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#11
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On Sun, 13 Apr 2008 19:55:49 -0700 (PDT), Jerry
wrote: On Apr 13, 9:14*pm, HW@....(Dr. Henri Wilson) wrote: On Mon, 7 Apr 2008 01:56:28 -0700 (PDT), Jerry wrote: On Apr 6, 4:31*pm, Steve Dorman wrote: OG wrote: But why does he continue to put the incorrect light curve on his website? Surely he must know that it removes all his credibility. It has been pointed out many times to Androcles and to Henri Wilson, that the light curve of Algol depends on the spectral band in which it is measured: http://www.astro.psu.edu/~mrichards/...h/journey.html Conventional eclipsing binary theory has no problem modeling these curves. The above paper makes a mockery of that statement. It is nothing but speculation from start to finish. What astronomers see when they view Algol type binaries is a willusion. The star may or may not involve an eclipsing pair. Most Algol type probably do not. The secondary spectrum could easily be a reflection from a large cool dead star or planet. BaTh might also expect the extinction rate in the associated EM control sphere to vary with wavelength, giving rise to different shaped brightness curves with wavelength. Emission theory cannot explain the spectral band dependence of the light curve at all. If you opened your eyes you would soon learn what BaTh can explain. There are many possibilities that haven't even been explored....and are not likely to be while Einsteiniana attracts so many brainwahsed fools. I have already shut you up about Sagnac, why don't you realise that most variable stars 'vary' because little planet earth is NOT the centre of the universe, as the religions preach, and starlight does not travel towards us at c but at c+v. No, you didn't "shut me up." I just got sick of your perpetual lies and megalomania. You are just too plain stupid to realize how worthless your theories are. You'll die soon enough, and the world will soon forget you as just another crackpot who never amounted to anything. Jerry You are so hopelessly indoctrinated you can't even accept plain truth no matter how glaringly obvious. All you are capable of doing is quoting from standard relativity texts. As I have shown, BaTh explains sagnac perfectly well by considering what happens in the inertial frame, just as SR does. SR says light moves at c in that frame and at c+/-v wrt the source. The ray travel times are different. BaTh says the rays move at c wrt the source and the frequencies are doppler shifted, which they must be. Both approaches produce the same answer. YOUR analysis of sagnac using the ROTATING frame is trivial nonsense. You are merely regarding the rotating apparatus viewed in the rotating frame as being identical to the nonrotating apparatus in the inertial frame. Henri Wilson. ASTC,BSc,DSc(T) www.users.bigpond.com/hewn/index.htm .....specialising in teaching physics to engineers and mathematicians.... |
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On Apr 14, 2:16*pm, HW@....(Dr. Henri Wilson) wrote:
[snip whining] YOUR analysis of sagnac using the ROTATING frame is trivial nonsense. You are merely regarding the rotating apparatus viewed in the rotating frame as being identical to the nonrotating apparatus in the inertial frame. It is, Ralph. What's the difference between a merry-go-round that is not rotating and a rotating merry-go-round that has a frame co-rotating with it? Henri Wilson. ASTC,BSc,DSc(T)www.users.bigpond.com/hewn/index.htm ....specialising in teaching physics to engineers and mathematicians.... |
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#13
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Eric Gisse wrote:
What's the difference between a merry-go-round that is not rotating and a rotating merry-go-round that has a frame co-rotating with it? The angle of a plumb line held by a rider. Trick question? -- tussock I'm like a box of chocolates; you never know what you're gunna get. |
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#14
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Dr. Henri Wilson wrote:
On Mon, 7 Apr 2008 01:56:28 -0700 (PDT), Jerry wrote: On Apr 6, 4:31 pm, Steve Dorman wrote: OG wrote: But why does he continue to put the incorrect light curve on his website? Surely he must know that it removes all his credibility. It has been pointed out many times to Androcles and to Henri Wilson, that the light curve of Algol depends on the spectral band in which it is measured: http://www.astro.psu.edu/~mrichards/...h/journey.html Conventional eclipsing binary theory has no problem modeling these curves. The above paper makes a mockery of that statement. It is nothing but speculation from start to finish. What astronomers see when they view Algol type binaries is a willusion. The star may or may not involve an eclipsing pair. Most Algol type probably do not. http://tinyurl.com/5ocloa ...showing that the secondary eclipse IS visible in IR. In November 2005 Henry Wilson wrote: "If the secondary eclipse IS visible in IR it probably REALLY is a secondary eclipse and not just a product of the BaTh. So what?" So Henri Wilson have