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GR and Magnetostatics?



 
 
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  #1  
Old July 7th 08 posted to sci.physics.relativity
Ken S. Tucker
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Posts: 7,675
Default GR and Magnetostatics?

**GR and Magnetostatics**
GR accounts for the magnetostatic force
quite simply, the key being the relation,

Length=(G/c^2)*Mass. , G is Newton's,

so that the Mass of the Sun is 1.47 km. That is
explained in Weinberg's "Grav&Cosmo" pg.181,
using R = r - MG on the Schwarzschild Solution.
That 1.47 km has been confirmed by light deflection.

The next thing to understand is Guv =Tuv means
Curvature (Guv) increases as the Energy Density
(Tuv) increases, so that two repelling magnetics
increase Tuv when forced together, while Tuv
decreases when attractive magnets are brought
together.
Consider the following diagram, using points p1
and p2 to designate locations in a field free space,
"s=n" is a bar magnet, and X, La and Lr are the
lengths, measured by light rays separating the
positions, of p1,p2 and "s=n", "n=s" and "s=n",
"n=s", respectively though exagerated, with the bar
magnets set exactly at p1 and p2, then the Length
in the attractive couple "La" is less than the distance
in the repulsive couple "Lr", due to Guv=Tuv,

p1---------X---------p2

s=n-----La-----s=n

s=n----------Lr-----------n=s

From that we can find the energy stored, using from
GR from above, Length(L) = (G/c^4)*Energy(E), and
E = K*L , K=c^4/G .

La - X = -DX , Ea= -K*DX , (attractive)
Lr - X = +DX , Er= +K*DX , (repulsive)

with the Energy Ea removed, from the Tuv as the
attractive bar magnets are moved from infinity to
p1 and p2, and the Er is the Energy put into the
system to move the repelling magnets to p1 and p2
from infinity and the above DX are the result of Tuv
on the Curvature Guv.

The Magnetostatic "Force" is measured by changing
the Energy of the system, and likewise the Curvature
change becomes real, such that D^2(X) =/=0.

The challenge is to determine how the metric g_uv varies
to produce the magnetostatic energy and forces above.
Regards
Ken S. Tucker
kxsxt8
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  #2  
Old July 7th 08 posted to sci.physics.relativity
Sue...
external usenet poster
 
Posts: 9,422
Default GR and Magnetostatics?

On Jul 7, 12:30 pm, "Ken S. Tucker" wrote:
[...]

The Magnetostatic "Force" is measured by changing
the Energy of the system, and likewise the Curvature
change becomes real, such that D^2(X) =/=0.

The challenge is to determine how the metric g_uv varies
to produce the magnetostatic energy and forces above.
Regards
Ken S. Tucker
kxsxt8


If someone stole the "3" from your keyboard I
think it is OK to write 1+2 as an exponent. )

http://www.sm.luth.se/~urban/master/Theory/3.html
39 items, totalling 240.5 KB for the dial-up challenged

Gudonya,
Sue...

  #3  
Old July 7th 08 posted to sci.physics.relativity
Ken S. Tucker
external usenet poster
 
Posts: 7,675
Default GR and Magnetostatics?

On Jul 7, 9:48 am, "Sue..." wrote:
On Jul 7, 12:30 pm, "Ken S. Tucker" wrote:
[...]



The Magnetostatic "Force" is measured by changing
the Energy of the system, and likewise the Curvature
change becomes real, such that D^2(X) =/=0.


The challenge is to determine how the metric g_uv varies
to produce the magnetostatic energy and forces above.
Regards
Ken S. Tucker
kxsxt8


If someone stole the "3" from your keyboard I
think it is OK to write 1+2 as an exponent. )

http://www.sm.luth.se/~urban/master/Theory/3.html
39 items, totalling 240.5 KB for the dial-up challenged
Gudonya,
Sue...


All you need to do is recognize the effect of
energy density on curvature to see how GR explains
magnetism via the spacetime field.
Even I can understand it!
Ken
  #4  
Old July 7th 08 posted to sci.physics.relativity
Sue...
external usenet poster
 
Posts: 9,422
Default GR and Magnetostatics?

On Jul 7, 1:26 pm, "Ken S. Tucker" wrote:
On Jul 7, 9:48 am, "Sue..." wrote:



On Jul 7, 12:30 pm, "Ken S. Tucker" wrote:
[...]


The Magnetostatic "Force" is measured by changing
the Energy of the system, and likewise the Curvature
change becomes real, such that D^2(X) =/=0.


The challenge is to determine how the metric g_uv varies
to produce the magnetostatic energy and forces above.
Regards
Ken S. Tucker
kxsxt8


If someone stole the "3" from your keyboard I
think it is OK to write 1+2 as an exponent. )


http://www.sm.luth.se/~urban/master/Theory/3.html
39 items, totalling 240.5 KB for the dial-up challenged
Gudonya,
Sue...


All you need to do is recognize the effect of
energy density on curvature to see how GR explains
magnetism via the spacetime field.
Even I can understand it!


Is that because you omitted the "challenging" part?

"Tensors and pseudo-tensors"
http://farside.ph.utexas.edu/teachin...s/node120.html

Sue...

Ken




  #5  
Old July 7th 08 posted to sci.physics.relativity
Ken S. Tucker
external usenet poster
 
Posts: 7,675
Default GR and Magnetostatics?

On Jul 7, 11:15 am, "Sue..." wrote:
On Jul 7, 1:26 pm, "Ken S. Tucker" wrote:



On Jul 7, 9:48 am, "Sue..." wrote:


On Jul 7, 12:30 pm, "Ken S. Tucker" wrote:
[...]


The Magnetostatic "Force" is measured by changing
the Energy of the system, and likewise the Curvature
change becomes real, such that D^2(X) =/=0.


The challenge is to determine how the metric g_uv varies
to produce the magnetostatic energy and forces above.
Regards
Ken S. Tucker
kxsxt8


If someone stole the "3" from your keyboard I
think it is OK to write 1+2 as an exponent. )


http://www.sm.luth.se/~urban/master/Theory/3.html
39 items, totalling 240.5 KB for the dial-up challenged
Gudonya,
Sue...


All you need to do is recognize the effect of
energy density on curvature to see how GR explains
magnetism via the spacetime field.
Even I can understand it!


Is that because you omitted the "challenging" part?
"Tensors and pseudo-tensors"http://farside.ph.utexas.edu/teaching/em/lectures/node120.html


GR provides the ability to simply connect
magnetism with the spacetime field conceptually,
using fairly primitive math. The best solutions
to the "challenge" (IMO) use asymmetric metrics
that become evident in rotation, but 1st is to
get the concept written out, then go to proofs.
Regards
Ken S. Tucker
 




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