"And then Schoenfeld-Einstein asked me to entertain his
relatives while he thought of a new name for his force."
-The non-credible guy

SCHOENFELD-EINSTEIN RELATIVISTIC FORCE:

F = (m + y^3 B/c m0 v)a

This is the relativistic mass-varying force.

PROOF:
let y = gamma = 1/sqrt(1-v^2/c^2)
let B = beta = v/c

Consider relativistic mass as a function of v.
m(v) = y(v) m0

Since
y(v) = 1 / sqrt(1 - v^2/c^2)
= 1 / sqrt(u) { where u(v) = 1 - v^2/c^2 }
= u^-1/2
Then,
dy/dv = -1/2 u^-3/2 (du/dv)
= -1/2 u^-3/2 2v/c^2
= v/[c^2 sqrt(u^3)]
= v/c^2 y^3 { since 1/sqrt(u^3) = y^3 }
= y^3 B/c

Consider the relativistic mass rate of change w.r.t velocity,
m(v) = y(v) m0
dm/dv = d(y(v) m0)/dv
= m0 (dy/dv)
= m0 y^3 B/c

Since relativistic mass is velocity-dependent, the mass-varying force
law is derived as:
F = dp/dt
= d(m(v) v)/dt
= m(v) (dv/dt) + v (dm/dv)(dv/dt)
= (m(v) + v dm/dv)a

Since the relativistic mass rate of change w.r.t velocity is,
dm/dv = m0 y^3 B/c

Then the relativistic mass-varying force (SCHOENFELD-EINSTEIN FORCE)
is,
F = (m(v) + y^3 B/c m0 v)a

QED

"John Schoenfeld" wrote in message
om...
SCHOENFELD-EINSTEIN RELATIVISTIC FORCE:

F = (m + y^3 B/c m0 v)a

This is the relativistic mass-varying force.

PROOF:
let y = gamma = 1/sqrt(1-v^2/c^2)
let B = beta = v/c

Consider relativistic mass as a function of v.
m(v) = y(v) m0

Since
y(v) = 1 / sqrt(1 - v^2/c^2)
= 1 / sqrt(u) { where u(v) = 1 - v^2/c^2 }
= u^-1/2
Then,
dy/dv = -1/2 u^-3/2 (du/dv)
= -1/2 u^-3/2 2v/c^2
= v/[c^2 sqrt(u^3)]
= v/c^2 y^3 { since 1/sqrt(u^3) = y^3 }
= y^3 B/c

Consider the relativistic mass rate of change w.r.t velocity,
m(v) = y(v) m0
dm/dv = d(y(v) m0)/dv
= m0 (dy/dv)
= m0 y^3 B/c

Since relativistic mass is velocity-dependent, the mass-varying force
law is derived as:
F = dp/dt
= d(m(v) v)/dt
= m(v) (dv/dt) + v (dm/dv)(dv/dt)
= (m(v) + v dm/dv)a

Since the relativistic mass rate of change w.r.t velocity is,
dm/dv = m0 y^3 B/c

Then the relativistic mass-varying force (SCHOENFELD-EINSTEIN FORCE)
is,
F = (m(v) + y^3 B/c m0 v)a

QED

I thought you said you were leaving this group. Why the about face?

Bill

Dear Bill Hobba:

"Bill Hobba" wrote in message
...

"John Schoenfeld" wrote in message
om...
SCHOENFELD-EINSTEIN RELATIVISTIC FORCE:
....
QED

I thought you said you were leaving this group. Why the about face?

Asperger's syndrome. He can't help it.

David A. Smith

John Schoenfeld wrote:

SCHOENFELD-EINSTEIN RELATIVISTIC FORCE:

F = (m + y^3 B/c m0 v)a


Oh man, you broke my bull**** meter!

Special Relativity
http://scienceworld.wolfram.com/phys...elativity.html

What is the experimental basis of Special Relativity?
http://math.ucr.edu/home/baez/physic...periments.html

Crank Information
http://www.google.com/search?q=Schoe...ers.pandora.be

John Schoenfeld wrote:
SCHOENFELD-EINSTEIN RELATIVISTIC FORCE:

F = (m + y^3 B/c m0 v)a

This is the relativistic mass-varying force.

