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| Tags: light, velocity |
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#21
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"Rudolf Drabek" wrote in message ... "kenseto" schrieb im Newsbeitrag ... "Rudolf Drabek" wrote in message ... Indeed its very simple. Look into the FAQ files for the Twin Paradoxon. The moving twin coming back e.g. from Sirius needed only e.g. 4 years on his clock. And the distance is about 8 lys. so 16ly years in 4y shiptime gives about avg. 4c. But observers on earth measure that the ship has never exceeded 1c. Its a question of where you are. Ah....but you can't compare the ship's 4 clock years with the earth's 16 clock years directly. Why? Because the passage of a clock year in the ship is not equal to the passage of a clock year on earth. To make the comparison you must convert the ship's clock years to the earth's clcok year as follows: Converting the ship's time to earth time=gamma*4 ship's clock years =16 earth's clcok years. What this means is that a physical clock is NOT a universal clock. A clock second does not contain the same amount of universal time (absolute time) in all frames of reference. Ken Seto Yes you are right. But I don't know a universal clock. But the original question was, if its possible to exceed c. The gamma of 4 is no question and o.k. The observation of the rocketeer twin after return is that he needed 4y and his twin on earth is 16y older. So the moving twin knows he had a passage of 16ly in 4y shiptime = 16y earthtime. speed in the rest frame was nearly c, speed in moving frame was about 4c. That's all what Androcles wanted to know I think. Rudi Not at all. I didn't ask the question you attempted to answer. If there were any such animal as time dilation, then GPS clocks would slow down, not speed up. They are actual evidence that your conjectures are hopelessly wrong, and there is nothing (except the practical difficulties of constructing a fuelling a suitable vehicle) to prevent a velocity exceeding c, except a religious-like faith in the word of one man that got his math wrong. Androcles |
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#22
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"Androcles" wrote in message ... "Martin Hogbin" wrote in message ... "Androcles" wrote in message ... No reason, if you have enough energy you can. For 'enough' read 'infinite'. Prove it. How much do you think is needed then? Martin Hogbin |
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#23
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In message , Androcles
writes "Rudolf Drabek" wrote in message ... "kenseto" schrieb im Newsbeitrag ... "Rudolf Drabek" wrote in message ... Indeed its very simple. Look into the FAQ files for the Twin Paradoxon. The moving twin coming back e.g. from Sirius needed only e.g. 4 years on his clock. And the distance is about 8 lys. so 16ly years in 4y shiptime gives about avg. 4c. But observers on earth measure that the ship has never exceeded 1c. Its a question of where you are. Ah....but you can't compare the ship's 4 clock years with the earth's 16 clock years directly. Why? Because the passage of a clock year in the ship is not equal to the passage of a clock year on earth. To make the comparison you must convert the ship's clock years to the earth's clcok year as follows: Converting the ship's time to earth time=gamma*4 ship's clock years =16 earth's clcok years. What this means is that a physical clock is NOT a universal clock. A clock second does not contain the same amount of universal time (absolute time) in all frames of reference. Ken Seto Yes you are right. But I don't know a universal clock. But the original question was, if its possible to exceed c. The gamma of 4 is no question and o.k. The observation of the rocketeer twin after return is that he needed 4y and his twin on earth is 16y older. So the moving twin knows he had a passage of 16ly in 4y shiptime = 16y earthtime. speed in the rest frame was nearly c, speed in moving frame was about 4c. That's all what Androcles wanted to know I think. Rudi Not at all. [Hiyaah!] I didn't ask the question you attempted to answer. Well maybe you should have done. If there were any such animal as time dilation, There is no time. then GPS clocks would slow down, not speed up. Androcles, haven't you heard of retro rockets? They are actual evidence that your conjectures are hopelessly wrong, and there is nothing (except the practical difficulties of constructing a fuelling a suitable vehicle) to prevent a velocity exceeding c, except a religious-like faith in the word of one man that got his math wrong. Androcles What a c***! -- [Hiyaah!] http://www.earthpoetry.demon.co.uk RC |
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#24
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In message , Androcles
