![]() |
| If this is your first visit, be sure to check out the FAQ by clicking the link above. You may have to register before you can post: click the register link above to proceed. To start viewing messages, select the forum that you want to visit from the selection below. |
|
|||||||
| Tags: einstein, fake |
|
|
Thread Tools | Display Modes |
|
#71
|
|||
|
|||
|
On Apr 29, 8:29�pm, Bryan Olson wrote:
rbwinn wrote: Bryan Olson wrote: rbwinn wrote: Look, after ten or twelve times of trying to get a scientist to admit that two clocks running at different rates cannot be represented by the equation t'=t, I think that this basic principle has been emphasized enough. There's no question that the same variable cannot represent two non-equal quantities. The problem is that you claim to use the Galilean transform, then you contradict the Galilean transform. I understand what you are saying. �You are a respected scientist and Party member, You must have me confused with someone else. Spoken like a scientist. �Only a scientist could claim that I am contradicting the Galilean transformation equations by using them. Spoken like a true kook. It's not the using and no one said it was. Exactly how am I contradicting the Galilean transformation equations? You say devices to measure time at rest in S' will find it to be something other than t'. The earth rotates on its axis the same number of times in S' as it does in S. The Sun rotates on its axis the same number of times in S' as it does in S. The planets revolve around the sun the same number of times in S' as they do in S. So how is t' different in S' than in S? Robert B. Winn |
| Ads |
|
#72
|
|||
|
|||
|
rbwinn wrote:
Bryan Olson wrote: rbwinn wrote: Bryan Olson wrote: rbwinn wrote: Look, after ten or twelve times of trying to get a scientist to admit that two clocks running at different rates cannot be represented by the equation t'=t, I think that this basic principle has been emphasized enough. There's no question that the same variable cannot represent two non-equal quantities. The problem is that you claim to use the Galilean transform, then you contradict the Galilean transform. I understand what you are saying. �You are a respected scientist and Party member, You must have me confused with someone else. Spoken like a scientist. �Only a scientist could claim that I am contradicting the Galilean transformation equations by using them. Spoken like a true kook. It's not the using and no one said it was. Exactly how am I contradicting the Galilean transformation equations? You say devices to measure time at rest in S' will find it to be something other than t'. The earth rotates on its axis the same number of times in S' as it does in S. The Sun rotates on its axis the same number of times in S' as it does in S. The planets revolve around the sun the same number of times in S' as they do in S. So how is t' different in S' than in S? Robert, *you* came up with n' for time measured in S', and *your* n' does not equal t in general. "How" time is different between frames is an interesting question (which has a well-established answer that many of us have tried to explain in this newsgroup), but you contradict Galileo's theory regardless of that issue. Contradicting Galileo's transform makes sense. His theory turns out not to hold when |v| is a significant fraction of the speed of light. Accepting Galileo's transform can also make sense. Considering the objects we encounter, "v c" holds with few exceptions. Galileo never had the chance to observe the phenomena that motivated development of the Lorentz transform and special relativity. What makes no sense is to do both simultaneously. To assert that time measured in S' will be n', while also holding that time in S' is t'=t, makes sense if and only if n'=t'=t in general. Robert, in your system n' does not equal t' in general. -- --Bryan |
|
#73
|
|||
|
|||
|
On Apr 29, 8:29�pm, Bryan Olson wrote:
rbwinn wrote: Bryan Olson wrote: rbwinn wrote: Look, after ten or twelve times of trying to get a scientist to admit that two clocks running at different rates cannot be represented by the equation t'=t, I think that this basic principle has been emphasized enough. There's no question that the same variable cannot represent two non-equal quantities. The problem is that you claim to use the Galilean transform, then you contradict the Galilean transform. I understand what you are saying. �You are a respected scientist and Party member, You must have me confused with someone else. Spoken like a scientist. �Only a scientist could claim that I am contradicting the Galilean transformation equations by using them. Spoken like a true kook. It's not the using and no one said it was. Exactly how am I contradicting the Galilean transformation equations? You say devices to measure time at rest in S' will find it to be something other than t'. No, Bryan, the earth rotates the same number of degrees whether observed fro S or S', the sun rotates the same number of degrees whether observed from S or S'. You do have this cesium clock running slower in S' than an identical clock in S. If a clock is running slower or faster, it can still be used with the Galilean transformation equations. You just have to determine the rate of the clock compared to t'. Robert B. Winn |
|
#74
|
|||
|
|||
|
On Apr 30, 8:10Â*pm, Bryan Olson wrote:
