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| Tags: dirac, diracs, equation, qft, questions, several, spinors |
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To all,
I have several queries about the Dirac equation and associated Dirac spinors psi and quantum field theory (QFT). 1. In units hbar=c=1, a Dirac spinor psi has mass dimension +3/2. Yet, the "inside" of a Dirac spinor for, say, a spin up electron is often written as (transposed, easier for ASCII): (1 0 p_z/(E+m) P_+/(E+m) ) (1) which is dimensionless, and the normalization factor is written as: sqrt [(E+m)/2m] or sqrt(E+m) (2) The latter of (2) at least has mass dimension of 1/2, but what is the representation (or normalization) of this which explicitly shows the +3/2 mass dimensionality? Do we just multiply (1) through by m? Or by E+m? What is the normalization for psi*T psi with mass dimension +3 which drives this? *T=conjugate transpose. 2. The Dirac spinor in compact form is often written as: psi = u(p) exp [-i p x] (3) I understand what happens from there, but why start with a complex plane wave? Why not, for example, start with a more general form: psi = u(p) exp [-(1/2)Ax^2 + Bx + V(x)] (4) where V(x) is a general polynomial in x? Aside from the math maybe being more difficult, would there be anything wrong with obtaining solutions to Dirac's equation: (i gamma^u d_u - m) psi (5) using the more general waveform (4)? 3. If (4) is a valid general waveform, and recognizing that to keep the exponent dimensionless, A must have mass dimension 2 and B mass dimension 1, is it reasonable to suppose that A=m^2 where m is the electron mass, and that B=p is the momentum (or B=E the energy) for the time dependence of the wavefunction? 4. The "central identity of quantum field theory" as it is called by Zee (see his page 167), for a quantum field psi, is given by: $Dpsi exp[-(1/2)A psi^2 + B^psi +V(psi) = exp[(1/2)B^2/A -V(d/dJ)] (6) (I have changed his K--A and J--B to contrast with (4).) Let's focus on V. As Zee puts it: "we single out the term quadratic in psi . . . and call the rest V(psi). This is just another way of saying that V is a generalized polynomial in psi, and, depending on the (unspecified) coefficients of each order can be ay function under the sun. Being in the exponent, V must be dimensionless. As a possible point of reference, let me also point out my one-page calculation, earlier posted, at http://jayryablon.files.wordpress.co...by-problem.pdf. (Download and open if left click does not work.) Several questions: A) V is often used to represent a potential. Yet a potential has mass dimension of 1. Is V to be understood in any context as a potential? (It seems somewhat apparent that it is.) If so, how does one get from mass dimension 0 to mass dimension +1? B) What is the most straightforward physical interpretation of V in (6)? What would be the most straightforward interpretation of V in (4)? C) If V in either or both of (4) and (6) is to be interpreted as a potential with mass dimension of +1, then where is the connection to gauge symmetry? That is, usually a potential comes about as the "0" component of the potential 4-vector A^u, which in turn enters through imposing gauge symmetry. How would one show V in (4) and (6) as arising from gauge symmetry, as the "0" component of A^u? Thanks, Jay. ____________________________ Jay R. Yablon Email: co-moderator: sci.physics.foundations Weblog: http://jayryablon.wordpress.com/ Web Site: http://home.nycap.rr.com/jry/FermionMass.htm ..htm |
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