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| Tags: circular, dilatation, motion, time |
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#61
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"Sam Wormley" escreveu na mensagem news:tXtTj.96038$TT4.72561@attbi_s22... El Enrrabadore-mor wrote: It is said that a speeding clock shows less elapsed time than the stay-at-home clock, because (if already speeding) it is running at a slower rate. Or else, because it had run at a slower rate when it was speeding, assuming now it is stopped near the stay-at-home clock. What I meant to say is... for satellite clocks in orbits approximating circular motion, time dilation is dependent on altitude in the gravity well as well as relative velocity. See graph in second link. Relativistic Effects on Satellite Clocks http://relativity.livingreviews.org/...age=node5.html http://relativity.livingreviews.org/...-1/frctfrq.png Take some time to learn what really happens. What really happens looks to be the following: - 98% is Sagnac effect (a non relativistic effect that is said to contradict SR on its most basic postulate about light) - 2% is due to all other effects (relativity, excentricities, and so on). References: - A QUOTE (from your link): "GPS can be used to compare times on two earth-fixed clocks when a single satellite is in view from both locations. This is the "common-view" method of comparison of Primary standards, whose locations on earth's surface are usually known very accurately in advance from ground-based surveys. Signals from a single GPS satellite in common view of receivers at the two locations provide enough information to determine the time difference between the two local clocks. The Sagnac effect is very important in making such comparisons, as it can amount to hundreds of nanoseconds, depending on the geometry. In 1984 GPS satellites 3, 4, 6, and 8 were used in simultaneous common view between three pairs of earth timing centers, to accomplish closure in performing an around-the-world Sagnac experiment. The centers were the National Bureau of Standards (NBS) in Boulder, CO, Physikalisch-Technische Bundesanstalt (PTB) in Braunschweig, West Germany, and Tokyo Astronomical Observatory (TAO). The size of the Sagnac correction varied from 240 to 350 ns. Enough data were collected to perform 90 independent circumnavigations. The actual mean value of the residual obtained after adding the three pairs of time differences was 5 ns, which was less than 2 percent of the magnitude of the calculated total Sagnac effect [4]." |
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#62
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"N:dlzc D:aol T:com (dlzc)" escreveu na mensagem ... Dear El Enrrabadore-mor: "El Enrrabadore-mor" wrote in message ... ... Nevertheless, there are two pillar stones in Physics: 1 - Conservation of Angular Momentum. (No matter if it is circular motion or linear motion. For circular motion the conservation only exists relative to the center of rotation, but for linear motion conservation exists relative to every point in space); 2 - Conservation of Energy. Now, energy is the time derivative of the angular momentum, and that time is an absolute time. No, energy is the path integral of momentum. The energy is a function of the observer's frame, so it clearly involves *nothing* absolute. You are right. My mistake, sorry. It is the other way around: Momentum is the derivative of energy, or like you said: "energy is the path integral of momentum". For linear motion: Momentum = d/dt Energy m v = d/dt (1/2 m v^2) For circular motion: Angular momentum = d/dt Energy I w = d/dt (1/2 I w^2) You're also right about energy being frame dependent. Nevertheless, for circular motion, in the given example, I've clearly implied that the center of rotation is a fixed point in space and it's the origin of the coordinates. Hence, relative to the center of rotation, my argument holds 100% : "Angular momentum is the time derivative of energy and that time is an absolute time." How can the above two pillar stones of Physics survive in view of time dilatation (and time not being absolute after all)? Because "absolute" is something artificially impressed by *human* expectation. Unfortunately for you, you cannot solve any Physical problem without that "absolute fixed frame of reference". You simply cannot solve problems in thin air. You need a paper for that, where you place an absolute fixed frame of reference. David A. Smith |
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#63
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"Greg Neill" escreveu na mensagem m... "El Enrrabadore-mor" wrote in message You've missed the fact that during a given amount of time a torque T = dL/dt have moved the body a given angle theta (which is a basic coordinate). No, I didn't miss anything. A torque doesn't have to be accompanied by an angular movement any more than a static force does. You did miss exactly what you're saying now, but never mind. You forget the fact that derivatives are of the form: d/dt f(x(t)) = x df/dt x - is an angular displacement Energy = Torque . angular displacement (dot product) No. Work is torque x displacement. I understand if you blame the 'dot product' and replace it by a simple multiplication sign. Actually, I've the strong feeling that I've messed up something about the derivative argument, because what I can get is a power balance, not an energy balance. Hence, it is a velocity that comes out, not an angular displacement. For circular motion: Work (Kg m^2 s^-2) = Torque (Kg m^2 s^-2) * * angular displacement (rad) (relative to the center of rotation). |
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#64