rbwinn wrote: Bryan Olson wrote: rbwinn wrote: Bryan Olson wrote: rbwinn wrote: Look, after ten or twelve times of trying to get a scientist to admit that two clocks running at different rates cannot be represented by the equation t'=t, I think that this basic principle has been emphasized enough. There's no question that the same variable cannot represent two non-equal quantities. The problem is that you claim to use the Galilean transform, then you contradict the Galilean transform. I understand what you are saying. �You are a respected scientist and Party member, You must have me confused with someone else. Spoken like a scientist. �Only a scientist could claim that I am contradicting the Galilean transformation equations by using them. Spoken like a true kook. It's not the using and no one said it was. Exactly how am I contradicting the Galilean transformation equations? You say devices to measure time at rest in S' will find it to be something other than t'. The earth rotates on its axis the same number of times in S' as it does in S. Â*The Sun rotates on its axis the same number of times in S' as it does in S. Â*The planets revolve around the sun the same number of times in S' as they do in S. Â*So how is t' different in S' than in S? Robert, *you* came up with n' for time measured in S', and *your* n' does not equal t in general. "How" time is different between frames is an interesting question (which has a well-established answer that many of us have tried to explain in this newsgroup), but you contradict Galileo's theory regardless of that issue. Contradicting Galileo's transform makes sense. His theory turns out not to hold when |v| is a significant fraction of the speed of light. Accepting Galileo's transform can also make sense. Considering the objects we encounter, "v c" holds with few exceptions. Galileo never had the chance to observe the phenomena that motivated development of the Lorentz transform and special relativity. What makes no sense is to do both simultaneously. To assert that time measured in S' will be n', while also holding that time in S' is t'=t, makes sense if and only if n'=t'=t in general. Robert, in your system n' does not equal t' in general. No, Bryan, scientists say that a cesium clock in S' is running slower than an identical clock in S. That means that it cannot be called t' in the Galilean transformation equations. Sorry, you would have to use a clock that is showing exactly the same time as a cesium clock in S. If you do not have a clock like that and are too lazy to construct one the way Eric Gisse and PD are, you might want to look at the cesium clock in S. That shows what a t' clock in S' would show. As for the slower clock in S', you will have to call the time on that clock by some other variable than t' if you want to use the Galilean transformation equations. This is really a moot point at this particular time, because I am fairly sure that there are no scientists who want to used the Galilean transformation equations. Just go ahead and use the Lorentz equations if that is what you want to do. Robert B. Winn |
|
#75
|
|||
|
|||
|
rbwinn wrote:
On Apr 30, 8:10 pm, Bryan Olson wrote: rbwinn wrote: Bryan Olson wrote: rbwinn wrote: Bryan Olson wrote: rbwinn wrote: Look, after ten or twelve times of trying to get a scientist to admit that two clocks running at different rates cannot be represented by the equation t'=t, I think that this basic principle has been emphasized enough. There's no question that the same variable cannot represent two non-equal quantities. The problem is that you claim to use the Galilean transform, then you contradict the Galilean transform. I understand what you are saying. �You are a respected scientist and Party member, You must have me confused with someone else. Spoken like a scientist. �Only a scientist could claim that I am contradicting the Galilean transformation equations by using them. Spoken like a true kook. It's not the using and no one said it was. Exactly how am I contradicting the Galilean transformation equations? You say devices to measure time at rest in S' will find it to be something other than t'. The earth rotates on its axis the same number of times in S' as it does in S. The Sun rotates on its axis the same number of times in S' as it does in S. The planets revolve around the sun the same number of times in S' as they do in S. So how is t' different in S' than in S? Robert, *you* came up with n' for time measured in S', and *your* n' does not equal t in general. "How" time is different between frames is an interesting question (which has a well-established answer that many of us have tried to explain in this newsgroup), but you contradict Galileo's theory regardless of that issue. Contradicting Galileo's transform makes sense. His theory turns out not to hold when |v| is a significant fraction of the speed of light. Accepting Galileo's transform can also make sense. Considering the objects we encounter, "v c" holds with few exceptions. Galileo never had the chance to observe the phenomena that motivated development of the Lorentz transform and special relativity. What makes no sense is to do both simultaneously. To assert that time measured in S' will be n', while also holding that time in S' is t'=t, makes sense if and only if n'=t'=t in general. Robert, in your system n' does not equal t' in general. No, Bryan, scientists say that a cesium clock in S' is running slower than an identical clock in S. That means that it cannot be called t' in the Galilean transformation equations. Calling it something else doesn't change the fact that time measured in S' is not equal to t. Sorry, you would have to use a clock that is showing exactly the same time as a cesium clock in S. If you do not have a clock like that and are too lazy to construct one the way Eric Gisse and PD are, you might want to look at the cesium clock in S. That shows what a t' clock in S' would show. As for the slower clock in S', you will have to call the time on that clock by some other variable than t' if you want to use the Galilean transformation equations. This is really a moot point at this particular time, because I am fairly sure that there are no scientists who want to used the Galilean transformation equations. Just go ahead and use the Lorentz equations if that is what you want to do. The choice is not arbitrary. We want to get things right. -- --Bryan |
