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The Traveling Twin: SR's ******* child.



 
 
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Old August 17th 03 posted to sci.physics.relativity
WaiteDavid137
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Posts: 574
Default The Traveling Twin: SR's ******* child.

Since you are trolling you are obviously not interested in learning, but if
I'm
wrong and you do want a better understanding of it then do problem 5.4.4 at
http://www.geocities.com/zcphysicsms/chap5.htm#BM65
for yourself.
On top of that I'll give you another exersize. Verify from equation 3.3.8

that
the inertial frame observer never observes the accelerated frame observer

to be
time reversed. (Hint look at part b of problem 5.4.4)



I am challenging you
and Tom to do the ratio of rates calculation for my scenario, in your
own way.


You don't have a contradictory calculation. If you did you would display it
instead of asking us to calculate it. The fact is you have nothing valid to say
and you know it. You are merely trolling. There is no physical clock that the
inertial frame observer reckons to be time reversed. That scenario does NOT
follow from the formula. The only thing that is time reverse is the rate of
clocks behind the horizon as reckoned by the accelerated frame. None of the
clocks in that region can be clocks for the accelerated frame. This observer
can not actually see light from events behind x' = - c^2/alpha so long as alpha
is maintained. Such light never catches him as long as its maintained and thus
there is a horizon. The accelerated observer can not have a physical clock
stationary with respect to his x' axis behind this horizon for such a clock
would be traveling faster than c with respect to the inertial frame. You have
trapped us in no way as you want to produce a scenario that actually violates
faster than c to show that the scenario yields a time machine.

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