observer moving at constant speed past the lab, it should be clear that you would get a picture like the "Rocket Frame" diagram on the same page (112) of T&W. OK. Now consider what happens if that is drawn for a free falling lab as in my question c). Since curvature cannot be removed, the central line for the observer must become curved and if the lab structure is rigid in the sense of no measurable strain due to the tidal forces then the mirror worldlines would run almost parallel to that of the observer (not quite parallel due to rotation of the spatial axis - at a constant distance). Agreed. Good stuff, I think we are making progress so I'll go straight to the hard part. Try taking the sketch I drew above and distort it sideways as in the two diagrams in T&W it so that the central source/ detector line is the worldline of the infalling observer shown in the spacetime diagrams on this page http://www.phy.syr.edu/courses/modul...arzschild.html Clearly a problem arises when the final detection is at the singularity but I cannot see any reason why the pattern should not extend across the event horizon. Bear in mind the scale, the diamonds in my sketch are 3m while the distance from the horizon to the singularity is vastly larger. Keep in mind that aether cannot be killed, so dual interchange of light will be required "to be in the same Universe". What aether? I am talking GR and I thought you were too, I have no interest in aether theories. "The laws of physics are the same for all inertial observers." "inertial observers" is problematic but I'll go with the principle of equivalence. Aether cannot be killed in any inertial frame. True, since an aether doesn't exist in the first place, at least not when we are learning GR. Anyway, I meant we were the students trying to figure out what the experts are telling us. I hope that's OK with you. Absolutely. I never got into D&D, but role playing can be instructive. Press on. Two students, and the professor has simply left clues in "strange" places. Ok, the next instalment is applying our agreement on the 'same universe' test to a free-falling lab and the next will be that as seen by an observer falling at constant speed in the gravitational field. The step after that should get us back to the web pages. Sounds good. I've got to get to an "integration surface", which hopefully is similar for sources near (eg. infalling matter colliding with an accretion disk) and far. Actually I've gone on the web page as we seem to be agreeing the important stuff. I have no idea why you keep referring to aether though. George |
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#104
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Dear George Dishman:
"George Dishman" wrote in message ... "N:dlzc D:aol T:com (dlzc)" N: dlzc1 D:cox wrote in message news:jxoYe.261460$E95.141026@fed1read01... Dear George Dishman: "George Dishman" wrote in message ... "N:dlzc D:aol T:com (dlzc)" N: dlzc1 D:cox wrote in message news:4p2Ye.256955$E95.192022@fed1read01... Dear George Dishman: "George Dishman" wrote in message ... "N:dlzc D:aol T:com (dlzc)" N: dlzc1 D:cox wrote in message news:3QKXe.253945$E95.216149@fed1read01... "George Dishman" wrote in message ... ... just snipping header a bit... A distant observer look back at our region and sees a red patch in the CMBR which will later become the Virgo cluster. The Andromeda galaxy is sufficiently close to his location that light emitted 'now' will reach that observer billions of years from now. It will take a long time because initially he sees that galaxy moving away from him at nearly the speed of light. However light from our galaxy will never reach him because we are a little farther away and hence we are moving "faster than c" relative to him. Okay, it's loose wording to talk of movement, really the space between Andromeda and him is expanding at the rates I indicate but I'm sure you get the point, that we and the Andromeda galaxy are not in separate universes just because some distant alien sees an event horizon between us. Can you prove that? Not without contacting an alien observer and asking [him] :-( ... which we stated cannot occur. I caution you in analogies involving expansion with the EH of a black hole. Note that light-based information can go one way across the event horizon of a black hole, but *neither way* across the entire span between source and emitter once over an "expansion horizon". I'm not trying to be a ball buster, but if you cannot *ever* measure something, it is neither in your future, nor your present, does it have any effect on you? That's not the point. We can measure light from the Andromeda galaxy with no problem, and also from other galaxies in the opposite direction. So the Andromeda galaxy is in our Universe, but the question is, is the alien? Light from the CMBRM is in our Universe, but likely, some/most of the corresponding substance is no longer within our "horizon". That is how two people in my 3m radius lab would view the 'observer at infinity' and his claim that a point half way between them was "falling at c". Yet said alien would receive light from us, and we could receive from him (given sufficent time). He would receive light from you but space is expanding so fast that he can never receive light from me, I'm just that little bit farther away. OK. Well that is the meaning of "event horizon". Events can happen in the same universe as us but we may not be able to ever receive light from them. The reason the term was coined, is because those events are *not* part