|
#76
|
|||
|
|||
|
On May 1, 2:53Â*am, Bryan Olson wrote:
rbwinn wrote: On Apr 30, 8:10 pm, Bryan Olson wrote: rbwinn wrote: Bryan Olson wrote: rbwinn wrote: Bryan Olson wrote: rbwinn wrote: Look, after ten or twelve times of trying to get a scientist to admit that two clocks running at different rates cannot be represented by the equation t'=t, I think that this basic principle has been emphasized enough. There's no question that the same variable cannot represent two non-equal quantities. The problem is that you claim to use the Galilean transform, then you contradict the Galilean transform. I understand what you are saying. �You are a respected scientist and Party member, You must have me confused with someone else. Spoken like a scientist. �Only a scientist could claim that I am contradicting the Galilean transformation equations by using them. Spoken like a true kook. It's not the using and no one said it was. Exactly how am I contradicting the Galilean transformation equations? You say devices to measure time at rest in S' will find it to be something other than t'. The earth rotates on its axis the same number of times in S' as it does in S. Â*The Sun rotates on its axis the same number of times in S' as it does in S. Â*The planets revolve around the sun the same number of times in S' as they do in S. Â*So how is t' different in S' than in S? Robert, *you* came up with n' for time measured in S', and *your* n' does not equal t in general. "How" time is different between frames is an interesting question (which has a well-established answer that many of us have tried to explain in this newsgroup), but you contradict Galileo's theory regardless of that issue. Contradicting Galileo's transform makes sense. His theory turns out not to hold when |v| is a significant fraction of the speed of light. Accepting Galileo's transform can also make sense. Considering the objects we encounter, "v c" holds with few exceptions. Galileo never had the chance to observe the phenomena that motivated development of the Lorentz transform and special relativity. What makes no sense is to do both simultaneously. To assert that time measured in S' will be n', while also holding that time in S' is t'=t, makes sense if and only if n'=t'=t in general. Robert, in your system n' does not equal t' in general. No, Bryan, scientists say that a cesium clock in S' is running slower than an identical clock in S. That means that it cannot be called t' in the Galilean transformation equations. Calling it something else doesn't change the fact that time measured in S' is not equal to t. Sorry, you would have to use a clock that is showing exactly the same time as a cesium clock in S. Â*If you do not have a clock like that and are too lazy to construct one the way Eric Gisse and PD are, you might want to look at the cesium clock in S. Â*That shows what a t' clock in S' would show. Â*As for the slower clock in S', you will have to call the time on that clock by some other variable than t' if you want to use the Galilean transformation equations. Â*This is really a moot point at this particular time, because I am fairly sure that there are no scientists who want to used the Galilean transformation equations. Â*Just go ahead and use the Lorentz equations if that is what you want to do. The choice is not arbitrary. We want to get things right. Well, the Lorentz equations will give you a fairly close approximation of the time on the cesium clock in S'. It will be accurate enough to do anything that scientists of this particular time are going to do. Robert B. Winn |
|
#77
|
|||
|
|||
|
On Apr 27, 8:52 pm, Koobee Wublee wrote:
On Apr 27, 10:39 am, JanPB, the film critic wrote: On Apr 27, 8:58 am, Koobee Wublee wrote: “Was Einstein a fake?” asked John Farrell. Einstein was a nitwit, a plagiarist, and a liar. You can consider him a fake I suppose. Detailed responses to your claims (which are FAPP false) were posted many times on this NG already. This is a wishful thinking on your part. It is OK to fantasize, but it is not if you cannot tell what your fantasy is and what is not. shrug For those unfamiliar with Koobee - he is a crank of the "technical mumbo-jumbo" variety. So, a special crank of some sort that you are so scared sh*tless. shrug Unlike those who got stuck early on some elementary algebra or calculus issue, he got stuck at a bit higher level: basic differential geometry. Another interpretation which is the correct one is that Koobee Wublee has surpassed beyond differential geometry. After he has pointed out the problem associated with what is commonly believed, you remained confused. You have no ability to comprehend even the basic stuff. shrug Because of that he can easily generate reams of technical nonsense which "looks" reasonable to a layman. Boy, you are really insulting the ‘layman’, Mr. film critic. Answering this sort of thing takes time so people who do know this stuff usually don't bother. As I said, keeping silent is a very good strategy to prolong the nonsense in SR and GR. shrug After all, it makes no difference. Well, if you keep silent, you would not be embarrassed by Koobee Wublee that seems to be the tail-between-the-legs approach favored by Professors Carlip and Roberts. shrug You write complete nonsense, as usual. Not worth responding to. -- Jan Bielawski |
