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| Tags: definition, quotlorentz, transformationquot |
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#22
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Subject: Definition of "Lorentz Transformation"
From: "Pmb" Date: 9/28/2003 12:48 PM US Mountain Standard Time Message-id: "WaiteDavid137" wrote I already mathematically proved it. Go back and read it. Are you gonna prove your definition is correct I already mathematically prove that my/everyone elses definition is correct. Go back and read the whole thing. |
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#23
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Subject: Definition of "Lorentz Transformation"
From: "Pmb" Date: 9/28/2003 12:49 PM US Mountain Standard Time Message-id: "WaiteDavid137" wrote in message ... Subject: Definition of "Lorentz Transformation" From: "Martin Hogbin" Date: 9/28/2003 5:11 AM US Mountain Standard Time Message-id: "Pmb" wrote in message . .. "Martin Hogbin" wrote in message ... I would have thought that calling them 'the Lorentz transformations in spherical polar coordinates' would make everyone happy. I'm going strictly on facts - i.e. what I see defined throughout the relativity literature. Are you merely saying that you have never seen the transformations of SR expressed in terms spherical polar coordinates described as the 'Lorentz transformations'? He must only see selectively because I posted them here already. A Lorentz transformation is that subset of transformations which are orthogonal and leave the Minkowski metric unchanged. Which is why what I wrote is indeed the Lorentz transformation in spherical coordinates. |
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#24
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"WaiteDavid137" wrote [****] And the moron is back to repeat **** siince he can't back up his claim I knew you were a coward - a dumb one too Mr. - Pmb - waite's relativity teacher |
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#25
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"WaiteDavid137" wrote in message ... Subject: Definition of "Lorentz Transformation" From: "Pmb" Date: 9/28/2003 12:49 PM US Mountain Standard Time Message-id: "WaiteDavid137" wrote in message ... Subject: Definition of "Lorentz Transformation" From: "Martin Hogbin" Date: 9/28/2003 5:11 AM US Mountain Standard Time Message-id: "Pmb" wrote in message . .. "Martin Hogbin" wrote in message ... I would have thought that calling them 'the Lorentz transformations in spherical polar coordinates' would make everyone happy. I'm going strictly on facts - i.e. what I see defined throughout the relativity literature. Are you merely saying that you have never seen the transformations of SR expressed in terms spherical polar coordinates described as the 'Lorentz transformations'? He must only see selectively because I posted them here already. A Lorentz transformation is that subset of transformations which are orthogonal and leave the Minkowski metric unchanged. Which is why what I wrote is indeed the Lorentz transformation in spherical coordinates. Wrong. You have no clue what you're talking about - again. A Lorentz transformation ONLY maps Lorentz coordinates to Lorentz coordinates and spherical coordinates ARE NOT Lorentz coordinate idiot. One CAN map from spherical to Cartesian in S and THEN ***Lorentz transform*** to Cartesian in S to Cartesian in S' and THEN map to spherical. Stop being a pest and go learn what an orthogonal transformation is - you're wasting everyone's time with this childish nonsense of your - refusing to learn just proves you're a crackpot. Mr. - Pmb - waite's relativity teacher |
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#26
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(Bilge) wrote in message ...
Hi Pmb: [...] incorrect. While there most certainly exists transformations as suich and which leave the spacetime interval ds^2 invariant they are not refered to as "Lorentz Transformations." That term has a very specific meaning. Lorentz transforms are transforms which preserve inertial frames. Let S have coordinates X = (t,x,y,z) and S' have coordinates X' = (t',x',y',z'). These coordinates are often refered to as "Lorentz Coordinates" or "Minkowski Coordinates." Let n = Minkowski metric = diag(1,-1,-1,-1). The correct, precise, definition of a Lorentz transformation is as follows Definition: A transformation L from X to X', i.e. X' = LX, is a transformation for which n'LL = n. Thats obviously incorrect. The rotation: [ cos(A) -sin(A) ] X' = [ ] X [ sin(A) cos(A) ] Doesn't satisfy the relation you've written, since LL = L^2 != 1. Multiply it out. You also might try actually writing the equations out instead of trying to use notational shortcuts that only let you shoot yourself in the foot. Such transformations include rotations, reflections and boosts. Unfortunately, your definition only gives reflections, since the operator LLX only equals X for L = +/- 1. This definition is found in most decent texts on relativity and tensor analysis. Sources - From Thorne and Blanchard's new text -- http://www.pma.caltech.edu/Courses/p...p01/0201.2.pdf - page 28 Which doesn't agree with you. What they have written is: q_uv L^u_a L^v_b = g_ab L^u_a and L^v_b are inverses of each other. That is not what you have written. In particular, rotations are orthogonal transformations and an orthogonal transformation is defined by a matrix for which the transpose is equal to the inverse. Also, note the example they give at the top of the next page (29). Furthermore, the relations given don't _define_ lorentz transforms. What your reference says is that a transform which satisfies those relations is a lorentz transform. But, that's strictly because the transforms were derived in order to preserve the scalar product under the assumption of the minkowski metric. To wit, your reference defines the transforms by first defining X and X' as inertial frames. In order to find a transform between them, the transformation has to preserve inertial frames. (I was worried about, bilge, started checking the obituaries) So far the only substance I have in Pmb's OP is the legalese difference between s^2 = g_uv x^u x^v and ds^2 = g_uv dx^u dx^v. The first requires uniform velocity and a constant metric, to be firmly the requirement of the Lorentz Transform. The second (ds^2) goes beyond simplistic LT and into the realm of accelerations and variable g_uv's in a manner consistent with both SR and GR, and LT. So I agree with Pete that there is not a specific name (I know of) for the second transform that renders the invariant ds^2. Regards Ken S. Tucker |
