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| Tags: apparent, fasterthanlight, mistake, travel, wheres |
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#31
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On Mar 12, 4:08*pm, (Daryl McCullough)
wrote: In article , says... On Mar 11, 9:08=A0pm, " wrote: Hello again, Assume I take a spaceship to Alpha Centauri, which is 4 light years away. And the ship goes so fast, that the travel time seems to me to be one hour. Will it not seem to me that Alpha Centauri made a journey that started at x=4[ly] and ended at x=0, during a time of one hour, and therefore its speed was much faster than lightspeed? Where is my mistake? Ram. Is there anyone interested in answering my question? First, note that your spaceship does *not* travel faster than light: if you sent a light signal towards Alpha Centauri at the same moment you launched your ship, the light signal would get there first. What your example illustrates is that the speed of light is only 300,000,000 meters per second if measured in an *inertial* coordinate system (Minkowsky coordinates). In a noninertial coordinate system, or in a curvilinear coordinate system, the speed of light can be position-dependent or time-dependent. From the accelerated coordinate system of a spaceship undergoing constant acceleration in the x-direction (as measured using on-board accelerometers), things seem very different from any inertial coordinate system: 1. There is an apparent "gravitational field" pushing things towards the rear of the spaceship. This field is not constant, but instead is stronger towards the rear of the spaceship and weaker towards the front of the spaceship. 2. The rate at which clocks advance (and the rate at which people get older) is position-dependent. Clocks run faster towards the front of the spaceship, and clocks run slower towards the rear of the spaceship. 3. The speed of a light signal is not constant; it varies with position. In the rear of the spaceship, the speed of light is slower, and in the front of the spaceship, the speed of light is faster. From the standpoint of this noninertial coordinate system, Alpha Centauri is in "freefall" under an enormous gravitational field (remember point 1: the apparent gravitational field is stronger the farther you get from the rear of the spaceship). So Alpha Centauri appears to be accelerating towards your spaceship at an enormous rate, quickly getting up to a speed that is much larger than 300,000,000 meters per second. If all this seems weird, it's because it's all just artifacts of using weird noninertial coordinates. That's why it's important in General Relativity especially to get clear about which effects are physical and which effects are artifacts of your coordinate system. -- Daryl McCullough Ithaca, NY Thank you Daryl! I think I understand. Correct me if I'm wrong: The law that says that objects can't move faster than light only applies when you are in an inertial frame, i.e. a frame that is not experiencing acceleration. When you are in an accelerating frame, things CAN go faster than light. So, for example, we on earth will correctly measure certain photons to be traveling faster than light, since we are in an accelerating frame. Is that true? |
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#32
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On Mar 11, 3:08*pm, "
wrote: Hello again, Assume I take a spaceship to Alpha Centauri, which is 4 light years away. And the ship goes so fast, that the travel time seems to me to be one hour. Will it not seem to me that Alpha Centauri made a journey that started at x=4[ly] and ended at x=0, during a time of one hour, and therefore its speed was much faster than lightspeed? Where is my mistake? Waking up this morning. |
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#33
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#34
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On Mar 12, 7:49*pm, (Daryl McCullough)
wrote: says... I think I understand. Correct me if I'm wrong: The law that says that objects can't move faster than light only applies when you are in an inertial frame, i.e. a frame that is not experiencing acceleration. When you are in an accelerating frame, things CAN go faster than light. Just for clarification: nothing ever goes faster than a light signal (at least not through vacuum), but things can go faster than 300,000,000 meters per second in an inertial frame (and so can light). So, for example, we on earth will correctly measure certain photons to be traveling faster than light, since we are in an accelerating frame. Is that true? I would rephrase this as follows: We can measure some photons to be traveling at a different speed than 300,000,000 meters per second. Near the surface of the Earth, photons travel radially outward at a slightly slower speed than this. As you get farther from the Earth, the radial speed of a photon increases, but it doesn't keep increasing without bound (unlike the accelerating rocket case). -- Daryl McCullough Ithaca, NY Thank you Daryl, and thanks to everyone who answered! Best Wishes, Ram. |
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#35
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On Mar 11, 2:08*pm, "
wrote: Hello again, Assume I take a spaceship to Alpha Centauri, which is 4 light years away. And the ship goes so fast, that the travel time seems to me to be one hour. Will it not seem to me that Alpha Centauri made a journey that started at x=4[ly] and ended at x=0, during a time of one hour, and therefore its speed was much faster than lightspeed? Where is my mistake? The answer is as follows: The passage of 1 hour of spaceship time = the passage of 35040 hours of earth time (or 4 years of earth time). In other words, the spaceship is moving at a speed that give rise to a gamma factor of 35040. The following link explains this new concept. http://www.geocities.com/kn_seto/2007IRT.pdf Ken Seto |
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#36
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"Dirk Van de moortel" wrote in message ... Martin Hogbin wrote in message wrote in message ... Hello again, Assume I take a spaceship to Alpha Centauri, which is 4 light years away. And the ship goes so fast, that the travel time seems to me to be one hour. Will it not seem to me that Alpha Centauri made a journey that started at x=4[ly] and ended at x=0, during a time of one hour, and therefore its speed was much faster than lightspeed? Where is my mistake? Does anyone know the name of the speed calculated by ram? Coordinate distance over proper time. I think it is called "proper velocity", or in this case "proper speed" Thanks, that is what I was looking for. I quick Google search shows that you are correct. Curious name, though.. -- Martin Hogbin |
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