|
#78
|
|||
|
|||
|
On May 1, 7:42 pm, JanPB wrote:
On Apr 27, 8:52 pm, Koobee Wublee wrote: Well, if you keep silent, you would not be embarrassed by Koobee Wublee that seems to be the tail-between-the-legs approach favored by Professors Carlip and Roberts. shrug You write complete nonsense, as usual. Not worth responding to. Sometime ago, you promised to look through the mathematics I have posted on GR. In doing so, you were gun-ho about pointing out errors within. Well, it has been over a year. The mathematics I have presented is actually very simple. You must have choked on seeing the nonsense manifested by the beauty of mathematics in GR. Why don’t you just accept it and stop torment yourself? It took me a few weeks of denial to finally accept the nonsense in what I was taught. It was a great relief after I have finally accepted the nonsense in what I was taught. You are taking it much harder than I did. It has been several years for you, and your internal struggle is eating you away in which I fully understand. However, this is science that we are discussing and not the integrity of your mental health. The brief Koobee Wublee’s summarization of GR is once again presented as follows for your pleasure. Please enjoy one more time, and don’t ever complain about Koobee Wublee ever not reaching out and helping out that queer of England. * * * * General Theory of Relativity (GR) * * * * The development of GR first diverged from Newtonian physics around the middle of the nineteenth century, when Riemann wrote down the relationship of an actual displacement segment to how an observer observes this same displacement segment. ds^2 = g_ij dq^i dq^j Where ** ds = Invariant geometry in displacement ** g_ij = Elements of the metric ** dg^i = Observer’s choice of coordinate system ** i, j = 1, 2, 3 (3 spatial dimensions) The shortest distance through the actual space (invariant geometry) can now be computed using the calculus of variations. This was exactly how Christoffel did it in the famous geodesic equations. d^2q^n/ds^2 + g^nk (@g_ik/@q^j + @g_jk/@q^i - @g_ij/@q^k) @q^i/@s @q^j/ @s / 2 = 0 Where ** i, j, k, n = 1, 2, 3 ** @ = Partial derivative operator The quantities called the connection coefficients in the geodesic equations become the Christoffel symbols of the second kind below. Y^n_ij = g^nk (@g_ik/@q^j + @g_jk/@q^i - @g_ij/@q^k) / 2 Where ** d^2q^n/ds^2 + Y^n_ij @q^i/@s @q^j/@s = 0 However, due to the symmetry in the metric, there is at least another way of presenting the geodesic equations. d^2q^n/ds^2 + g^nk (@g_ik/@q^j - @g_ij/@q^k / 2) @q^i/@s @q^j/@s = 0 In doing so, the connection coefficients are very different from the Christoffel symbols of the second kind. Z^n_ij = g^nk @g_ik/@q^j - @g_ij/@q^k / 2 Where ** d^2q^n/ds^2 + Z^n_ij @q^i/@s @q^j/@s = 0 About a decade before the transition of the nineteenth and the twentieth centuries, Ricci defined the covariant derivative based on the geodesic equations and the connection coefficients. However, Ricci did not know there is another set of connection coefficients that are equally valid to describe the geodesic equations as the Christoffel symbols of the second kind. DX^n/Ds = dX^n/ds + Y^n_ij dq^i/ds X^j Where ** DX^n/DS = Covariant derivative on X, a vector The idea is to allow the covariant derivative of (X = dq^n/ds) to be null in accordance with the geodesic equations. However, mathematically there exists another operator that can achieve the exact same thing. EX^n/Es = dX^n/ds + Z^n_ij dq^i/ds X^j Where ** EX^n/ES = Another operator on X, a vector Ricci went on to derive (invent) the Riemann tensor which just like the metric is merely a matrix. The derivation takes us through the null geodesic variations. R^n_ikj = @Y^n_ij/@q^k - @Y^n_ik/@q^j + Y^n_kl Y^l_jk – Y^n_jl Y^l_ik Or R^n_ikj = @Y^n_ij/@q^k - @Y^n_ik/@q^j + Y^n_jl Y^l_ik – Y^n_jl Y^l_ik Ricci, however, only discovered the first tensor above while the second one is also very mathematically valid in accordance with the method of null geodesic variations. Ricci’s student Levi-Civita then invented the Ricci tensor based on the Riemann tensor derived by Ricci (the first equation above). R_ij = @Y^k_ij/@q^k - @Y^k_ik/@q^j + Y^k_kl Y^l_ij – Y^k_jl Y^l_ik Where ** R_ij = R^k_ikj The Ricci scalar follows as described below. R = g^ij R_ij Where ** g^ij = inverse of the matrix g_ij the metric After the introduction of the Lorentz transformation, the Goettingen group of physicists including Minkowski, Hilbert, Schwarzschild, and Klein extended Riemann’s description of curved space into a four- dimensional spacetime. ds^2 = g_ij dq^i dq^j Where ** ds = Invariant geometry in spacetime ** g_ij = Elements of the metric ** dg^i = Observer’s choice of coordinate system ** i, j = 0, 1, 2, 3 (1 temporal and 3 spatial dimensions) In 1915, Hilbert