writes "Rudolf Drabek" wrote in message ... "kenseto" schrieb im Newsbeitrag ... "Rudolf Drabek" wrote in message ... Indeed its very simple. Look into the FAQ files for the Twin Paradoxon. The moving twin coming back e.g. from Sirius needed only e.g. 4 years on his clock. And the distance is about 8 lys. so 16ly years in 4y shiptime gives about avg. 4c. But observers on earth measure that the ship has never exceeded 1c. Its a question of where you are. Ah....but you can't compare the ship's 4 clock years with the earth's 16 clock years directly. Why? Because the passage of a clock year in the ship is not equal to the passage of a clock year on earth. To make the comparison you must convert the ship's clock years to the earth's clcok year as follows: Converting the ship's time to earth time=gamma*4 ship's clock years =16 earth's clcok years. What this means is that a physical clock is NOT a universal clock. A clock second does not contain the same amount of universal time (absolute time) in all frames of reference. Ken Seto Yes you are right. But I don't know a universal clock. But the original question was, if its possible to exceed c. The gamma of 4 is no question and o.k. The observation of the rocketeer twin after return is that he needed 4y and his twin on earth is 16y older. So the moving twin knows he had a passage of 16ly in 4y shiptime = 16y earthtime. speed in the rest frame was nearly c, speed in moving frame was about 4c. That's all what Androcles wanted to know I think. Rudi Not at all. [Hiyaah!] I didn't ask the question you attempted to answer. Well maybe you should have done. If there were any such animal as time dilation, There is no time. then GPS clocks would slow down, not speed up. Androcles, haven't you heard of retro rockets? They are actual evidence that your conjectures are hopelessly wrong, and there is nothing (except the practical difficulties of constructing a fuelling a suitable vehicle) to prevent a velocity exceeding c, except a religious-like faith in the word of one man that got his math wrong. Androcles What a c***! -- [Hiyaah!] http://www.earthpoetry.demon.co.uk RC |
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#25
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"Gauge" wrote in message om... "Androcles" wrote in message ... "Pmb" wrote in message ... "Jean" wrote in message om... My Query is quite simple........ Why can't a body simply accelerate and exceed the velocity of light???????? Just increase the velocity by some m/s for some time to reach the C ....! The faster the body goes the greater its mass becomes since mass is a function of velocity even though your rest mass remains the unchanged. As you appoach c your mass will become infinite. That means the momentum becomes infinite since mass is defined as the "m" in p = mv. So while v is still finite, m becomes infinite. It would require a force greater than infinity to accelerate to or past c. This follows from the fact that force is the time rate of change of momentum. See also -- http://www.fnal.gov/pub/inquiring/qu...accel_obj.html Pmb Nonsense. When mass is defined as the "m" in p = mv it follows that m is a function of speed (when the object is a normal object, i.e. it has a finite rest mass). When mass is not defined as the m in p = mv then "m" is not generally meaningfull. See http://www.geocities.com/physics_wor...riant_mass.htm Prove it. I did. I've posted it many times before. See http://www.geocities.com/physics_wor...rtial_mass.htm Your turn. Prove that I'm wrong. And do not claim that the definiton is wrong since a definition can't be wrong - it's a definiton. And you didn't say that you disagreed with the definition. Pmb Quote When mass is defined as the "m" in p = mv it follows that m is a function of speed. Unquote. 1) I write m(v) = p/v. That would make m() a function of v, but what is p? If you can give me a definition of p that is both independent of m and independent of v, I'd like to see it. I can write f(x) = x+1, but f(x) = f.x/x is meaningless. How do you make the argument of a function into the function? At best, I can see that m(v) = p/v = mv/v = m, which is a constant and independent of v. 2) How does it follow? Androcles |
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#26
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"Martin Hogbin" wrote in message ... "Androcles" wrote in message ... "Martin Hogbin" wrote in message ... "Androcles" wrote in message ... No reason, if you have enough energy you can. For 'enough' read 'infinite'. Prove it. How much do you think is needed then? Martin Hogbin .. E = 1/2mv^2, v = c = 1, m = 1, so in the units I've chosen, 0.5. You can convert to SI units if you wish. Androcles |
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#27
