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Finite precision measurement does not nullify the Kochen-Specker theorem



 
 
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  #1  
Old November 7th 03 posted to sci.physics.relativity
Bill Hobba
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Posts: 1,485
Default Finite precision measurement does not nullify the Kochen-Specker theorem

In recent discussions about the Kochen-Specker theorem some posters pointed
to finite precision of measurement as a possible refutation of the theroem.
As stated in other threads a number of objections have been bought ageist
the theorem - and to the best of my knowledge all have been found wanting.
The refutation of the finite precision claim can be found at
http://arxiv.org/abs/quant-ph/0104024.

Thanks
Bill


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  #2  
Old November 7th 03 posted to sci.physics.relativity
ueb
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Posts: 639
Default Finite precision measurement does not nullify the Kochen-Specker theorem

Bill Hobba wrote:
In recent discussions about the Kochen-Specker theorem some posters pointed
to finite precision of measurement as a possible refutation of the theroem.
As stated in other threads a number of objections have been bought ageist
the theorem - and to the best of my knowledge all have been found wanting.
The refutation of the finite precision claim can be found at
http://arxiv.org/abs/quant-ph/0104024.


I believe, you overestimate this theorem enormously. For the discussion
in the thread "Quanta & particles related to the continuum ?", it is
simply not relevant. My last reply there should be clear enough.
BTW: Does one deny the subject line ? (I don't do.)

Ulrich

 




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