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What's wrong with these pictures???



 
 
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  #111  
Old May 9th 08 posted to sci.physics.relativity,sci.physics
rbwinn
external usenet poster
 
Posts: 9,274
Default What's wrong with these pictures???

On May 8, 5:04Â*pm, PD wrote:
On May 7, 8:54Â*pm, rbwinn wrote:





On May 7, 6:43Â*pm, PD wrote:


On May 7, 7:17Â*pm, rbwinn wrote:


On May 7, 3:57Â*pm, " wrote:


On 7 mayo, 18:38, rbwinn wrote:


On May 7, 12:54 pm, " wrote:


On 7 mayo, 14:34, rbwinn wrote:


On May 7, 10:40�am, " wrote:


On 7 mayo, 12:25, rbwinn wrote:


On May 7, 8:06 am, PD wrote:


Well, no, if lightining strikes the front and rear of a moving train,
leaving marks on the train and the track, the marks on the track will
be the length of the train apart, which relativity of simultaneity
cannot explain. �According to mathematics, if the bolts of lightning
are simultaneous in the frame of reference of the track, the marks on
the track will be closer together than the length of the train; if the
bolts of lightning are simultaneous in the frame of reference of the
train, the marks on the track are further apart than the length of the
train. �Reality shows that the marks on the track will be the length
of the train apart, disproving this false teaching of Einstein.
Robert B. Winn


Nonsense. That is a bunch of words salad. What in the world those
marks you mention have to do with relativity of simultaneity?
This shows you have not read anything about SR. What does it mean
"according to mathematics"? And where does Einstein say the nonsense
of the marks on the track?
There are two events (the strikes) and two observers. What these
observers see is the light signal information that tells them about
the occurrence of those strikes. That is the reason one of them can
certify "I saw both strikes to be simultaneous", while the second
certify "I saw the front strike occurring before the back strike".


Einstein was the one who thought of the train and two bolts of
lightning. Â*He did not fully consider the mathematics of the situation
he described. Â*Einstein did not say anything about marks on the track,
but I did. Â*The marks on the track prove that relativity of
simultaneity cannot exist in reality. Â*Lightning hits the front and
rear of the train simultaneously as seen by an observer by the track,
leaving marks on the front and rear of the train and marks on the
railroad track. Â*The distance between the marks on the train is the
length of the train. Â*The distance between the marks on the track is
the length of the train. Â*In order for relativity of simultaneity to
exist, the marks on the track would have to be closer together than
the length of the train. Â*Conversely, if the bolts of lightning are
seen simultaneously by the observer on the train, in order for
relativity of simultaneity to exist, the marks on the track would have
to be further apart than the length of the train. Â*Reality shows that
the marks on the track are the length of the train apart.
Robert B. Winn


That is complete nonsense. What Einstein wrote about this subject,
just for people like you, can be seen inhttp://www.bartleby.com/173/9.html
Observers do not have to measure any length (actually it would be very
tough to measure a 200000km train, not speaking of how to build it and
how to place the tracks). The only requirement is for the observers to
coincide at t=0 at x=0, that the strikes occurred at x=-X0 and at x=
+X0 and that the train with its observer is moving at a speed v into
the +x direction.
The observations consist of both observers receiving the light signals
that communicate them of the strikes occurrence. Where in the world
are you seeing something related to measuring lengths?


c=176,000 miles /sec. Â*The mile is a unit of length. Â*The velocity of
the train is also measured in units of length divided by time. Â*In
addition to that, the train has a length that is measured in units of
length.
Robert B. Winn


And what are you trying to say with that?.
We are talking about the relativity of simultaneity, and that refers
to time relations, not to length contraction.
The whole point of this train thought experiment is to prove that time
is not absolute.


Miguel Rios- Hide quoted text -


- Show quoted text -


Relativity of simultaneity, as explained by Einstein, is dependent on
length contraction.


Actually, no it's not. You'll notice that the relativity of
simultaneity is established without needing to reference the distance
between the marks. However, you brought up the *additional*
information about the distance between the marks. In so doing, you
find out that there is a *consequence* of relativity of simultaneity:
relativity of length.


Â*If lightning strikes both ends of a train,
leaving marks on the ends of the train and marks on the track, the
only way the marks can be closer together than the length of the
train, as is required if the lightning at the front strikes first, is
if there is a distance contraction, as seen from the frame of
reference of the track.
Robert B. Winn- Hide quoted text -


Well, as I said, that would be the problem of people who believe it
exists. Â*I believe the Galilean transformation equations which
indicate that relativity of simultaneity and distance contraction do
not exist.


I know you believe that. That's Â*because you're ignorant of the
experimental data, I believe. If you're not interested enough in the
truth to investigate the data, then I'm under no compunction to make
you change your beliefs.

PD


Ignorant of experimental dataI

Ignorant of experimental data? The only experiment I have to run is
posting equations in sci.physics.relativity. So, PD, when are you
going to tell us about the experiments that disprove the Galilean
transformation equations?
Robert B. Winn
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  #112  
Old May 9th 08 posted to sci.physics.relativity,sci.physics
rbwinn
external usenet poster
 
Posts: 9,274
Default What's wrong with these pictures???

