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| Tags: emr, mass, particleswaves, relativistic |
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#11
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Subject: Relativistic mass of EMR particles/waves
From: (Gauge) Date: 11/13/03 3:12 PM US Mountain Standard Time Message-id: Several examples contrary to cardinale's claims can be found listed at http://www.geocities.com/physics_wor...istic_mass.htm Your own crank site is not a valid reference. Instead see http://www.geocities.com/zcphysicsms/chap3.htm |
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#12
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Subject: Relativistic mass of EMR particles/waves
From: (Gauge) Date: 11/13/03 3:20 PM US Mountain Standard Time Message-id: http://www.geocities.com/physics_wor...nservation.htm http://www.geocities.com/physics_wor...er_of_mass.htm Your crank sites are not valid references so the foundation of your entire argument is invalid. Instead see http://www.geocities.com/zcphysicsms/chap3.htm |
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#13
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On Thu, 13 Nov 2003 14:14:18 -0800, Gauge wrote:
(Bilge) wrote If by "you guys", you mean those of us that are physicists, "us guys" don't use "relativistic mass" in general .. This is a lie. Pay no attention to him. Check out the counter examples I've listed to bilge's claims. Why most you consistently act like a grade school punk? Jeff -- Add an underscore between 'd' and 's' for email. |
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#14
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#15
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Jeff Krimmel wrote [flame]
Why do you constantly act so childsish with these responses? |
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#16
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#17
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"Zarkovic" wrote in message news:_fQsb.384619$9l5.370470@pd7tw2no...
Thanks guys, by the way, EMR=electro-magnetic radiation. I just came across another referance on relativistic mass. It's in "An elementary development of mass-energy equivalence," Daniel J. Steck, Frank Rioux, Am. J. Phys. 51(5), May 1983 (This is a popular derivation. It's been published in at least two other places that I'm aware of.) Note: It should be noted that this is another case where the term "mass" is used instead of "relativistic mass." Recall that relativistic mass is the m in p = mv. However you will not find the term "relativistic mass" in this paper. I.e. the authors are doing an derivation like Einstein's original one but in a slightly different way. A box is at rest in S. The box emits two photons of equal energy in opposite directions towards observers A and B. The box remains at rest due to conservation of momentum. In S', moving relative to S, the change in momentum is calculated. The auhtors write --------------------------------------- The classical definition of momentum is maintained by requiring that p_block = mv. Since no recoil is observed in the rest frame, the relativity principle requires that delta(v) = 0 in the moving frame also. This means that the principle of the conservation of linear momentum can only be preserved for A and B by postulating a mass change for the block upon emission of the photons, or that delta(p_block) = delta(mv) = v*delta(m). In light of these considerations, Eq. (8) can be written as delta(E) = delta(m)c^2 We note that an equivalent expression (delta(E^0) = delta(m^0)c^2) can be written for the rest frame by combining Eqs. (7) and (9) and interpreting delta(m)sqrt[1-v^2/c^2) as the change in rest mass of the block resulting from the emission of the two photons: delta(m^0) = delta(m)sqrt[1-v^2/c^2) Generalizing on the basis of Eqs. (9) and (10) suggests that we can write E = mc^2 where m = m^0/sqrt[1-v^2/c^2] --------------------------------------- Notice that, according to the definition of mass in p = mv, light must have mass. Pmb |
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#19
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(Paul Cardinale) wrote [bs]
Read some of CERN's onbline literature http://humanresources.web.cern.ch/hu..._24Feb03pm.pdf and learn. Then hit the library and read the American Journal of Physics etc etc etc |
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#20
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