admitted that Algol is an eclipsing binary. Had you forgotten that, Henri? The secondary spectrum could easily be a reflection from a large cool dead star or planet. BaTh might also expect the extinction rate in the associated EM control sphere to vary with wavelength, giving rise to different shaped brightness curves with wavelength. So when an A8 spectrum (A8 is close to B0) http://cass.ucsd.edu/public/tutorial...s/O-Gspect.gif is reflected off "a large cool star", it is mysteriously transformed to a K2 spectrum. http://cass.ucsd.edu/public/tutorial...s/G-Mspect.gif A very reasonable explanation indeed. :-) Nothing is so stupid that... you know the rest. :-) Emission theory cannot explain the spectral band dependence of the light curve at all. If you opened your eyes you would soon learn what BaTh can explain. There are many possibilities that haven't even been explored....and are not likely to be while Einsteiniana attracts so many brainwahsed fools. In November 2005 Henri Wilson reluctantly opened his eyes and realized that the emission theory cannot explain the spectral band dependence of the light curve at all. So he admitted: "If the secondary eclipse IS visible in IR it probably REALLY is a secondary eclipse and not just a product of the BaTh. So what?" So what, indeed! :-) Will Henri admit that he has admitted that the emission theory cannot explain the spectral band dependence of the light curve at all? :-) I predict he won't. Henri never admits having admitted what he has admitted. :-) I have already shut you up about Sagnac, why don't you realise that most variable stars 'vary' because little planet earth is NOT the centre of the universe, as the religions preach, and starlight does not travel towards us at c but at c+v. Ah. Sagnac! :-) We all know what Sagnac does to the emission theory, don't we? http://home.c2i.net/pb_andersen/pdf/sagnac_ring.pdf http://home.c2i.net/pb_andersen/pdf/...ror_sagnac.pdf http://home.c2i.net/pb_andersen/pdf/...optic_gyro.pdf http://home.c2i.net/pb_andersen/FourMirrorSagnac.html BTW, Henri. About half of all stars are components of binaries or multiples. Only a very few of them are variables. The emission theory predicts that the vast majority of the binaries should be variables. This makes it blatantly obvious that the emission theory is wrong. We simply do not observe what the emission theory predicts we should. -- Paul http://home.c2i.net/pb_andersen/ |
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On Tue, 15 Apr 2008 21:22:43 +0200, "Paul B. Andersen"
wrote: Dr. Henri Wilson wrote: On Mon, 7 Apr 2008 01:56:28 -0700 (PDT), Jerry wrote: Conventional eclipsing binary theory has no problem modeling these curves. The above paper makes a mockery of that statement. It is nothing but speculation from start to finish. What astronomers see when they view Algol type binaries is a willusion. The star may or may not involve an eclipsing pair. Most Algol type probably do not. http://tinyurl.com/5ocloa ..showing that the secondary eclipse IS visible in IR. In November 2005 Henry Wilson wrote: "If the secondary eclipse IS visible in IR it probably REALLY is a secondary eclipse and not just a product of the BaTh. So what?" So Henri Wilson have admitted that Algol is an eclipsing binary. Had you forgotten that, Henri? No. I have always stressed that stars with Algol type curves might or might not be really eclipsing. The secondary spectrum could easily be a reflection from a large cool dead star or planet. BaTh might also expect the extinction rate in the associated EM control sphere to vary with wavelength, giving rise to different shaped brightness curves with wavelength. So when an A8 spectrum (A8 is close to B0) http://cass.ucsd.edu/public/tutorial...s/O-Gspect.gif is reflected off "a large cool star", it is mysteriously transformed to a K2 spectrum. http://cass.ucsd.edu/public/tutorial...s/G-Mspect.gif A very reasonable explanation indeed. :-) Even YOU should know why some roses are red and others yellow in the same sunlight. Nothing is so stupid that... you know the rest. :-) Is physics still taught in Norway? Emission theory cannot explain the spectral band dependence of the light curve at all. If you opened your eyes you would soon learn what BaTh can explain. There are many possibilities that haven't even been explored....and are not likely to be while Einsteiniana attracts so many brainwahsed fools. In November 2005 Henri Wilson reluctantly opened his eyes and realized that the emission theory cannot explain the spectral band dependence of the light curve at all. So he admitted: "If the secondary eclipse IS visible in IR it probably REALLY is a secondary eclipse and not just a product of the BaTh. So what?" So what, indeed! :-) Will Henri admit that he has admitted that the emission theory cannot explain the spectral band dependence of the light curve at all? :-) I predict he won't. Henri never admits having admitted what he has admitted. :-) Henri has already explained such phenomena. Different bands tend to originate from slightly different levels...which makes the 'v' in c+v different. Also, the local extinction rate is presumably wavelength dependent. I