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| Tags: proven, schoenfeld, theorem |
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#1
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Previous posting had a working out error, although the final result
remains the same. Replace all "1 / [ (m-n)^L + 1]" with "1 / [ (m-n) + 1]^L" SCHOENFELD THEOREM: An infinite bounded sequence of random numbers contains all finite sequences of bounded numbers. P(S occurs in R) = 1 - lim j-+inf (1 - 1 / [(m-n) + 1]^L)^j = 1 - 0 = 1 where R : random sequence of numbers where all elements Ri are n = Ri = m m : largest number in R n : smallest number in R S : arbitrary sequence of numbers where all elements Si are n = Si = m L : length of S JS |
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#2
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Le 8 Dec 2003 03:42:26 -0800,
John Schoenfeld grava à la saucisse et au marteau: Previous posting had a working out error, although the final result remains the same. Replace all "1 / [ (m-n)^L + 1]" with "1 / [ (m-n) + 1]^L" SCHOENFELD THEOREM: An infinite bounded sequence of random numbers contains all finite sequences of bounded numbers. It's false ![]() 1 2 3 1 2 3 1 2 3 1 2 3 1 2 3 ... ad vitam aeternam is an infinite bounded sequence of random numbers. What you want to say is that the probability of a given sequence to appear in your infinite sequence tends towards 1 as the number of terms goes to infinity, which is not the same thing. -- Nicolas |
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#4
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John Schoenfeld wrote: SCHOENFELD THEOREM: An infinite bounded sequence of random numbers contains all finite sequences of bounded numbers. I assume you meant to say "...finite sequences of numbers bounded by bounds contained within the bounds of the infinite sequence..." This seems pretty obvious -- in fact, it also seems pretty obvious that each finite subsequence must occur in the infinite sequence an infinite number of times. In fact, I think that's even mentioned in various texts as an example of a corollary to some theorem. Don't recall which, tho. I also don't see the relevance of this to relativity, which is the newsgroup in which I saw it. Why was it cross posted there? |
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#5
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In article ,
John Schoenfeld wrote: SCHOENFELD THEOREM: An infinite bounded sequence of random numbers contains all finite sequences of bounded numbers. At the very least you should phrase your theorem carefully. There is no such thing as a "random number". I think what you mean is something like a "random number generator", where "random" modifies "generator", not "number". Better: "A randomly selected bounded sequence of numbers..." But then of course the result is nonsense: if you select a bounded sequence at random, you might very well select (0,0,0,0,0,...). See how clear things become when you try to state things with precision? (As you try to do so, you will eventually find that the word "random" almost never belongs in a carefully-worded mathematical sentence! "For all..." "There exists..." "...measure..." -- thoses are the phrases you probably want to use instead.) dave |
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#6
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SCHOENFELD THEOREM:
An infinite bounded sequence of random numbers contains all finite sequences of bounded numbers. At the very least you should phrase your theorem carefully. There is no such thing as a "random number". I think what you mean is something like a "random number generator", where "random" modifies "generator", not "number". Better: "A randomly selected bounded sequence of numbers..." Your arguments are of little value. Whether or not I chose to disguise simple concepts with excessive academic pedantry is irrespective of the validity of the Schoenfeld Theorem. But then of course the result is nonsense: if you select a bounded sequence at random, you might very well select (0,0,0,0,0,...). If the infinite random sequence R contains all 0's, then it is bound by [0,0], and the Schoenfeld Theorem remains true. Also, the Schoenfeld Theorem says "sequence of random numbers" not "random sequence of numbers". See how clear things become when you try to state things with precision? (As you try to do so, you will eventually find that the word "random" almost never belongs in a carefully-worded mathematical sentence! "For all..." "There exists..." "...measure..." -- thoses are the phrases you probably want to use instead.) Your disproof of the Schoenfeld Theorem [Copyright(c) John Schoenfeld] amounts to a set of befuddled attacks on my mathematical ettiquette. Try again, champ. JS |
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#7
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In message , John
Schoenfeld writes SCHOENFELD THEOREM: An infinite bounded sequence of random numbers contains all finite sequences of bounded numbers. At the very least you should phrase your theorem carefully. There is no such thing as a "random number". I think what you mean is something like a "random number generator", where "random" modifies "generator", not "number". Better: "A randomly selected bounded sequence of numbers..." Your arguments are of little value. Why not counter them, then? All you have to do is to define what you mean by "sequence of random numbers". Whether or not I chose to disguise simple concepts with excessive academic pedantry In mathematics, that's usually phrased "rigorous proof". Do it, and you're unassailable. Don't, and you're open to onslaught by a host of academic pedants. And one or two people who wonder what you think a "random number" might be. is irrespective of the validity of the Schoenfeld Theorem. That much is true. Your "simple concepts" say nothing about its validity. But then of course the result is nonsense: if you select a bounded sequence at random, you might very well select (0,0,0,0,0,...). If the infinite random sequence R contains all 0's, then it is bound Bounded. by [0,0], and the Schoenfeld Theorem remains true. Also, the Schoenfeld Theorem says "sequence of random numbers" not "random sequence of numbers". That's worse, until you define "random numbers".. See how clear things become when you try to state things with precision? (As you try to do so, you will eventually find that the word "random" almost never belongs in a carefully-worded mathematical sentence! "For all..." "There exists..." "...measure..." -- thoses are the phrases you probably want to use instead.) Your disproof of the Schoenfeld Theorem [Copyright(c) John Schoenfeld] amounts to a set of befuddled attacks on my mathematical ettiquette. Try again, champ. -- Richard Herring |
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#8
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