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| Tags: gravity, revisited, speed |
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#361
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"Androcles" wrote in message ... "hanson" wrote in message ... ------------- ahahahahahaha ----------- ---------- ahahAHAHAahaha ---------- -------- AHAHAHAHAHAHAHA ----------- in http://groups.google.com/group/sci.p...547cca30?hl=en "Androcles" wrote ************************************* * Androcles 10, cha-cha-hanson 0 * ************************************* Thanks for your help. Own goals are always satisfying. hanson wrote: You are welcome. But be careful. There's an Ancient Celtic Proverb that says : "Self-Praise Stinks" .... ahahahaha... |
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#362
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On Oct 1, 3:09*am, "Tom Van Flandern" wrote:
Pentcho Valev writes: [Valev]: Does the speed of light vary with the frequency, in accordance with Einstein's 1911 equation c'=c(1+V/c^2), or is it the wavelength that varies with the frequency (as half of today's Einsteinians claim)? * * When the time coordinate is the proper time of the observer, the speed of light is invariant by construction. When coordinate time is used instead, the speed of light slows in a stronger potential field. For example, radar beams slow when passing the Sun in any analysis using barycentric coordinate time. This is called the "Shapiro effect". [Valev]: If Einstein's 1911 equation is correct, then perhaps light leaves the gravitational field of the emitting body, continues its journey and in the end reaches the observer having a reduced speed all along? * * Basically, you are correct. But it does depend on what you are using as a clock or time coordinate, which is why the answer is not simply "yes" or "no". -|Tom|- Tom Van Flandern - Sequim, WA - see our web site on frontier astronomy research at http://metaresearch.org You avoid (or are unable to give) a clear answer. Or perhaps my question was not clear enough so again: The observer measures the frequency shift to be: f'=f(1+V/c^2) as demonstrated by Pound and Rebka. Then, in accordance with the formula: frequency = (speed of light)/(wavelength) either the observer INDIRECTLY MEASURES the speed of light shift to be: c'=c(1+V/c^2) /1/ which is Einstein's 1911 equation, or the observer INDIRECTLY MEASURES the wavelength shift to be: L'=L/(1+V/c^2) /2/ as half of today's Einsteinians claim (the other half claim that Einstein's 1911 equation is correct). So which equation is correct: /1/ or /2/? Pentcho Valev |
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#363
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"Tom" wrote:
"Lorentzian relativity easily accommodates faster-than-light propagation and communication in forward time..." No, your erroneous claims about this have already been falsified. To repeat, both Lorentzian and Einsteinian relativity agree that the momentum of a particle goes to infinity as the speed of the particle approaches c. Therefore, regardless of interpretation, no material entity can be accelerated to a speed greater than c. "Tom" wrote: "...experiments showing gravitational force propagating faster-than- light in forward time falsify SR in favor of LR." If there were any such experiments, they would falsify both SR and LR, but there are no such experiments. Your erroneous claims about this have already been debunked. The interactactions of objects by relativistic fields obey conservation of momentum, and exhibit much less aberration than would occur for simplistic Laplacian-style non- relativistic interactions. The reason that the Laplacian aberration argument fails for relativistic field theories was already explained in 1900 by Poincare (yes, five years before Einstein's paper on special relativity). "Tom" wrote: "These two interpretations [field and geometric) of GR have the same math but different underlying physics." Your erroneous claims about this have already been debunked. Again, a theory of physics consists not just of equations, but of a mapping between the terms of those equations and the results of some empirical operations. If you begin with a successful scientific theory, and then assign empirically distinguishable meanings to the terms of the equations (compared with the meanings they have in the original theory), you do not thereby produce a different interpretation of the theory, you produce a different theory. Your theory makes different empirical predictions. You can then no longer claim that your theory passes all the empirical tests of the original theory. You are recognized as a charlatan because you perpetrate a mental shell game, by first claiming to espouse ideas that are empirically indistinguishable from some successful theory (so that you can claim the empirical successes of that theory) and then you immediately assert profound empirical differences for your "interpretation". "Tom" wrote: "The geometric interpretation lacks a cause to initiate 3-space motion..." Yawn. This old canard? Your erroneous claim has been debunked many times, revealing that you simply have a severe misunderstanding of the geometric interpretation, not to mention the rest of physics. Again, energy-momentum is explicitly conserved, at every time and place, in any relativistic field theory. There is an unambiguous flow of momentum and stress-energy. Hence your claims about "lacking a cause" are completely without merit. "Tom" wrote: "The geometric interpretation lacks ... a source for the new momentum of orbiting target bodies." Again, your erroneous claims have already been thoroughly debunked. Relativistic field theories fully and explicitly satisfy the conservation of momentum, both translational and angular. See the explanations of the Trouton and Noble experiment. Study it to the point where you can explain why the torque due to aberration of the force doesn't result in any rotation. (Hint, angular momentum is perfectly conserved.) "Tom" says "It requires ... the creation of new 3-space momentum out of nothing." That claim isn't just false, it's nonsense, because momentum inherently involves motion, which involves changes of spatial position in time. By referring to "3-space momentum", excluding time, you are simply gibbering. And even if you managed to stop gibbering and express a coherent claim about violation of energy-momentum conservation, the claim would be false, because energy-momentum is explicitly conserved at each time and place in relativistic field theories (including both electromagnetism and general relativity). "Tom" says "...is falsified by the axiom "no miracles allowed"..." Falsified by an axiom, huh? And of course your definition of "miracle" presumably includes the creation of 3-space momentum out of nothing. Actually, a real miracle would be if you ever stopped making your idiotic anti-scientific claims and finally learned something about science. Unfortunately, as it says on the big sign over the entrance to the Crackpot Clubhouse: No Miracles Allowed. "Tom" says "...the distinguishing characteristic of deep-reality physics." Yes, it's definitely deep. I wish I'd worn my boots. |
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