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Tensor curvature of space-time and orbits



 
 
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  #1  
Old March 28th 08 posted to rec.org.mensa,sci.physics,sci.physics.relativity
mitchgrav@hotmail.com
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Posts: 1,073
Default Tensor curvature of space-time and orbits

We cannot calculate the tensor for every point on an entire orbit (or
even less than that.) General Relativity does not take us forward
experimentally rather theoretically. Calculating an orbit with it
cannot be done to completion. We have approximation.

Mitch Raemsch Twice Nobel Laureate 2008
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  #3  
Old March 30th 08 posted to sci.physics.relativity
mitchgrav@hotmail.com
external usenet poster
 
Posts: 1,073
Default Tensor curvature of space-time and orbits

On Mar 29, 6:01*pm, The TimeLord wrote:
Am Fri, 28 Mar 2008 15:10:10 -0700 schrieb in
in
sci.physics.relativity:

We cannot calculate the tensor for every point on an entire orbit (or
even less than that.) *General Relativity does not take us forward
experimentally rather theoretically. Calculating an orbit with it cannot
be done to completion. We have approximation.


Why would you say something that silly? Of course you can calculate the
tensor for the entire orbit.

There is a different tensor for every point along an eliptical orbit.
For a circular orbit you would be right. There is infinite
calculations to be done.


Since the orbit is inertial, it's just a geodesic defined by the metric;
and that is one of the simplest things to calculate.


The fact is orbit motion speeds up toward perehlion and slows down
toward apehelion.



Mitch Raemsch Twice Nobel Laureate 2008


I doubt it.


I won for unmoving acceleration and wave function collapse.

Mitch Raemsch Twice Nobel Laureate 2008
  #4  
Old March 30th 08 posted to sci.physics.relativity
The TimeLord[_2_]
external usenet poster
 
Posts: 321
Default Tensor curvature of space-time and orbits

Am Sat, 29 Mar 2008 19:12:35 -0700 schrieb in
:

On Mar 29, 6:01Â*pm, The TimeLord wrote:
Am Fri, 28 Mar 2008 15:10:10 -0700 schrieb in
in
sci.physics.relativity:

We cannot calculate the tensor for every point on an entire orbit (or
even less than that.) Â*General Relativity does not take us forward
experimentally rather theoretically. Calculating an orbit with it
cannot be done to completion. We have approximation.


Why would you say something that silly? Of course you can calculate the
tensor for the entire orbit.

There is a different tensor for every point along an eliptical orbit.
For a circular orbit you would be right. There is infinite calculations
to be done.


If you mean that the (one) tensor changes value throughout the orbit,
I'll agree, but I don't see that the orbit *requires* more than one
tensor. As far as recalculating the tensor, that's really what computers
are for. At any rate, to get a closed form solution just start with the
metric and calculate the geodesic of the orbit: simple.



Since the orbit is inertial, it's just a geodesic defined by the
metric; and that is one of the simplest things to calculate.


The fact is orbit motion speeds up toward perehlion and slows down
toward apehelion.


So what, it's still included in the geodesic. Also the precession of the
orbit is included. So I don't see the problem.




Mitch Raemsch Twice Nobel Laureate 2008


I doubt it.


I won for unmoving acceleration and wave function collapse.

Mitch Raemsch Twice Nobel Laureate 2008


You are such a b---sh--er! The Nobel committee hasn't made the 2008
announcements yet and your name is not on the previous list:

http://topics.nytimes.com/top/news/s...es/index.html?
inline=nyt-classifier

Given that you are such a liar, I doubt you will ever be a Nobel Laureate.
 




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