finally invented the following Lagrangian which does not even satisfy as a Lagrangian according to the variations of calculus. L = (H R + p c^2) sqrt(-det(g^ij)) Where ** L = Hilbert's Lagragian ** R = Ricci scalar ** p = density of matter ** det() = determinant of the matrix as operand ** H = a constant Hilbert then went on to take the partial derivative of this Lagrangian with respect to each element of the metric represented by g^ij and setting it to zero. @L/@g^ij = H sqrt(-det(g^ij)) @R/@g^ij - H R @det(g^ij)/@g^ij / sqrt(- det(g^ij)) / 2 - p c^2 @det(g^ij)/@g^ij / sqrt(-det(g^ij)) / 2 = 0 Where (mathematical identity) ** @R/@g^ij = R_ij ** @det(g^ij)/@g^ij = g_ij det(g^ij) The result is the set of Einstein field equations. R_ij - R g_ij / 2 = c^2 p g_ij / H / 2 Or G_ij = T_ij Where ** G_ij = R_ij - R g_ij / 2 ** T_ij = c^2 p g_ij / H / 2 Einstein played no role. His rediscovery of the equivalence principle also finds no role in the derivation. The derivation of GR is totally based on mathematical nonsense. Very soon after the introduction of the field equations, Schwarzschild discovered the following static and spherically symmetric solution (metric). ds^2 = c^2 (1 – R / (r^3 + R^3)^(1/3)) dt^2 – r^4 dr^2 / (r^3 + R^3) / ((r^3 + R^3)^(1/3) – R) – (r^3 + R^3)^(2/3) dO^2 Where ** R = G M / c^2 ** dO^2 = cos^2Phi dTheta^2 + dPhi^2 There are actually an infinite number of solutions (metric) to the field equations using the same set of coordinate system. The most popular one was derived by Hilbert in 1916 now called the Schwarzschild metric. ds^2 = c^2 (1 – 2 R / r) dt^2 – dr^2 / (1 – 2 R / r) – r^2 dO^2 Notice Schwarzschild’s original solution does not manifest black holes but Schwarzschild metric does. The following solution also as simple as the Schwarzschild metric does not manifest black holes as well. ds^2 = c^2 dt^2 / ( 1 + 2 R / r) – (1 + 2 R / r) dr^2 – (r + R)^2 dO^2 Although not all the static and spherically symmetric solutions degenerate to Newtonian law of gravity, all these three metrics above do. This means the universe must be expanding and finally collapsing back to itself. After observing the universe to be static, Einstein correctly identified the field equations and Newtonian law of gravity as not fit this observation. He cleverly introduced (pull out of his *ss) a negative mass density to counter the attraction of gravity. The reason is very simple. Positive mass manifests attraction in gravity; negative mass manifests repulsion in gravity. In order to hide the embarrassment of introducing negative mass in vacuum, he again cleverly called this quantity as the Cosmological constant. The development of GR at this stage is a total joke, but the nonsense did not end here. Friedman, Lemaitre, Robertson, and Walker discovered a non-static but spherically symmetric solution to the field equations called the Friedman-Lemaitre-Robertson-Walker (FLRW) metric. ds^2 = c^2 dt^2 – a^2 (dr^2 / (1 – r^2 / R^2) + r^2 dO^2) Where ** a = Function of t only ** R = Constant This means two of the field equations are ** (da/dt)^2 / a^2 + c^2 / R^2 / a^2 = 8 pi G p / 3 ** 2 d^2a/dt^2 / a + (da/dt)^2 / a^2 + c^2 / R^2 / a^2 = 8 pi G p We can very easily solve these differential equations. If R^2 = 0, ** a^2 = c^2 cosh^2(w(t+T)) / (w^2 R^2) ** p = 3 w^2 / (4 pi G) If R^2 0, ** a^2 = - c^2 cos^2(w(t+T)) / (w^2 R^2) ** p = - 3 w^2 / (4 pi G) Where ** w, T = Integration constants The density of the universe, p, must always remain constant. This means the universe must be static as observed back then. Even with the introduction of the Cosmological constant, the basic form of the solution above remains the same. The Cosmological becomes totally useless. The introduction of the Cosmological constant is the only blunder in Einstein’s contribution in GR. There are two problems with this FLRW metric. ** There is no solution combining the Schwarzschild metric and the FLRW metric. This means the FLRW metric does not satisfy the Newtonian law of gravity. Gravity is not caused by a curvature in spacetime in general but only the gravitational time dilation. ** When Lemaitre first then Hubble discovered the red shift of distant galaxies, there is no remedy for the FLRW metric to satisfy this observation even with the Cosmological constant. There are so many problems with GR right from the start. The most basic is even more embarrassing. Any diligent grade school children can identify the mathematical relationship below. Given that A = B C If (A = constant and B != 0), then (C = A / B). This blunder came as early as during Ricci’s time when the Riemann tensor which is merely a matrix was incorrectly identified as a tensor which means invariance to any coordinate transformation. Similarly, the metric is merely a matrix. Ricci deified the metric into a tensor. Mathematically, this can easily be proven wrong. We have two different geometries described by the same coordinate system with two different metrics. ** ds^2 = [g] * [dq^2] = g_ij dq^i dq^j ** ds'^2 = [g'] * [dq^2] = g'_ij dq^i dq^j Where ** ds^2 = Geometry #1 ** ds'^2 = Geometry #2 ** [g] = Metric #1 ** [g'] = Metric #2 ** [dq^2] = Coordinate system, same ** * = Dot/inner product of two matrices Or we have the same geometry described below by different metrics and different coordinate systems. One example involves the linearly rectangular and the spherically symmetric polar coordinate systems. ** ds^2 = [g] * [dq^2] = [g']* [dq'^2] ** ds^2 = g_ij dq^i dq^j = g'_ab