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| Tags: aka, barry, greywolf42, mingst, regarding |
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#31
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Matthew Nobes wrote in message ... greywolf42 wrote: Tom Roberts wrote in message ... greywolf42 wrote: If the speed of gravity = c in GR (and 'that's it'), then the speed of gravity is 'c' in the weak limit. NOT infinity. This is not true. In order to obtain the Newtonian limit of GR, one must have: a) weak fields b) velocities small compared to c c) Newtonian-like coordinates Nobody is talking about the 'Newtonian' approximation, Tom. We're discussing the weak-field limit of GR. Umm, when you neglect *all* terms that go like 1/c they're one and the same. Well, yeah. When you neglect all the differences, they're the same. This is supposed to be information? That's the case *I* was talking about when disputing your claim that GR was "backfit". I'll try to be really clear here, I'm not sure what your point was, then. Why would you use an approximation to GR to demonstrate a point about how GR was derived? *If* you *neglect* *all* terms that go like 1/c then GR reduces to a *1/r* potential. Hence there is no "backfit" onto Newtonian gravity. But GR includes terms that 'go like' 1/c in the weak-field limit. And the two sentences appear to be a non-sequiteur. How does the first sentence have anything to do with the second sentence? [snip] Precisely my point. No one was talking about an approximation to GR. We were discussing the weak-field limit (which is not an approximation). Yes it is. The weak-field limit is NOT an 'approximation.' There is a fundamental distinction between a limit and an approximation. A limit is 'really' reached with all terms. An approximation simply ignores portions of the theory. You keep terms up to some power of 1/c and throw the rest away. If you neglect *all* terms of order 1/c and higher you get Newtonian gravity, hence there was no "backfit". And, again, the last two phrases appear to be a non-sequiteur. How does the first phrase have anything to do with the second phrase? greywolf42 ubi dubium ibi libertas |
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#32
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greywolf42 wrote:
Matthew Nobes wrote in message ... greywolf42 wrote: Tom Roberts wrote in message ... greywolf42 wrote: If the speed of gravity = c in GR (and 'that's it'), then the speed of gravity is 'c' in the weak limit. NOT infinity. This is not true. In order to obtain the Newtonian limit of GR, one must have: a) weak fields b) velocities small compared to c c) Newtonian-like coordinates Nobody is talking about the 'Newtonian' approximation, Tom. We're discussing the weak-field limit of GR. Umm, when you neglect *all* terms that go like 1/c they're one and the same. Well, yeah. When you neglect all the differences, they're the same. This is supposed to be information? Okay, let me put it another way. I am talking about *THE*LIMIT*THAT*TOM*DESCRIBED. In *THAT* limit, GR gives you a 1/r potential *uniquely* hence there was no "backfit" onto Newton. A "backfit" onto Newton would have invovled tweaking some arbitrary function of "r" to give you the 1/r. You do not need to do that in GR. Is that 100% clear? Do you dispute that at all? [snip the rest, which is a pointless diversion from the main issue] -- Matthew Nobes c/o Physics Dept. Simon Fraser University, 8888 University Drive Burnaby, B.C., Canada http://www.sfu.ca/~manobes |
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#33
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greywolf42 wrote:
[...] The weak-field limit is NOT an 'approximation.' There is a fundamental distinction between a limit and an approximation. A limit is 'really' reached with all terms. An approximation simply ignores portions of the theory. With that terminology, the weak field limit *is* an approximation -- it's obtained by explicitly throwing away terms that are quadratic and higher in the deviation of the metric from the Minkowski metric. The Newtonian approximation, on the other hand, is a limit -- see Frittelli and Ruela, Commun. Math. Phys. 166 (1994) 221. Steve Carlip |
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#34
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Steve Carlip wrote in message ...
greywolf42 wrote: [...] The weak-field limit is NOT an 'approximation.' There is a fundamental distinction between a limit and an approximation. A limit is 'really' reached with all terms. An approximation simply ignores portions of the theory. With that terminology, the weak field limit *is* an approximation -- it's obtained by explicitly throwing away terms that are quadratic and higher in the deviation of the metric from the Minkowski metric. The Newtonian approximation, on the other hand, is a limit -- see Frittelli and Ruela, Commun. Math. Phys. 166 (1994) 221. Steve Carlip Esteemed Dr. Carlip, If a massive shell of matter has the same gravity as a solid sphere with the same number of atoms, would the collapse of the shell result in an increase in mass, ie. the original mass plus the IR radiation that results from the conversion of kenetic energy to heat? Respectfully, stephen kearney |
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#35
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Old Physics wrote:
If a massive shell of matter has the same gravity as a solid sphere with the same number of atoms, would the collapse of the shell result in an increase in mass, Not according to general relativity. The gravitational field at a fixed distance will remain he same, as long as you're looking at a point that was always outside the shell and the collapse is spherically symmetric. ie. the original mass plus the IR radiation that results from the conversion of kenetic energy to heat? If you want to think of it in these terms, the relevant energy you need to look at is ``quasilocal energy,'' which includes a contribution analogous to Newtonian gravitational potential energy. The change in this potential energy piece balances the other energy changes; the total quasilocal energy remains constant. (Of course, some of the IR radiation you speak of will eventually radiate out past the point at which you're measuring the gravitational field. As that happens, the field at that point will decrease.) Steve Carlip |
