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| Tags: confirmed, empirically, superluminal, velocities |
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#101
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"Bill Hobba" wrote in message ...
EL: (Robert Clark) wrote in message .com... Here they explain that the laser pulse exited the 6 cm long cesium chamber 62 nanoseconds sooner than if the laser traveled the 6 cm in vacuum. Since it takes only 0.2 nanoseconds for light to traverse 6 cm in vacuum, this means the pulse exited the chamber before it entered it. [EL] My problem with those supposedly scientists is that they do not feel ashamed to say that nonsense and repeat it as if it was so normal logic and they claim with boldness that it does not violate causality. If that nonsense did not violate causality then what else does? Bilge replied: You actually have to read several of their papers to figure out what they mean. The buzzword used is "rephasing". It's not clear to me that "superluminal" applies to a signal that can carry information, or at least carry information superluminally. The papers show some plots that give a better idea of what's going on, but it's too hard to try and reproduce them or describe them here. Search for "rephasing" and "superluminal" Having actually read some of their papers a while ago they freely admit that their results in no way violate either SR or QM - indeed it is predicted by it. Thus they can not send information faster than light - casualty guarantees it. Thanks Bill [EL] So Sam tells to you that he was already an adult before his father was born and that that fact does not violate SR or QM and indeed is predicted by them. Also he may not walk or run faster than his younger father and that that is guaranteed by [sic] casualty not causality. So you believe Sam because he said so! Even if you can obviously see that Sam was full of ****! How about the equations I have demonstrated! They made an error by mimicking a classical theoretical error that was never verified then and certainly is not being verified now. The error is taking negative time from negative slopes of delta-lambda/delta-velocity to be subtracted rather than added to the total time required for the completion of a change of state. This error is hidden in the jargon of: u = v – (L (dv/dL)) where u is the group velocity, v is the phase velocity, L is the wavelength, dv is the difference between wave packet components' velocities and dL is the difference between their wavelengths. A negative slope means a negative frequency! A negative frequency is the inverse of a negative time. There is no negative frequency because frequency is a count of integers per unit of proper time. The correct mathematical formula is: u = v – (L (|dv/dL|)) There is no physical meaning for the moronic label "negative dispersion". A negative slope still takes an absolute quantity of time to happen. So there is no superluminal speed at all to be in agreement or disagreement with SR, GR, QM or any other system whatsoever. To verify the logic, draw a proper time line and mark a time window to be the proper Time Frame of the experiment. Inside that Time Frame draw the intervals of every time period in which a sequence of events took place. Conclude your logical conclusions from paper and not from dreams, please. EL |
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#103
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[EL]
Let me help you and the readers by proposing a much more tenable scenario Robert. Assume that the experimenters used a symmetrical wave the wavelength of which is about 38 meters long or anything approximately oscillating at 8MHz (These values are very rough and just for demonstration). Assume that the wave shape is symmetrical and that the wavefront has the minimum amplitude but the maximum tare of amplitude change of state. The maximum amplitude is at the centre of the wave. Now let that wave enter the chamber and propagate at c and the wavefront reaches the far end after exactly 0.2 nanoseconds but the detector translates the maximum rate of change of the amplitude to a maximum output amplitude, and the wavefront thus triggers the timer to register the arrival of the wave-peak, which did not yet enter the chamber, which when on entering the chamber triggers the near end detector of a wave peak about 62 nanoseconds which is half the full period of the wave. In other words it could be a clumsy mistake or a deliberate foul play with experimental results. If those experimenters were serious, they must repeat the same experiment showing the arrival time being ahead by 31 nanoseconds when they double the frequency of the wave being transmitted and 124 nanoseconds when the frequency is halved or the wavelength doubled. Then my scenario should make full sense and they should discard the relevance of their experiment for any proof of a superluminal speed. A much better experiment is to send a square wave pulse from a chopper. In that scenario the wave front is the same as the maximum rate of change in the amplitude. The body of the wave having a constant amplitude shall not induce changes at the far end until the falling edge arrives and produces a second peak. This frequency doubler shall prove my suspicions and give them accurate time of the arrival of each edge and by the knowledge of the wavelength the