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| Tags: apparent, fasterthanlight, mistake, travel, wheres |
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#21
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" wrote in
: On Mar 12, 12:20*am, "Dirk Van de moortel" dirkvandemoor...@ThankS-NO- SperM.hotmail.com wrote: wrote in message * On Mar 11, 9:08 pm, " wrote: Hello again, Assume I take a spaceship to Alpha Centauri, which is 4 light years away. And the ship goes so fast, that the travel time seems to me to be one hour. Will it not seem to me that Alpha Centauri made a journey that started at x=4[ly] and ended at x=0, during a time of one hour , and therefore its speed was much faster than lightspeed? Where is my mistake? Ram. Is there anyone interested in answering my question? Like David said, you divide a distance as measured in the Earth system (4ly) by the time measured on your lock (1 hour), but speed is defined as the ratio of distance to time both measured in the same frame. To you the distance looks shorter and to the Earth the time looks longer in such a way that both measure the same value for the speed. Dirk Vdm I did not change frames. We are talking about the frame of the spaceship. The ship was first at rest on earth, and then it accelerated towards Centauri. It is not inertial, true: Does that mean that objects can go faster than light in a non-inertial frame? Ram. Assume that someone in orbit around AC sends a pulse every year toward earth. You leave earth just as a pulse arrives. You intercept 8 pulses during your trip to AC. By your clock, they are 7.5 minutes apart. You measure their wavelength and frequency and compute the velocity from wavelength and frequency. You find it to be 'c'. You conclude that the distance from earth to AC is slightly more than 1/2 light hours. Nothing went faster than light. You compute your velocity as ~c/2 so it should take you an hour to travel the distance. [it is not important if I got the exact numbers right, the idea is correct per SR.] As you were told earlier, you were mixing measurements made in one frame [stationary frame, distance to AC] with measurements made in another frame[moving frame, time]. You can not do that and expect to get a correct answer. The distance and time need to be measured in the same Frame of Reference -- bz please pardon my infinite ignorance, the set-of-things-I-do-not-know is an infinite set. remove ch100-5 to avoid spam trap |
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#22
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On Mar 11, 9:02*pm, "N:dlzc D:aol T:com \(dlzc\)"
wrote: Dear xxein: "xxein" wrote in message ... On Mar 11, 6:44 pm, dlzc wrote: ... Is there anyone interested in answering my question? Answered. xxein: *Who is moving to have a timerate? All processes have a time rate. *Part of (or requirement of) the second law of thermodynamics. What determines a timerate? The System. David A. Smith xxein: Define the system. Why does c exist? |
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#23
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Dear xxein:
"xxein" wrote in message ... On Mar 11, 9:02 pm, "N:dlzc D:aol T:com \(dlzc\)" wrote: Dear xxein: "xxein" wrote in message ... On Mar 11, 6:44 pm, dlzc wrote: ... Is there anyone interested in answering my question? Answered. xxein: Who is moving to have a timerate? All processes have a time rate. Part of (or requirement of) the second law of thermodynamics. What determines a timerate? The System. xxein: Define the system. Everything you would / could assign coordinates (or mass / energy) to. Why does c exist? Coupling constant between "adjacent" *nows*. We are only ever in contact with a single point in both space and time, and light is the only messenger "between" points. The question is, is the evolution parameter between "decisions" (or choice and result) time, or is time only that which binds *now* to an ever evolving "Big Bang"? Do we have no free will, or do we mutually form the Universe around us? David A. Smith |
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#25
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On Mar 12, 2:05*am, Randy Poe wrote:
On Mar 11, 6:52*pm, " wrote: On Mar 12, 12:20*am, "Dirk Van de moortel" dirkvandemoor...@ThankS-NO- SperM.hotmail.com wrote: wrote in message * On Mar 11, 9:08 pm, " wrote: Hello again, Assume I take a spaceship to Alpha Centauri, which is 4 light years away. And the ship goes so fast, that the travel time seems to me to be one hour. Will it not seem to me that Alpha Centauri made a journey that started at x=4[ly] and ended at x=0, during a time of one hour, and therefore its speed was much faster than lightspeed? Where is my mistake? Ram. Is there anyone interested in answering my question? Like David said, you divide a distance as measured in the Earth system (4ly) by the time measured on your lock (1 hour), but speed is defined as the ratio of distance to time both measured in the same frame. To you the distance looks shorter and to the Earth the time looks longer in such a way that both measure the same value for the speed. Dirk Vdm I did not change frames. You are using numbers from two different frames. We are talking about the frame of the spaceship. The travel distance is not 4 light years in that frame. The ship was first at rest on earth, and then it accelerated towards Centauri. When it is moving at the very high gamma you proposed, the distance to Centauri is a small fraction of 4 light years in that frame. It is not inertial, true: Does that mean that objects can go faster than light in a non-inertial frame? Huh? * * * * * * * - Randy Randy: How is this two frames? How? Imagine a guy sitting in the spaceship. The ship is resting on earth, not moving. Then the ship accelerates and AC becomes closer, until eventually coming to the spaceships. I am talking about the frame of the guy in the spaceship? It is a non-inertial frame, true, but it's still a frame, isn't it? I mean, for that guy sitting in the ship, AC seemed to travel faster than light! It seems that the core of our argument is that you claim that these are two separate frames. Why? Is it because by "frame" you mean "inertial frame"? Best Wishes, Ram. |
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#26