have already shut you up about Sagnac, why don't you realise that most variable stars 'vary' because little planet earth is NOT the centre of the universe, as the religions preach, and starlight does not travel towards us at c but at c+v. Ah. Sagnac! :-) We all know what Sagnac does to the emission theory, don't we? http://home.c2i.net/pb_andersen/pdf/sagnac_ring.pdf http://home.c2i.net/pb_andersen/pdf/...ror_sagnac.pdf http://home.c2i.net/pb_andersen/pdf/...optic_gyro.pdf http://home.c2i.net/pb_andersen/FourMirrorSagnac.html All wrong. Quite hilarious really. BTW, Henri. About half of all stars are components of binaries or multiples. Only a very few of them are variables. The emission theory predicts that the vast majority of the binaries should be variables. Wrong. Quite hilarious really. This makes it blatantly obvious that the emission theory is wrong. We simply do not observe what the emission theory predicts we should. You have never bothered to investigate. How would you know? Henri Wilson. ASTC,BSc,DSc(T) www.users.bigpond.com/hewn/index.htm .....specialising in teaching physics to engineers and mathematicians.... |
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#16
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Dr. Henri Wilson wrote:
On Tue, 15 Apr 2008 21:22:43 +0200, "Paul B. Andersen" wrote: Dr. Henri Wilson wrote: On Mon, 7 Apr 2008 01:56:28 -0700 (PDT), Jerry wrote: Conventional eclipsing binary theory has no problem modeling these curves. The above paper makes a mockery of that statement. It is nothing but speculation from start to finish. What astronomers see when they view Algol type binaries is a willusion. The star may or may not involve an eclipsing pair. Most Algol type probably do not. http://tinyurl.com/5ocloa ..showing that the secondary eclipse IS visible in IR. In November 2005 Henry Wilson wrote: "If the secondary eclipse IS visible in IR it probably REALLY is a secondary eclipse and not just a product of the BaTh. So what?" So Henri Wilson have admitted that Algol is an eclipsing binary. Had you forgotten that, Henri? No. I have always stressed that stars with Algol type curves might or might not be really eclipsing. But since the secondary eclipse IS visible in IR, this statement of yours: If the secondary eclipse IS visible in IR it probably REALLY is a secondary eclipse and not just a product of the BaTh. So what? ...is an admission that Algol IS an eclipsing binary. The secondary spectrum could easily be a reflection from a large cool dead star or planet. BaTh might also expect the extinction rate in the associated EM control sphere to vary with wavelength, giving rise to different shaped brightness curves with wavelength. So when an A8 spectrum (A8 is close to B0) http://cass.ucsd.edu/public/tutorial...s/O-Gspect.gif is reflected off "a large cool star", it is mysteriously transformed to a K2 spectrum. http://cass.ucsd.edu/public/tutorial...s/G-Mspect.gif A very reasonable explanation indeed. :-) Even YOU should know why some roses are red and others yellow in the same sunlight. So you think the fact that roses come in multiple colours can defend this quite hillarious statement: The secondary [K2] spectrum could easily be a reflection [of an A8 spectrum] from a large cool dead star or planet. But you are possibly too stupid to understand the gigantic stupidity of this statement. Nothing is too stupid .. etc. Nothing is so stupid that... you know the rest. :-) Is physics still taught in Norway? Emission theory cannot explain the spectral band dependence of the light curve at all. If you opened your eyes you would soon learn what BaTh can explain. There are many possibilities that haven't even been explored....and are not likely to be while Einsteiniana attracts so many brainwahsed fools. In November 2005 Henri Wilson reluctantly opened his eyes and realized that the emission theory cannot explain the spectral band dependence of the light curve at all. So he admitted: "If the secondary eclipse IS visible in IR it probably REALLY is a secondary eclipse and not just a product of the BaTh. So what?" So what, indeed! :-) Will Henri admit that he has admitted that the emission theory cannot explain the spectral band dependence of the light curve at all? :-) I predict he won't. Henri never admits having admitted what he has admitted. :-) Henri has already explained such phenomena. Different bands tend to originate from slightly different levels...which makes the 'v' in c+v different. Also, the local extinction rate is presumably wavelength dependent. Should I remind you why you gave up these arguments back in 2005, when you ended up admitting that: If the secondary eclipse IS visible in IR it probably REALLY is a secondary eclipse and not just a product of the BaTh. So what? ? No, I won't bother. What you admit one day, you have forgotten the next. I have already shut you up about Sagnac, why don't you realise that most variable stars 'vary' because little planet earth is NOT the centre of the universe, as the religions preach, and starlight does not travel towards us at c but at c+v. Ah. Sagnac! :-) We all know what Sagnac does to the emission theory, don't