On May 8, 8:45�pm, Bryan Olson wrote:
rbwinn wrote:

[...]

All you have is a clock running at a different rate than the clock in
the frame of reference of the track. �Other than that, the train,
bolts of lightning, and motion of the train happen the same as shown
by these equations.


� � � � � � � � �x'=x-vt
� � � � � � � � �y'=y
� � � � � � � � �z'=z
� � � � � � � � �t'=t


The bolts of lightning strike simultaneously in both frames of
reference. �The flashes of lightning are seen at the same time by the
observer by the track. �The flashes of lightning are seen at the same
time by the observer on the train.


Doesn't work. Consider two events: light from the front flash
reaching the observer on the train, and light from the rear
flash reaching that same observer. According to your last
sentence above, Robert, the observer on the train finds that
those two events coincide; they happen at the same point in
space and time.

Both the Galilean transform and the Lorentz transform are
1-to-1. A single point in the space and time coordinates
of one frame maps to just one point in the other. Therefore
in the coordinate system in which the track is stationary,
the two events must likewise occur at the same point in
space and time.

When we work out the results from the track-bound observer's
frame of reference, either the two light fronts moves at
different speeds in that frame, or the two events happen at
different places and different times. Robert, if I understood
correctly, your theory accepts that the speed of light is the
same in all frames that are in Galilean motion. If so, your
theory is self-contradictory.

--

Thank you for your input, Bryan. As a matter of fact, we can work out
this little difficulty that you have envisioning what happens. We
have two observers, one by the track and one on the train. As far as
the coordinates of space are concerned, the Galilean transformation
equations have no distance contraction, no relativity of simultaneity,
no other shell games. The light is where it is in both frames of
reference. The difference is in the time in each frame of reference
at any given x and x'.
The lightning strikes in both frames of reference at t'=t=0. The
two observers are both at the middle of the train. A photon starts
toward the observers from the front of the train toward both
observers, a photon starts from the back of the train toward both
observers. The train moves in the +x direction at a velocity of v.
When the photon from the front of the train reaches the observer on
the train, it has traveled a distance of .5L in the frame of reference
of the train, where L is the length of the train. In the frame of
reference of the track, it has traveled a shorter distance. The point
it is traveling from in the frame of reference of the track is the
mark left by the lightning on the track. The point where it is
traveling from in the frame of reference of the train is the mark left
by the lightning on the front of the train. Since the photon is
traveling at a speed of c in both frames of reference, when it reaches
the observer on the train, it has traveled a time of .5L/c, but in the
frame of reference of the track, it has only traveled (.5L minus the
distance the train has traveled)/c, so time at that event is less in
the frame of reference of the track. The photon passes the observer
on the train and continues on to the observer by the track, reaching
him in a time of .5L/c in the frame of reference of the track.
The flash of light from the rear of the train proceeds from the
point where it was emitted in the frame of reference of the track, the
mark left by the lightning on the track, to the observer by the track,
reaching him in a time of .5L/c. When the light reaches the observer
by the track, the train has moved forward, so in the frame of
reference of the train, it hs prosceeded from the point where it was
emitted in the frame of reference of the train, the mark on the
caboose of the train, to the observer by the track, a shorter distance
because the distance between the caboose of the train and the observer
by the track has decreased. Therefore in the frame of reference of
the train, the light reaches the observer by the track in a time of (.
5L minus the distance the train has traveled) divided by c. The light
then continues on to the observer at the middle of the train, reaching
him in a time of .5L/c.
The time the observer on the ground sees the two flashes of light
is .5L/c as measured by a cesium clock in S, the frame of reference of
the track, and the time the observer on the train sees the two flashes
of light is .5L/c as measured by a cesium clock on the train. Time on
the cesium clock in S is t in the Galilean transformation equations.
Time on the cesium clock in S' is given by

n'=t(1-v/w)
w= velocity of light.

All that is necessary is relativity of time, which can be determined
in each frame of reference by the distance a photon has traveled in
that frame of reference from the time it is emitted until the time it
is observed.
Robert B. Winn

  #113  
Old May 9th 08 posted to sci.physics.relativity,sci.physics
PD
external usenet poster
 
Posts: 20,119
Default What's wrong with these pictures???

On May 8, 10:54Â*pm, rbwinn wrote:
On May 8, 5:02Â*pm, PD wrote:

On May 7, 10:25Â*pm, rbwinn wrote:


On May 7, 6:54Â*pm, PD wrote:


On May 7, 8:53Â*pm, rbwinn wrote:


On May 7, 6:40Â*pm, PD wrote:


On May 7, 5:46Â*pm, rbwinn wrote:


On May 7, 1:11Â*pm, PD wrote:


On May 7, 1:45Â*pm, rbwinn wrote:


On May 7, 10:40�am, PD wrote:


On May 7, 11:25�am, rbwinn wrote:


Well, no, if lightining strikes the front and rear of a moving train,
leaving marks on the train and the track, the marks on the track will
be the length of the train apart, which relativity of simultaneity
cannot explain.


Sure, it explains it.


