A Physics forum. Physics Banter

If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below.

Go Back   Home » Physics Banter forum » Physics Newsgroups » The Theory of Relativity
Site Map Home Register Authors List Search Today's Posts Mark Forums Read Web Partners

Tags: , , , ,

Precession of The Perihelion of Mercury's Orbit revisited



 
 
Thread Tools Display Modes
  #1  
Old October 4th 03 posted to sci.physics.relativity
Australopithecus Afarensis
external usenet poster
 
Posts: 179
Default Precession of The Perihelion of Mercury's Orbit revisited

From the previously derived Aether Stress Equation,

c'^2 = c^2 + 2 U, where

c' = speed of light under no gravitational influence
c = speed of lgiht under gravity
U = gravitational potential

- - -

The precession of Mercury's orbit around the sun is observed very accurately
to be 5,600" (seconds) per century by astronomers through out several
generations. Among those, 5,025" are due to the effect of equinox
(inclination of Mercury's orbit), and 532" are the result of other planets.
That leaves a tiny fraction of 43" unaccounted for. The Newtonian mechanics
modified by the Principle of Relativity only accounts for 14" (about 1/3 of
43"). That leaves 28" to 29" unaccounted for in which the General Theory of
Relativity triumphally is able to explain this. Let's examine if the Aether
Stress Equation is able to do so as well.

First of all, let's assume there is no relativistic affect. So,

E = (1/2) mo v^2 - mo U, orbital mechanics equation
L = mo v R, angular momentum, where

E = total energy = constant
mo = rest mass of Mercury
v = speed of Mercury
U = gravitational potential
R = distance to the center of the sun at perihelion
L = angular momentum = constant, then

U = G M / R = (G M / L) mo v, where

G = gravitational constant
M = mass of the sun, thus

E = (1 / 2) mo v^2 - (G M / L) mo^2 v

Secondly, let's include relativistic effect of the mass. So,

E = (m - mo) c^2 - mo U
L = m v R, where

m = relativistic mass of Mercury, then

U = G M / R = (G M / L) m v = (1 + (1 / 2) v^2 / c^2) (G M / L) mo v, thus

E = (1 / 2) mo v^2 - (1 + (1 / 2) v^2 / c^2) (G M / L) mo^2 v, in which

The extra term, (1 / 2) (v^2 / c^2) (G M / L) mo^2 v, compared with
non-relativistic study, obviously is what causes the 14" of precession.

Lastly, let's examine the Aether Stress Equation as observed on Earth. So,

E = (m - mo) c^2 - mo U
L = m v R, then

U = (1 + (1 / 2) v^2 / c^2) (G M / L) mo v, thus from c'^2 = c^2 + 2 U,

E = (m - mo) c'^2 - (2 m - mo) U, or

E = (1 / 2) (c'^2 / c^2) mo v^2 - (1 + v^2 / c^2) (1 + (1 / 2) v^2 / c^2) (G
M / L) mo^2 v, or

E = (1 / 2) mo v^2 - (1 + (3 / 2) v^2 / c^2) (G M / L) mo^2 v, in which

The extra term, (3 / 2) (v^2 / c^2) (G M / L) mo^2 v, must be causing 3
times the precession of 14".

The Aether Stress Equation does agree with the Theory of General Relativity
on the unaccountable precession of Mercury's orbit's perihelion to the sun.



Ads
  #2  
Old October 4th 03 posted to sci.physics.relativity
Ken S. Tucker
external usenet poster
 
Posts: 7,544
Default Precession of The Perihelion of Mercury's Orbit revisited

"Australopithecus Afarensis" wrote in message news:86sfb.46997$vj2.21813@fed1read06...
Hi Lucy,

From the previously derived Aether Stress Equation,

c'^2 = c^2 + 2 U, where

c' = speed of light under no gravitational influence
c = speed of lgiht under gravity
U = gravitational potential


In which direction is the the light going?
Is it radial, or tangential?
We discussed this before and you are not clear
on the meaning of c' or c, so would you specify
directions and magnitudes.
Ken S. Tucker
  #3  
Old October 4th 03 posted to sci.physics.relativity
xxein
external usenet poster
 
