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| Tags: relation |
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#1
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All,
A while back I wanted to model a solar sail so I used the special relativy equation and integrated over a distance to get the approximate velocity vs time. Basicly, I did a force ballance to calculated the accelleration and then integrated the accelleration to get the velocity and the distance (two integrations). I think this is how I did it. p = gamma*m*u dp/dt = d gamma/dt * (m*U) + d(m*u)/dt * gamma dpt/dt = d gamma d gamma/dt = (u/c^2)*gamma^3* du/dt after some manipulation (I love when they do this in books )dp/dt = ma*[gamma^3 * (u/c^2) + gamma] I obtained a final equation for the accelleration: a = (dEphotons/dt)/ m*c[gamma^3 * (u/c)^2 + gamma] m = mass u = accelleration c = speed of light E = energy of the light p = momentum (Note: all of these values are in the stationary reference frame) I integrated (numerically) this eqation with respect to time to get the velocity and again to get the distance. Now, I am an engineer and not a physicist so I used Euclidean space to integrate over - I'm not concerned about small changes in cordinates due to small variations in the the coordinated system due to gravity. Does my rational have any inherent flaws? The results seemed reasonable. Eric |
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#3
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Eric Malroy wrote:
All, A while back I wanted to model a solar sail so I used the special relativy equation and integrated over a distance to get the approximate velocity vs time. Basicly, I did a force ballance to calculated the accelleration and then integrated the accelleration to get the velocity and the distance (two integrations). I think this is how I did it. p = gamma*m*u dp/dt = d gamma/dt * (m*U) + d(m*u)/dt * gamma dpt/dt = d gamma d gamma/dt = (u/c^2)*gamma^3* du/dt after some manipulation (I love when they do this in books )dp/dt = ma*[gamma^3 * (u/c^2) + gamma] I obtained a final equation for the accelleration: a = (dEphotons/dt)/ m*c[gamma^3 * (u/c)^2 + gamma] m = mass u = accelleration c = speed of light E = energy of the light p = momentum (Note: all of these values are in the stationary reference frame) I integrated (numerically) this eqation with respect to time to get the velocity and again to get the distance. Now, I am an engineer and not a physicist so I used Euclidean space to integrate over - I'm not concerned about small changes in cordinates due to small variations in the the coordinated system due to gravity. Does my rational have any inherent flaws? The results seemed reasonable. Eric I haven't checked the calculations, but I have number of questions. First, what is the probability a solar sail will reach relativistic speeds? I would argue it's nil. Hence, you can take gamma to be 1. Second, how do you intend on determining dEphotons/dt? Precisely how does the energy of the photon change with time? Third, do you understand the concept of sailing? If you do, why is the calculation independent of the surface area of the sail? |
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#4
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Eric Malroy wrote:
[snip] p = gamma*m*u dp/dt = d gamma/dt * (m*U) + d(m*u)/dt * gamma dpt/dt = d gamma d gamma/dt = (u/c^2)*gamma^3* du/dt after some manipulation (I love when they do this in books )dp/dt = ma*[gamma^3 * (u/c^2) + gamma] I obtained a final equation for the accelleration: a = (dEphotons/dt)/ m*c[gamma^3 * (u/c)^2 + gamma] [snip] Does my rational have any inherent flaws? The results seemed reasonable. Actually, there are two major flaws, namely, (1) you applied special relativity to the sail (2) your calculation violates the conservation of momemtum Let Flux = solar radiation flux in Watts/meter^2 E = energy of the photons in Joules t = time in seconds A = area in meters^2 of the sales c = speed of light in meters/sec. m = mass of payload and sail in kilograms Flux = E/(t*A) hence E = Flux*t*A = pc or p = Flux*t*A/c Assuming you're bouncing light off a mirror and perpendicular to the mirror, then the momentum change is twice the incident momentum, and dp/dt = 2*Flux*A/c ma = 2*Flux*A/c or a = 2*Flux*A/(m*c) At the earth the solar radiation flux is Flux = 1.4 x 10^3 Watts/meter^2. Let r = distance from the sail to center of the sun r_earth = distance from center of sun to center of sail Then Flux(r) = Flux*r_earth^2/r^2 and a = 2*Flux(r)*A/(m*c) |
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