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| Tags: einstein, getr, great, robbery, train |
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#1
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I guess this is mostly for Tom Roberts' consumption, but anyone who
thinks they can understand should play. It has the common ingredients of train car, the central observer/emitter/receiver/clock within, the detector/reflector/clocks - #1 and #2, and the track side observers. And light, of course! No diagram is needed. You will need two Wendy's napkins and a pen. Study the light Doppler effect formula one more time to make sure that you understand that it not only includes a simple Doppler effect, but also the difference in clock rates for the emitter vs. the receiver. Why do clocks have different rates of time? Because of v/c. v/c is self-referential so that v/c = 0 for the inertial observer of record. That leaves everything else that is moving with a relative v/c 0. Light is anisotropic for those moving objects in most considerations that you may have. That is the future point to be made amid the obscurity. The train is non-moving at the station. This is the crux. Can we let the clocks on the train e-synch now, before it starts moving? After all, all three clocks will undergo the same changes in velocity (forget the little push/pull on the train car). At some future velocity, all the clocks will still be in the same inertial frame, right? Finally moving to my point, at any v/c 0, the central train observer WILL still measure the return of both emissions (fore and aft) simultaneously. But what time will the fore and aft clocks record for when they received it? Again, the crux. We let the train e-synch at rest. If we let the train e-synch while in its final motion, the fore and aft clocks would record the same time for the event (the reception of the emission from the central train observer). All of this falls within the so-called "SR-LET equivalence". This puts more of a point to the difference between "observer-based" SR (subjective) and the more objective "LET-type" consideration. Notice how the track side observer is nonrelavent in all this? What this boils down to is a partial victory for an absolute v/c. You will now know how fast you are traveling relative to when you e-synched your clocks last. But it is still a relative measurement (not an absolute delta v) and it only conforms to how you measure NOW at whatever v/c you have. Of course the delta v must exceed the error brackets for such measurements and it must include the possible changeover from the positive |v| to the negative |v| along the line of measurement. H-K tried to exemplify this, if I guess it right. So, I can figure the additional gravitational effects to clocks as long as R/M remains constant. Perturbations of Sun, Moon, etc. are, of course, an almost insignificant noise to be reckoned with - but defined to set up the error bars. This little, almost insignificant thought (above) has been nagging at my logic for years without ever surfacing. There are more and I wish they would come forward soon. Maybe this will be a prompt. I need a good kick now and again. I guess what I am saying is that SR can make a "physic" of subjective observation, but it is only that. It is enough to "handle" what we know and do with it (to an unspecified point). But we need more sense of objective reality to do "real science". I'll throw this in that I have a "gravity" that is simple and compliant to all consideration except for prior beliefs. That is why I don't post it. It is not "unscientific" --- I just know the belief barrier. Btw, the answers to the above initial e-synch with the train car length of x meters (and assuming T'=0) are .5 * x/c * 1/((v-c) * gamma^2) for the fore clock and .5 * x/c * 1/((v+c) * gamma^2) for the aft clock. They add up to the time it takes light to transverse fore to aft (or vv) in the train car as measured by an onboard (v/c) clock. A little deeper symmetry than you are used to? That is what an "LET" consideration provides. I might add (Tom, if you read this) that our universe is connected continuously. There is no breakage that is not assymtopic. This means (in short words) that BB had a prior history. All symmetry that we can observe (and all that we cannot) is caused by this connectiveness. There would be no causal mechanism for symmetry if this were not so. I don't think anyone should reply to this until you (TR) do. (I think you are respected) Other than that, let the forum roll. |
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#2
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"xxein" wrote in message om... I guess this is mostly for Tom Roberts' consumption, but anyone who thinks they can understand should play. Submitted to http://groups.google.com/groups?&thr... ng.google.com Dirk Vdm |
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#3
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#4
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"Dirk Van de moortel" wrote in message ...