Posts: 609
Default Precession of The Perihelion of Mercury's Orbit revisited

"Australopithecus Afarensis" wrote in message news:86sfb.46997$vj2.21813@fed1read06...
From the previously derived Aether Stress Equation,

c'^2 = c^2 + 2 U, where

c' = speed of light under no gravitational influence
c = speed of lgiht under gravity
U = gravitational potential

- - -

The precession of Mercury's orbit around the sun is observed very accurately
to be 5,600" (seconds) per century by astronomers through out several
generations. Among those, 5,025" are due to the effect of equinox
(inclination of Mercury's orbit), and 532" are the result of other planets.
That leaves a tiny fraction of 43" unaccounted for. The Newtonian mechanics
modified by the Principle of Relativity only accounts for 14" (about 1/3 of
43"). That leaves 28" to 29" unaccounted for in which the General Theory of
Relativity triumphally is able to explain this. Let's examine if the Aether
Stress Equation is able to do so as well.

First of all, let's assume there is no relativistic affect. So,

E = (1/2) mo v^2 - mo U, orbital mechanics equation
L = mo v R, angular momentum, where

E = total energy = constant
mo = rest mass of Mercury
v = speed of Mercury
U = gravitational potential
R = distance to the center of the sun at perihelion
L = angular momentum = constant, then

U = G M / R = (G M / L) mo v, where

G = gravitational constant
M = mass of the sun, thus

E = (1 / 2) mo v^2 - (G M / L) mo^2 v

Secondly, let's include relativistic effect of the mass. So,

E = (m - mo) c^2 - mo U
L = m v R, where

m = relativistic mass of Mercury, then

U = G M / R = (G M / L) m v = (1 + (1 / 2) v^2 / c^2) (G M / L) mo v, thus

E = (1 / 2) mo v^2 - (1 + (1 / 2) v^2 / c^2) (G M / L) mo^2 v, in which

The extra term, (1 / 2) (v^2 / c^2) (G M / L) mo^2 v, compared with
non-relativistic study, obviously is what causes the 14" of precession.

Lastly, let's examine the Aether Stress Equation as observed on Earth. So,

E = (m - mo) c^2 - mo U
L = m v R, then

U = (1 + (1 / 2) v^2 / c^2) (G M / L) mo v, thus from c'^2 = c^2 + 2 U,

E = (m - mo) c'^2 - (2 m - mo) U, or

E = (1 / 2) (c'^2 / c^2) mo v^2 - (1 + v^2 / c^2) (1 + (1 / 2) v^2 / c^2) (G
M / L) mo^2 v, or

E = (1 / 2) mo v^2 - (1 + (3 / 2) v^2 / c^2) (G M / L) mo^2 v, in which

The extra term, (3 / 2) (v^2 / c^2) (G M / L) mo^2 v, must be causing 3
times the precession of 14".

The Aether Stress Equation does agree with the Theory of General Relativity
on the unaccountable precession of Mercury's orbit's perihelion to the sun.


xxein: Are you saying that it is still unaccountable? Kidding.
  #4  
Old October 4th 03 posted to sci.physics.relativity
Australopithecus Afarensis
external usenet poster
 
Posts: 179
Default Precession of The Perihelion of Mercury's Orbit revisited

Since U = G M / r, where

r = distance away from the center of the sun

Therefore, according to the Aether Stress Equation, the speed of light would
decrease radially into the sun. c' is thus the speed of light in the
interstellar space or intergalactic space.

U, c, and c' are all scalars with c' being the constant according to the
size of our universe. As our universe expands, c' would also increase.

c(r) = c' sqrt(1 - 2 U(r) / c'^2) = c' sqrt(1 - 2 G M / (r c'^2))

With the Aether Stress Equation, I can explain everything which GR can
except the deflection of a photon near the sun. This equation tells me a
photon would not be deflected but shifted by (2 G M / c'^2 = 3,000m) instead
as it leaves the sun. The amount of shifting is derived from Snell's Law as
the speed of light decreases going into the vicinity of the sun and
increases leaving the sun. Not by gravity because a photon has zero rest
mass so no gravitational effect just the lens effect. In this way, both the
energy and momentum are conserved unlike GR.