of our experience. In other words "event" is "coordinate", and "coordinate" defines spacetime. No events, no ability to define spacetime, no effect on spacetime, not *in* spacetime... except as a "boundary condition". The boundary being the event horizon. ... a) The lab is sitting on the surface of the Earth and the lower mirror is level with the surface of the Earth. Parallel. Not as exciting as "falling at c"... Light going from source to upper mirror will be red shifted as in Pound-Rebka but after reflection it is blue shifted by an equal amount so a frequency change is not detected. This is very poor wording, IMO. It was phenomenologically worded. We observe a frequency shift without assuming a specific mechanism. However, I'll correct that below! The light emitted is characeristic of the process that emitted it and the location of the process in curved space at the time of emission. Oh dear. No, frequency of the light measured locally is characteristic of the process, period. Note where I said "location of the process in curved space". This means *not* local. I don't [read] it that way, "location of the process" refers to the one location where the atom is situated when it was involved in the process of emitting the photon. It's my turn to say "This is very poor wording, IMO." Let's put the context back in... The light emitted is characeristic of the process that emitted it and the location of the process in curved space at the time of emission. Since we cannot steal some energy from a photon, then the photon does not change on the trip "up and down"... only the clocks, that decide what the frequency is, change. I then brought up the GPS. *I* think I was clear, in the context I wrote. But of course the context was disassembled. So one sentence chewed on twice, loses some of its flavor. I'll try not to do that to you. See next. Since we cannot steal some energy from a photon, then the photon does not change on the trip "up and down"... only the clocks, that decide what the frequency is, change. Not in SR or GR, you are describing aether theory. Yes, in GR, and in QM. You cannot alter a photon, except by absorbing or scattering it. You don't "alter a photon" when receiving it on a moving detector yet the Doppler effect alters the frequency. The Doppler effect describes one component of a frequency shift, yes. Nothing is altered between the observer and the photon by motion, since it arrives at c regardless. What is altered by proper or kinetic motion is your relationship with the emitter (and the underlying process). However, I wasn't talking about the photon. You said "the photon does not change on the trip ... only the clocks" but according to GR good clocks are not directly affected as they would be in aether theory. GPS has "two components"... the dice roll again? Even good clocks *are* directly affected by their position in curved space, compared to a different clock at a different "elevation". They are however only reporting/recording the correct passage of time in that location/position. "Position in a gravity well" is meaningless to a photon. I don't know about what aether theory would predict, and I don't claim to. Lorentzian aether theory says clocks run slow if they are in motion through the aether. And Ilja would likely also have the relationship to collections of mass similarly affect "local clock rate". But I cannot get my head around it, which is why I did not know what its predictions would be where gravity was concerned. Let's correct the wording in relation to Pound-Rebka. An atom at the bottom of their tower produced light of a characteristic frequency. Considering one cycle, it has a well defined period. The atom's proper time is measured as always along the tangent to its worldline (4-velocity) so consider a vector in that direction of length equal to the period. Now parallel-transport that along a null (light-like) geodesic to the mirror or in the case of Pound-Rebka to the reference atom at the top of the tower. Because of the curvature, this transported vector is not parallel to the 4-velocity of the upper atom. ... and hence the apparent "frequency change". which is what I said next: Project the transported vector onto the worldline of the atom and it does not match the period of the local atom, in other words it exhibits a 'red shift'. Which is not altering the light, only acknowledging the variance in curvature at the two *non-local* endpoints. That's right, GR says gravitational potential doesn't influence the emitting or detecting processes, it is the relationship between the ends (integrated curvature if I have it right) that produces the effects. Sounds right. (Neglecting differential motion between the emitting process and the observer's instruments, of course.) Any differential motion adds to the angle between the transported vector from the lower atom and the tangent to the worldline of the upper atom. Adds or *subtracts*, yes. I assumed you were happy with signed numbers ;-) Well, with "vector", I'd have to be, now wouldn't I? Vector subtraction isn't really defined directly... Well duh! Just correlate the observations with GPS-vs-ground clocks to light emitting processes. Two factors, one due to gravity and one due to the orbital speed, exactly as described above. Yet the characteristic process indicates a different "time base" at different altitudes. "time base" is not a standard term so I have to guess what you mean. The "time bases" are not different in that an atomic transition gives the same frequency in terms of proper time of