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| Tags: bastard, child, srs, traveling, twin |
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Since you are trolling you are obviously not interested in learning, but if
I'm wrong and you do want a better understanding of it then do problem 5.4.4 at http://www.geocities.com/zcphysicsms/chap5.htm#BM65 for yourself. On top of that I'll give you another exersize. Verify from equation 3.3.8 that the inertial frame observer never observes the accelerated frame observer to be time reversed. (Hint look at part b of problem 5.4.4) I am challenging you and Tom to do the ratio of rates calculation for my scenario, in your own way. You don't have a contradictory calculation. If you did you would display it instead of asking us to calculate it. The fact is you have nothing valid to say and you know it. You are merely trolling. There is no physical clock that the inertial frame observer reckons to be time reversed. That scenario does NOT follow from the formula. The only thing that is time reverse is the rate of clocks behind the horizon as reckoned by the accelerated frame. None of the clocks in that region can be clocks for the accelerated frame. This observer can not actually see light from events behind x' = - c^2/alpha so long as alpha is maintained. Such light never catches him as long as its maintained and thus there is a horizon. The accelerated observer can not have a physical clock stationary with respect to his x' axis behind this horizon for such a clock would be traveling faster than c with respect to the inertial frame. You have trapped us in no way as you want to produce a scenario that actually violates faster than c to show that the scenario yields a time machine. |
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