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#36
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Matthew Nobes wrote in message ... greywolf42 wrote: Matthew Nobes wrote in message ... greywolf42 wrote: Tom Roberts wrote in message ... greywolf42 wrote: If the speed of gravity = c in GR (and 'that's it'), then the speed of gravity is 'c' in the weak limit. NOT infinity. This is not true. In order to obtain the Newtonian limit of GR, one must have: a) weak fields b) velocities small compared to c c) Newtonian-like coordinates Nobody is talking about the 'Newtonian' approximation, Tom. We're discussing the weak-field limit of GR. Umm, when you neglect *all* terms that go like 1/c they're one and the same. Well, yeah. When you neglect all the differences, they're the same. This is supposed to be information? Okay, let me put it another way. I am talking about *THE*LIMIT*THAT*TOM*DESCRIBED. In *THAT* limit, GR gives you a 1/r potential *uniquely* hence there was no "backfit" onto Newton. A "backfit" onto Newton would have invovled tweaking some arbitrary function of "r" to give you the 1/r. You do not need to do that in GR. Is that 100% clear? No, it is not. I'm still trying to understand why you want to use an approximation to GR to demonstrate a point about how GR was derived. Do you dispute that at all? Let me try one step at a time. The original point under discussion was your dislike of my claim that Einstein 'backfit' the equations of GR onto Newton's equation. Your current line of reasoning started when you proffered the statement that "The point is in GR the speed of gravity is c and that's it." I happen to agree that the base speed of gravity in GR is 'c.' (We've found that we disagree on what happens in the strong limit of GR -- but I believe that is irrelevant to the subject under discussion.) So, the base theory of GR -- as Einstein described it in "The Foundation of the General Theory of Relativity", 1916 -- includes a speed of 'c' for the speed of gravity. Are we together on this first step? [snip the rest, which is a pointless diversion from the main issue] If those statements were 'pointless diversions,' I'm curious why you (Matthew and Tom) started them. But it really doesn't matter. greywolf42 ubi dubium ibi libertas |
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#37
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Steve Carlip wrote in message ... greywolf42 wrote: [...] The weak-field limit is NOT an 'approximation.' There is a fundamental distinction between a limit and an approximation. A limit is 'really' reached with all terms. An approximation simply ignores portions of the theory. With that terminology, the weak field limit *is* an approximation -- it's obtained by explicitly throwing away terms that are quadratic and higher in the deviation of the metric from the Minkowski metric. The Newtonian approximation, on the other hand, is a limit -- see Frittelli and Ruela, Commun. Math. Phys. 166 (1994) 221. So, according to Steve, the "approximation" term used by Relativists is really a "limit." And the "limit" term used by Relativists is really an "approximation." If true, this would merely be another sloppy set of terms by relativists. (Like "defining" the speed of gravity to be '1' unit ... and then dropping the physical term from the equations.) But 'approximation' and 'limit' are still not the same thing. I suspect there is actually a misunderstanding on what constitutes 'GR,' versus what constitutes a 'deviation' from GR. Or what constitutes a mathematical procedure for approximating GR. But next time I'm at the library, I'll see what the mathematical priests have come up with this time. greywolf42 ubi dubium ibi libertas |
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#38
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greywolf42 wrote:
[...] The weak-field limit is NOT an 'approximation.' There is a fundamental distinction between a limit and an approximation. A limit is 'really' reached with all terms. An approximation simply ignores portions of the theory. With that terminology, the weak field limit *is* an approximation -- it's obtained by explicitly throwing away terms that are quadratic and higher in the deviation of the metric from the Minkowski metric. The Newtonian approximation, on the other hand, is a limit -- see Frittelli and Ruela, Commun. Math. Phys. 166 (1994) 221. Steve Carlip Esteemed Dr. Carlip, If a massive shell of matter has the same gravity as a solid sphere with the same number of atoms, would the collapse of the shell result in an increase in mass, ie. the original mass plus the IR radiation that results from the conversion of kenetic energy to heat? Respectfully, stephen kearney My question maybe off thread, but it is not off topic. sk |
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#39
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"Tom Roberts" wrote in message
GR applied to a weak-field situation has a "speed of gravity" equal to c. Indeed, one need not limit oneself to weak fields.... What about strong field solutions like the Alcubierre "warp drive". http://www.wikipedia.org/wiki/Alcubierre_drive This seems like a situation governed by GR in which there is a "wave" traveling faster than light. Of course it requires "exotic matter" which may not exist, or have a substitute, so such faster than light "waves" may not exist. Tom Clarke -- Posted via Mailgate.ORG Server - http://www.Mailgate.ORG |
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#40
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greywolf42 wrote:
Nobody is talking about the 'Newtonian' approximation, Tom. We're discussing the weak-field limit of GR. The disconnect here is that you seem to think that there is some sort of "weak-field limit of GR" that is still GR. In the standard vocabulary of physics, the phrase "weak-field limit of theory X" is shorthand for "an APPROXIMATION to theory X in which one considers weak fields, and neglects higher-order terms in a suitable expansion of theory X". So the rest of us interpret the phrase "weak-field limit of GR" as an approximation. What you are trying to say would more properly be expressed as: GR applied to a weak-field situation. GR applied to a weak-field situation has a "speed of gravity" equal to c. Indeed, one need not limit oneself to weak fields.... Tom Roberts |
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