the atom. It is the angle between one and the other after parallel transport that produces the effect. Right. My intention was not the velocity-term of GPS, but the "elevation in a gravity field". Hence Shapiro time delay. Or type II supernovae spectra to supervonvae duration. I think you mean type Ia. Probably. But I have "6200 ly" down pat! ;) This is more interesting. If you parallel transport a unit time vector *v*/|v| where *v* is the 4-velocity of the CoM from the source to the observer along a light-like path, the result is at a significant angle to our local 4-velocity due to curvature hence is 'gravitational red shift'. However over short distances one can extend the local coordinate patch to nearby SNe and the angle can then be thought of as 'motion of the SNe'. "Motion" as Ned Wright has presented, OK. Yes, just "motion" in the normal sense. Not just motion in the normal sense. In the normal sense, we have motion wrt the Universe of about 300 km/sec. Expansion of space did not involve thrusters, or changing kinetic energy (of us or other objects) to acheive recession velocities of nearly c. "Normal" perhaps because you consider it everyday, but not "normal" to the average Joe. Yet it is still "only" characteristic of the relative positions (and yes kinetic velocities) of the emitters and receiver in curved space. Right. We are spending a lot of time talking past each other. Lets move on, unless you have quibbles with what I've said up to here. I think there would be a very slight Shapiro delay hence the vertical height might not be quite the same as the horizontal width but I'm not sure if that too would cancel out. It is exactly equal to the detected red shift. The delay would need be the integral of the shift over the path to get the units right. Good point. Just nitpicking again. Necessary. The next question may shed some light on this. The acceleration of gravity varies between lower and upper as r^-2 from the centre of the Earth but this is not evident as the profile remains constant throughout the duration of the experiment. 3m is still pretty small. Send a signal to the altitude of GPS and transpond it back (without an onboard shift) and you get the same frequency you sent. The gravitational effects cancel. (I'm glossing over the speed effect.) No issues. It is not the fact that 3m is small but that everything is exactly reversed on the way back down. More clear is to say the at the emitting clock is not affected by the path the reflected photon took. Since the photon's frequency is unaffected by the path (other than deflection of vector, and possible boosting by frame dragging). I think that's actually less clear. For example "photon's frequency" sounds like some intrinsic attribute but like kinetic energy frequency is only meaningful so a specific observer. Yet "everything is reversed on the way back down" is clearly wrong, since nothing intrinsic to the photon is altered by simply moving through on a short two-way path through curved space. Only a choice of "endpoints" yields "redshift" or "blueshift". Also, in later examples where the frequency is affected, there is still no effect on "the emitting clock". It is purely a path thing. The "end points on the path" thing yes. A path thing alone, no. Witness Einstein rings. Quite a different path, and through highly curved space, yet the endpoints are the same, so the observation is unsurprising. b) The lab is on a ship in deep space which is undergoing constant acceleration as measured by an accelerometer on the ship. ... no inertial frames in GR so would there be measurable length contraction vertically? Yes. But not for our "too small to detect system". If so could the observer attribute it to Shapiro delay? Yes, and correctly so, I believe. For a different observer. For the observer at the centre. The effect applies in his frame when the photon is at some distance from him. It is very slight but integrated over the path could be comparable to any length effect. I disagree. I suspect, but don't know without doing the math, that given sufficient resolution, the observer will appear to simply "shift away from center" towards the "gravitational source". Not really length contraction... since one axis should "symmetrically" get longer. I was using 'centre' perhaps a little loosely just to identify which observer, good nitpick. I think that the heart of the matter lies in what, and how, this is modelled. I think your finger is on the pulse. Good thinking! BTW these aren't rhetorical questions, I don't know the answers myself yet but I intend to find out if I can. OK. I think we agree, but we might both be wrong. Nah! ;) c) The lab is freefalling frame into a mine having been dropped from a high crane and event '2' occurs when the lower mirror is level with the surface of the Earth. The curvature is still present, and increasing slightly for some distance down, before it levels out. The "curvature penalty" is permanent. Clocks don't run faster deeper in. The light going from source to upper mirror is red shifted as in Pound-Rebka. The base process is "red shifted", rather. Not according to SR/GR, it is a system effect rather than local to either end. The base process is changed by an interaction with the aether in LET. In LET (I believe) as in SR/GR, it is still a system effect, since both the emitter and receiver are immersed in aether that controls "local" processes/measurements. I was not as clear as I should have been. Sorry. No that is still wrong. In aether theory, the emitter is slowed by speed relative