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| Tags: because, doesnt, sense, wrong |
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#1
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The Special Theory of Relativity says that nothing travels faster than
light because light is the speed of existence. This is how we can explain why light doesn't move faster when the observers are moving faster. But this is not the only way to answer this question. I have deduced multiple levels of time, and the time that we comprehend is partially created by light, as Einstien correctly suggests. But if we were to answer the question of why light doesn't speed up in the following way: Because light exists and works at a level of time that is different than the level of time that the observer exists in then we can still get to the same conclusion that nothing travels faster than light in our level of existence, and still allow for the possibility of objects travelling faster than light in lower, fundamental levels of existence/time. Now the question is, are there really multiple levels of time? I have laid out why I think that there are multiple levels, at least two that we can deduce he http://www.techmocracy.net/science/time.htm But I don't know how to go about proving that there are or are not multiple levels. Anyone got ideas? |
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#3
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Mike Helland:
The Special Theory of Relativity says that nothing travels faster than light because light is the speed of existence. That isn't what relativity says. This is how we can explain why light doesn't move faster when the observers are moving faster. It's not how a physicist explains it. http://www.techmocracy.net/science/time.htm But I don't know how to go about proving that there are or are not multiple levels. Anyone got ideas? Yes. First obtain a good physics book on special relativity. Then spend some time studying it rather than writing web pages about why it's wrong. |
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#4
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"Mike Helland" wrote in message om... Bilge, The Special Theory of Relativity says that nothing travels faster than light because light is the speed of existence. That isn't what relativity says. Special Relativity doesn't that say nothing travels faster than the speed of light? And it doesn't say that all light cones are shaped the same and pointed in the same direction? SR doesn't say the part "because light is the speed of existence." I'll leave the other juicy bits for Bilge ;-) Dirk Vdm |
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#5
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#6
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#7
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You mean Special Relativity wasn't used to explain why light is always the same speed no matter how you observe it?
You obviously don't know the first thing about relativity. Ok then, if we don't use Special Relativity to explain that phenomenon, how do we explain it? We don't, its a basic postulate of science and the Special Theory of Relativity was a result of that postulate. So we can loosely say: science uses SR to explain that phenomenon. I think you guys are trying really hard to dig apart the semantics I'm using to introduce what I'd really like some feed back on. And that is how can we test the hypothesis that there are multiple levels of time and that our time is a result of interactions occuring at another time that quantum mechanics runs on? The fact that you make public statements about something that you clearly haven't studied pegs you as an arrogant fool. A fool perhaps, but I'm not sure how you got arrogant. You guys know more than I do, which is why I posted this hypothesis here. |
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#8
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Mike Helland:
You mean Special Relativity wasn't used to explain why light is always the same speed no matter how you observe it? You obviously don't know the first thing about relativity. Ok then, if we don't use Special Relativity to explain that phenomenon, how do we explain it? We don't, its a basic postulate of science and the Special Theory of Relativity was a result of that postulate. So we can loosely say: science uses SR to explain that phenomenon. What special relativity says is this: The physics in all inertial frames is the same. That alone is sufficient to define _some_ constant, `c', which is a velocity and that anything which propagates at that velocity, does so at `c' in every inertial frame. Whether or not anything does propagate at `c' is an experimental question, but the numerical value of `c' itself is no more relevant than introducing a constant `a' to relate the x and y axes by y = ax. Physicists typically define c = 1 in recognition of that fact. However, since humans already had chosen units of meters and seconds, we will end up with a numerical value. Einstein's second postulate comes about because there exists a phenomena which apperently can be used to define `c' - electromag- netism. The experiments led maxwell to a theory in which the propagation of light occurs at a constant velocity which doesn't depend upon the motion of the source or the observer. This was puzzling to physicists of that era, but einstein noticed that all laws of physics could be made independent of any inertial frame if `c' is the velocity maxwell found. I think you guys are trying really hard to dig apart the semantics I'm using to introduce what I'd really like some feed back on. And that is how can we test the hypothesis that there are multiple levels of time and that our time is a result of interactions occuring at another time that quantum mechanics runs on? No one is digging apart semantics. What you have said is not semantic- ally clear. In order to "test" your hypothesis, it is first necessary for you to state it in the form of a mathematical relationship which can be used to derive quantities that experiments can be designed to measure. For example, einsteins first postulate may be stated in the form of a coordinate transformation to another inertial frame. If you change coordinates by an infinitessimal amount, all of the physics must remain unchanged. If you require the length of a rod to be frame independent, i.e., assume the length l is a function of x, l(x) then change to coordinates x' = x + dx l'(x) = l(x') = l(x + dx) = l(x) + (dl(x)/dx)\delta x and take the scalar product of that length to be invariant (just like the length of a vector in 3-d is given by sqrt(|V.V|), i.e., l = sqrt(x^2 + y^2 + z^2)), then you get: |l'| = |l|^2 + l (dl/dx) \delta x + ((dl/dx)\delta x) l + higher order terms Now you require that |l'|^2 - |l|^2 = 0, so that the scalar product is the same in both the primed and unprimed coordinates. That requires: l (dl/dx) \delta x + ((dl/dx)\delta x) = 0 However, since l contains four coordinates, the above is a matrix equation l_i M_ij \delta x_j + l_j M_ji \delta x_i = 0. If you solve for M_ij, you get the lorentz transforms. The lorentz transdforms can be tested. In order to say something about your hypothesis, it's necessary to be able to address it mathematically, otherwise no one knows what it means, if it's self-consistent, or what insight it offers to physical phenomena. |
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#9
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Mike Helland:
Bilge, In order to say something about your hypothesis, it's necessary to be able to address it mathematically, otherwise no one knows what it means, if it's self-consistent, or what insight it offers to physical phenomena. And what do you think it is that I'm asking for help on? You aren't asking for help, you're insisting that have an explanation for something. You also argue with every response. I'm unsure of how a scientist could read my posts, post something completely unrelated, and then tell me that I'm missing what I said I'm missing. Oh well. Perfect example of what I said above. |
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#10
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Mr. Anderson said,
You can't disprove a theory by coming up with another one that explains the same set of experiments. You need an experiment that disagrees with one but not the other. I understand that. As I admited, I have no testable hypothesis based on my idea yet. I have a question, matter causes space-time to curve, correct? What do we call that phenomenon? |
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