With the Aether Stress Equation, I can also tie all four forces together and
explain the history as well as the fate of our universe which GR fails on
both accounts.

* * *

"Ken S. Tucker" wrote in message
om...
"Australopithecus Afarensis" wrote in message
news:86sfb.46997$vj2.21813@fed1read06...
Hi Lucy,

From the previously derived Aether Stress Equation,

c'^2 = c^2 + 2 U, where

c' = speed of light under no gravitational influence
c = speed of lgiht under gravity
U = gravitational potential


In which direction is the the light going?
Is it radial, or tangential?
We discussed this before and you are not clear
on the meaning of c' or c, so would you specify
directions and magnitudes.
Ken S. Tucker


  #5  
Old October 5th 03 posted to sci.physics.relativity
Ken S. Tucker
external usenet poster
 
Posts: 7,544
Default Precession of The Perihelion of Mercury's Orbit revisited

"Australopithecus Afarensis" wrote in message news:K%Gfb.47301$vj2.34526@fed1read06...

Since U = G M / r, where

r = distance away from the center of the sun

Therefore, according to the Aether Stress Equation,


Lucy, you either prove to yourself that you are an
extremely brilliant mathematical physicist able to
displace the 1906 Theory of Relativity, that needs
no Aether or move forward into the year 2003.

the speed of light would
decrease radially into the sun. c' is thus the speed of light in the
interstellar space or intergalactic space.

U, c, and c' are all scalars with c' being the constant according to the
size of our universe. As our universe expands, c' would also increase.

c(r) = c' sqrt(1 - 2 U(r) / c'^2) = c' sqrt(1 - 2 G M / (r c'^2))


This equation disagrees with GR.

With the Aether Stress Equation, I can explain everything which GR can
except the deflection of a photon near the sun.


Thats because in GR

c(r) = c*(1-2GM/rc^2)
and does indeed predict the correct deflection.
Ken S. Tucker
.....
  #6  
Old October 6th 03 posted to sci.physics.relativity
Australopithecus Afarensis
external usenet poster
 
Posts: 179
Default Precession of The Perihelion of Mercury's Orbit revisited

In GR, the speed of light = c = 3e8m/sec. To balance Minkowski's Space-Time
Equation, it is necessary for Einstein to introduce time dilation and curved
space. In my hypothesis, there is no time dilation nor curved space. To
equation Minkowski's Space-Time Equation, the speed of light has to vary.
This is worked out backwards. The expanding universe creates the Aether.
Presence of rest mass stresses the Aether surrounding it. Since the speed
of light is the property of the Aether, it varies according to how much the
Aether is stressed. Conveniently, the gradient, del(c^2 / 2) = dU/dr, is
the perceived gravitational force which only affect the rest mass. Gravity
is the manifestation of the Aether.

On the subject of the Aether, it does not have to be something of substance
or tangible. The Aether I am describing is just simply the difference
between the space inside of our universe and the space outside of our
universe. Over time, the space inside our universe would have properties
very close to the space outside of our universe. Remember that the property
of Maxwell's Aether is c^2. c' (the speed of light in intergalactic space)
is a far more important entity than what Einstein just called it another
constant. Physicists even equate c = 1 or c' = 1 to my horror. c' started
as (c' = 0+) infinite years ago and grows to be 3e8m/sec today. It will
blossom to infinity infinite years from now. At one time or at some
gravitational potential, the gravitational force dominates over all other
forces because the speed of light is much lower.

I'd rather be convinced by others to myself that I need to move forward into
the year 2,003 and beyond than be regarded as the most brilliant theoretical
physicist of all time posthumously. If any one can help me to move forward
into the year 2,003 and beyond in a logical and scientifically
conformed-to-2,003 way, I will be grateful. In the meantime, I have
finished my white paper on this subject. Upon request, I can drop a pdf
file into your email.