we? http://home.c2i.net/pb_andersen/pdf/sagnac_ring.pdf http://home.c2i.net/pb_andersen/pdf/...ror_sagnac.pdf http://home.c2i.net/pb_andersen/pdf/...optic_gyro.pdf http://home.c2i.net/pb_andersen/FourMirrorSagnac.html All wrong. Quite hilarious really. I challenge you to point out a single error in those articles. We both know you won't do it because you can't. Sagnac falsifies the emission theory. No question about it. BTW, Henri. About half of all stars are components of binaries or multiples. Only a very few of them are variables. The emission theory predicts that the vast majority of the binaries should be variables. Wrong. Quite hilarious really. Please point out which of these statement are wrong: 1. About half of all stars are components of binaries or multiples. 2. Only a very few of them are variables. 3. The emission theory predicts that the vast majority of the binaries should be variables. We both know you won't do it because you can't. This makes it blatantly obvious that the emission theory is wrong. We simply do not observe what the emission theory predicts we should. You have never bothered to investigate. How would you know? From these statements which you are unable to refute: 1. About half of all stars are components of binaries or multiples. 2. Only a very few of them are variables. 3. The emission theory predicts that the vast majority of the binaries should be variables. it follows: It is blatantly obvious that the emission theory is wrong. We simply do not observe what the emission theory predicts we should. -- Paul http://home.c2i.net/pb_andersen/ |
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#17
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On Wed, 16 Apr 2008 16:28:07 +0200, "Paul B. Andersen"
wrote: Dr. Henri Wilson wrote: On Tue, 15 Apr 2008 21:22:43 +0200, "Paul B. Andersen" wrote: So Henri Wilson have admitted that Algol is an eclipsing binary. Had you forgotten that, Henri? No. I have always stressed that stars with Algol type curves might or might not be really eclipsing. But since the secondary eclipse IS visible in IR, this statement of yours: If the secondary eclipse IS visible in IR it probably REALLY is a secondary eclipse and not just a product of the BaTh. So what? ..is an admission that Algol IS an eclipsing binary. It is of little importance whether it is or is not. The undeniable fact according to BaTh, is that many stars in moderately eccentric orbit with their perihelia nearest Earth will exhibit brightness curves similar to genuinely eclipsing binaries. Spectral analysis may resolve the issue or it may be quite misleading. Having been completely misled for 100 years already, Einsteinian relativists are unlikely to notice the difference. The secondary spectrum could easily be a reflection from a large cool dead star or planet. BaTh might also expect the extinction rate in the associated EM control sphere to vary with wavelength, giving rise to different shaped brightness curves with wavelength. So when an A8 spectrum (A8 is close to B0) http://cass.ucsd.edu/public/tutorial...s/O-Gspect.gif is reflected off "a large cool star", it is mysteriously transformed to a K2 spectrum. http://cass.ucsd.edu/public/tutorial...s/G-Mspect.gif A very reasonable explanation indeed. :-) Even YOU should know why some roses are red and others yellow in the same sunlight. So you think the fact that roses come in multiple colours can defend this quite hillarious statement: The secondary [K2] spectrum could easily be a reflection [of an A8 spectrum] from a large cool dead star or planet. But you are possibly too stupid to understand the gigantic stupidity of this statement. Nothing is too stupid .. etc. Which is the star and which is the planet? Have you not considered the possible existence of binaries that consist of a small hot and bright star orbiting a very large cool object that appears maybe as bright as the star. In fact this configuration might explain some of the larger magnitude fluctuations that are observed. So what, indeed! :-) Will Henri admit that he has admitted that the emission theory cannot explain the spectral band dependence of the light curve at all? :-) I predict he won't. Henri never admits having admitted what he has admitted. :-) Henri has already explained such phenomena. Different bands tend to originate from slightly different levels...which makes the 'v' in c+v different. Also, the local extinction rate is presumably wavelength dependent. Should I remind you why you gave up these arguments back in 2005, when you ended up admitting that: If the secondary eclipse IS visible in IR it probably REALLY is a secondary eclipse and not just a product of the BaTh. So what? So what? Just because I others have finally exposed the relativity myth doesn't mean we can produce all the answers overninght. No, I won't bother. What you admit one day, you have forgotten the next. What I say one day you misquote the next. I have already shut you up about Sagnac, why don't you realise that most variable stars 'vary' because little planet earth is NOT the centre of the universe, as the religions preach, and starlight does not travel towards us at c but at