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| Tags: invariant, length |
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#1
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I was wondering if the electron compton wavelength divided by 2pi is an
invariant quantity? A main result from compton scattering is, lambda_C/2pi = hbar/m_e*c Everything on the right hand side of the equation is invariant, so why wouldn't this length be invariant? FrediFizzx |
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#2
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FrediFizzx wrote in message ... I was wondering if the electron compton wavelength divided by 2pi is an invariant quantity? A main result from compton scattering is, lambda_C/2pi = hbar/m_e*c Everything on the right hand side of the equation is invariant, so why wouldn't this length be invariant? FrediFizzx Old Man Thinks that freddi is correct. In anology to (mc^2)^2 = E^2 - (pc)^2 or (mc)^2 = (E / c)^2 - p^2 wherein mc^2 is Lorentz invariant, we can write (hbar / L_compton)^2 = (hbar / L_einstein)^2 - (hbar / L_debroglie)^2 [Old Man] |
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#3
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FrediFizzx wrote:
I was wondering if the electron compton wavelength divided by 2pi is an invariant quantity? A main result from compton scattering is, lambda_C/2pi = hbar/m_e*c Everything on the right hand side of the equation is invariant, so why wouldn't this length be invariant? Are you sure the m is the rest mass? Thanks Bill |
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#4
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"Bill Hobba" wrote in message
... | FrediFizzx wrote: | I was wondering if the electron compton wavelength divided by 2pi is an | invariant quantity? A main result from compton scattering is, | | lambda_C/2pi = hbar/m_e*c | | Everything on the right hand side of the equation is invariant, so why | wouldn't this length be invariant? | | Are you sure the m is the rest mass? Why wouldn't it be? FrediFizzx |
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#5
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"Old Man" wrote in message
... | | FrediFizzx wrote in message | ... | I was wondering if the electron compton wavelength divided by 2pi is an | invariant quantity? A main result from compton scattering is, | | lambda_C/2pi = hbar/m_e*c | | Everything on the right hand side of the equation is invariant, so why | wouldn't this length be invariant? | | FrediFizzx | | Old Man Thinks that freddi is correct. In anology to | | (mc^2)^2 = E^2 - (pc)^2 | | or (mc)^2 = (E / c)^2 - p^2 | | wherein mc^2 is Lorentz invariant, we can write | | (hbar / L_compton)^2 = (hbar / L_einstein)^2 - (hbar / L_debroglie)^2 | | [Old Man] Thanks Old Man. Then wouldn't photon energy at the electron compton frequency be invariant? This seems strange. From the looks of your equation above, it isn't. We lose the rest mass energy of the electron. FrediFizzx |
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#6
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FrediFizzx wrote:
I was wondering if the electron compton wavelength divided by 2pi is an invariant quantity? A main result from compton scattering is, lambda_C/2pi = hbar/m_e*c That's not a "result", it's a "definition" - so in a trivial sense it is "invariant", although not in the way we usually apply the term. The Compton Wavelenth is not a fundamental property, but rather a dimensional shorthand to tidy up the expression for the wavelenth shift resulting from scattering gamma rays off of effectively stationary electrons. The equation can be written down just fine without it. For dimensional reasons, you'll also see the Compton wavelenth popping up in other contexts as well; however, if you examine Compton Scattring in a different frame (i.e. one in which the electrons are moving), you get a different scattering relationship. -Eric Everything on the right hand side of the equation is invariant, so why wouldn't this length be invariant? FrediFizzx -- ------------------------------------------------------------------- Eric Prebys, Fermi National Accelerator Laboratory Office: 630-840-8369, Email: WWW: http://home.fnal.gov/~prebys ------------------------------------------------------------------- |
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#7
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| FrediFizzx wrote: | I was wondering if the electron compton wavelength divided by 2pi is an | invariant quantity? A main result from compton scattering is, | | lambda_C/2pi = hbar/m_e*c | | Everything on the right hand side of the equation is invariant, so why | wouldn't this length be invariant? | Bill Hobba wrote: | Are you sure the m is the rest mass? FrediFizzx wrote; Why wouldn't it be? No particular reason except it has been a while since I looked at compton wavelength and thought it may have been an out for the invariance. I cant recall if it is invariant or not. A quick look at the textbooks I had left me none the wiser. Thanks Bill |
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#8
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"Bill Hobba" wrote in message
... | | | FrediFizzx wrote: | | I was wondering if the electron compton wavelength divided by 2pi is | an | | invariant quantity? A main result from compton scattering is, | | | | lambda_C/2pi = hbar/m_e*c | | | | Everything on the right hand side of the equation is invariant, so why | | wouldn't this length be invariant? | | | | Bill Hobba wrote: | | Are you sure the m is the rest mass? | | | FrediFizzx wrote; | Why wouldn't it be? | | No particular reason except it has been a while since I looked at compton | wavelength and thought it may have been an out for the invariance. I cant | recall if it is invariant or not. A quick look at the textbooks I had left | me none the wiser. Eric says it is a definition, which seems to be right. We just take three invariant constants and produce an invariant length. However, now that we have this invariant length, what is its significance? This seems to be somewhat mind boggling. Does this mean this length will always be the same no matter what frame you are looking from? Seems like it would mean that. FrediFizzx |
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#9
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Regarding the Compton wavelength Bill Hobba wrote:| | No particular reason except it has been a while since I looked at compton | wavelength and thought it may have been an out for the invariance. I cant | recall if it is invariant or not. A quick look at the textbooks I had left | me none the wiser. FrediFizzx replied: Eric says it is a definition, which seems to be right. We just take three invariant constants and produce an invariant length. However, now that we have this invariant length, what is its significance? This seems to be somewhat mind boggling. Does this mean this length will always be the same no matter what frame you are looking from? Seems like it would mean that. Not really because one would need to know the physical meaning in other reference frames. My recollection of the Compton wavelength is such that I have no idea what that. Suppose you need to have a read in a textbook. Thanks Bill |
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#10
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"Bill Hobba" wrote in message
... | | Regarding the Compton wavelength Bill Hobba wrote:| | | No particular reason except it has been a while since I looked at | compton | | wavelength and thought it may have been an out for the invariance. I | cant | | recall if it is invariant or not. A quick look at the textbooks I had | left | | me none the wiser. | | | FrediFizzx replied: | Eric says it is a definition, which seems to be right. We just take three | invariant constants and produce an invariant length. However, now that we | have this invariant length, what is its significance? This seems to be | somewhat mind boggling. Does this mean this length will always be the | same | no matter what frame you are looking from? Seems like it would mean that. | | Not really because one would need to know the physical meaning in other | reference frames. My recollection of the Compton wavelength is such that I | have no idea what that. Suppose you need to have a read in a textbook. | | Thanks | Bill If it is just a definition, which I am sure that it is, then maybe mass is our way out of this as you originally proposed. We know that mass can be converted completely to energy so to me that would mean that it can't be 100 percent invariant. It is maybe only "partially" invariant. Yeah, must hit the books for this one. But maybe it is just due to the compton wavelength applying to a photon and the mass is applying to an electron. FrediFizzx |
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