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| Tags: amperes, field, law, magnetic, proves, reality |
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#11
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"Bilge" wrote in message ... Harold Ensle: "Bilge" wrote in message e-al.net... V.K.Tamhane: Taking into consideration that the currents are vectors, Currents are _NOT_ vectors. Currents are _scalars_. Current _densities_ are vectors and a current is the surface integral of J, I = \integral J . dS Note the scalar product. Whoooo.....this is one of those basic physics errors that worry me. Current is by definition a vector since it has a direction. (Is the current going East...west...north..south....up....down...etc) Wrong. Current is a scalar. Note that ampere's law reads: Why do you not confess your mistake? If you did, I would just reply OK. Since you can't seem to follow my simple argument above, perhaps you will listen to authority (which seems to be your only ability): Griffiths states in "Introduction to Electrodynamics" page 202: "The current at each point is actually a _vector_: ..........." duh, not that anyone but yourself would be surprised. curl B = J = \integral (curl B) . dS = \integral J . dS = I Your equation determines the _magnitude_ of current that passes throught the surface. And yes, the _magnitude_ of current is a scalar. Scalars do not have directions. Yes I know....that is why current is a vector. Note that the bio-savart law reads: I dl x r, not dI x r. magnetic force may change in magnitude but never in the direction. Therefore under all conditions, eq.1 alone should have been found true. But it is true only as a special case, that when Ib rotates in the y-z plane. When the direction of Ib is x, the force exerted on Ib is parallel to Ia. The force is no more 'between' the current elements and so no more 'due' to the current elements. It's completely inappropriate to consider the current elements outside of the integral sign. Ampere's law does not permit you to do that. Clearly in the above case, Ib is not responding directly to Ia; it is responding to the B field of Ia and this is possible only if B field is real. Obviously Ib, too, has a real field and the actual mechanical fore between the current elements is due to the interaction of these real fields. What is your deal with magnetic fields being ``real'' or not ``real''? I think he means does the magnetic field exist as a real property of a space instead of merely mathematical book-keeping relating to the interaction of separate particles. What he means is his problem and it does appear to be some pet problem of his. They are obviously real to the extent that I can measure something I call a magnetic field. The fact that div B = 0 in maxwell's equations tells you that there exists no source (or sink) for the magnetic field. Again irrelevant. Harold, if all you are going to is make dumb comments, I'm simply going to tell you that they're dumb. Of course it's relevant. How can you have a field which is a field in its own right if there exists no source of that field? This is still irrelevant. You are arguing apples and oranges. The fact that delxB=0 does not necessarily imply that the magnetic field is not "a field in its own right". The reason the B-field is considered to be an artifact of a changing E-field, is because there is no source for the B-field other than a changing E-field. This may be the reason for the prevalent attitudes, but it is not rigorous. Feel free to change that. Maxwells equations may be rewritten with complete symmetry between electric and magnetic fields, You cannot have complete symmetry without a magnetic monopole. It's not worth repeating this until you get it, since I've posted it before. Go look in jackson instead of posting uninformed bull****. You'll find the details to what you snipped just before the section on monopoles. So I assume you are beginning to babble here....... If you could have understood what you snipped, you would have seen your comment above was the result of your own ignorance. .....just the contrary actually. H.Ellis Ensle |
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#12
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"Franz Heymann" wrote in message ... "V.K.Tamhane" wrote in message m... Let us first ponder over force acting at a distance. Whenever there exists such a force between two bodies, the force vector always lies between them. The bodies, depending on their nature, either attract or repel in the direction of the line joining them. Force between two current elements is a bit complex, because sources are vectors and so, justifiably, we can say that, in this case, the force depends not only on magnitude but also on the orientation of the sources as well. Hence for the magnetic force, we have following Biot-Savart law (neglect constants), F=(Ia) dot (Ib)/r^2 .........1. That is not the Biot Savart law. Current is not a vector. This seems to be a universal idiocy. Of course current is a vector. It can have a direction...therefore it is a vector....duh. Practically, people are usually just interested in the magnitude, since the direction is confined to the direction of the wire, but even in practical applications, there could be situations where one would need to treat it as a vector. (e.g. in a plasma) [.........] H.Ellis Ensle |
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#13
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Harold Ensle wrote:
