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| Tags: physics, same, slow, stays, time |
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#1
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The order doesn't change if time rate does. Now in proper time always
looks the same to the observer of itself. All Nows are the same. |
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#2
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On Jun 8, 10:33*pm, wrote:
The order doesn't change if time rate does. Now in proper time always looks the same to the observer of itself. All Nows are the same. The effective inertia increases linearly with the slowdown in time. That's why everything appears so sluggish in slow motion ... their inertia is that much larger. I see and know that first-hand. My reaction speed is 7 ms and on that time scale everything is like it weighs a ton and it's impossible to get anything moving without great effort. The exact same trajectory (t |- r(t)) on a time scale attenuated by a factor s (t |- r(st)) becomes an acceleration d^2/dt^2 (r(st)) = s^2 r''(st) = s^2 a(st), which in the smaller time scale (1 new unit = s old units) is s-times larger and, hence, effectively requires a force s times larger on that time scale (and s^2 times larger on the ordinary time scale). The world is (obviously!) NOT scale-invariant. That would even be obvious without all the bother of explanation. If the world were scale-invariant with respect to time, everyone would be able to react to anything at arbitrary speed without any impedance and films run in slow motion would look the same at those run at ordinary speed. |
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#3
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On Jun 10, 12:59*pm, Rock Brentwood wrote:
On Jun 8, 10:33*pm, wrote: The order doesn't change if time rate does. Now in proper time always looks the same to the observer of itself. All Nows are the same. The effective inertia increases linearly with the slowdown in time. That's why everything appears so sluggish in slow motion ... their inertia is that much larger. I see and know that first-hand. My reaction speed is 7 ms and on that time scale everything is like it weighs a ton and it's impossible to get anything moving without great effort. The exact same trajectory (t |- r(t)) on a time scale attenuated by a factor s (t |- r(st)) becomes an acceleration d^2/dt^2 (r(st)) = s^2 r''(st) = s^2 a(st), which in the smaller time scale (1 new unit = s old units) is s-times larger and, hence, effectively requires a force s times larger on that time scale (and s^2 times larger on the ordinary time scale). The world is (obviously!) NOT scale-invariant. That would even be obvious without all the bother of explanation. If the world were scale-invariant with respect to time, everyone would be able to react to anything at arbitrary speed without any impedance and films run in slow motion would look the same at those run at ordinary speed. The universe is expanding on all scales. |
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