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wrote in message ... On Mar 12, 2:05 am, Randy Poe wrote: On Mar 11, 6:52 pm, " wrote: On Mar 12, 12:20 am, "Dirk Van de moortel" dirkvandemoor...@ThankS-NO- SperM.hotmail.com wrote: wrote in message On Mar 11, 9:08 pm, " wrote: Hello again, Assume I take a spaceship to Alpha Centauri, which is 4 light years away. And the ship goes so fast, that the travel time seems to me to be one hour. Will it not seem to me that Alpha Centauri made a journey that started at x=4[ly] and ended at x=0, during a time of one hour, and therefore its speed was much faster than lightspeed? Where is my mistake? Ram. Is there anyone interested in answering my question? Like David said, you divide a distance as measured in the Earth system (4ly) by the time measured on your lock (1 hour), but speed is defined as the ratio of distance to time both measured in the same frame. To you the distance looks shorter and to the Earth the time looks longer in such a way that both measure the same value for the speed. Dirk Vdm I did not change frames. You are using numbers from two different frames. We are talking about the frame of the spaceship. The travel distance is not 4 light years in that frame. The ship was first at rest on earth, and then it accelerated towards Centauri. When it is moving at the very high gamma you proposed, the distance to Centauri is a small fraction of 4 light years in that frame. It is not inertial, true: Does that mean that objects can go faster than light in a non-inertial frame? Huh? - Randy | Randy: How is this two frames? How? Imagine a guy sitting in the | spaceship. The ship is resting on earth, not moving. Then the ship | accelerates No problem, we'll just add acceleration of AC to the list of things Poe doesn't believe in. | and AC becomes closer, That's frame hopping. AC accelerated, the rocket exhaust gas (fourth frame) moved away from AC twice as fast as the rocket moved toward AC. Net mass displacement zero. If you see AC coming toward you then AC accelerated without any exhaust. Magic. | until eventually coming to the | spaceships. I am talking about the frame of the guy in the spaceship? | It is a non-inertial frame, true, but it's still a frame, isn't it? Of course. So is the photon. So is the exhaust gas. | I | mean, for that guy sitting in the ship, AC seemed to travel faster | than light! No problem, we'll just add parallax to the list of things Poe doesn't believe in. | It seems that the core of our argument is that you claim that these | are two separate frames. Why? Because each has their own origin. Why? | Is it because by "frame" you mean | "inertial frame"? Einstein never once use the term "inertial" and did not mean inertial. "If we assume that the result proved for a polygonal line is also valid for a continuously curved line" Not that he ever proved the result for a polygonal line anyway... |
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#27
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#28
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On Mar 12, 3:24 am, "
wrote: On Mar 12, 2:05 am, Randy Poe wrote: On Mar 11, 6:52 pm, " wrote: On Mar 12, 12:20 am, "Dirk Van de moortel" dirkvandemoor...@ThankS-NO- SperM.hotmail.com wrote: wrote in message On Mar 11, 9:08 pm, " wrote: Hello again, Assume I take a spaceship to Alpha Centauri, which is 4 light years away. And the ship goes so fast, that the travel time seems to me to be one hour. Will it not seem to me that Alpha Centauri made a journey that started at x=4[ly] and ended at x=0, during a time of one hour, and therefore its speed was much faster than lightspeed? Where is my mistake? Ram. Is there anyone interested in answering my question? Like David said, you divide a distance as measured in the Earth system (4ly) by the time measured on your lock (1 hour), but speed is defined as the ratio of distance to time both measured in the same frame. To you the distance looks shorter and to the Earth the time looks longer in such a way that both measure the same value for the speed. Dirk Vdm I did not change frames. You are using numbers from two different frames. We are talking about the frame of the spaceship. The travel distance is not 4 light years in that frame. The ship was first at rest on earth, and then it accelerated towards Centauri. When it is moving at the very high gamma you proposed, the distance to Centauri is a small fraction of 4 light years in that frame. It is not inertial, true: Does that mean that objects can go faster than light in a non-inertial frame? Huh? - Randy Randy: How is this two frames? How? 1. Earth 2. Spaceship They have a relative velocity. How is that not two frames? Do you know what a frame of reference is? Imagine a guy sitting in the spaceship. The ship is resting on earth, not moving. It is at rest in the earth frame. Then the ship accelerates and AC becomes closer, As soon as the spaceship has a nonzero velocity relative to earth, it is now at rest in a different frame of reference than earth. Hence Lorentz transforms apply, as they do to any two frames with a relative velocity. until eventually coming to the spaceships. I am talking about the frame of the guy in the spaceship? It is a non-inertial frame, true, but it's still a frame, isn't it? Yes. And the earth is another. That makes two. I mean, for that guy sitting in the ship, AC seemed to travel faster than light! Wrong. That's where you get it wrong. His perception of the trip is not that he was moving faster than c at any point. It seems that the core of our argument is that you claim that these are two separate frames. Why? Is it because by "frame" you mean "inertial frame"? No, I mean "rest frame of earth" and "rest frame of spaceship". Why does it seem strange to you to say that during the trip, he is not at rest in the rest frame of the earth? Isn't the earth getting farther away? - Randy |
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#29
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#30
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wrote in message ... Hello again, Assume I take a spaceship to Alpha Centauri, which is 4 light years away. And the ship goes so fast, that the travel time seems to me to be one hour. Will it not seem to me that Alpha Centauri made a journey that started at x=4[ly] and ended at x=0, during a time of one hour, and therefore its speed was much faster than lightspeed? Where is my mistake? Does anyone know the name of the speed calculated by ram? -- Martin Hogbin |
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