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| Tags: emr, mass, particleswaves, relativistic |
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#21
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#22
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Subject: Relativistic mass of EMR particles/waves
From: (Gauge) Date: 11/14/03 8:10 AM US Mountain Standard Time Message-id: (WaiteDavid137) wrote [flame] When waite is unable to find an error in a web page of mine he calls it a crank site. That is the reason he has always been unable to find an error besides typos No, you know I've explained to you corrections behind very many of your conceptual and mathematical errors as well as caught mistakes in what you often try to copy. Instead of continuing correcting them I just decided to let you keep all the mistakes without any more correction so people will see more easily for themselves what a rediculously flawed crank site you've built. I don't mind you looking like the fool you are. So instead I just tell people its a crank site and point out where to look for the correct physics. |
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#23
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On Fri, 14 Nov 2003 03:21:38 -0800, Gauge wrote:
Jeff Krimmel wrote [flame] Why do you constantly act so childsish with these responses? I'm not the one begging people not to pay attention to other posters, or consistently acting like a seven year old whining about people picking on me. You're a grown man. Act like it. Jeff -- Add an underscore between 'd' and 's' for email. |
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#24
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#25
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"Zarkovic" wrote in message news:_fQsb.384619$9l5.370470@pd7tw2no...
Thanks guys, by the way, EMR=electro-magnetic radiation. Hi guys. HI, I've read through the thread before posting. From a person by the posting name of Bilge, I copied this part of the conversation: "photon has relativistic mass m =hf/c^2." My apologies for the ignorance, what exactly does relativistic mass mean? Before relativity the laws of conservation of mass and conservation of energy were separate. A great achievement of relativity was to unify these laws. This resulted in the famous relation E_o=m_o c^2, (E_o and m_o are rest energy and mass respectively). Because of the equivalence of mass and energy, it stands to reason that the *kinetic energy* of a moving object may also be equated to a measure of mass. The sum of this *kinetic mass* (=kinetic energy/c^2) + the rest mass is the so-called relativistic mass. I agree with most other posters that this quantity is most accurately termed the *invariant energy*. Does this mean that if photon was not traveling, it would no have mass, or does this mean that regardless of whether or not it's moving, it has as you guys call it relativistic mass? When a photon is absorbed it is brought to rest, and provides an energy E=hf, so we should call this the rest energy of the photon. This rest energy depends on how the absorber is moving relative to the source due to Doppler effects. Sorry again, but for years I could never get why a wave/particle such as those of the EMR do not have mass, how could they then have energy and so on. A good question. You know anything moving at the speed of light transforms the units of cm, grams, secs to 0, oo, 0. (length =0, mass= infinite, time=0), so it is useless to consider a photon in terms of units. Instead only invariants apply. Consider Plancks Equation E=hf, and call frequency = N cycles/sec. In this definition of frequency, N is a pure number. The rest energy of a photon is , E_o = h*N/t assuming the rest energy = covariant energy E_0 then an invariant energy is h*N, if the contravariant component is E^0 = h*N*t by the relation, e^2 = invariant energy = E_0 E^0 This is somewhat subjective, but the required invariant energy of the photon becomes, e = h*N. (c=1). This invariant becomes actualized, (measured) only when the photon is absorbed into some system, then components of vector e are projected onto some mass and the energy increment can be recorded. (this is the process of vision). Now I kind of got used to the fact that this is true, yet could someone please explain the concept to me of relativistic mass of the EMR particles/waves and so on, and do particles alone have relativistic mass, and what about the waves alone as well. I think your question concerns a Generally Relativistic solution to Quantum Mechanics, and Wave Mechanics. That's a neat question. It appears the mathematicians cannot solve the problem generally, and the physicists cannot solve the problem specifically from any general solution , ie. the specific solution requires boundaries because there is no general solution. Regards Ken S. Tucker |
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