to the aether (characterised by the usual gamma function) due to some unexplained interaction at the atomic level. The same happens to any clock measuring it but there is no change along the path. In SR there is no interaction because there is no aether so processes are unaltered and the effects are due to curvature along the path. There is no curvature in LET. Both emitter and observer are immersed in aether, and neither can be counted on to be at rest wrt to it. It *is* a system effect. And LET is indifferentiable from SR (so there is curvature since both time and space are its product). LET's not talk about this any further. ;) It is also blue shifted while returning to the detector however the lab has fallen some distance so on the return the gravitational acceleration is greater so there will be a net blue shift. This allows the tidal force to be measured even in a freefall condition. Do you agree? Not if 3m is "too small to detect". Well yes, I am saying that there is a blue shift in question c) where there is none in questions a) and b) which allows it to be distinguished assuming your can measure such a small quantity. Pound-Rebka used 22.5m so my 3m isn't unreasonable. ... as long as you aren't falling into a black hole, with a short finite time before impacting at a "central singularity". Pound-Rebka accumulated counts over a (relatively) long period of time to achieve a measureable result. We just need quicker tools which are always available in thought experiments. However, perhaps you would like to work out how long (proper time of course) it takes from the event horizon to the centre for a black hole large enough to have a 1g acceleration at the horizon. Since there is no center (other than in outer geometry), and since I already know how long in this Unvierse from Big Bang to "infinitely diffuse future" with "no particle in any other particle's future" (125 billion years, give or take tens of billion years), all that remains is to find out what size BH the Big Bang was. You are right, a sensitive spectrometer could do that but it still produces only a minimal change to the distance measurement (if any). IMHO I can still claim the roof and floor are in the same universe during the measurement. As long as the roof and floor are interchanging light, this would be a valid claim. OK, that was where I wanted to get to. I finally did the diagram for an inertial lab, just SR: http://www.georgedishman.f2s.com/david/in_the_lab.png .... Now consider what happens if that is drawn for a free falling lab as in my question c). Since curvature cannot be removed, the central line for the observer must become curved and if the lab structure is rigid in the sense of no measurable strain due to the tidal forces then the mirror worldlines would run almost parallel to that of the observer (not quite parallel due to rotation of the spatial axis - at a constant distance). Agreed. Good stuff, I think we are making progress so I'll go straight to the hard part. Try taking the sketch I drew above and distort it sideways as in the two diagrams in T&W it so that the central source/ detector line is the worldline of the infalling observer shown in the spacetime diagrams on this page http://www.phy.syr.edu/courses/modul...arzschild.html Clearly a problem arises when the final detection is at the singularity but I cannot see any reason why the pattern should not extend across the event horizon. Bear in mind the scale, the diamonds in my sketch are 3m while the distance from the horizon to the singularity is vastly larger. At the event horizon, light cannot go outwards to *infinity* because escape velocity is exactly c. I see problems with this, but I need to cogitate a bit more. Keep in mind that aether cannot be killed, so dual interchange of light will be required "to be in the same Universe". What aether? I am talking GR and I thought you were too, I have no interest in aether theories. "The laws of physics are the same for all inertial observers." "inertial observers" is problematic but I'll go with the principle of equivalence. Aether cannot be killed in any inertial frame. True, since an aether doesn't exist in the first place, at least not when we are learning GR. "Double entry bookkeeping". It is always good to know your limitations. Anyway, I meant we were the students trying to figure out what the experts are telling us. I hope that's OK with you. Absolutely. I never got into D&D, but role playing can be instructive. Press on. Two students, and the professor has simply left clues in "strange" places. Ok, the next instalment is applying our agreement on the 'same universe' test to a free-falling lab and the next will be that as seen by an observer falling at constant speed in the gravitational field. The step after that should get us back to the web pages. Sounds good. I've got to get to an "integration surface", which hopefully is similar for sources near (eg. infalling matter colliding with an accretion disk) and far. Actually I've gone on the web page as we seem to be agreeing the important stuff. I have no idea why you keep referring to aether though. As a double-check. The rules of this Universe do not disallow a Lorentz-class aether for any "macroscopic model". I don't expect anything we do will disallow it either. I don't depend on aether for answers, or for (for me) a workable model of how things work, but it has certain limitations on how things *can't* be, that are useful in first pass modelling. David A. Smith |
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