dq'^a dq'^b The geometry, ds^2, must be invariant due to obvious reason. The choice of coordinate system, d[q^2], is observer dependent. This can only mean the metric, [g], must also be observer dependent. The metric, the Riemann, and the Ricci tensors cannot be tensors after all. All solutions to the field equations must be unique and independent of each one where all solutions must reference to the same choice of coordinate system in describing vastly different invariant geometries. What good is the set of field equations that can generate an infinite numbers of solutions to describe infinitely different and independent universes? What good is the set of field equations that can either generate a solution that manifests black holes and also ones that don’t? * * * * Malicious Troll McCullough’s Stupid Question * * * * The static and spherically symmetric solutions to the field equations in general take one such form below. ds^2 = c^2 dt^2 / (1 + K / R) – (1 + K / R) (dR/dr)^2 dr^2 – (R + K)^2 dO^2 Where ** R(r) = Function of r ** dO^2 = cos^2(Phi) dTheta^2 + dPhi^2 ** K = Integration constant ** dr, dTheta, dPhi = Choiced coordinate system Only if the following is true, you get the Schwarzschild metric. ** R = r - K Where ** K = 2 G M / c^2 If the following is true, you get Schwarzschild’s original solution which does not manifest any black holes. ** R = (r^3 + K^3)^(1/3) - K If the following is true, you get another solution just as simple as the Schwarzschild metric but without manifestation of black holes. ** R = r If the following is true, you get a constantly expanding universe that also obeys the Schwarzschild metric --- a trait that even the FLRW metric fails to do so. ** R = r / (1 + r^2 / K / L) Where ** L = Cosmic constant If the following is true, you get an accelerated expanding universe. ** R = r / (1 + r^2 / K / L + r^3 / K / L / N) Where ** L, N = Cosmic constants Each of these solutions is uniquely independent of the others. Claiming these solutions being the same is utter nonsense --- a misunderstanding on your part of failure to understand the metric is not a tensor but merely a matrix. In addition, the last two metrics prove the Birkhoff’s theorem wrong. |
|
#79
|
|||
|
|||
|
On May 1, 11:56*pm, Koobee Wublee wrote:
On May 1, 7:42 pm, JanPB wrote: On Apr 27, 8:52 pm, Koobee Wublee wrote: Well, if you keep silent, you would not be embarrassed by Koobee Wublee that seems to be the tail-between-the-legs approach favored by Professors Carlip and Roberts. *shrug You write complete nonsense, as usual. Not worth responding to. Sometime ago, you promised to look through the mathematics I have posted on GR. *In doing so, you were gun-ho about pointing out errors within. *Well, it has been over a year. Unfortunately, this proves nothing (besides my having not as much time to post to this NG as I had thought). It's really quite simple: 1. In general, it's easy to make false claims with bogus technical terminology, 2. In general, it's a lot of work to dissect such claims and expose them for what they are (namely, baloney). The technical complication of the argument makes it irrelevant to 99.9% of the population anyway - most of them will make their judgment based on common sense which obviously concludes that the probablity you are right is infinitesimal. The remaining 0.1% already knows your claims are nonsense from start to finish. -- Jan Bielawski |
|
#80
|
|||
|
|||
|
On May 2, 2:36 pm, JanPB wrote:
On May 1, 11:56 pm, Koobee Wublee wrote: Sometime ago, you promised to look through the mathematics I have posted on GR. In doing so, you were gun-ho about pointing out errors within. Well, it has been over a year. It's really quite simple: 1. In general, it's easy to make false claims with bogus technical terminology, Yes, but what I have presented was GR pre-1958, and it is an actual account of mathematical history. shrug 2. In general, it's a lot of work to dissect such claims and expose them for what they are (namely, baloney). The technical complication of the argument makes it irrelevant to 99.9% of the population anyway - most of them will make their judgment based on common sense which obviously concludes that the probablity you are right is infinitesimal. The remaining 0.1% already knows your claims are nonsense from start to finish. Therefore, your promise is worth nothing. shrug What I have presented is the reason why Einstein never received that Nobel Prize in GR as everyone thinks he should deserve. In fact, there is nothing the Einstein had contributed. Your idol is a nitwit, a plagiarist, and a liar. shrug Well, here is once again for you enjoyment. Upon request, I have SR as well. * * * * General Theory of Relativity (GR) * * * * The development of GR first diverged from Newtonian physics around the middle of the nineteenth century, when Riemann wrote down the relationship of an actual displacement segment to how an observer observes this same displacement segment. ds^2 = g_ij dq^i dq^j Where ** ds = Invariant geometry in displacement ** g_ij = Elements of the metric ** dg^i = Observer’s choice of coordinate system ** i, j = 1, 2, 3 (3 spatial dimensions) The shortest distance through the actual space (invariant geometry) can now be computed using the calculus of variations. This was exactly how Christoffel did it in the famous geodesic equations. d^2q^n/ds^2 + g^nk (@g_ik/@q^j + @g_jk/@q^i - @g_ij/@q^k) @q^i/@s @q^j/ @s / 2 = 0 Where ** i, j, k, n = 1, 2, 3 ** @ = Partial derivative