This seems to be a universal idiocy. Of course current is a vector. It can have a direction...therefore it is a vector....duh. Current is a *phasor* which exists somewhere in between a vector and a scalar value. In a single wire, its directions are limited to a binary existence and it possesses an imaginary phased component which doesn't exist in our universe. Reality should dictate the model, not vice versa. An H-field can exist in any vector direction but a current cannot. All a current needs is a +/- sign and a magnitude. -- cheers, Cecil -----= Posted via Newsfeeds.Com, Uncensored Usenet News =----- http://www.newsfeeds.com - The #1 Newsgroup Service in the World! -----== Over 100,000 Newsgroups - 19 Different Servers! =----- |
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#14
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Harold Ensle, crackpot and idiot,
"Bilge" wrote in message Wrong. Current is a scalar. Note that ampere's law reads: Why do you not confess your mistake? Because I havent made a mistake. You have. If you did, I would just reply OK. And if you didn't post nonsense, you wouldn't have a need to try and defend it. Since you can't seem to follow my simple argument above, perhaps you Your argument is silly and naive. Which parts of the equations I = \integral J . dS and I = dq/dt, do you not understand? Are you trying to tell me that charge is also a vector? will listen to authority (which seems to be your only ability): You are an idiot. You happen to be the one with that hangup, only after to listen to an authority, you feel compelled to disagree. I can derive anything I post from scratch, using my own arguments. You seem to be stuck misunderstanding passages in books. Griffiths states in "Introduction to Electrodynamics" page 202: "The current at each point is actually a _vector_: ..........." duh, not that anyone but yourself would be surprised. Since I have a copy of griffith's and did not find that statement on that page, I can only guess what you don't comprehend. A ``current at each point'' is not a current, it's a current density and if griffiths really said that, he used a very poor choice of words. Currents are scalars. If you don't understand the meaning of the `.' in J . dS, look up ``scalar product''. [...] Harold, if all you are going to is make dumb comments, I'm simply going to tell you that they're dumb. Of course it's relevant. How can you have a field which is a field in its own right if there exists no source of that field? This is still irrelevant. You are arguing apples and oranges. The fact that delxB=0 does not necessarily imply that the magnetic field is not "a field in its own right". curl B = J, (in magnetostatics) not zero. The reason the B-field is considered to be an artifact of a changing E-field, is because there is no source for the B-field other than a changing E-field. This may be the reason for the prevalent attitudes, but it is not rigorous. No, but you snipped the argument I made which clarified what I said. [...] If you could have understood what you snipped, you would have seen your comment above was the result of your own ignorance. ....just the contrary actually. Then why did you not understand it? Again, go look in jackson right before the section on monopoles. |
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#15
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"Harold Ensle" wrote in message k.net...
Harold sometimes you have to ignore some people. Now that I have understood his calibre, I will always ignore him. In the last message he said that when the coil loop is linked with maximum flux induced emf is maximum. In this he proves that he doesn't even know what a vector is. He says, out of I.dl, I is a scaler and dl is a vector, when either I or dl can be assigned a direction. Other follows it. Are we going to waste our time over this kid and a kid that belongs to a barking brigade? |
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#16
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"Franz Heymann" wrote in message ...
"V.K.Tamhane" wrote in message m... Let us first ponder over force acting at a distance. Whenever there exists such a force between two bodies, the force vector always lies between them. The bodies, depending on their nature, either attract or repel in the direction of the line joining them. Force between two current elements is a bit complex, because sources are vectors and so, justifiably, we can say that, in this case, the force depends not only on magnitude but also on the orientation of the sources as well. Hence for the magnetic force, we have following Biot-Savart law (neglect constants), F=(Ia) dot (Ib)/r^2 .........1. That is not the Biot Savart law. Current is not a vector. Where Ia and Ib are two parallel current elements in the y direction, having a distance vector r in the x direction. This dot product should have been the final word. It is not! You are telling me. It is not even the initial word. Correct equation is given by following Ampere's law. (Also known as Ampere's Biot-Savart law), F= (Ia cross r) cross Ib/r^3 ........2. That is not Ampere's law. Current is not a vector. How is it that you can't understand simple things. If you don't like current to be treated as a vector, then treat length of the conductor as a vector. Do I have to simplify everything? The rest was just a garbled recital of your own misconceptions, so I will snip it. [snip] What you snip is truth, but of course it is beyond your comprehension. Franz |