* * *

"Ken S. Tucker" wrote in message
om...
"Australopithecus Afarensis" wrote in message
news:K%Gfb.47301$vj2.34526@fed1read06...

Since U = G M / r, where

r = distance away from the center of the sun

Therefore, according to the Aether Stress Equation,


Lucy, you either prove to yourself that you are an
extremely brilliant mathematical physicist able to
displace the 1906 Theory of Relativity, that needs
no Aether or move forward into the year 2003.

the speed of light would
decrease radially into the sun. c' is thus the speed of light in the
interstellar space or intergalactic space.

U, c, and c' are all scalars with c' being the constant according to the
size of our universe. As our universe expands, c' would also increase.

c(r) = c' sqrt(1 - 2 U(r) / c'^2) = c' sqrt(1 - 2 G M / (r c'^2))


This equation disagrees with GR.

With the Aether Stress Equation, I can explain everything which GR can
except the deflection of a photon near the sun.


Thats because in GR

c(r) = c*(1-2GM/rc^2)
and does indeed predict the correct deflection.
Ken S. Tucker
.....


  #7  
Old October 6th 03 posted to sci.physics.relativity
Ken S. Tucker
external usenet poster
 
Posts: 7,544
Default Precession of The Perihelion of Mercury's Orbit revisited

"Australopithecus Afarensis" wrote in message news:cq5gb.52656$vj2.8915@fed1read06...
Lucy please do not top post...

In GR, the speed of light = c = 3e8m/sec.


We discussed this before, in GR there is a vacuum speed of light
commonly denoted c, a radial c(r) and a tangential c(t), why
do I need to guess which you are referring too?

To balance Minkowski's Space-Time
Equation, it is necessary for Einstein to introduce time dilation and curved
space. In my hypothesis, there is no time dilation nor curved space. To
equation Minkowski's Space-Time Equation, the speed of light has to vary.


It does in a g-field, and that's equivalent to time dilation and
curvature.

This is worked out backwards. The expanding universe creates the Aether.
Presence of rest mass stresses the Aether surrounding it. Since the speed
of light is the property of the Aether, it varies according to how much the
Aether is stressed. Conveniently, the gradient, del(c^2 / 2) = dU/dr, is
the perceived gravitational force which only affect the rest mass. Gravity
is the manifestation of the Aether.

On the subject of the Aether, it does not have to be something of substance
or tangible. The Aether I am describing is just simply the difference
between the space inside of our universe and the space outside of our
universe. Over time, the space inside our universe would have properties
very close to the space outside of our universe. Remember that the property
of Maxwell's Aether is c^2. c' (the speed of light in intergalactic space)
is a far more important entity than what Einstein just called it another
constant. Physicists even equate c = 1 or c' = 1 to my horror. c' started
as (c' = 0+) infinite years ago and grows to be 3e8m/sec today. It will
blossom to infinity infinite years from now. At one time or at some
gravitational potential, the gravitational force dominates over all other
forces because the speed of light is much lower.

I'd rather be convinced by others to myself that I need to move forward into
the year 2,003 and beyond than be regarded as the most brilliant theoretical
physicist of all time posthumously.
If any one can help me to move forward
into the year 2,003 and beyond in a logical and scientifically
conformed-to-2,003 way, I will be grateful. In the meantime, I have
finished my white paper on this subject. Upon request, I can drop a pdf
file into your email.


Set up a link for all to view, that way, if my comments are
untrue, they will be critcized. My personal point of view
is rather unimportant left uncriticized.
Ken S. Tucker

* * *

"Ken S. Tucker" wrote in message
. com...
"Australopithecus Afarensis" wrote in message
news:K%Gfb.47301$vj2.34526@fed1read06...

Since U = G M / r, where

r = distance away from the center of the sun

Therefore, according to the Aether Stress Equation,


Lucy, you either prove to yourself that you are an
extremely brilliant mathematical physicist able to
displace the 1906 Theory of Relativity, that needs
no Aether or move forward into the year 2003.

the speed of light would
decrease radially into the sun. c' is thus the speed of light in the
interstellar space or intergalactic space.