Here's how:
The track observer goes back after the train has passed and notes that
the marks on the track are 400 m apart. Remember that, for the track
observer, the strikes hit simultaneously. Since the marks are also on
the train, the track observer correctly notes that the train is 400 m
long. (This is what a length measurement entails anyway: marking the
locations of the ends of an object at the same time.)


Now the train observer goes back after the strikes have hit and notes
that the marks on the train are 500 m apart. But it's also true that
this observer saw the front strike happen before the rear strike ---
the strikes are not simultaneous in this frame. So it doesn't bother
this observer at all that the track observer sees the marks 400 m
apart. That's exactly what you'd expect if you marked the location of
the front of a moving object before you marked the location of the
rear of the moving object -- and that's exactly what the train
observer is sure happened.


The length of the train is frame-dependent. Whether the marks at the
end of the train were made at the same time, is also frame-dependent.


Does this help you understand?


The train has an actual length.


No, actually, it does not. Length is a frame-dependent quantity. The
value in one frame is no more "actual" than the value in another
frame. Now, there is a "rest length" which is the length measured in
the frame in which the train just happens to be at rest, but there is
nothing preferential about this frame.


Well, no, length is not a frame dependent quantity.


That is at variance with experimental observation. Nice conjecture,
though.
How's that working for ya?


Â*Length is
length. Â*There is no distance contraction.
Robert B. Winn- Hide quoted text -


Well, the Galilean transformation equations indicate otherwise.


The Galilean transformation equations are also at variance with
experimental observation. That's why they've been dropped. You can do
that with mathematics that doesn't model reality well.


Nice conjecture, though. How's that working for ya?


PD


The Galilean transformation equations work very well. Â*The Lorentz
equations not so well, but they give a fairly close approximation. Â*So
when are you going to tell us what the experiment was that proved the
Galilean transformation equations wrong?


I've already told you and pointed it out to you. You responded that
you don't read what scientists point out to you. How's that working
for you?


It got me to the Galilean transformation equations. Â*As far as I can
tell, I am the only one in the world who understands this subject.
Robert B. Winn


OK, so let's recap, shall we?
You believe the Galilean transformations work well.
However, you are unaware of the experimental evidence that shows the
Galilean transformations do not work well.
You have the policy of not reading references provided to you by
scientists that the Galilean transformations do not work well.
This policy has led you to believe further in the truth of the
Galilean transformations, and you further believe that you are the
only person in the world that understands this to be the case.

PD
  #114  
Old May 9th 08 posted to sci.physics.relativity,sci.physics
PD
external usenet poster
 
Posts: 20,119
Default What's wrong with these pictures???

On May 8, 7:20Â*pm, rbwinn wrote:
On May 8, 5:04Â*pm, PD wrote:



On May 7, 8:54Â*pm, rbwinn wrote:


On May 7, 6:43Â*pm, PD wrote:


On May 7, 7:17Â*pm, rbwinn wrote:


On May 7, 3:57Â*pm, " wrote:


On 7 mayo, 18:38, rbwinn wrote:


On May 7, 12:54 pm, " wrote:


On 7 mayo, 14:34, rbwinn wrote:


On May 7, 10:40�am, " wrote:


On 7 mayo, 12:25, rbwinn wrote:


On May 7, 8:06 am, PD wrote:


Well, no, if lightining strikes the front and rear of a moving train,
leaving marks on the train and the track, the marks on the track will
be the length of the train apart, which relativity of simultaneity
cannot explain. �According to mathematics, if the bolts of lightning
are simultaneous in the frame of reference of the track, the marks on
the track will be closer together than the length of the train; if the
bolts of lightning are simultaneous in the frame of reference of the
train, the marks on the track are further apart than the length of the
train. �Reality shows that the marks on the track will be the length
of the train apart, disproving this false teaching of Einstein.
Robert B. Winn


Nonsense. That is a bunch of words salad. What in the world those
marks you mention have to do with relativity of simultaneity?
This shows you have not read anything about SR. What does it mean
"according to mathematics"? And where does Einstein say the nonsense
of the marks on the track?
There are two events (the strikes) and two observers. What these
observers see is the light signal information that tells them about
the occurrence of those strikes. That is the reason one of them can
certify "I saw both strikes to be simultaneous", while the second
certify "I saw the front strike occurring before the back strike".


Einstein was the one who thought of the train and two bolts of
lightning. Â*He did not fully consider the mathematics of the situation
he described. Â*Einstein did not say anything about marks on the track,
but I did. Â*The marks on the track prove that relativity of
simultaneity cannot exist in reality. Â*Lightning hits the front and
rear of the train simultaneously as seen by an observer by the track,
leaving marks on the front and rear of the train and marks on the
railroad track. Â*The distance between the marks on the train is the
length of the train. Â*The distance between the marks on the track is
the length of the train. Â*In order for relativity of simultaneity to
exist, the marks on the track would have to be closer together than
the length of the train. Â*Conversely, if the bolts of lightning are
seen simultaneously by the observer on the train, in order for
relativity of simultaneity to exist, the marks on the track would have
to be further apart than the length of the train. Â*Reality shows that
the marks on the track are the length of the train apart.
Robert B. Winn