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"Darwin123" escreveu na mensagem ... On May 4, 7:31 pm, "El Enrrabadore-mor" wrote: "Darwin123" escreveu na ... On May 3, 2:25 pm, "El Enrrabadore-mor" wrote: It is said that a speeding clock shows less elapsed time than the stay-at-home clock, because (if already speeding) it is running at a slower rate. Or else, because it had run at a slower rate when it was speeding, assuming now it is stopped near the stay-at-home clock. The funny thing about this is that time and length change at the same time, but not the ratio between both (velocity). If we keep length constant, the only possible solution is uniform circular motion. That is a twin travelling in circles, of constant radius r, around the first twin assumed to be stopped at the center of rotation. Let's say the radius r is a constant value of 100 light-seconds (r = 100c). The speeding twin goes on a spaceship at 0.999c. Therefore, the angular speed 'omega' is v/r = 0.999c/100c = 0.01 rad/s. The speeding twin takes 628 seconds to have a complete turn of 360 degrees. For small values of t, the speeding twin is almost going in a straight line, but is fact it has a centripetal force f = m c^2/r = m c/100, being the centripetal acceleration c/100, towards the first stopped twin in the center of rotation. Both twins have powerful antennas that broadcast radio spherically around the entire space. Both twins are tuned to each other frequency/radio-station. Since the distance r = 100c between the emitter and the receptor is constant, obviously that both twin will hear each other radio (music) in perfect conditions. Nevertheless, relativity says that the clock synchronising the emission of the speeding twin must be running at a clock rate close to zero. Theoretically, the speeding twin won't have any trouble receiving the stay-at-home radio emission, but the stay-at-home twin cannot receive the speeding twin radio emission, because the speeding clock is running near zero. The speeding twin radio emission will take infinite time to broadcast one single spoken word. The stay-at-home will be dead by the time the speeding twin could say a single word. The trouble seams to be the acceleration: a = (0.999)^2 c/100 which is about c/100. (Here the number 100 means 100 seconds). That's a huge gravity field of 300,000g at a radius of 100 light-seconds, just imagine the value it will be at Earth radius based on the inverse-square Law.) I presume that such acceleration of 300,000g will be responsible for a clock speed up rate that should keep time unchanged after all. Ys, Einstein proposed this as a thought experiment. However, his analysis was done using the inertial frame as seen by an observer at the center of the earth. The moving clock on the edge of the circle will seem to be slowed down relative to the clock at the center of the circle, the one that is not accelerating. The clock in the center will seem speeded up compared to the clock on the circle. However, this clock is not accelerating. Yes, the assymmetry come from the centripetal force. The twin in the center does not experience the centripetal force as the twin on the circle. The clocks relative to each other will see differences in the rate of ticking. The clock with the largest acceleration ticks the fastest. The other clocks lag behind. However, the clock that accelerates least (i.e., moves at the slowest tangential speed on the circle) lags behind the clocks with more acceleration. Any comments welcome. This is a description of the Hafele-Keating experiment. The experiment was performed, and matched Einsteins predictions. Hafele had two articles in Nature that describe both the experiment and the analysis of the results. The experiment was performed with atomic clocks. It is a classic validation of special relativity. Clearly, your arguments blame acceleration to be the cause of time dilatation. Fine. The circular motion at constant angular velocity and constant radius adds something more. Not only you have acceleration, but also velocity relative to any inertial frame of reference nearby. You cannot add both effects: Velocity + Acceleration If you sum both effects chances are that you come up with the conclusion that they cancel each other out. That's what happens for a stable orbit anyway. No they don't. They don't exactly speed up. In fact, the acceleration at some point wins out over the effect of speed. Where did you get the impression they speed up? That's what you've said (your words below): "The clock with the largest acceleration ticks the fastest." And you keep saying it now, plenty of times, above and below. A good approximation of the effect of acceleration on time, derived from the Lorentz transformation (i.e., SR), is by a factor (1+ax/c^2). Note this is independent of relative velocity. a) - Acceleration causes the clock to speed up. b) - Velocity causes the clock to speed down. Summing both a) and b) will give what ? Depends on their relative magnitude. If the factors were the same, the effect is nothing at all. If the factor for acceleration is bigger, then there is a total speed up. If the factor for acceleration is smaller, there is an effective slow down. This is a problem that must be solved quantitatively. You can't wave your hand and say "they balance out." I've a strong feeling they must balance out for a stable orbit. Stable orbits always balance centrifugal force with the force of gravity. 1 - Absolute time? No such thing. I meant that for a perfect balance among a) and b). 2 - Partially absolute time? What is that? That's the case where a perfect balance doesn't exist. According to your above statements, that should be the most probable case. 3 - Discard one of the effects and have relativity time dilatation solution? Yes. Discard the acceleration and you have the Lorentz time dilation formula. Now I'm puzzled. You've been talking about accelerations all the time. Now you discard acceleration and step forward? I bet on conservation of energy, but I was already told that General Relativity essentially discards nonlocal conservation of energy. The same goes for Newton's Laws. An observer in an accelerating frame of reference, according to Principia, observes a fictional force that violates the Third Law of Motion. This fictional force creates a fictional potential energy that creates a fictional violation of the conservation of energy and momentum. Key qualifier here is fictional. Newton's Laws are defined only in nonaccelerating reference frames. Therefore, the accelerating observer sees a "fictional" increase in energy, nonlocally. That's an Invention without any bases. No such fictional force exists. I bet "your" fiction requires motion. No