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Gamma Formula



 
 
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  #1  
Old September 16th 03 posted to sci.physics,sci.physics.relativity
rotheini@yahoo.de
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Posts: 7
Default Gamma Formula

Gamma

I am a passenger on a spaceship named Frame1. We left earth (Frame0)
yesterday and accelerated to 150,000,000m/sec wrt Frame0. On earth,
our spaceship was built to be 1000m long.

As we continue to maintain our speed of 150,000,000m/sec, the Captain
tells us that our length as seen by earth would be 866m. He said that
the reduced length was the result of relativity. He said it could be
calculated by the gamma formula, ie
1000*sqrt(1-1500000000^2/300000000^2).

Did the Captain apply the formula correctly?

Rotheini
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  #3  
Old September 17th 03 posted to sci.physics,sci.physics.relativity
Pmb
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Posts: 817
Default Gamma Formula


wrote in message
om...
Gamma

I am a passenger on a spaceship named Frame1. We left earth (Frame0)
yesterday and accelerated to 150,000,000m/sec wrt Frame0. On earth,
our spaceship was built to be 1000m long.

As we continue to maintain our speed of 150,000,000m/sec, the Captain
tells us that our length as seen by earth would be 866m. He said that
the reduced length was the result of relativity. He said it could be
calculated by the gamma formula, ie
1000*sqrt(1-1500000000^2/300000000^2).

Did the Captain apply the formula correctly?


Seems like someone added an extra zero to the velocity in the gamma factor.
To make this more transparent let

L = 1000m
v = 150,000,000m/s
c = 298,000,000m/s

L' = Length measured in Earth Frame

Then L' = L*sqrt[1-(v/c)^2]

Pmb


  #7  
Old October 1st 03 posted to sci.physics,sci.physics.relativity
rotheini@yahoo.de
external usenet poster
 
Posts: 7
Default Gamma Formula

(HenriWilson) wrote in message . ..
On 16 Sep 2003 14:28:06 -0700,
wrote:

Gamma

I am a passenger on a spaceship named Frame1. We left earth (Frame0)
yesterday and accelerated to 150,000,000m/sec wrt Frame0. On earth,
our spaceship was built to be 1000m long.

As we continue to maintain our speed of 150,000,000m/sec, the Captain
tells us that our length as seen by earth would be 866m. He said that
the reduced length was the result of relativity. He said it could be
calculated by the gamma formula, ie
1000*sqrt(1-1500000000^2/300000000^2).

Did the Captain apply the formula correctly?

Rotheini


Why does an Earth observer's hypothetical measurement using a bogus equation
have any bearing on reality?

No changes occur in the spaceship's length or clocks due to its velocity.

Henri Wilson.

See my animations at:
http://www.users.bigpond.com/HeWn/index.htm
My latest: http://www.users.bigpond.com/HeWn/movingrod.exe


Henri,

SR and Gamma are accepted by a great majority of physicists and are
taught by higher educational institutions as the correct state of
knowledge. Your objections according to the material you have
published lacks from simplicity and therefore can easily be faulted by
experts. You place much emphasis on your animated MMX demonstration
diagram. People may actually believe your clever program is meant not
only to replace MMX but to 'prove' with the power of the computer that
MMX has a rational null effect explanation. At best, the computer can
only illustrate a point, just as a drawing can. It cannot 'prove'
anything.

Rotheini
  #8  
Old October 1st 03 posted to sci.physics,sci.physics.relativity
HenriWilson
external usenet poster
 
Posts: 2,762
Default Gamma Formula

On 30 Sep 2003 20:52:56 -0700, wrote:

(HenriWilson) wrote in message . ..
On 16 Sep 2003 14:28:06 -0700,
wrote:

Gamma

I am a passenger on a spaceship named Frame1. We left earth (Frame0)
yesterday and accelerated to 150,000,000m/sec wrt Frame0. On earth,
our spaceship was built to be 1000m long.

As we continue to maintain our speed of 150,000,000m/sec, the Captain
tells us that our length as seen by earth would be 866m. He said that
the reduced length was the result of relativity. He said it could be
calculated by the gamma formula, ie
1000*sqrt(1-1500000000^2/300000000^2).

Did the Captain apply the formula correctly?

Rotheini


Why does an Earth observer's hypothetical measurement using a bogus equation
have any bearing on reality?

No changes occur in the spaceship's length or clocks due to its velocity.

Henri Wilson.

See my animations at:
http://www.users.bigpond.com/HeWn/index.htm
My latest: http://www.users.bigpond.com/HeWn/movingrod.exe


Henri,

SR and Gamma are accepted by a great majority of physicists and are
taught by higher educational institutions as the correct state of
knowledge. Your objections according to the material you have
published lacks from simplicity and therefore can easily be faulted by
experts. You place much emphasis on your animated MMX demonstration
diagram. People may actually believe your clever program is meant not
only to replace MMX but to 'prove' with the power of the computer that
MMX has a rational null effect explanation. At best, the computer can
only illustrate a point, just as a drawing can. It cannot 'prove'
anything.

Rotheini


LT's are illusions.

Physical properties do not change just because an observer passes by, you know.
If all measurements are made using my 'instantaneous universe' concept, we
don't have to interpret physical reality from what we perceive using a finite
communication rate.

The fact that a majority accepts Einstein's stupid theory only highlights the
extent of the indoctrination throughout the physics establishment.

Henri Wilson.

"Whenever a relativist moves, half the universe shrinks and the other half expands".

See my animations at:
http://www.users.bigpond.com/HeWn/index.htm
 




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