PROOF:
let y = gamma = 1/sqrt(1-v^2/c^2)
let B = beta = v/c

Consider relativistic mass as a function of v.
m(v) = y(v) m0

Since
y(v) = 1 / sqrt(1 - v^2/c^2)
= 1 / sqrt(u) { where u(v) = 1 - v^2/c^2 }
= u^-1/2
Then,
dy/dv = -1/2 u^-3/2 (du/dv)
= -1/2 u^-3/2 2v/c^2
= v/[c^2 sqrt(u^3)]
= v/c^2 y^3 { since 1/sqrt(u^3) = y^3 }
= y^3 B/c

Consider the relativistic mass rate of change w.r.t velocity,
m(v) = y(v) m0
dm/dv = d(y(v) m0)/dv
= m0 (dy/dv)
= m0 y^3 B/c

Since relativistic mass is velocity-dependent, the mass-varying force
law is derived as:
F = dp/dt
= d(m(v) v)/dt
= m(v) (dv/dt) + v (dm/dv)(dv/dt)
= (m(v) + v dm/dv)a

Since the relativistic mass rate of change w.r.t velocity is,
dm/dv = m0 y^3 B/c

Then the relativistic mass-varying force (SCHOENFELD-EINSTEIN FORCE)
is,
F = (m(v) + y^3 B/c m0 v)a

QED

Nice. And why do you think this formula is useful for anything?


Bye,
Bjoern

John Schoenfeld wrote:

SCHOENFELD-EINSTEIN RELATIVISTIC FORCE:
[snip]

http://www.freefarts.com/farts.html
Move cursor over blinkers to hear Schoenfeld's lecture.

--
Uncle Al
http://www.mazepath.com/uncleal/qz.pdf
http://www.mazepath.com/uncleal/eotvos.htm
(Do something naughty to physics)

"John Schoenfeld" wrote in message
om...
SCHOENFELD-EINSTEIN RELATIVISTIC FORCE:

You are an ignorant, arrogant jackass Schoenfeld. Go play with Cesar.

"John Schoenfeld" wrote in message
om...
SCHOENFELD-EINSTEIN RELATIVISTIC FORCE:

F = (m + y^3 B/c m0 v)a

This is the relativistic mass-varying force.

PROOF:
let y = gamma = 1/sqrt(1-v^2/c^2)
let B = beta = v/c

Consider relativistic mass as a function of v.
m(v) = y(v) m0

Since
y(v) = 1 / sqrt(1 - v^2/c^2)
= 1 / sqrt(u) { where u(v) = 1 - v^2/c^2 }
= u^-1/2
Then,
dy/dv = -1/2 u^-3/2 (du/dv)
= -1/2 u^-3/2 2v/c^2
= v/[c^2 sqrt(u^3)]
= v/c^2 y^3 { since 1/sqrt(u^3) = y^3 }
= y^3 B/c

Consider the relativistic mass rate of change w.r.t velocity,
m(v) = y(v) m0
dm/dv = d(y(v) m0)/dv
= m0 (dy/dv)
= m0 y^3 B/c

Since relativistic mass is velocity-dependent, the mass-varying
force
law is derived as:
F = dp/dt
= d(m(v) v)/dt
= m(v) (dv/dt) + v (dm/dv)(dv/dt)
= (m(v) + v dm/dv)a

Since the relativistic mass rate of change w.r.t velocity is,
dm/dv = m0 y^3 B/c

Then the relativistic mass-varying force (SCHOENFELD-EINSTEIN FORCE)
is,
F = (m(v) + y^3 B/c m0 v)a

All of that is pure horse dung.
All particle accelerators were designed by utilising only one
equation, namely

dp/dt = e(E + v x B)

No particle accelerator has ever been built which has not worked
acording to specifications anywhere in the world. Accelerators have
been built in which the particles move a speeds of approximately
{1-10^-11) c.
The design of the ISR was based on this equation. It was possible to
keep two proton beams on track to within a couple of millimetres for a
distance of 6 light months in that machine. So, not to be too polite
about it, to hell with your nonsense.

Franz

"Michael Varney" escribió en el mensaje
...

"John Schoenfeld" wrote in message
om...
SCHOENFELD-EINSTEIN RELATIVISTIC FORCE:

You are an ignorant, arrogant jackass Schoenfeld. Go play with Cesar.

Mike, go play with the other psychos...