U, c, and c' are all scalars with c' being the constant according to the
size of our universe. As our universe expands, c' would also increase.

c(r) = c' sqrt(1 - 2 U(r) / c'^2) = c' sqrt(1 - 2 G M / (r c'^2))


This equation disagrees with GR.

With the Aether Stress Equation, I can explain everything which GR can
except the deflection of a photon near the sun.


Thats because in GR

c(r) = c*(1-2GM/rc^2)
and does indeed predict the correct deflection.
Ken S. Tucker

  #8  
Old October 7th 03 posted to sci.physics.relativity
Australopithecus Afarensis
external usenet poster
 
Posts: 179
Default Precession of The Perihelion of Mercury's Orbit revisited

Come on, Ken. You are turning the speed of light, which has been regarded
as a scalar ever since I don't remember when in the history of science, into
a vector!!! I can sort of follow what you are saying because of the
curvature of space introduced by GR which can result in a radial velocity of
the speed of light into the geometric center of the curved space and the
tangential component of the speed of light along the geodesic (one of the
tall words invented by GR to deify the priesthood governing the faith
created by Einstein).

Although we have exact equation regarding c(r), my equation is strictly
applied to the speed of light in the scalar form in which it is very much
tangible and very Euclidean that you and I can detect, measure, and feel.
It is the way physics is supposed to be through observation according to our
intellects.

As Dirk has pointed out, I am trained as an engineer by profession. In my
career, I have examined and modified quite a few engineering systems into
something a lot simpler than the initial design which is extremely
eye-popping to the original designer. In this problem of GR versus gravity
deal, I do see the same tend. It is nothing new to me. Perhaps, that is
why all things are getting simpler. Have you hear what Feynman said?

"You can recognize truth by its beauty and simplicity. When you get it
right, it is obvious that it is right -- at least if you have any
experience -- because usually what happens is that more comes out than goes
in... The inexperienced, the crackpots, and people like that, make guesses
that are simple, but you can immediately see that they are wrong, so that
does not count. Others, the inexperienced students, make guesses that are
very complicated, and it sort of looks as if it is all right, but I know it
is not true because the truth always turns out to be simpler that you
thought..."


In my humble career, I have done just exactly what he was saying. I even
tried to live a very simple life with great success until I got married.
Now, my wife is expecting twins. I am still expecting and pursuing
simplicity to my life.

* * *

"Ken S. Tucker" wrote in message
om...
"Australopithecus Afarensis" wrote in message
news:cq5gb.52656$vj2.8915@fed1read06...
Lucy please do not top post...

In GR, the speed of light = c = 3e8m/sec.


We discussed this before, in GR there is a vacuum speed of light
commonly denoted c, a radial c(r) and a tangential c(t), why
do I need to guess which you are referring too?

To balance Minkowski's Space-Time
Equation, it is necessary for Einstein to introduce time dilation and

curved
space. In my hypothesis, there is no time dilation nor curved space. To
equation Minkowski's Space-Time Equation, the speed of light has to vary.


It does in a g-field, and that's equivalent to time dilation and
curvature.

This is worked out backwards. The expanding universe creates the Aether.
Presence of rest mass stresses the Aether surrounding it. Since the speed
of light is the property of the Aether, it varies according to how much the
Aether is stressed. Conveniently, the gradient, del(c^2 / 2) = dU/dr, is
the perceived gravitational force which only affect the rest mass. Gravity
is the manifestation of the Aether.

On the subject of the Aether, it does not have to be something of substance
or tangible. The Aether I am describing is just simply the difference
between the space inside of our universe and the space outside of our
universe. Over time, the space inside our universe would have properties
very close to the space outside of our universe. Remember that the

property
of Maxwell's Aether is c^2. c' (the speed of light in intergalactic space)
is a far more important entity than what Einstein just called it another
constant. Physicists even equate c = 1 or c' = 1 to my horror. c' started
as (c' = 0+) infinite years ago and grows to be 3e8m/sec today. It will
blossom to infinity infinite years from now. At one time or at some
gravitational potential, the gravitational force dominates over all other
forces because the speed of light is much lower.