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#17
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"Bilge" wrote in message ... Harold Ensle: "Bilge" wrote in message e-al.net... V.K.Tamhane: Taking into consideration that the currents are vectors, Currents are _NOT_ vectors. Currents are _scalars_. Current _densities_ are vectors and a current is the surface integral of J, I = \integral J . dS Note the scalar product. Whoooo.....this is one of those basic physics errors that worry me. Current is by definition a vector since it has a direction. (Is the current going East...west...north..south....up....down...etc) Wrong. Current is a scalar. Note that ampere's law reads: curl B = J = \integral (curl B) . dS = \integral J . dS = I Your equation determines the _magnitude_ of current that passes throught the surface. And yes, the _magnitude_ of current is a scalar. Scalars do not have directions. Note that the bio-savart law reads: I dl x r, not dI x r. SNIP Bilge, indeed for example Alonso&Finn part 2 (Electromagnetism) treats "I" as only a scalar. But W.D.Day (Intro to vector analysis for Radio and electronic eng.) treats "I" as a vector and writes: F = I x B (he apparently took l=1). When a current has one single direction as well as a magnitude it can be presented as a vector. Maybe a little sloppy, but very handy! Harald |
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#19
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"Bilge" wrote in message
... Harold Ensle, crackpot and idiot, This is a sign that you know that you are wrong... you always get more insultive in such cases. (perhaps you should seek some counseling) "Bilge" wrote in message Wrong. Current is a scalar. Note that ampere's law reads: Why do you not confess your mistake? Because I havent made a mistake. You have. If you did, I would just reply OK. And if you didn't post nonsense, you wouldn't have a need to try and defend it. Since you can't seem to follow my simple argument above, perhaps you Your argument is silly and naive. Which parts of the equations I = \integral J . dS and I = dq/dt, do you not understand? Are you trying to tell me that charge is also a vector? will listen to authority (which seems to be your only ability): You are an idiot. You happen to be the one with that hangup, only after to listen to an authority, you feel compelled to disagree. I can derive anything I post from scratch, using my own arguments. You seem to be stuck misunderstanding passages in books. Griffiths states in "Introduction to Electrodynamics" page 202: "The current at each point is actually a _vector_: ..........." duh, not that anyone but yourself would be surprised. Since I have a copy of griffith's and did not find that statement on that page, I can only guess what you don't comprehend. A ``current at each point'' is not a current, it's a current density and if griffiths really said that, he used a very poor choice of words. No he explained quite well, sufficient for anyone with even meagre understanding to grasp. If you don't have the 2nd Ed. then look on the page with section "5.3.3 Currents". It is quite clear that he is refering to _current_ and not _current density_. The truely amazing thing is that you can't see it for yourself that current is a vector. Currents are scalars. If you don't understand the meaning of the `.' in J . dS, look up ``scalar product''. I know what scalar products are. And as I tried to explain to you. This equation yields the _magnitude_ of the current _vector(s)_ which is of course a scalar. I cannot believe that you don't get this. [...] Harold, if all you are going to is make dumb comments, I'm simply going to tell you that they're dumb. Of course it's relevant. How can you have a field which is a field in its own right if there exists no source of that field? This is still irrelevant. You are arguing apples and oranges. The fact that delxB=0 does not necessarily imply that the magnetic field is not "a field in its own right". curl B = J, (in magnetostatics) not zero. Actually that was a typo. I meant del dot B. The reason the B-field is considered to be an artifact of a changing E-field, is because there is no source for the B-field other than a changing E-field. This may be the reason for the prevalent attitudes, but it is not rigorous. No, but you snipped the argument I made which clarified what I said. [...] If you could have understood what you snipped, you would have seen your comment above was the result of your own ignorance. ....just the contrary actually. Then why did you not understand it? Again, go look in jackson right before the section on monopoles. I couldn't find it. You need to be more specific. (I have the 2nd edition) H.Ellis Ensle |
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#20
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Harry:
"Bilge" wrote in message ue-al.net... Scalars do not have directions. Note that the bio-savart law reads: I dl x r, not dI x r. SNIP Bilge, indeed for example Alonso&Finn part 2 (Electromagnetism) treats "I" as only a scalar. But W.D.Day (Intro to vector analysis for Radio and electronic eng.) treats "I" as a vector and writes: F = I x B (he apparently took l=1). When a current has one single direction as well as a magnitude it can be presented as a vector. Maybe a little sloppy, but very handy! I's a question of physics, not (somewhat dubious) notational convenience. |
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