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| Tags: addition, paradox, velocity |
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#1
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Suppose you have an observer looking at two moving masses, A and B. A
is seen to move vertically up (+y) with speed u and B to left (-x) with speed v. How does B see A moving? We apply SR velocity addition formulae to get: x velocity: +v, y velocity: u*sqrt(1-v^2/c^2) A sees B moving: x velocity: -v*srqt(1-u^2/c^2), y velocity: -u. What is going on? Should they not see each other going opposite? If it were 1-D velocity addition we would have them going opposite when we applied SR. Can we arrange another paradox out of this, Ha, Ha! |
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#2
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"John Tapper" skrev i melding om... Suppose you have an observer looking at two moving masses, A and B. A is seen to move vertically up (+y) with speed u and B to left (-x) with speed v. How does B see A moving? We apply SR velocity addition formulae to get: x velocity: +v, y velocity: u*sqrt(1-v^2/c^2) A sees B moving: x velocity: -v*srqt(1-u^2/c^2), y velocity: -u. What is going on? What's going on is that you are demonstrating that you don't know how to transform velocities. Paul |
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#3
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John Tapper wrote:
Suppose you have an observer looking at two moving masses, A and B. A is seen to move vertically up (+y) with speed u and B to left (-x) with speed v. How does B see A moving? We apply SR velocity addition formulae to get: x velocity: +v, y velocity: u*sqrt(1-v^2/c^2) A sees B moving: x velocity: -v*srqt(1-u^2/c^2), y velocity: -u. What is going on? Should they not see each other going opposite? If it were 1-D velocity addition we would have them going opposite when we applied SR. Can we arrange another paradox out of this, Ha, Ha! This paradox is already known as "The Paradox No Relativist Can Weasel Out Of": news:XUJZATNT38251.8705787037@anonymous |
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#4
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Theo Wollenleben wrote:
John Tapper wrote: Suppose you have an observer looking at two moving masses, A and B. A is seen to move vertically up (+y) with speed u and B to left (-x) with speed v. How does B see A moving? We apply SR velocity addition formulae to get: x velocity: +v, y velocity: u*sqrt(1-v^2/c^2) The formula you used is valid ONLY for collinear velocitites. For non-collinear velocities the composition is much more complicated. It's given in any intermediate or advanced textbookon relativity, but is usually omitted from elementary textbooks. This paradox is already known as "The Paradox No Relativist Can Weasel Out Of" That may be the Subject of the thread in this newsgroup, but its sentiment is completely wrong -- it's merely your lack of understanding of the Lorentz group that prompted you to initiate that thread. There's no problem in SR, and no need to "weasel". Tom Roberts |
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#5
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"Tom Roberts" wrote in message ... Theo Wollenleben wrote: John Tapper wrote: Suppose you have an observer looking at two moving masses, A and B. A is seen to move vertically up (+y) with speed u and B to left (-x) with speed v. How does B see A moving? We apply SR velocity addition formulae to get: x velocity: +v, y velocity: u*sqrt(1-v^2/c^2) The formula you used is valid ONLY for collinear velocitites. For non-collinear velocities the composition is much more complicated. It's given in any intermediate or advanced textbookon relativity, but is usually omitted from elementary textbooks. This paradox is already known as "The Paradox No Relativist Can Weasel Out Of" That may be the Subject of the thread in this newsgroup, but its sentiment is completely wrong -- it's merely your lack of understanding of the Lorentz group that prompted you to initiate that thread. There's no problem in SR, and no need to "weasel". Just for the record, Theo was talking ironically ;-) Dirk Vdm |
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#6
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Tom Roberts wrote in message ...
Theo Wollenleben wrote: John Tapper wrote: The formula you used is valid ONLY for collinear velocitites. For non-collinear velocities the composition is much more complicated. It's given in any intermediate or advanced textbookon relativity, but is usually omitted from elementary textbooks. ... Tom Roberts You, of course, have no idea what you are talking about! (BTW, who would admit to working for Lucent? :-) ) |
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#7
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"Eli Botkin" wrote in message news:1096055108.c46DejH1WszbkV/i7QWXPA@teranews...
"John Tapper" wrote in message om... Suppose you have an observer looking at two moving masses, A and B. A is seen to move vertically up (+y) with speed u and B to left (-x) with speed v. ... What is going on? Should they not see each other going opposite? Can we arrange another paradox out of this, Ha, Ha! Sorry John, can't arrange a paradox here since each sees the other moving at the same speed, namely sqrt(u^2+v^2-(uv/c)^2). Eli Eli, I explicitly stated that velocity direction and not magnitude was the issue! |
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