That is complete nonsense. What Einstein wrote about this subject,
just for people like you, can be seen inhttp://www.bartleby.com/173/9.html
Observers do not have to measure any length (actually it would be very
tough to measure a 200000km train, not speaking of how to build it and
how to place the tracks). The only requirement is for the observers to
coincide at t=0 at x=0, that the strikes occurred at x=-X0 and at x=
+X0 and that the train with its observer is moving at a speed v into
the +x direction.
The observations consist of both observers receiving the light signals
that communicate them of the strikes occurrence. Where in the world
are you seeing something related to measuring lengths?


c=176,000 miles /sec. Â*The mile is a unit of length. Â*The velocity of
the train is also measured in units of length divided by time. Â*In
addition to that, the train has a length that is measured in units of
length.
Robert B. Winn


And what are you trying to say with that?.
We are talking about the relativity of simultaneity, and that refers
to time relations, not to length contraction.
The whole point of this train thought experiment is to prove that time
is not absolute.


Miguel Rios- Hide quoted text -


- Show quoted text -


Relativity of simultaneity, as explained by Einstein, is dependent on
length contraction.


Actually, no it's not. You'll notice that the relativity of
simultaneity is established without needing to reference the distance
between the marks. However, you brought up the *additional*
information about the distance between the marks. In so doing, you
find out that there is a *consequence* of relativity of simultaneity:
relativity of length.


Â*If lightning strikes both ends of a train,
leaving marks on the ends of the train and marks on the track, the
only way the marks can be closer together than the length of the
train, as is required if the lightning at the front strikes first, is
if there is a distance contraction, as seen from the frame of
reference of the track.
Robert B. Winn- Hide quoted text -


Well, as I said, that would be the problem of people who believe it
exists. Â*I believe the Galilean transformation equations which
indicate that relativity of simultaneity and distance contraction do
not exist.


I know you believe that. That's Â*because you're ignorant of the
experimental data, I believe. If you're not interested enough in the
truth to investigate the data, then I'm under no compunction to make
you change your beliefs.


PD


Well, you talk about experiments. Â*Go ahead and tell us about one of
these experiments. Â*You were going to do this once before and then
changed your mind.
Robert B. Winn


I try wherever possible not to jump through the same hoop twice,
Bobby. Do you know how to research what's already been posted?
  #115  
Old May 9th 08 posted to sci.physics.relativity,sci.physics
PD
external usenet poster
 
Posts: 20,119
Default What's wrong with these pictures???

On May 8, 11:00Â*pm, rbwinn wrote:
On May 8, 5:04Â*pm, PD wrote:



On May 7, 8:54Â*pm, rbwinn wrote:


On May 7, 6:43Â*pm, PD wrote:


On May 7, 7:17Â*pm, rbwinn wrote:


On May 7, 3:57Â*pm, " wrote:


On 7 mayo, 18:38, rbwinn wrote:


On May 7, 12:54 pm, " wrote:


On 7 mayo, 14:34, rbwinn wrote:


On May 7, 10:40�am, " wrote:


On 7 mayo, 12:25, rbwinn wrote:


On May 7, 8:06 am, PD wrote:


Well, no, if lightining strikes the front and rear of a moving train,
leaving marks on the train and the track, the marks on the track will
be the length of the train apart, which relativity of simultaneity
cannot explain. �According to mathematics, if the bolts of lightning
are simultaneous in the frame of reference of the track, the marks on
the track will be closer together than the length of the train; if the
bolts of lightning are simultaneous in the frame of reference of the
train, the marks on the track are further apart than the length of the
train. �Reality shows that the marks on the track will be the length
of the train apart, disproving this false teaching of Einstein.
Robert B. Winn


Nonsense. That is a bunch of words salad. What in the world those
marks you mention have to do with relativity of simultaneity?
This shows you have not read anything about SR. What does it mean
"according to mathematics"? And where does Einstein say the nonsense
of the marks on the track?
There are two events (the strikes) and two observers. What these
observers see is the light signal information that tells them about
the occurrence of those strikes. That is the reason one of them can
certify "I saw both strikes to be simultaneous", while the second
certify "I saw the front strike occurring before the back strike".


Einstein was the one who thought of the train and two bolts of
lightning. Â*He did not fully consider the mathematics of the situation
he described. Â*Einstein did not say anything about marks on the track,
but I did. Â*The marks on the track prove that relativity of
simultaneity cannot exist in reality. Â*Lightning hits the front and
rear of the train simultaneously as seen by an observer by the track,
leaving marks on the front and rear of the train and marks on the
railroad track. Â*The distance between the marks on the train is the
length of the train. Â*The distance between the marks on the track is
the length of the train. Â*In order for relativity of simultaneity to
exist, the marks on the track would have to be closer together than
the length of the train. Â*Conversely, if the bolts of lightning are
seen simultaneously by the observer on the train, in order for
relativity of simultaneity to exist, the marks on the track would have
to be further apart than the length of the train. Â*Reality shows that
the marks on the track are the length of the train apart.
Robert B. Winn


That is complete nonsense. What Einstein wrote about this subject,
just for people like you, can be seen inhttp://www.bartleby.com/173/9.html
Observers do not have to measure any length (actually it would be very
tough to measure a 200000km train, not speaking of how to build it and
how to place the tracks). The only requirement is for the observers to
coincide at t=0 at x=0, that the strikes occurred at x=-X0 and at x=
+X0 and that the train with its observer is moving at a speed v into
the +x direction.
The observations consist of both observers receiving the light signals
that communicate them of the strikes occurrence. Where in the world
are you seeing something related to measuring lengths?


c=176,000 miles /sec. Â*The mile is a unit of length. Â*The velocity of
the train is also measured in units of length divided by time. Â*In
addition to that, the train has a length that is measured in units of
length.
Robert B. Winn


And what are you trying to say with that?.
We are talking about the relativity of simultaneity, and that refers
to time relations, not to length contraction.
The whole point of this train thought experiment is to prove that time
is not absolute.