I'd rather be convinced by others to myself that I need to move forward

into
the year 2,003 and beyond than be regarded as the most brilliant

theoretical
physicist of all time posthumously.
If any one can help me to move forward
into the year 2,003 and beyond in a logical and scientifically
conformed-to-2,003 way, I will be grateful. In the meantime, I have
finished my white paper on this subject. Upon request, I can drop a pdf
file into your email.


Set up a link for all to view, that way, if my comments are
untrue, they will be critcized. My personal point of view
is rather unimportant left uncriticized.
Ken S. Tucker

* * *

"Ken S. Tucker" wrote in message
. com...
"Australopithecus Afarensis" wrote in message
news:K%Gfb.47301$vj2.34526@fed1read06...

Since U = G M / r, where

r = distance away from the center of the sun

Therefore, according to the Aether Stress Equation,


Lucy, you either prove to yourself that you are an
extremely brilliant mathematical physicist able to
displace the 1906 Theory of Relativity, that needs
no Aether or move forward into the year 2003.

the speed of light would
decrease radially into the sun. c' is thus the speed of light in the
interstellar space or intergalactic space.

U, c, and c' are all scalars with c' being the constant according to the
size of our universe. As our universe expands, c' would also increase.

c(r) = c' sqrt(1 - 2 U(r) / c'^2) = c' sqrt(1 - 2 G M / (r c'^2))


This equation disagrees with GR.

With the Aether Stress Equation, I can explain everything which GR can
except the deflection of a photon near the sun.


Thats because in GR

c(r) = c*(1-2GM/rc^2)
and does indeed predict the correct deflection.
Ken S. Tucker



  #9  
Old October 7th 03 posted to sci.physics.relativity
Ken S. Tucker
external usenet poster
 
Posts: 7,544
Default Precession of The Perihelion of Mercury's Orbit revisited

"Australopithecus Afarensis" wrote in message news:E8sgb.52938$vj2.42004@fed1read06...

((lucy I thought you we're a girl, congrads
on your wife expecting twins...I guess you
have sperm squared)).

Allow me to top post...as you do...
First this is nearly right,
then this is almost wrong,
next, I might agree with this,
and I think this is way out.
KST

Come on, Ken. You are turning the speed of light, which has been regarded
as a scalar ever since I don't remember when in the history of science, into
a vector!!! I can sort of follow what you are saying because of the
curvature of space introduced by GR which can result in a radial velocity of
the speed of light into the geometric center of the curved space and the
tangential component of the speed of light along the geodesic (one of the
tall words invented by GR to deify the priesthood governing the faith
created by Einstein).


I know a lot more about relativity than Einstein, (he passed
away in 1955), and I respect his basic developements. I've
been able to improve some of the technical mathematical
details, so that some awkward math (circa 1914) can be
improved. But his application of tensors to Newtons g-field
was first class.
 




Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Forum Jump

Similar Threads
Thread Thread Starter Forum Replies Last Post
Mercury's precession in Marion's Classical Dynamics Dave L. Renfro Physics - General Discussion 0 December 5th 05 11:14 PM
Mercury's precession in Marion's Classical Dynamics Dave L. Renfro Current Physics Research (Moderated) 0 December 5th 05 11:14 PM
LeSagian drag and the advance of Mercury's perihelion stopgoblinlittleminds@yahoo.com Physics - General Discussion 7 June 17th 05 03:56 AM
Photon Mass, Measuring Distance, and Mercury's orbit Mike Helland Physics - General Discussion 1 July 27th 04 01:06 AM
Is Mercury's perihelion skrinking? Bob Day Current Physics Research (Moderated) 4 November 3rd 03 03:41 AM


All times are GMT +1. The time now is 04:27 AM.


Powered by vBulletin® Version 3.6.4
Copyright ©2000 - 2008, Jelsoft Enterprises Ltd.Search Engine Friendly URLs by vBSEO 2.4.0
Copyright ©2004-2008 Physics Banter, part of the NewsgroupBanter project.
The comments are property of their posters.
Mortgages - Loans - Credit Cards - Loans - Online Loans