"xxein" wrote in message om... I guess this is mostly for Tom Roberts' consumption, but anyone who thinks they can understand should play. Submitted to http://groups.google.com/groups?&thr... ng.google.com Dirk Vdm xxein: You may be excused from this homework, Dirk. I would never force anyone to injure their brain. |
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#5
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#6
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"xxein" wrote in message m... (xxein) wrote in message . com... I made an ideosyncratic typo by typing "v-c" and "v+c" instead of "c-v" and "c+v". However, it takes but a few adjacent brain cells to guess the intended script. Also, some of the wording of that paragraph is hard to understand. I will not change THAT though. No worries. I don't think anyone has even had a look at it beyond the second paragraph. Dirk Vdm |
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#8
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"xxein" wrote in message om... I guess this is mostly for Tom Roberts' consumption, but anyone who thinks they can understand should play. I'll have a look. It has the common ingredients of train car, the central observer/emitter/receiver/clock within, the detector/reflector/clocks - #1 and #2, and the track side observers. And light, of course! No diagram is needed. I'll provide one anyway: http://www.bartleby.com/173/9.html You will need two Wendy's napkins and a pen. Study the light Doppler effect formula one more time to make sure that you understand that it not only includes a simple Doppler effect, but also the difference in clock rates for the emitter vs. the receiver. You mean Einstein's combined Doppler and time dilation equation that also is called "relativistic Doppler"? Why do clocks have different rates of time? Because of v/c. v/c is self-referential so that v/c = 0 for the inertial observer of record. That leaves everything else that is moving with a relative v/c 0. Light is anisotropic for those moving objects in most considerations that you may have. That is the future point to be made amid the obscurity. Completely obvious and logical, but indeed succesfully obscured for many. The train is non-moving at the station. This is the crux. Can we let the clocks on the train e-synch now, before it starts moving? After all, all three clocks will undergo the same changes in velocity (forget the little push/pull on the train car). At some future velocity, all the clocks will still be in the same inertial frame, right? Last year I did a similar thought experiment for three rockets. Yours is slightly different because of length contraction, affecting the e-synch a littlebit. Finally moving to my point, at any v/c 0, the central train observer WILL still measure the return of both emissions (fore and aft) simultaneously. But what time will the fore and aft clocks record for when they received it? Again, the crux. We let the train e-synch at rest. If we let the train e-synch while in its final motion, the fore and aft clocks would record the same time for the event (the reception of the emission from the central train observer). All of this falls within the so-called "SR-LET equivalence". This puts more of a point to the difference between "observer-based" SR (subjective) and the more objective "LET-type" consideration. Notice how the track side observer is nonrelavent in all this? When doing dynamics one can compare two frames of reference using only one observer. What this boils down to is a partial victory for an absolute v/c. You will now know how fast you are traveling relative to when you e-synched your clocks last. But it is still a relative measurement (not an absolute delta v) and it only conforms to how you measure NOW at whatever v/c you have. Yup, just as with stellar aberration. Of course the delta v must exceed the error brackets for such measurements and it must include the possible changeover from the positive |v| to the negative |v| along the line of measurement. H-K tried to exemplify this, if I guess it right. I didn't follow that one. So, I can figure the additional gravitational effects to clocks as long as R/M remains constant. Perturbations of Sun, Moon, etc. are, of course, an almost insignificant noise to be reckoned with - but defined to set up the error bars. R/M = radius/mass? This little, almost insignificant thought (above) has been nagging at my logic for years without ever surfacing. There are more and I wish they would come forward soon. Maybe this will be a prompt. I need a good kick now and again. I guess what I am saying is that SR can make a "physic" of subjective observation, but it is only that. It is enough to "handle" what we know and do with it (to an unspecified point). But we need more sense of objective reality to do "real science". I'll throw this in that I have a "gravity" that is simple and compliant to all consideration except for prior beliefs. That is why I don't post it. It is not "unscientific" --- I just know the belief barrier. [corrected:] Btw, the answers to the above initial e-synch with the train car length of x meters (and assuming T'=0) are .5 * x/c * 1/((c-v) * gamma^2) for the fore clock and .5 * x/c * 1/((c+v) * gamma^2) for the aft clock. They add up to the time it takes light to transverse fore to aft (or vv) in the train car as measured by an onboard (v/c) clock. A little deeper symmetry than you are used to? That is what an "LET" consideration provides. I am too lazy to check that now. I might add (Tom, if you read this) that our universe is connected continuously. There is no breakage that is not assymtopic. This means (in short words) that BB had a prior history. All symmetry that we can observe (and all that we cannot) is caused by this connectiveness. There would be no causal mechanism for symmetry if this were not so. I don't think anyone should reply to this until you (TR) do. (I think you are respected) Other than that, let the forum roll. Nice, but I have the feeling that you didn't really made your point... Harald |
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#9
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"Harry" wrote in message ...