Miguel Rios- Hide quoted text -


- Show quoted text -


Relativity of simultaneity, as explained by Einstein, is dependent on
length contraction.


Actually, no it's not. You'll notice that the relativity of
simultaneity is established without needing to reference the distance
between the marks. However, you brought up the *additional*
information about the distance between the marks. In so doing, you
find out that there is a *consequence* of relativity of simultaneity:
relativity of length.


Â*If lightning strikes both ends of a train,
leaving marks on the ends of the train and marks on the track, the
only way the marks can be closer together than the length of the
train, as is required if the lightning at the front strikes first, is
if there is a distance contraction, as seen from the frame of
reference of the track.
Robert B. Winn- Hide quoted text -


Well, as I said, that would be the problem of people who believe it
exists. Â*I believe the Galilean transformation equations which
indicate that relativity of simultaneity and distance contraction do
not exist.


I know you believe that. That's Â*because you're ignorant of the
experimental data, I believe. If you're not interested enough in the
truth to investigate the data, then I'm under no compunction to make
you change your beliefs.


PD


Ignorant of experimental dataI

Ignorant of experimental data? Â*The only experiment I have to run is
posting equations in sci.physics.relativity.


Aha. There, you see, is where you make a basic mistake, confusing
looking at equations with looking at experimental data. You keep
wanting to look at equations, and you shy away from looking at data.

You might consider asking a scientist how science is done, Bobby,
rather than just playing it the way you want to play it.

Â*So, PD, when are you
going to tell us about the experiments that disprove the Galilean
transformation equations?


I already have, Bobby, and I've reminded you about it too. Just
because you're still holding the hoop up, Bobby, doesn't mean that I'm
going to jump through it again. You can lift a finger too.

Robert B. Winn


  #116  
Old May 9th 08 posted to sci.physics.relativity,sci.physics
kenseto
external usenet poster
 
Posts: 9,779
Default What's wrong with these pictures???

On May 8, 10:49Â*am, " wrote:
On 8 mayo, 10:27, kenseto wrote:





On May 8, 9:53 am, " wrote:


On 8 mayo, 09:25, kenseto wrote:


On May 7, 5:01 pm, " wrote:


On 7 mayo, 16:27, kenseto wrote:


On May 7, 3:43 pm, " wrote:


On 7 mayo, 15:32, kenseto wrote:


On May 7, 11:42 am, " wrote:


On 7 mayo, 10:28, rbwinn wrote:


On May 7, 6:48�am, YBM wrote:


kenseto a �crit :


ROTFLOL....you are not responding because you don't have a valid
argument. I am not going to respond the rest of your post until you
admit that Einstein did stipulate that the lightning strikes occur
simultaneously and that:
1. the track observer sees them to be simultaneous because he is not
moving wrt the light fronts.
2. the train observer sees them to be not simultaneous because he is
moving wrt the light fronts.


In SR, "not moving with respect to a light front" makes no sense.


I have a question, YBM. Â*Whether you talk about photons or light
fronts, in the frame of reference of the train, the light is traveling
at a speed of c from the two points where light was emitted in the
frame of reference of the train. Â*Those two points remain exactly
where they were relative to the frame of reference of the train, and
the movement of the track relative to the train changes nothing. Â*How
do you get that the observer on the train is moving wrt the light
fronts in his frame of reference?


Your mistake is treating the points where the information (light) was
generated the same as the information.
They are quite different!


Â* Â* The observer on the train is not moving in his frame of
reference. Â*The train is not moving in the frame of reference of the
train, and the observer is at the middle of the train the entire
time. Â*The two light fronts are moving with a speed of c toward the
observer. Â*The track is moving toward the rear of the train. Â*What the
track does is irrelevant because the light travels with a speed of c
in the frame of reference of the train, regardless of the motion of
the source of light. Â*Since the track is moving toward the rear of the
train at a speed less than the speed of light, any photons emitted in
the frame of reference of the train after the first photons emitted
will still reach the observer at the middle of the train after the
first ones emitted.


The light carrying the information is moving isotropically from the
points where it was generated. So the train observer will receive
first the front light signal and later the back light signal.


This bogus assertion is based on the bogus assumption that the speed
of light is anisotropic in the train.