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"Rudolf Drabek" wrote in message ... "Androcles" schrieb im Newsbeitrag ... "HenriWilson" wrote in message ... On 22 Nov 2003 23:01:50 -0800, (Jean) wrote: My Query is quite simple........ Why can't a body simply accelerate and exceed the velocity of light???????? Just increase the velocity by some m/s for some time to reach the C ....! 'Velocity' on its own does not exist. 'Velocity can only be defined wrt another object. If relative velocity is measured using light, it is pretty obvious that problems will arise near and beyond light speed. This has caused great confusion in the physics ranks. If relative velocity is measured using an infinite grid of synched clocks, (simulating instantaneous communication) these problems disappear. Thus it should be quite possible to travel to a planet 10 LY away in '5 minutes' if suitable rocket engines are available and your body can stand the g's. What is more, when you return, you will be only 10 minutes older. However an observer on Earth will still be monitoring your spaceship's journey for twenty years after you have returned. Relativity is BULL!!! For the outward trip, monitoring would fail when c was achieved relative to the monitoring station, doppler shift would fall to zero. At any speed beyond that, the light would never reach the monitoring station. As the ship decelerated to less that c to turn around, the signal would resume. On the return trip, the frequency at c will double. The ship will be able to read its own signals that it outrun in the first part of the journey. Note that this in no different to firing bullets backwards as you accelerate. When you return they'll still be there, you'll run right into them. Androcles Your last statements are not correct. You are mixing up shiptime and earthtime. No I'm not, Ship time and Earth time are the same. GPS clocks run fast, not slow, and have to be corrected to Earthtime from the ground since they were misprogrammed by relativists. Seen from earth the ship never exceeded c, so its not possible to run into the own signals. Only the moving clock has a dilated time. Rudi Prove it. Androcles |
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#28
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"Bill Rowe" wrote in message ... In article , (HenriWilson) wrote: 'Velocity' on its own does not exist. 'Velocity can only be defined wrt another object. True. If relative velocity is measured using light, it is pretty obvious that problems will arise near and beyond light speed. This has caused great confusion in the physics ranks. Not true. It seems to cause great confusion only among those who do not understand physics or don't take the time to understand. Not true. It is relativists that do not understand physics or mathematics, or take the time to understand. GPS clocks run fast. Period. They have to be corrected from the ground, because they've been misprogrammed on the word of relativists. They do not run slow, they are in orbits that follow straight lines in curved space and therefore have inertial frames, and they do NOT obey SR. If you were to take the time to understand, then you'd take the time to examine the luminosity curves of stars in elliptical orbits from a model that uses source dependency, and from that conclude that Einstein's second postulate was valid according to Nature only to a first approximation, and the first exactly right, because they match empirical data. [remainder snipped.] Androcles |
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#29
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"Pmb" schreef in bericht ... "Jean" wrote in message om... My Query is quite simple........ Why can't a body simply accelerate and exceed the velocity of light???????? Just increase the velocity by some m/s for some time to reach the C .....! The faster the body goes the greater its mass becomes since mass is a function of velocity even though your rest mass remains the unchanged. As you appoach c your mass will become infinite. That means the momentum becomes infinite since mass is defined as the "m" in p = mv. relatively speaking momentum is defined as p=M*v*gamma. if you leave out the gamma you could still exceed speed of light. So while v is still finite, m becomes infinite. It would require a force greater than infinity to accelerate to or past c. This follows from the fact that force is the time rate of change of momentum. See also -- http://www.fnal.gov/pub/inquiring/qu...accel_obj.html Pmb |
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#30
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"Androcles" schreef in bericht news ![]() "Martin Hogbin" wrote in message ... "Androcles" wrote in message ... "Martin Hogbin" wrote in message ... "Androcles" wrote in message ... No reason, if you have enough energy you can. For 'enough' read 'infinite'. Prove it. How much do you think is needed then? Martin Hogbin . E = 1/2mv^2, v = c = 1, m = 1, so in the units I've chosen, 0.5. You can convert to SI units if you wish. Androcles E=1/2mv^2 is NON-relativistic. Relativistic it would be E=gamma*m*c^2. Gamma would be 1/(sqrt(1-v^2/c^2)) 1. You really dont understand physics my friend ![]() Floris |
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