"xxein" wrote in message om... I guess this is mostly for Tom Roberts' consumption, but anyone who thinks they can understand should play. I'll have a look. "Harry" wrote in message ... "xxein" wrote in message om... I guess this is mostly for Tom Roberts' consumption, but anyone who thinks they can understand should play. I'll have a look. Nice, but I have the feeling that you didn't really made your point... Harald xxein: Simple point. Railroad car. Aft, central and fore clocks. All share the same frame of reference. SR does not care how fast it may be moving. That is because SR e-synchs clocks in the same frame at its current velocity. To e-synch, you send a signal to the clock that you wish to e-synch with. That signal "tells" the other clock what time to reset itself . You depend on the second relativity postulate - that light travels at c in any inertial frame - to determine (with a distance measurement between clocks), what clock time it is supposed to have. Nothing all that bad here. It allows cause and effect to maintain a constant relation wrt c as measured by TWLS. But what if you accelerate that frame to a different velocity without the frame e-synching the clocks within itself again? Won't all three clocks undergo the same physical effects? Won't all three share the same change in timerate? There would be no need to e-synch again, would there (if you are to believe that all light passes at c = OWLS for all inertial frames)? Any change of velocity wrt another frame IS a change of v/c. That is why the relativistic Doppler formula exists. It defines the simple Doppler of motion and the timerate difference. Timerate difference because of what? v/c! Does your emitted light travel at a different velocity than mine? If so, then lightspeed is determined by the speed of the emitter object. We know that is not the case for a myriad of reasons (some, more definitive than others). Perhaps you could answer one simple question. Why do the clocks on the moving train car have a different timerate than the track-side observer? Remember that if the train came back to rest again along-side the track-side observer (for whatever its length of journey), the clocks will beat the same but will not read the same time as before (when they were e-synched). That leaves out a mere optical reading of moving clocks. Something caused a change of timerate. What? (And there is no gravity mumbo-jumbo to complicate things either.) |
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#10
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"xxein" wrote in message om... "Harry" wrote in message ... "xxein" wrote in message om... I guess this is mostly for Tom Roberts' consumption, but anyone who thinks they can understand should play. I'll have a look. "Harry" wrote in message ... "xxein" wrote in message om... I guess this is mostly for Tom Roberts' consumption, but anyone who thinks they can understand should play. I'll have a look. Nice, but I have the feeling that you didn't really made your point... Harald xxein: Simple point. Railroad car. Aft, central and fore clocks. All share the same frame of reference. SR does not care how fast it may be moving. That is because SR e-synchs clocks in the same frame at its current velocity. To e-synch, you send a signal to the clock that you wish to e-synch with. That signal "tells" the other clock what time to reset itself . You depend on the second relativity postulate - that light travels at c in any inertial frame - to determine (with a distance measurement between clocks), what clock time it is supposed to have. Nothing all that bad here. It allows cause and effect to maintain a constant relation wrt c as measured by TWLS. But what if you accelerate that frame to a different velocity without the frame e-synching the clocks within itself again? Won't all three clocks undergo the same physical effects? Not exactly, but almost, as I pointed out to you. Won't all three share the same change in timerate? Thus again, almost. Better change to my three rockets. There would be no need to e-synch again, would there (if you are to believe that all light passes at c = OWLS for all inertial frames)? Now you made your point clair. Indeed, that is exactly the purpose of my three rockets example. The math behind it could distract from considering what happens. The fact that there is a need to recalibrate, proves that something physical happened. Any change of velocity wrt another frame IS a change of v/c. That is why the relativistic Doppler formula exists. It defines the simple Doppler of motion and the timerate difference. Timerate difference because of what? v/c! Does your emitted light travel at a different velocity than mine? If so, then lightspeed is determined by the speed of the emitter object. We know that is not the case for a myriad of reasons (some, more definitive than others). Perhaps you could answer one simple question. Why do the clocks on the moving train car have a different timerate than the track-side observer? That is so in general, but not necessarily always. They are measured to have a different time rate by the track-side observer, because something physical happened. I deduced from such and other thought experiments that it is caused by a change of speed relative to an "absolute" (although not necessarily perfectly stationary) frame of reference - also called physical space, the ether, or quantum vacuum. Remember that if the train came back to rest again along-side the track-side observer (for whatever its length of journey), the clocks will beat the same but will not read the same time as before (when they were e-synched). I think that you mean that they will be behind on identical clocks that stayed there. That leaves out a mere optical reading of moving clocks. Something caused a change of timerate. What? (And there is no gravity mumbo-jumbo to complicate things either.) Harald |
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