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#27
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PMB The Earth goes around the sun at 20 mps ,and is foreshortened by 3
inches. Earth being 8,000 miles in diameter that is so tiny. Best to keep in mind 20 mps is not very fast as compared to "C" Bert |
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#28
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Subject: Definition of "Lorentz Transformation"
From: "Pmb" Date: 9/28/2003 1:42 PM US Mountain Standard Time Message-id: "WaiteDavid137" wrote in message ... Subject: Definition of "Lorentz Transformation" From: "Pmb" Date: 9/28/2003 12:49 PM US Mountain Standard Time Message-id: "WaiteDavid137" wrote in message ... Subject: Definition of "Lorentz Transformation" From: "Martin Hogbin" Date: 9/28/2003 5:11 AM US Mountain Standard Time Message-id: "Pmb" wrote in message . .. "Martin Hogbin" wrote in message ... I would have thought that calling them 'the Lorentz transformations in spherical polar coordinates' would make everyone happy. I'm going strictly on facts - i.e. what I see defined throughout the relativity literature. Are you merely saying that you have never seen the transformations of SR expressed in terms spherical polar coordinates described as the 'Lorentz transformations'? He must only see selectively because I posted them here already. A Lorentz transformation is that subset of transformations which are orthogonal and leave the Minkowski metric unchanged. Which is why what I wrote is indeed the Lorentz transformation in spherical coordinates. A Lorentz transformation ONLY maps Lorentz coordinates to Lorentz coordinates Its rather silly that you are so insistant on renaming Cartesian coordinates Lorentz coordinates, but no that is not the definition of Lorentz transformation. The definition is that which preserves the invariance that I discussed. |
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#29
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Subject: Definition of "Lorentz Transformation"
From: (Ken S. Tucker) Date: 9/28/2003 2:06 PM US Mountain Standard Time Message-id: (Bilge) wrote in message e-al.net... Hi Pmb: [...] incorrect. While there most certainly exists transformations as suich and which leave the spacetime interval ds^2 invariant they are not refered to as "Lorentz Transformations." That term has a very specific meaning. Lorentz transforms are transforms which preserve inertial frames. Let S have coordinates X = (t,x,y,z) and S' have coordinates X' = (t',x',y',z'). These coordinates are often refered to as "Lorentz Coordinates" or "Minkowski Coordinates." Let n = Minkowski metric = diag(1,-1,-1,-1). The correct, precise, definition of a Lorentz transformation is as follows Definition: A transformation L from X to X', i.e. X' = LX, is a transformation for which n'LL = n. Thats obviously incorrect. The rotation: [ cos(A) -sin(A) ] X' = [ ] X [ sin(A) cos(A) ] Doesn't satisfy the relation you've written, since LL = L^2 != 1. Multiply it out. You also might try actually writing the equations out instead of trying to use notational shortcuts that only let you shoot yourself in the foot. Such transformations include rotations, reflections and boosts. Unfortunately, your definition only gives reflections, since the operator LLX only equals X for L = +/- 1. This definition is found in most decent texts on relativity and tensor analysis. Sources - From Thorne and Blanchard's new text -- http://www.pma.caltech.edu/Courses/p...p01/0201.2.pdf - page 28 Which doesn't agree with you. What they have written is: q_uv L^u_a L^v_b = g_ab L^u_a and L^v_b are inverses of each other. That is not what you have written. In particular, rotations are orthogonal transformations and an orthogonal transformation is defined by a matrix for which the transpose is equal to the inverse. Also, note the example they give at the top of the next page (29). Furthermore, the relations given don't _define_ lorentz transforms. What your reference says is that a transform which satisfies those relations is a lorentz transform. But, that's strictly because the transforms were derived in order to preserve the scalar product under the assumption of the minkowski metric. To wit, your reference defines the transforms by first defining X and X' as inertial frames. In order to find a transform between them, the transformation has to preserve inertial frames. (I was worried about, bilge, started checking the obituaries) So far the only substance I have in Pmb's OP is the legalese difference between s^2 = g_uv x^u x^v and ds^2 = g_uv dx^u dx^v. The first requires uniform velocity and a constant metric, to be firmly the requirement of the Lorentz Transform. The second (ds^2) goes beyond simplistic LT and into the realm of accelerations and variable g_uv's in a manner consistent with both SR and GR, and LT. So I agree with Pete that there is not a specific name (I know of) for the second transform that renders the invariant ds^2. Regards Ken S. Tucker No, the first is wrong. The second isn't directly relavent. The next is what Lorentz transformations preserve the invariance of ds^2 = eta_mu_nudx^mudx^nu The Lorentz transformations I gave in spherical coordinates do so where eta and dx are expressed in terms of those spherical coordinates. Special relativity is usually best done, but need not be done in Cartesian coordinates. |
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#30
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"WaiteDavid137" wrote [nonsense] More proof and less unsubstantiated parroting waite Pmb |
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