operator The quantities called the connection coefficients in the geodesic equations become the Christoffel symbols of the second kind below. Y^n_ij = g^nk (@g_ik/@q^j + @g_jk/@q^i - @g_ij/@q^k) / 2 Where ** d^2q^n/ds^2 + Y^n_ij @q^i/@s @q^j/@s = 0 However, due to the symmetry in the metric, there is at least another way of presenting the geodesic equations. d^2q^n/ds^2 + g^nk (@g_ik/@q^j - @g_ij/@q^k / 2) @q^i/@s @q^j/@s = 0 In doing so, the connection coefficients are very different from the Christoffel symbols of the second kind. Z^n_ij = g^nk @g_ik/@q^j - @g_ij/@q^k / 2 Where ** d^2q^n/ds^2 + Z^n_ij @q^i/@s @q^j/@s = 0 About a decade before the transition of the nineteenth and the twentieth centuries, Ricci defined the covariant derivative based on the geodesic equations and the connection coefficients. However, Ricci did not know there is another set of connection coefficients that are equally valid to describe the geodesic equations as the Christoffel symbols of the second kind. DX^n/Ds = dX^n/ds + Y^n_ij dq^i/ds X^j Where ** DX^n/DS = Covariant derivative on X, a vector The idea is to allow the covariant derivative of (X = dq^n/ds) to be null in accordance with the geodesic equations. However, mathematically there exists another operator that can achieve the exact same thing. EX^n/Es = dX^n/ds + Z^n_ij dq^i/ds X^j Where ** EX^n/ES = Another operator on X, a vector Ricci went on to derive (invent) the Riemann tensor which just like the metric is merely a matrix. The derivation takes us through the null geodesic variations. R^n_ikj = @Y^n_ij/@q^k - @Y^n_ik/@q^j + Y^n_kl Y^l_jk – Y^n_jl Y^l_ik Or R^n_ikj = @Y^n_ij/@q^k - @Y^n_ik/@q^j + Y^n_jl Y^l_ik – Y^n_jl Y^l_ik Ricci, however, only discovered the first tensor above while the second one is also very mathematically valid in accordance with the method of null geodesic variations. Ricci’s student Levi-Civita then invented the Ricci tensor based on the Riemann tensor derived by Ricci (the first equation above). R_ij = @Y^k_ij/@q^k - @Y^k_ik/@q^j + Y^k_kl Y^l_ij – Y^k_jl Y^l_ik Where ** R_ij = R^k_ikj The Ricci scalar follows as described below. R = g^ij R_ij Where ** g^ij = inverse of the matrix g_ij the metric After the introduction of the Lorentz transformation, the Goettingen group of physicists including Minkowski, Hilbert, Schwarzschild, and Klein extended Riemann’s description of curved space into a four- dimensional spacetime. ds^2 = g_ij dq^i dq^j Where ** ds = Invariant geometry in spacetime ** g_ij = Elements of the metric ** dg^i = Observer’s choice of coordinate system ** i, j = 0, 1, 2, 3 (1 temporal and 3 spatial dimensions) In 1915, Hilbert finally invented the following Lagrangian which does not even satisfy as a Lagrangian according to the variations of calculus. L = (H R + p c^2) sqrt(-det(g^ij)) Where ** L = Hilbert's Lagragian ** R = Ricci scalar ** p = density of matter ** det() = determinant of the matrix as operand ** H = a constant Hilbert then went on to take the partial derivative of this Lagrangian with respect to each element of the metric represented by g^ij and setting it to zero. @L/@g^ij = H sqrt(-det(g^ij)) @R/@g^ij - H R @det(g^ij)/@g^ij / sqrt(- det(g^ij)) / 2 - p c^2 @det(g^ij)/@g^ij / sqrt(-det(g^ij)) / 2 = 0 Where (mathematical identity) ** @R/@g^ij = R_ij ** @det(g^ij)/@g^ij = g_ij det(g^ij) The result is the set of Einstein field equations. R_ij - R g_ij / 2 = c^2 p g_ij / H / 2 Or G_ij = T_ij Where ** G_ij = R_ij - R g_ij / 2 ** T_ij = c^2 p g_ij / H / 2 Einstein played no role. His rediscovery of the equivalence principle also finds no role in the derivation. The derivation of GR is totally based on mathematical nonsense. Very soon after the introduction of the field equations, Schwarzschild discovered the following static and spherically symmetric solution (metric). ds^2 = c^2 (1 – R / (r^3 + R^3)^(1/3)) dt^2 – r^4 dr^2 / (r^3 + R^3) / ((r^3 + R^3)^(1/3) – R) – (r^3 + R^3)^(2/3) dO^2 Where ** R = G M / c^2 ** dO^2 = cos^2Phi dTheta^2 + dPhi^2 There are actually an infinite number of solutions (metric) to the field equations using the same set of coordinate system. The most popular one was derived by Hilbert in 1916 now called the Schwarzschild metric. ds^2 = c^2 (1 – 2 R / r) dt^2 – dr^2 / (1 – 2 R / r) – r^2 dO^2 Notice Schwarzschild’s original solution does not manifest black holes but Schwarzschild metric does. The following solution also as simple as the Schwarzschild metric does not manifest black holes as well. ds^2 = c^2 dt^2 / ( 1 + 2 R / r) – (1 + 2 R / r) dr^2 – (r + R)^2 dO^2 Although not all the static and spherically symmetric solutions degenerate to Newtonian law of gravity, all these three metrics above do. This means the universe must be expanding and finally collapsing back to itself. After observing the universe to be static, Einstein correctly identified the field equations and Newtonian law of gravity as not fit this observation. He cleverly introduced (pull out of his *ss) a negative mass density to counter the attraction of gravity. The reason is very simple. Positive mass manifests attraction in gravity; negative mass manifests repulsion in gravity. In order to hide the embarrassment of introducing negative mass in vacuum, he again cleverly called this quantity as the Cosmological constant. The development of GR at this stage is a total joke, but the nonsense did not end here. Friedman, Lemaitre, Robertson, and Walker discovered a non-static but spherically symmetric solution to