Ken Seto


Â* Â* Â*What you and Einstein and all other believers in relativity of
simultaneity are doing is clinging to some beliefs that pertain to
absolute time by making the frame of reference of the track a
preferred frame of reference as far as transmission of light is
concerned. Â*According to you, the train moves toward the source of
light at the front of the train, so that light reaches the observer
first. Â*Wrong. Â*The train is not moving in its own frame of
reference. Â*The track is moving toward the rear of the train. Â*That is
entirely irrelevant as far as when the light will reach the observer
at the middle of the train. Â*You scientists have faithfully copied
Einstein's mistake for more than 100 years. Â*Don't you think it might
be time to think about it?
Robert B. Winn


Nonsense


Miguel Rios- Hide quoted text -


- Show quoted text -


The only person making bogus assertions here is you.
Check your dictionary for the meaning of isotropy.
If you do not have one, here is the definition:
Isotropy is uniformity in all directions. The word is made up from
Greek iso (equal) and tropos (direction).


Right....so when Einstein asserted that the train observer rush toward
the light front from the front and receding from the light front from
the rear he is describing a scenario that destroys the isotropy of the
speed of light in the train.
So I guess it is you runt of the SRians failed to comprehend this
simple fact.


Ken Seto


On the contrary, light signals from both strokes are precisely
isotropically propagating (in a spherical growing at c shape) from
their origin, which is exactly what isotropy propagation means. When
that sphere finds an eye (either the track or the train observer eyes)
the observers will say "hey I have detected a strike!".
So how you explain this nonsense of "destroying the isotropy of the
speed of light". Do you understand English at all?


Hey idiot....do you have reading comprehension problem???
According to Einstein: When the train observer rushes toward the light
front from the front the transit time is less for that light front to
reach him. When the train observer receding away from the light front
from the rear the transit time is more for that light front to reach
him. This means that different arrival times for the two light fronts
that were generated at the same distance from the train observer and
thus what Einstein asserted destroyed the SR postulate that the speed
of light is isotropic in the train. Are you too stupid to understand
that???????


You are the moron with comprehension problems. What the heck has the
transit time to do with the isotropy of the light?.


****ing idiot runt.....isotropy of the speed of light means that light
takes the same transit time to reach the observer for the same
distance in different directions.


Ken Seto


Again you have to
go back to elementary school and learn to read and write.
The information carried by the light signals is moving at c
isotropically in both the track and the train frame.
The difference in arrival times is not produced by how the light is
moving, but because the train observer is moving relatively to the
light signals.
What drugs are you taken that make you think you know something about
physics?
You have provided substantial evidence that you do not have the
slightest idea of what you are talking, like your famous and hilarious
theory about the Sodium.


Miguel Rios- Hide quoted text -


- Show quoted text -


****ing idiot moron.....the observer *moved* after the light signals
started their voyage towards the observer.


Hey ****ing idiot runt....This shows me that you don't know what
isotropic means. The SR postulates says that the speed of light is
isotropic in the observer's frame. In case you are too stupid to
understand that means that the observer doesn't move wrt different
light fronts from the same distance in different directions. You are
so ****ing stupid I suggest that you go off to a corner and commit
suicide.

Ken Seto


You are such an imbecile
that somehow thinks (in your drunk brain) that these signals are
different on the train with respect to the same signals traveling on
the ground. Well moron, precisely that thought of yours would break
the isotropy of light, because you would have two different light
fronts, generated by the same event.

What a stupid soul you are

Miguel Rios- Hide quoted text -

- Show quoted text -


  #117  
Old May 9th 08 posted to sci.physics.relativity,sci.physics
kenseto
external usenet poster
 
Posts: 9,779
Default What's wrong with these pictures???

On May 8, 1:47*pm, "Dirk Van de moortel" dirkvandemoor...@ThankS-NO-
SperM.hotmail.com wrote:
kenseto wrote in message

*

On May 7, 6:20 pm, PD wrote:
On May 7, 3:27 pm, kenseto wrote:
On May 7, 3:43 pm, " wrote:


[snip]





Why no, Ken, isotropy is still the same.


The track observer notes:
The light from the front of the train is heading backwards at c, while
the train observer rushes toward that light at v.
The light from the back of the train is heading forwards at c, while
the train observer is receding from it at v.
The speed of light is c in both cases. It is still isotropic in the
track frame.


Hey idiot....that's not what Einstein said. He said that:
1. the train observer rushes toward the light front from the front and
thus it takes less time for that light front to reach him.
2. the train observer recedes away from the light front from the rear
and thus it takes more time for that light front to reach him.


This means that two different transit times for two light fronts
generated at the same distance from the train observer and thus the
isotropy of the speed of light is not preserved by Einstein's
assertion.


O help.... all that trouble PD went through.
Would there be *anything* Seto understands all by himself?
I seriously doubt it.
Perhaps Androcles should try to explain the concept of
closing speed to Seto.


****ing idiot runt....Einstein asserted what the train observer will
see based on closing speed as perceived by the track observer. That is
wrong. The train observer must make his own observation whether the
strikes are simultaneous.


  #118  
Old May 9th 08 posted to sci.physics.relativity,sci.physics
rbwinn
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Posts: 9,274
Default What's wrong with these pictures???