c+v. Ah. Sagnac! :-) We all know what Sagnac does to the emission theory, don't we? http://home.c2i.net/pb_andersen/pdf/sagnac_ring.pdf http://home.c2i.net/pb_andersen/pdf/...ror_sagnac.pdf http://home.c2i.net/pb_andersen/pdf/...optic_gyro.pdf http://home.c2i.net/pb_andersen/FourMirrorSagnac.html All wrong. Quite hilarious really. I challenge you to point out a single error in those articles. We both know you won't do it because you can't. Sagnac falsifies the emission theory. No question about it. Sagnac is fully explained by BaTh. Absolutely no doubt about it. BTW, Henri. About half of all stars are components of binaries or multiples. Only a very few of them are variables. The emission theory predicts that the vast majority of the binaries should be variables. Wrong. Quite hilarious really. Please point out which of these statement are wrong: 1. About half of all stars are components of binaries or multiples. 2. Only a very few of them are variables. 3. The emission theory predicts that the vast majority of the binaries should be variables. We both know you won't do it because you can't. I have already explained that most would not be expected to vary because the conditions are not right. Here again are a few reasons: 1) If the members of binary pair are fairly similar, the sum of the individual brightness variations adds to nearly zero. (I have tried to explain that sinx+sin(x+180) = zero....but apparently trig functions are not taught in Norway.) 2) All the light emitted by close binaries leaves the vicinity at c wrt the barycentre of the pair, hence no expected variation. The individual contributions are still doppler shifted correctly. 3) The distance from earth is not conducive to brightness variation. 4) A statistical proportion of orbits are approximately face on to Earth. This makes it blatantly obvious that the emission theory is wrong. We simply do not observe what the emission theory predicts we should. You have never bothered to investigate. How would you know? From these statements which you are unable to refute: 1. About half of all stars are components of binaries or multiples. 2. Only a very few of them are variables. 3. The emission theory predicts that the vast majority of the binaries should be variables. it follows: It is blatantly obvious that the emission theory is wrong. We simply do not observe what the emission theory predicts we should. It really is a tragedy that people like yourself are so indoctrinated at an early age that they are quite incapable of seeing beyond their own belief system.. Henri Wilson. ASTC,BSc,DSc(T) www.users.bigpond.com/hewn/index.htm .....specialising in teaching physics to engineers and mathematicians.... |
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#18
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Dr. Henri Wilson wrote:
On Wed, 16 Apr 2008 16:28:07 +0200, "Paul B. Andersen" wrote: Dr. Henri Wilson wrote: On Tue, 15 Apr 2008 21:22:43 +0200, "Paul B. Andersen" wrote: So Henri Wilson have admitted that Algol is an eclipsing binary. Had you forgotten that, Henri? No. I have always stressed that stars with Algol type curves might or might not be really eclipsing. But since the secondary eclipse IS visible in IR, this statement of yours: If the secondary eclipse IS visible in IR it probably REALLY is a secondary eclipse and not just a product of the BaTh. So what? ..is an admission that Algol IS an eclipsing binary. It is of little importance whether it is or is not. The undeniable fact according to BaTh, is that many stars in moderately eccentric orbit with their perihelia nearest Earth will exhibit brightness curves similar to genuinely eclipsing binaries. Spectral analysis may resolve the issue or it may be quite misleading. Having been completely misled for 100 years already, Einsteinian relativists are unlikely to notice the difference. The fact is that the BaTh fails to predict what we observe. You have admitted that the obseved light curve of Algol in visible and IR can only be explained by the conventional theory, and that it is an eclipsing binary. But even if it is eclipsing, the BaTh still predicts a variation due to the motion of the components. This variation is _not_ opserved. The secondary spectrum could easily be a reflection from a large cool dead star or planet. BaTh might also expect the extinction rate in the associated EM control sphere to vary with wavelength, giving rise to different shaped brightness curves with wavelength. So when an A8 spectrum (A8 is close to B0) That should be A B8 spectrum. http://cass.ucsd.edu/public/tutorial...s/O-Gspect.gif is reflected off "a large cool star", it is mysteriously transformed to a K2 spectrum. http://cass.ucsd.edu/public/tutorial...s/G-Mspect.gif A very reasonable explanation indeed. :-) Even YOU should know why some roses are red and others yellow in the same sunlight. So you think the fact that roses come in multiple colours can defend this quite hillarious statement: The secondary [K2] spectrum could easily be a reflection [of an A8 spectrum] from a large cool dead star or planet. But you are possibly too stupid to understand the gigantic stupidity of this statement. Nothing