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Is the extrinsic curvature of a curve related to its 4-acceleration?



 
 
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Old February 29th 08 posted to sci.physics.relativity
babaluyee@gmail.com
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Posts: 20
Default Is the extrinsic curvature of a curve related to its 4-acceleration?

Say we have a curve embedded in a 2-D manifold. I actually have two
notions of curvature for this curve (not counting intrinsic since it's
zero). One is its extrinsic curvature and the other its 4-
acceleration. It seems to me they must be somehow related but I have
no clue how or what the equation relating them is (I'm aware that one
is a tensor and the other a vector). Also, what about higher
dimensional embeddings? Can the extrinsic curvature be related to 4-
acceleration of curves that generate the embedding?

Thanks for any help!

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  #2  
Old February 29th 08 posted to sci.physics.relativity
babaluyee@gmail.com
external usenet poster
 
Posts: 20
Default Is the extrinsic curvature of a curve related to its4-acceleration?

On Feb 28, 10:17*pm, wrote:
Say we have a curve embedded in a 2-D manifold. I actually have two
notions of curvature for this curve (not counting intrinsic since it's
zero). One is its extrinsic curvature and the other its 4-
acceleration. It seems to me they must be somehow related but I have
no clue how or what the equation relating them is (I'm aware that one
is a tensor and the other a vector). Also, what about higher
dimensional embeddings? Can the extrinsic curvature be related to 4-
acceleration of curves that generate the embedding?

Thanks for any help!


I guess the trace of extrinsic curvature of the curve is proportional
to the projection of its 4-acceleration onto its normal (I'm using the
definition of the extrinsic curvature that assumes that the normal
vector is tangent to a geodesic).
 




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