![]() |
| If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. |
|
|||||||
| Tags: divergence, ultraviolet |
|
|
Thread Tools | Display Modes |
|
#1
|
|||
|
|||
|
Ultraviolet divegence is very old problem and is not solved completely
yet. I thought we might approach this problem through introducing new quantisation into Lorentz space which is different from that on quantum mechanics. For details: http://139.134.5.123/tiddler2/c21508/relativity.htm |
| Ads |
|
#2
|
|||
|
|||
|
|
|
#4
|
|||
|
|||
|
tontoko hirorin:
Ultraviolet divegence is very old problem and is not solved completely yet. I thought we might approach this problem through introducing new quantisation into Lorentz space which is different from that on quantum mechanics. Uh, the uncertainty relations are not just defined. They are derived from the definitions of the operators (which are also canonical conjugates). You can't simply define an uncertainty relation between two variables and create a value for the commutator based upon dimensional analysis (and your dimensional analysis isn't even correct area/momentum does not give meter-seconds). You have a "commutation relation" for t and x, but t isn't an operator, nor did you define an operator for t. |
|
#5
|
|||
|
|||
|
tontoko hirorin wrote:
Ultraviolet divegence is very old problem and is not solved completely yet. I thought we might approach this problem through introducing new quantisation into Lorentz space which is different from that on quantum mechanics. I am not quite so sure you can dismiss renormalization that quickly. The divergence is cancelled by counter terms in the bare coupling constant which is itself assumed divergent. All you need to assume is the exact form of the bare coupling constant is not known at this stage. If it was known when combined with the other divergent terms they would cancel. From page 505 of Weinberg Quantum Theory of Fields he considers some rather interesting integrals: i(q) = integral 0 - infinity (dk/(k+q)). Now di/dq = integral (0 - infinity) -dk/(k+q)2 = -1/q or i(q) = -In q + c where c is divergent. Now if we have terms like the above in the Lagrangian then by adopting the effective field theory approach we can say that at this stage we do not know the full form of the bare coupling constant. If we assume it has a form like the above so that when summed together the divergent terms (which also have a form like the above) cancel then we are ok. At first I thought this was taking infinity from infinity but after thinking a little bit I realized it really was not the case because: 1. If we group the terms before taking the limit (which is what we are really doing in an indefinite integral) then they cancel before reaching infinity. 2. We can take the view we are only dealing with approximations to a more accurate theory that do not yield divergent terms but only very large numbers then the subtraction is ok. 3. We can assume the theory only applies to a certain cutof in energy. This leaves finite terms but strongly dependant on the cutoff. Again if we can assume that the greater the cutoff is taken the more we approach energies where the theory does not apply the more uncertain we become. So what we can do is beyond a certain energy say the theory does not apply - put it in the form above and the terms we do not want go. The most elegant alternative seems to be 1. Now I learnt Quantum field Theory from Weinberg's book so all I know is this effective field theory approach. It is my understanding that this is a new approach so critics of renormalization (of which I there have been many - even perhaps including Feynman) may not have considered how this resolves the issue. Thanks Bill |
|
#6
|
|||
|
|||
|
(Bilge) wrote in message ...
tontoko hirorin: Ultraviolet divegence is very old problem and is not solved completely yet. I thought we might approach this problem through introducing new quantisation into Lorentz space which is different from that on quantum mechanics. Uh, the uncertainty relations are not just defined. They are derived from the definitions of the operators (which are also canonical conjugates). You can't simply define an uncertainty relation between two variables and create a value for the commutator based upon dimensional analysis (and your dimensional analysis isn't even correct area/momentum does not give meter-seconds). You have a "commutation relation" for t and x, but t isn't an operator, nor did you define an operator for t. My supposition for the uncertainty relations on my webpage: http://139.134.5.123/tiddler2/c21508/relativity.htm is very simple, i.e. x(meter)*t(second)-t(second)*x(meter) = constant(meter*second) (please forget Plank constant!) Since in the special relativity 1 second = 3e10^8 meter, that constant has the unit of area. As well as quantum mechanics, there are several ways to express t and x as operators such as matrices or differential operators. One of them is to make x correspond to identity mapping and t correspond to (constant)*(partial deriavtive by x) as described in the webpage shown above. Additionally recently I found the clue to determine the concrete value of that constant. For details how to calculate that constant, please visit: http://139.134.5.123/tiddler2/lepton/lepton2.htm My rough estimate for that constant is around 1e-38 meter^2 as shown in the above webpage. |
|
#7
|
|||
|
|||
|
In my Astronomy news group I posted how ultraviolet photons can create
photolysis,and this seperated water into its two elements,and that is a big reason Mars has no surface water. Bert |
|
#8
|
|||
|
|||
|
"Bill Hobba" wrote in message ...
tontoko hirorin wrote: Truly currently the ultraviolet divergence may be regarded as not "problem" but "solved problem" by most of people since no actual "divergence" appearing through the calculation owing to renormalization. However I think the ultraviolet divergence is more fundamental problem that that solved by renormalization. Which is the whole idea of effective field theory - we do not assume we have the final theory. Thanks Bill Practically QED is a complete theory since every calculation coincides with experimental result as long as dealing with electron and its electrical interaction. However mathematically some inconsistency is still remaining. For example, on the perturbation development the mass of bare electron is supposed as finite, neverthless when cancelling out the divergence, it is supposed as infinte. About the final theory - actually I'm not sure what the final theory you've said is, though - isn't it impossible to reach "final" theory until physicists abandon pursuing physics? |
| Thread Tools | |
| Display Modes | |
|
|
Similar Threads
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| Conformal divergence | DRLunsford | Current Physics Research (Moderated) | 0 | November 20th 05 11:45 PM |
| Fun With Ultraviolet | Kaalyce | Physics - General Discussion | 6 | January 18th 05 04:02 PM |
| Quartz parity divergence calculation | Uncle Al | Physics - General Discussion | 0 | November 9th 04 12:24 AM |
| Ultraviolet problem | David Fleming | Physics - General Discussion | 4 | October 29th 03 05:53 PM |
| Curl ......Divergence......... | Jean | Physics - General Discussion | 1 | October 27th 03 12:07 PM |