is too stupid .. etc. Which is the star and which is the planet? There is no planet. The spectrum tells us that it is an B8 and a K2 star orbiting each other. Have you not considered the possible existence of binaries that consist of a small hot and bright star orbiting a very large cool object that appears maybe as bright as the star. That would be a hot (young) white dwarf orbiting a red giant. Sure there are binaries like that. So what? We are talking about Algol, which is a hot B8 star orbiting a cool K2 giant. The cool object is larger than hot hot object, but not brighter. In fact this configuration might explain some of the larger magnitude fluctuations that are observed. Was this meant to defend this statement of yours, which you said about Algol? The secondary [K2] spectrum could easily be a reflection [ of an B8 spectrum] from a large cool dead star or planet. You _are_ too stupid to grasp the idiocy of this statement, are you not? :-) So what, indeed! :-) Will Henri admit that he has admitted that the emission theory cannot explain the spectral band dependence of the light curve at all? :-) I predict he won't. Henri never admits having admitted what he has admitted. :-) Henri has already explained such phenomena. Different bands tend to originate from slightly different levels...which makes the 'v' in c+v different. Also, the local extinction rate is presumably wavelength dependent. Should I remind you why you gave up these arguments back in 2005, when you ended up admitting that: If the secondary eclipse IS visible in IR it probably REALLY is a secondary eclipse and not just a product of the BaTh. So what? So what? Just because I others have finally exposed the relativity myth doesn't mean we can produce all the answers overninght. And you have "exposed" that the conventional theory is wrong because it so very well explains what is observed? :-) And from this you conclude that the "BaTh" must be correct because it is unable to explain what is observed? :-) You are indeed doing very well now, are you not? :-) No, I won't bother. What you admit one day, you have forgotten the next. What I say one day you misquote the next. I have already shut you up about Sagnac, why don't you realise that most variable stars 'vary' because little planet earth is NOT the centre of the universe, as the religions preach, and starlight does not travel towards us at c but at c+v. Ah. Sagnac! :-) We all know what Sagnac does to the emission theory, don't we? http://home.c2i.net/pb_andersen/pdf/sagnac_ring.pdf http://home.c2i.net/pb_andersen/pdf/...ror_sagnac.pdf http://home.c2i.net/pb_andersen/pdf/...optic_gyro.pdf http://home.c2i.net/pb_andersen/FourMirrorSagnac.html All wrong. Quite hilarious really. I challenge you to point out a single error in those articles. We both know you won't do it because you can't. Sagnac falsifies the emission theory. No question about it. Sagnac is fully explained by BaTh. Absolutely no doubt about it. :-) BTW, Henri. About half of all stars are components of binaries or multiples. Only a very few of them are variables. The emission theory predicts that the vast majority of the binaries should be variables. Wrong. Quite hilarious really. Please point out which of these statement are wrong: 1. About half of all stars are components of binaries or multiples. 2. Only a very few of them are variables. 3. The emission theory predicts that the vast majority of the binaries should be variables. We both know you won't do it because you can't. I have already explained that most would not be expected to vary because the conditions are not right. Here again are a few reasons: 1) If the members of binary pair are fairly similar, the sum of the individual brightness variations adds to nearly zero. (I have tried to explain that sinx+sin(x+180) = zero....but apparently trig functions are not taught in Norway.) This is nonsense, and you know it. The predicted brightness variation from each component will almost never be sinusoidal, so they will not cancel each other. 2) All the light emitted by close binaries leaves the vicinity at c wrt the barycentre of the pair, hence no expected variation. The individual contributions are still doppler shifted correctly. Most binaries are not close. 3) The distance from earth is not conducive to brightness variation. 4) A statistical proportion of orbits are approximately face on to Earth. Sure. But those are the binaries we don't know about. The vast majority of known binaries are spectroscopic, and they are never face on to the Earth, of reasons so obvious that even you must understand it. http://lheawww.gsfc.nasa.gov/~corcoran/sb8.html You still haven't refuted any of these statements: 1. About half of all stars are components of binaries or multiples. 2. Only a very few of them are variables. 3. The emission theory predicts that the vast majority of the binaries should be variables. so the conclusion stands: It is blatantly obvious that the emission theory is wrong. We simply do not observe what the emission theory predicts we should. This makes it blatantly obvious that the emission theory is wrong. We simply do not observe what the emission theory predicts we should. You have never bothered to investigate. How would you know? From these statements which you are unable to refute: 1. About half of all stars are components of binaries or multiples. 