motion, zero work done. Is it the centrifugal force you are talking about? No one, ever, could prove Newton wrong, nor prove any violation of Energy Conservation. Potential fields are just that: A potential. No work will be done if no motion exists. In GR, they replace the words "accelerating reference frame" by curve in "space-time path". Basically the same thing. The observer on the curved space time path sees "fictional" changes in energy. That should be another relativistic invention. The word "fictional" says it all. You need to explain this much better, so that I can understand what you're talking about. You can imagine whatever you want, the problem is to prove that imagination a true fact. That simply shots down a Physics pillar stone, but who cares? Bad metaphor. There was never a "physics pillar stone" like "nonlocal conservation of energy." See above comment on Newton's Laws and nonlocal conservation. I'm still to see a true violation of Newton's Law, or a violation on "Energy conservation". Unfortunately, the local process looks to be irreversible. If it was reversible, non-conservation of energy locally leads to local free-energy generation. Actually, it is easily reversible. The rocket enegines turn off, the observer is no longer accelerating, and energy is conserved once more even on a nonlocal basis. If you had an energy lost during acceleration, during de-acceleration you've reverted the sign. Mathematics and simple logic says you should see a gain in energy. Please respond. |
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#65
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"Ken S. Tucker" escreveu na mensagem ... Use h = energy*time, = E*t = E'*t' then E' = (t/t')*E, Fortunately "h" is a universal constant and invariant. Two different observers can disagree on the measurement of E and E', and t and t', but they agree on the product "h". It is good to know that observers can agree on something. You've made some good points Ken. Regards. Regards Ken S. Tucker |
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#66
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"bz" escreveu na mensagem 98.139... "El Enrrabadore-mor" wrote in : "Tom Roberts" escreveu na mensagem ... One can analyze their experiment (including comparison to muon decay at rest) in two different ways: a) use the overall inertial frame of their storage ring and apply SR. b) use the equivalence principle of GR, and treat the LOCAL acceleration of the stored muons as a gravitational field and compute the gravitational time dilation in LOCAL coordinates in which the stored muon is at rest. These obtain the same answer. Moreover: Your a) appeals on velocity as the cause of time dilatation. Your b) appeals on acceleration (or gravity by equivalence principle) to be the cause on time dilatation. It is not the velocity or the acceleration (in SR) that explains the time difference. It is the different trajectory. Trajectory through space-time. And that space-time is a Gaussian coordinate system made of curved lines like two orthogonal mirror spirals? Please explain Bob. Physics say: c) Acceleration is the time derivative of velocity. My c) proves your a) and b) to be incompatible, since time used on the derivative is ABSOLUTE TIME. a = dv/dt says nothing about ABSOLUTE time. Where did you get the impression that it did? dt is CHANGE in time. I wonder how derivatives will be if the said changing time had been already affected by time dilatation. Just imagine that velocity changes. Time dilatation will change too. You get a derivative where time himself changes. What a mess I presume. |
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#67
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On May 5, 9:19*am, "El Enrrabadore-mor"
What really happens looks to be the following: - 98% is Sagnac effect (a non relativistic effect that is said to contradict SR on its most basic postulate about light) The Sagnac effect does not contradict SR. You are an imbecillic troll |
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#68
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"Dono" looking for an Enrrabadore spew in the message: ... The Sagnac effect does not contradict SR. You are an imbecillic troll In Sagnac experiment, light speed is *measured* not to be independent from either, the source and the observer. That's so obvious and so many times proved, by so many, that it should hurt very bad. Doesn't it Dono? Of course, nothing that one cannot re-arrange, like making 1+1=3 should be easy for any good relativist using a convenient coordinate system, perfectly engineered for the show-off. Now, please send the "jpg" pictures. Got new ones? |
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#69
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On May 5, 11:04*am, "El Enrrabadore-mor"
wrote: "Dono" looking for an Enrrabadore spew in the ... The Sagnac effect does not contradict SR. You are an imbecillic troll In Sagnac experiment, light speed is *measured* not to be independent from either, the source and the observer. No, it isn't. This means that you are both an imbecile and a troll. |
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#70
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Dear El Enrrabadore-mor:
On May 5, 9:19*am, "El Enrrabadore-mor" wrote: "N:dlzcD:aol T:com (dlzc)" escreveu na ... Dear Greg Neill: "Greg Neill" wrote in message om... ... No, in a propagating transverse electromagnetic wave *may be orthogonal, but they are in phase. In a vacuum they are in phase. *As a medium in interposed, the phase relationship changes. *When bound to a conductor, and "pushing" charges around, they are 90 degrees out-of-phase. From my knowledge on power generation, the electric and magnetic fields are 90 degrees out-of-phase if no mechanical energy is converted into electric power. That is what pushing electrons (with their mass... remember simple harmonic motion?) does. ... Couldn't it be the case that electromagnetic radiation in vacuum interacts with sensors in-phase for an unitary power factor (and zero losses)? No. The rest of the physics doesn't work. David A. Smith |
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