the field equations called the Friedman-Lemaitre-Robertson-Walker (FLRW) metric. ds^2 = c^2 dt^2 – a^2 (dr^2 / (1 – r^2 / R^2) + r^2 dO^2) Where ** a = Function of t only ** R = Constant This means two of the field equations are ** (da/dt)^2 / a^2 + c^2 / R^2 / a^2 = 8 pi G p / 3 ** 2 d^2a/dt^2 / a + (da/dt)^2 / a^2 + c^2 / R^2 / a^2 = 8 pi G p We can very easily solve these differential equations. If R^2 = 0, ** a^2 = c^2 cosh^2(w(t+T)) / (w^2 R^2) ** p = 3 w^2 / (4 pi G) If R^2 0, ** a^2 = - c^2 cos^2(w(t+T)) / (w^2 R^2) ** p = - 3 w^2 / (4 pi G) Where ** w, T = Integration constants The density of the universe, p, must always remain constant. This means the universe must be static as observed back then. Even with the introduction of the Cosmological constant, the basic form of the solution above remains the same. The Cosmological becomes totally useless. The introduction of the Cosmological constant is the only blunder in Einstein’s contribution in GR. There are two problems with this FLRW metric. ** There is no solution combining the Schwarzschild metric and the FLRW metric. This means the FLRW metric does not satisfy the Newtonian law of gravity. Gravity is not caused by a curvature in spacetime in general but only the gravitational time dilation. ** When Lemaitre first then Hubble discovered the red shift of distant galaxies, there is no remedy for the FLRW metric to satisfy this observation even with the Cosmological constant. There are so many problems with GR right from the start. The most basic is even more embarrassing. Any diligent grade school children can identify the mathematical relationship below. Given that A = B C If (A = constant and B != 0), then (C = A / B). This blunder came as early as during Ricci’s time when the Riemann tensor which is merely a matrix was incorrectly identified as a tensor which means invariance to any coordinate transformation. Similarly, the metric is merely a matrix. Ricci deified the metric into a tensor. Mathematically, this can easily be proven wrong. We have two different geometries described by the same coordinate system with two different metrics. ** ds^2 = [g] * [dq^2] = g_ij dq^i dq^j ** ds'^2 = [g'] * [dq^2] = g'_ij dq^i dq^j Where ** ds^2 = Geometry #1 ** ds'^2 = Geometry #2 ** [g] = Metric #1 ** [g'] = Metric #2 ** [dq^2] = Coordinate system, same ** * = Dot/inner product of two matrices Or we have the same geometry described below by different metrics and different coordinate systems. One example involves the linearly rectangular and the spherically symmetric polar coordinate systems. ** ds^2 = [g] * [dq^2] = [g']* [dq'^2] ** ds^2 = g_ij dq^i dq^j = g'_ab dq'^a dq'^b The geometry, ds^2, must be invariant due to obvious reason. The choice of coordinate system, d[q^2], is observer dependent. This can only mean the metric, [g], must also be observer dependent. The metric, the Riemann, and the Ricci tensors cannot be tensors after all. All solutions to the field equations must be unique and independent of each one where all solutions must reference to the same choice of coordinate system in describing vastly different invariant geometries. What good is the set of field equations that can generate an infinite numbers of solutions to describe infinitely different and independent universes? What good is the set of field equations that can either generate a solution that manifests black holes and also ones that don’t? * * * * Malicious Troll McCullough’s Stupid Question * * * * The static and spherically symmetric solutions to the field equations in general take one such form below. ds^2 = c^2 dt^2 / (1 + K / R) – (1 + K / R) (dR/dr)^2 dr^2 – (R + K)^2 dO^2 Where ** R(r) = Function of r ** dO^2 = cos^2(Phi) dTheta^2 + dPhi^2 ** K = Integration constant ** dr, dTheta, dPhi = Choiced coordinate system Only if the following is true, you get the Schwarzschild metric. ** R = r - K Where ** K = 2 G M / c^2 If the following is true, you get Schwarzschild’s original solution which does not manifest any black holes. ** R = (r^3 + K^3)^(1/3) - K If the following is true, you get another solution just as simple as the Schwarzschild metric but without manifestation of black holes. ** R = r If the following is true, you get a constantly expanding universe that also obeys the Schwarzschild metric --- a trait that even the FLRW metric fails to do so. ** R = r / (1 + r^2 / K / L) Where ** L = Cosmic constant If the following is true, you get an accelerated expanding universe. ** R = r / (1 + r^2 / K / L + r^3 / K / L / N) Where ** L, N = Cosmic constants Each of these solutions is uniquely independent of the others. Claiming these solutions being the same is utter nonsense --- a misunderstanding on your part of failure to understand the metric is not a tensor but merely a matrix. In addition, the last two metrics prove the Birkhoff’s theorem wrong. |
| Thread Tools | |
| Display Modes | |
|
|
Similar Threads
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| Discussion: Was Einstein a fake? | Pentcho Valev | Physics - General Discussion | 11 | April 22nd 07 08:25 PM |
| Discussion: Was Einstein a fake? | Pentcho Valev | The Theory of Relativity | 10 | April 22nd 07 08:25 PM |
| A Fake Rainbow? | The Dougster | Current Physics Research (Moderated) | 3 | March 21st 07 03:11 PM |
| The Nuclear Fake. | israel t | Physics - General (alternative forum) | 17 | January 25th 05 06:21 AM |
| Newton was a fake | Dnlzmmr | The Theory of Relativity | 37 | June 15th 04 01:12 PM |