2. Only a very few of them are variables. 3. The emission theory predicts that the vast majority of the binaries should be variables. it follows: It is blatantly obvious that the emission theory is wrong. We simply do not observe what the emission theory predicts we should. It really is a tragedy that people like yourself are so indoctrinated at an early age that they are quite incapable of seeing beyond their own belief system.. So you think I should convert to your belief system, and share your blind faith in a theory which is thorowly falsified? :-) -- Paul http://home.c2i.net/pb_andersen/ |
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#19
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"Paul B. Andersen" wrote in message
... | Dr. Henri Wilson wrote: | On Wed, 16 Apr 2008 16:28:07 +0200, "Paul B. Andersen" | wrote: | | Dr. Henri Wilson wrote: | On Tue, 15 Apr 2008 21:22:43 +0200, "Paul B. Andersen" | wrote: | | So Henri Wilson have admitted that Algol is an eclipsing binary. | Had you forgotten that, Henri? | No. I have always stressed that stars with Algol type curves might or might not | be really eclipsing. | But since the secondary eclipse IS visible in IR, this statement of yours: | | If the secondary eclipse IS visible in IR it probably REALLY is a secondary | eclipse and not just a product of the BaTh. So what? | ..is an admission that Algol IS an eclipsing binary. | | It is of little importance whether it is or is not. The undeniable fact | according to BaTh, is that many stars in moderately eccentric orbit with their | perihelia nearest Earth will exhibit brightness curves similar to genuinely | eclipsing binaries. | Spectral analysis may resolve the issue or it may be quite misleading. | Having been completely misled for 100 years already, Einsteinian relativists | are unlikely to notice the difference. | | The fact is that the BaTh fails to predict what we observe. The fact is that there should be a significant velocity curve if the eclipsing theory were credible. The fact is emission fact is a fact. The fact is Tusseladd is a proven liar and a jealous, prejudiced bigot, and as we know, dishonest through and through.) http://www.androcles01.pwp.blueyonde.../DeriveMC2.htm (Fox didn't write a single word of what Androcles "quoted" on his page above. Androcles is, as we know, dishonest through and through.) - ASSistant Professor Paul B. Andersen of Agder University College, Kristiansand, Norway. The fact is Mira doesn't have a tail, even if Andersen does. http://www.androcles01.pwp.blueyonde...rbit/Orbit.htm |
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#20
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On Fri, 18 Apr 2008 12:07:01 +0200, "Paul B. Andersen"
wrote: Dr. Henri Wilson wrote: On Wed, 16 Apr 2008 16:28:07 +0200, "Paul B. Andersen" wrote: It is of little importance whether it is or is not. The undeniable fact according to BaTh, is that many stars in moderately eccentric orbit with their perihelia nearest Earth will exhibit brightness curves similar to genuinely eclipsing binaries. Spectral analysis may resolve the issue or it may be quite misleading. Having been completely misled for 100 years already, Einsteinian relativists are unlikely to notice the difference. The fact is that the BaTh fails to predict what we observe. How would YOU know. You don't even understand the basics. You have admitted that the obseved light curve of Algol in visible and IR can only be explained by the conventional theory, and that it is an eclipsing binary. But even if it is eclipsing, the BaTh still predicts a variation due to the motion of the components. This variation is _not_ opserved. I have admitted no such thing. Whatever we observe is must be in accordance with BaTh. Light clearly moves at c wrt its source and c+v wrt the observer. The secondary spectrum could easily be a reflection from a large cool dead star or planet. BaTh might also expect the extinction rate in the associated EM control sphere to vary with wavelength, giving rise to different shaped brightness curves with wavelength. So when an A8 spectrum (A8 is close to B0) That should be A B8 spectrum. how weak is it? http://cass.ucsd.edu/public/tutorial...s/O-Gspect.gif is reflected off "a large cool star", it is mysteriously transformed to a K2 spectrum. http://cass.ucsd.edu/public/tutorial...s/G-Mspect.gif A very reasonable explanation indeed. :-) Even YOU should know why some roses are red and others yellow in the same sunlight. So you think the fact that roses come in multiple colours can defend this quite hillarious statement: The secondary [K2] spectrum could easily be a reflection [of an A8 spectrum] from a large cool dead star or planet. But you are possibly too stupid to understand the gigantic stupidity of this statement. Nothing is too stupid .. etc. Which is the star and which is the planet? There is no planet. The spectrum tells us that it is an B8 and a K2 star orbiting each other. What is