On May 9, 5:58Â*am, PD wrote:
On May 8, 10:54Â*pm, rbwinn wrote:





On May 8, 5:02Â*pm, PD wrote:


On May 7, 10:25Â*pm, rbwinn wrote:


On May 7, 6:54Â*pm, PD wrote:


On May 7, 8:53Â*pm, rbwinn wrote:


On May 7, 6:40Â*pm, PD wrote:


On May 7, 5:46Â*pm, rbwinn wrote:


On May 7, 1:11Â*pm, PD wrote:


On May 7, 1:45Â*pm, rbwinn wrote:


On May 7, 10:40�am, PD wrote:


On May 7, 11:25�am, rbwinn wrote:


Well, no, if lightining strikes the front and rear of a moving train,
leaving marks on the train and the track, the marks on the track will
be the length of the train apart, which relativity of simultaneity
cannot explain.


Sure, it explains it.


Here's how:
The track observer goes back after the train has passed and notes that
the marks on the track are 400 m apart. Remember that, for the track
observer, the strikes hit simultaneously. Since the marks are also on
the train, the track observer correctly notes that the train is 400 m
long. (This is what a length measurement entails anyway: marking the
locations of the ends of an object at the same time.)


Now the train observer goes back after the strikes have hit and notes
that the marks on the train are 500 m apart. But it's also true that
this observer saw the front strike happen before the rear strike ---
the strikes are not simultaneous in this frame. So it doesn't bother
this observer at all that the track observer sees the marks 400 m
apart. That's exactly what you'd expect if you marked the location of
the front of a moving object before you marked the location of the
rear of the moving object -- and that's exactly what the train
observer is sure happened.


The length of the train is frame-dependent. Whether the marks at the
end of the train were made at the same time, is also frame-dependent.


Does this help you understand?


The train has an actual length.


No, actually, it does not. Length is a frame-dependent quantity. The
value in one frame is no more "actual" than the value in another
frame. Now, there is a "rest length" which is the length measured in
the frame in which the train just happens to be at rest, but there is
nothing preferential about this frame.


Well, no, length is not a frame dependent quantity.


That is at variance with experimental observation. Nice conjecture,
though.
How's that working for ya?


Â*Length is
length. Â*There is no distance contraction.
Robert B. Winn- Hide quoted text -


Well, the Galilean transformation equations indicate otherwise.


The Galilean transformation equations are also at variance with
experimental observation. That's why they've been dropped. You can do
that with mathematics that doesn't model reality well.


Nice conjecture, though. How's that working for ya?


PD


The Galilean transformation equations work very well. Â*The Lorentz
equations not so well, but they give a fairly close approximation. Â*So
when are you going to tell us what the experiment was that proved the
Galilean transformation equations wrong?


I've already told you and pointed it out to you. You responded that
you don't read what scientists point out to you. How's that working
for you?


It got me to the Galilean transformation equations. Â*As far as I can
tell, I am the only one in the world who understands this subject.
Robert B. Winn


OK, so let's recap, shall we?
You believe the Galilean transformations work well.
However, you are unaware of the experimental evidence that shows the
Galilean transformations do not work well.
You have the policy of not reading references provided to you by
scientists that the Galilean transformations do not work well.
This policy has led you to believe further in the truth of the
Galilean transformations, and you further believe that you are the
only person in the world that understands this to be the case.


As far as I know, I am the only person in the world who uses the
Galiilean transformation equations. They work fine for me. So unless
you can show me they do not work,I have to just discount anything that
you and other scientists say about it. You have posted nothing here
that shows them to be wrong. With regard to your complaint that I do
not fulfill the fool's errands that you try to send me on, it is not
going to happen. If you have a reference that you claim proves that
the Galilean transformation equations do not work, go ahead and tell
us what it is and why you think it proves the Galilean transformation
equations wrong. You have plenty of time to assign these fool's
errands. Take a little of that time to explain yourself.
Robert B. Winn
  #119  
Old May 9th 08 posted to sci.physics.relativity,sci.physics
kenseto
external usenet poster
 
Posts: 9,779
Default What's wrong with these pictures???

On May 8, 8:08*pm, PD wrote:
On May 8, 9:32*am, kenseto wrote:





On May 7, 4:20*pm, PD wrote:


On May 7, 2:44*pm, kenseto wrote:


On May 7, 10:17*am, PD wrote:


On May 7, 8:16*am, kenseto wrote:


ROTFLOL...this runt of the SRians failed to come up with a valid
argument so he back paddled.


So, Ken, let's recap your position for a moment.


Lets capture your position: Apparently you are so desperate that you
tried to swindle $22,000 from me!!!!!


I don't need your money, Ken, so desperation has nothing to do with
it.


Sure it has everything to do with it. You tried to swindle money from
me


How did I try to swindle you, Ken? I gave you a fee estimate for my
services. How is that a swindle. If you take your car to the shop, and
they tell you what it's going to cost to fix it, and the number is
more than you thought it was going to be, is that a swindle?

and at the same time gains the opportunity to sabotage my
experiment.


I'd gain nothing by sabotaging your experiments. If you thought they
were sabotaged, you could always repeat them with someone else's help.


The point is: It would be too late...you already got my money.
  #120  
Old May 9th 08 posted to sci.physics.relativity,sci.physics
rbwinn
external usenet poster
 
Posts: 9,274
Default What's wrong with these pictures???