velocity may be calculated. As far as I know and am sure of my knowledge in electronics that somewhere in there measuring system there is an inverter that reports the inverse of the wave amplitude at the caesium far end while it reports a none-inverted wave amplitude at the vacuum far end. This might explain what you meant by wave-reshaping or the weird expression of rephasing. In any case of which I have presented, there is no superluminal propagation of anything but we do have a screwed up experiment with results prepared before experimenting. To fully understand what I am explaining here you need access to the full specifications of the caesium cell, wave splitters, the vacuum cell, the wave detector integrated circuit and if its part number causes inversion or not and its sensitivity curves and the length of leads and the recording of data and the acquisition methods. After studying the specifications of the device you may proceed to inspect the data that was recorded before any mathematical manipulation of that data. Kind regards. EL (Robert Clark) wrote in message . com... Microsoft Outlook Express uses a proportional font by default in reading newsgroup messages. To properly view the diagram below in OE, you need to tell it to use a fixed-width font such as Courier: go to Tools - Options...- Read - Fonts ... Then choose actually a fixed-width font such as Courier in the pull-down list under the box for the Proportional Font. Or you can read the post he From: Robert Clark ) Subject: Empirically Confirmed Superluminal Velocities? Newsgroups: sci.physics.relativity, alt.sci.physics.new-theories, sci.physics, sci.astro Date: 2003-11-07 11:49:03 PST http://groups.google.com/groups?selm...g .google.com The diagram itself I took from the article: "Slow" and "Fast" Light. by Robert W. Boyd and Daniel J. Gauthier http://www.phy.duke.edu/research/pho...ssInOptics.pdf It appears in Fig. 1 on page 21. The conclusion that under the accepted explanation the exiting Sommerfeld precursor reflected back reaches the start 124 nanoseconds before the start peak reaches the chamber is puzzling however. This would also seem to mean that this reflected precursor reaches the start *before* the precursor of the start pulse as well. But it is this precursor of the start pulse that is supposed to get the process going to begin with. Then you are back to a causality problem. I tried making the precursor of the start pulse arrive at the chamber shorter or longer than 62 nanoseconds before the start peak but I still keep coming back to the conclusion that the reflected precursor arrives at the start before the starting precursor. The only thing I can think, following the accepted explanation, is that the exiting pulse really does not look just like the entering pulse. It would for example not have that leading exiting portion. But this should be visible in the shape of the exiting pulse if true. The exiting pulse would be chopped off at the front. Bob Clark |
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#104
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EL:
Now let that wave enter the chamber and propagate at c and the wavefront reaches the far end after exactly 0.2 nanoseconds but the detector translates the maximum rate of change of the amplitude to a maximum output amplitude, and the wavefront thus triggers the timer to register the arrival of the wave-peak, which did not yet enter the chamber, which when on entering the chamber triggers the near end detector of a wave peak about 62 nanoseconds which is half the full period of the wave. A constant fraction discriminator solves that problem and is one of the most common, if not the most common method of obtaining timing marks which are independent of rise time and amplitude. Timing considerations are such a crucial part of any experiment that no experimental physicist would make such a mistake. A cfd works by splitting an input signal, inverting one of those, delaying it slightly, adding it to the non-inverted signal and taking the zero crossing of the summed signal as the timing mark, which is then output as a digital pulse (typically NIM). [...] As far as I know and am sure of my knowledge in electronics that somewhere in there measuring system there is an inverter that reports the inverse of the wave amplitude at the caesium far end while it reports a none-inverted wave amplitude at the vacuum far end. A standard way of determining the timing of two pulses is the following: +--------------- analog pulse data | ------+-|cfd|-|TAC|-- timing information In 1 +--------------- analog pulse data | ------+-|cfd|-|TAC|-- timing information In 2 Or some variation on that theme. A time-to-digital converter or time-to-amplitude (TAC) converter follows the constant fraction discriminator. The analog pulse data are then completely irrelevant for timing information. All of the timing information is in a time spectrum. It's trivial to get time resolution at a resolution of a couple of nseconds. It's possible to better than 1 ns by being careful and using a good cfd and TAC. Propagation times are always matched to account for any differences due to cable delays or elec- tronics. If anything, they would have a set up that is better than this, not worse, since this is very basic. |
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#105
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