the orbit eccentricity? Have you not considered the possible existence of binaries that consist of a small hot and bright star orbiting a very large cool object that appears maybe as bright as the star. That would be a hot (young) white dwarf orbiting a red giant. Sure there are binaries like that. So what? We are talking about Algol, which is a hot B8 star orbiting a cool K2 giant. The cool object is larger than hot hot object, but not brighter. I'm not particularly interested in Algol. Its brightness curve may or may not indicate an eclipse. It may or may no be a consequence of c+v variation. In fact this configuration might explain some of the larger magnitude fluctuations that are observed. Was this meant to defend this statement of yours, which you said about Algol? The secondary [K2] spectrum could easily be a reflection [ of an B8 spectrum] from a large cool dead star or planet. You _are_ too stupid to grasp the idiocy of this statement, are you not? :-) A small hot star refecting off a very large orbiting WCH could easily result in two different spectra, B and K, shifted 180 out of phase. If the secondary eclipse IS visible in IR it probably REALLY is a secondary eclipse and not just a product of the BaTh. So what? So what? Just because I others have finally exposed the relativity myth doesn't mean we can produce all the answers overninght. And you have "exposed" that the conventional theory is wrong because it so very well explains what is observed? :-) It doesn't. It tries to explain willusions and ends up in a helluva mess. And from this you conclude that the "BaTh" must be correct because it is unable to explain what is observed? :-) You are indeed doing very well now, are you not? :-) BaTh explains what is observed. We both know you won't do it because you can't. I have already explained that most would not be expected to vary because the conditions are not right. Here again are a few reasons: 1) If the members of binary pair are fairly similar, the sum of the individual brightness variations adds to nearly zero. (I have tried to explain that sinx+sin(x+180) = zero....but apparently trig functions are not taught in Norway.) This is nonsense, and you know it. The predicted brightness variation from each component will almost never be sinusoidal, so they will not cancel each other. Paul, run my program and see for yourself. I have done the work. You know nothing about the subject and continue to make a fool of yourself. Most binaries have fairly circular orbits. If the members are similar in size, their brightness curves almost cancel each other. In fact, if one is considerably larger than the other, it will move more slowly and have a smaller magnitude variation. But its larger size makes it brighter...so much of the cancellation remains. 2) All the light emitted by close binaries leaves the vicinity at c wrt the barycentre of the pair, hence no expected variation. The individual contributions are still doppler shifted correctly. Most binaries are not close. That's OK. see above. 3) The distance from earth is not conducive to brightness variation. 4) A statistical proportion of orbits are approximately face on to Earth. Sure. But those are the binaries we don't know about. The vast majority of known binaries are spectroscopic, and they are never face on to the Earth, of reasons so obvious that even you must understand it. http://lheawww.gsfc.nasa.gov/~corcoran/sb8.html You still haven't refuted any of these statements: 1. About half of all stars are components of binaries or multiples. 2. Only a very few of them are variables. 3. The emission theory predicts that the vast majority of the binaries should be variables. It does not. Usually the iindividual curves will canel each other. Read above. so the conclusion stands: It is blatantly obvious that the emission theory is wrong. We simply do not observe what the emission theory predicts we should. The only blatantly obvious conclusion is that you do not wish to improve your knowledge or mind. This makes it blatantly obvious that the emission theory is wrong. We simply do not observe what the emission theory predicts we should. You have never bothered to investigate. How would you know? From these statements which you are unable to refute: 1. About half of all stars are components of binaries or multiples. 2. Only a very few of them are variables. 3. The emission theory predicts that the vast majority of the binaries should be variables. it follows: It is blatantly obvious that the emission theory is wrong. We simply do not observe what the emission theory predicts we should. It really is a tragedy that people like yourself are so indoctrinated at an early age that they are quite incapable of seeing beyond their own belief system.. So you think I should convert to your belief system, and share your blind faith in a theory which is thorowly falsified? :-) BaTh is not a belief system. It is established fact. Every known light experiment supports it. Henri Wilson. ASTC,BSc,DSc(T) www.users.bigpond.com/hewn/index.htm .....specialising in teaching physics to engineers and mathematicians.... |
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