On May 9, 6:18Â*am, PD wrote:
On May 8, 7:20Â*pm, rbwinn wrote:





On May 8, 5:04Â*pm, PD wrote:


On May 7, 8:54Â*pm, rbwinn wrote:


On May 7, 6:43Â*pm, PD wrote:


On May 7, 7:17Â*pm, rbwinn wrote:


On May 7, 3:57Â*pm, " wrote:


On 7 mayo, 18:38, rbwinn wrote:


On May 7, 12:54 pm, " wrote:


On 7 mayo, 14:34, rbwinn wrote:


On May 7, 10:40�am, " wrote:


On 7 mayo, 12:25, rbwinn wrote:


On May 7, 8:06 am, PD wrote:


Well, no, if lightining strikes the front and rear of a moving train,
leaving marks on the train and the track, the marks on the track will
be the length of the train apart, which relativity of simultaneity
cannot explain. �According to mathematics, if the bolts of lightning
are simultaneous in the frame of reference of the track, the marks on
the track will be closer together than the length of the train; if the
bolts of lightning are simultaneous in the frame of reference of the
train, the marks on the track are further apart than the length of the
train. �Reality shows that the marks on the track will be the length
of the train apart, disproving this false teaching of Einstein.
Robert B. Winn


Nonsense. That is a bunch of words salad. What in the world those
marks you mention have to do with relativity of simultaneity?
This shows you have not read anything about SR. What does it mean
"according to mathematics"? And where does Einstein say the nonsense
of the marks on the track?
There are two events (the strikes) and two observers. What these
observers see is the light signal information that tells them about
the occurrence of those strikes. That is the reason one of them can
certify "I saw both strikes to be simultaneous", while the second
certify "I saw the front strike occurring before the back strike".


Einstein was the one who thought of the train and two bolts of
lightning. Â*He did not fully consider the mathematics of the situation
he described. Â*Einstein did not say anything about marks on the track,
but I did. Â*The marks on the track prove that relativity of
simultaneity cannot exist in reality. Â*Lightning hits the front and
rear of the train simultaneously as seen by an observer by the track,
leaving marks on the front and rear of the train and marks on the
railroad track. Â*The distance between the marks on the train is the
length of the train. Â*The distance between the marks on the track is
the length of the train. Â*In order for relativity of simultaneity to
exist, the marks on the track would have to be closer together than
the length of the train. Â*Conversely, if the bolts of lightning are
seen simultaneously by the observer on the train, in order for
relativity of simultaneity to exist, the marks on the track would have
to be further apart than the length of the train. Â*Reality shows that
the marks on the track are the length of the train apart..
Robert B. Winn


That is complete nonsense. What Einstein wrote about this subject,
just for people like you, can be seen inhttp://www.bartleby.com/173/9.html
Observers do not have to measure any length (actually it would be very
tough to measure a 200000km train, not speaking of how to build it and
how to place the tracks). The only requirement is for the observers to
coincide at t=0 at x=0, that the strikes occurred at x=-X0 and at x=
+X0 and that the train with its observer is moving at a speed v into
the +x direction.
The observations consist of both observers receiving the light signals
that communicate them of the strikes occurrence. Where in the world
are you seeing something related to measuring lengths?


c=176,000 miles /sec. Â*The mile is a unit of length. Â*The velocity of
the train is also measured in units of length divided by time. Â*In
addition to that, the train has a length that is measured in units of
length.
Robert B. Winn


And what are you trying to say with that?.
We are talking about the relativity of simultaneity, and that refers
to time relations, not to length contraction.
The whole point of this train thought experiment is to prove that time
is not absolute.


Miguel Rios- Hide quoted text -


- Show quoted text -


Relativity of simultaneity, as explained by Einstein, is dependent on
length contraction.


Actually, no it's not. You'll notice that the relativity of
simultaneity is established without needing to reference the distance
between the marks. However, you brought up the *additional*
information about the distance between the marks. In so doing, you
find out that there is a *consequence* of relativity of simultaneity:
relativity of length.


Â*If lightning strikes both ends of a train,
leaving marks on the ends of the train and marks on the track, the
only way the marks can be closer together than the length of the
train, as is required if the lightning at the front strikes first, is
if there is a distance contraction, as seen from the frame of
reference of the track.
Robert B. Winn- Hide quoted text -


Well, as I said, that would be the problem of people who believe it
exists. Â*I believe the Galilean transformation equations which
indicate that relativity of simultaneity and distance contraction do
not exist.


I know you believe that. That's Â*because you're ignorant of the
experimental data, I believe. If you're not interested enough in the
truth to investigate the data, then I'm under no compunction to make
you change your beliefs.


PD


Well, you talk about experiments. Â*Go ahead and tell us about one of
these experiments. Â*You were going to do this once before and then
changed your mind.
Robert B. Winn


I try wherever possible not to jump through the same hoop twice,
Bobby. Do you know how to research what's already been posted?- Hide quoted text -

I do. First you post it. Otherwise, it is just more mumbo jumbo.
If you think you have something go ahead and post it. Without even
looking at your references, I can tell you what they are. They are
refutations of the idea of absolute time that scientists were using
with the Galilean transformation equations to explain transmission of
light. It was called ether theory. I am not using ether theory.
Robert B. Winn